Spectral radius formula (Gelfand)
[62/60%]Find the norm, the spectral radius, the set of eigenvalues and the spectrum of an operator .
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Let be a Hilbert space, be a normal operator (for example, self-adjoint or unitary). Prove that
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An operator , where is a Banach space, is called quasinilpotent if . Prove that is quasinilpotent if and only if .
Consider the operator , which is defined by the formula .
find for all and ;
find ;
find and prove that it is a projector onto a one-dimensional subspace, which consists of constant functions.
Find the spectrum of the Volterra integral operator in with a continuous kernel , i.e., the operator , where .
Let be a Banach space, and . Prove that
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Are these statements correct if and do not commute?
Let and . Prove that .
The operator in is defined by the formula
Prove that .
Prove that for all .
Prove Theorem 12.1.
Theorem 12.1: Let be a Banach space. If , then the limit exists and
where is the spectral radius of the operator (Definition 12.2).
Find the spectrum, spectral radius, and resolvent of the operator in the spaces:
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Find the spectrum, spectral radius, and resolvent of the operator :
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Let be a Hilbert space, a normal operator. Prove that (see problem 8.78).
Let be a Banach space, and . Prove that
Prove that the integral operator
is a Volterra operator in the space
, if the function is continuous for ;
, if the function is measurable and bounded for .
Let be a Volterra operator and . Prove that the equation in a Banach space is solvable for every right-hand side and every . Prove that the solution is representable as the series .
Let be a complex infinite-dimensional Banach space, and . Is it true that is compact?
Let be a Banach space, and . Prove that .
If is a Banach algebra with identity and is the spectral radius, show that is upper semicontinuous. If such that , show that is continuous at .
Verify the statements made in the following example. A measurable function is called a Volterra kernel if is bounded and when . If and is a Volterra kernel, define by
Then and . If are Volterra kernels and , then is a Volterra kernel, , and . If is the characteristic function of , then is the Volterra operator. If is any Volterra kernel, then .
(McCabe) If is a complex Banach space and , show that the following statements are equivalent.
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for some positive integer .
for every in .
Define by for all in .
Show that .
Find and show that so that .
Show that is injective.
Find and show that is dense.
Define with and show that with .
For each operator ,
in the sense that the indicated limit always exists and has the indicated value.
Express the norm and the spectral radius of a weighted shift in terms of its weights.
For which sequences of positive numbers does there exist an operator such that , ?
The power norms of an operator , that is the numbers , constitute an interesting sequence.
If is a sequence of positive numbers such that is bounded, what, in terms of , is the spectral radius of the shift on ?
Let be a sequence of strictly positive numbers, and let be the set of complex sequences with . With respect to the coordinatewise linear operations and the inner product defined by
the set is a Hilbert space; it may be called a weighted sequence space.
Construct a quasinilpotent operator whose point spectrum is empty.
An operator is nilpotent if some positive integral power of it is zero (and the least such power is the index of nilpotence); an operator is quasinilpotent if . Nilpotence implies quasinilpotence. The spectral mapping theorem implies that if is nilpotent, then . The expression for the spectral radius in terms of norms implies that if is quasinilpotent, then , and, moreover, the converse is true. A nilpotent operator always has a non-trivial kernel, and hence a non-empty point spectrum; for quasinilpotent operators that is not so. (Observe that on finite-dimensional spaces such a construction is clearly impossible.)
Is every quasinilpotent operator analytic?
If is a quasinilpotent operator, and if is a function that is analytic in a neighborhood of , then has a power series expansion, , convergent when, say, ; in that case write . This operator series converges (in the norm), since for sufficiently large, so that for sufficiently large. The correspondence between functions analytic at and operators (for a fixed quasinilpotent operator ) is called a functional calculus; it is an extension of the trivial functional calculus for polynomials.
An operator is called algebraic if there exists a non-zero polynomial such that ; by a natural extension of language it seems proper to say that is analytic if there exists a non-zero function analytic at such that . Every nilpotent operator is algebraic.
Is the spectrum of a direct sum of operators always the closure of the union of their spectra?
The spectrum of the direct sum of two operators is the union of their spectra, and the same is true of the point spectrum, the approximate point spectrum, and the compression spectrum. The extension of this result from two direct summands to any finite number is a trivial induction.
Is it true that to each operator and to each positive number there corresponds a positive number such that if , then ? Equivalently: if , does it follow that ?
Note that the example of Problem 102 gives no information; in that case the spectral radius is equal to for each term of the sequence and also for the limit.
If and are operators such that for , does it follow that is quasinilpotent?
If small is interpreted in the sense of norm, a perturbation that produces only a small change in the spectrum does not have to be small: if, for instance, and , then , but is not small; in fact for all . The answer is clearly yes in some degenerate cases: if, for instance, is a scalar, and if for just one non-zero value of , then .
If , is similar to a contraction?
A Volterra operator with a bounded kernel is quasinilpotent.
A Volterra kernel is a kernel in (where is Lebesgue measure on the unit interval) such that when ; equivalently, a Volterra kernel is a Hilbert--Schmidt kernel that vanishes above the diagonal () of the unit square. The integral operator (a Volterra operator) induced by a Volterra kernel is given by
"Bounded" refers to the kernel, not the operator: the assumption is that is bounded almost everywhere in the unit square. An operator is quasinilpotent if .
Is every Volterra operator quasinilpotent?
A Volterra kernel is a kernel in (where is Lebesgue measure on the unit interval) such that when . The integral operator induced by a Volterra kernel is a Volterra operator, given by . An operator is quasinilpotent if .
If is hyponormal, then for every positive integer .
An operator such that is called hyponormal.
Compute the spectral radius of the Volterra operator on defined by the formula
Let be a commutative Banach algebra with unit. The radical of is defined to be the intersection of all maximal ideals of . Prove that the following three statements about an element are equivalent:
is in the radical of .
for every complex homomorphism of .
Find an element in a Banach algebra (for instance, a bounded linear operator on a Hilbert space) such that for all , but .
Suppose is a commutative Banach algebra with unit, and let be the set of all complex homomorphisms of , as in Sec. 18.16. Associate with each a function on by the formula
is called the Gelfand transform of . Prove that the mapping is a homomorphism of onto an algebra of complex functions on , with pointwise multiplication. Under what condition on is this homomorphism an isomorphism? (See Exercise 12).
Prove that the spectral radius is equal to
Prove that the range of the function is exactly the spectrum .
Define a shift operator and a multiplication operator on by
Put . Show that is a compact operator which has no eigenvalue and whose spectrum consists of exactly one point. Compute , for , and compute .
Use the identity to prove that and always have the same spectral radius.
Let be the right shift, acting on , as in Exercise 2. Let be a sequence of complex numbers such that but as . Define by
and define by .
Compute , for .
Show that .
Show that has no eigenvalue. (Its point spectrum is therefore empty, although its spectrum consists of a single point!)
Show that does not have a pole at 0.
Show that is a compact operator.
Prove that is commutative if there is a constant such that for all and in A. Hint: if is invertible in . Replace by , where and . Continue as in Theorem 12.16.
Prove that is commutative if for every . Hint: Show that . Use Exercise 1 to deduce that . Continue as in (a).
If for some and in a Banach algebra, prove that
Let be a large positive number, and define a norm on by
Let be the algebra of all complex 2-by-2 matrices, with the corresponding operator norm:
For , let be the conjugate transpose of . Consider a fixed , namely,
Prove the following statements.
; hence .
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Therefore commutativity is required in Theorem 11.23 and in Exercise 12.
If is the sum of the four entries in , for , then is a positive functional on .
The equality [see (e) of Theorem 11.31] does not hold, because and , so that .
If is the set of all positive functionals on that satisfy (as in Theorem 11.33), then has many extreme points, although 0 is the only multiplicative linear functional on . Commutativity is therefore required in the implication of Theorem 11.33.
Suppose is a Banach algebra, is an integer, , and
for every . Show that there exist constants , for , such that
(This extends Theorem 11.12).
Put . Define , where , by
so that , etc. (Note that is presented in its polar decomposition ).
Find . Compute that
Conclude that is one-to-one, that is dense in , and that . Define , with domain , by
Prove that is empty.
Let be a normed algebra over a complete normed field . Prove that if , then the limit exists
Prove that .