Section VII.3

The Spectrum

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Problem VII.3.1

Let SS be the unilateral shift on ℓ2\ell^2, the Hilbert space operator defined by S(x1,x2,x3,…)=(0,x1,x2,…)S(x_1, x_2, x_3, \ldots ) = (0, x_1, x_2, \ldots ). Show that SS is left invertible but not right invertible.

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Problem VII.3.2

If A\mathcal{A} is a Banach algebra with identity and a∈Aa \in \mathcal{A} and is nilpotent (that is, an=0a^n = 0 for some nn), then σ(a)={0}\sigma (a) = \{ 0\}.

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Problem VII.3.3

Let (X,Ω,μ)(X, \Omega , \mu ) be a σ\sigma-finite measure space and let A=L∞(X,Ω,μ)\mathcal{A} = L^\infty (X, \Omega , \mu ) (1.6). If ϕ∈A\phi \in \mathcal{A}, show that the following are equivalent:

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(a)

α∈σ(ϕ)\alpha \in \sigma (\phi );

(b)

0=sup⁡{inf⁡{∣ϕ(x)−α∣:x∈X∖Δ}:Δ∈Ω and μ(Δ)=0}0 = \sup \left\{ \inf \left\{ \left|\phi (x) - \alpha \right| : x \in X \setminus \Delta \right\} : \Delta \in \Omega \text{ and } \mu (\Delta ) = 0\right\};

(c)

if ε>0\varepsilon > 0, μ({x∈X:∣ϕ(x)−α∣<ε})>0\mu (\left\{ x \in X : \left|\phi (x) - \alpha \right| < \varepsilon \right\} ) > 0;

(d)

if ν\nu is the measure defined on the Borel subsets of C\mathbb {C} by ν(Δ)=μ(ϕ−1(Δ))\nu (\Delta ) = \mu (\phi^{-1}(\Delta )), then α∈\alpha \in the support of ν\nu.

Problem VII.3.4

If GG is an open subset of C\mathbb {C} and f:G→Xf: G \to \mathcal{X} is a function such that for each x∗x^* in X∗\mathcal{X}^*, x∗∘f:G→Cx^* \circ f: G \to \mathbb {C} is analytic, then ff is analytic. If the word continuous'' is substituted for both occurrences of the word analytic,'' is the preceding statement still true?

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Problem VII.3.5

If A\mathcal{A} is a Banach algebra with identity, {an}⊆A\{ a_n\} \subseteq \mathcal{A}, an→aa_n \to a, αn∈σ(an)\alpha_n \in \sigma (a_n), and αn→α\alpha_n \to \alpha, then α∈σ(a)\alpha \in \sigma (a).

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Problem VII.3.6

If A\mathcal{A} is a Banach algebra with identity and r:A→[0,∞)r: \mathcal{A} \to [0, \infty ) is the spectral radius, show that rr is upper semicontinuous. If a∈Aa \in \mathcal{A} such that r(a)=0r(a) = 0, show that rr is continuous at aa.

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Problem VII.3.7

If A\mathcal{A} is a Banach algebra with identity, a,b∈Aa, b \in \mathcal{A}, and α\alpha is a nonzero scalar such that (α−ab)(\alpha - ab) is invertible, show that (α−ba)(\alpha - ba) is invertible and (α−ba)−1=α−1+α−1b(α−ab)−1a(\alpha - ba)^{-1} = \alpha^{-1} + \alpha^{-1} b(\alpha - ab)^{-1} a. Show that σ(ab)∪{0}=σ(ba)∪{0}\sigma (ab) \cup \{ 0\} = \sigma (ba) \cup \{ 0\} and give an example such that σ(ab)≠σ(ba)\sigma (ab) \ne \sigma (ba).

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