Section VII.6

The Spectrum of a Linear Operator

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Problem VII.6.1

Prove the following proposition.

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(a)

If X\mathcal{X} is a Banach space and A∈B(X)A \in \mathcal{B}(\mathcal{X}), then σ(A∗)=σ(A)\sigma (A^*) = \sigma (A).

(b)

If H\mathcal{H} is a Hilbert space and A∈B(H)A \in \mathcal{B}(\mathcal{H}), then σ(A∗)=σ(A)∗\sigma (A^*) = \sigma (A)^*, where for any subset Δ\Delta of C\mathbb {C}, Δ∗≡{zˉ:z∈Δ}\Delta^* \equiv \left\{ \bar{z} : z \in \Delta \right\}.

Problem VII.6.2

Show that for X\mathcal{X} a Banach space and AA in B(X)\mathcal{B}(\mathcal{X}), σl(A)=σr(A∗)\sigma_l(A) = \sigma_r(A^*), where σl\sigma_l and σr\sigma_r denote the left and right spectra of AA. What happens in a Hilbert space?

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Problem VII.6.3

If H\mathcal{H} is an infinite dimensional Hilbert space and KK is a non-empty compact subset of C\mathbb {C}, show that there is an AA in B(H)\mathcal{B}(\mathcal{H}) such that σ(A)=K\sigma (A) = K. Can AA be found such that σ(A)=σap(A)=K\sigma (A) = \sigma_{ap}(A) = K?

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Problem VII.6.4

Let KK be a compact subset of C\mathbb {C}. Does there exist an operator AA in B(C[0,1])\mathcal{B}(C[0,1]) such that σ(A)=K\sigma (A) = K?

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Problem VII.6.5

If X\mathcal{X} is a Banach space and A∈B(X)A \in \mathcal{B}(\mathcal{X}), show that AA is left invertible if and only if ker⁡A=(0)\ker A = (0) and ran A\text{ran}\, A is a closed complemented subspace of X\mathcal{X}.

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Problem VII.6.6

If X\mathcal{X} is a Banach space and A∈B(X)A \in \mathcal{B}(\mathcal{X}), show that AA is right invertible if and only if ran A=X\text{ran}\, A = \mathcal{X} and ker⁡A\ker A is a complemented subspace of X\mathcal{X}.

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Problem VII.6.7

If X\mathcal{X} is a Banach space and T:X→XT: \mathcal{X} \to \mathcal{X} is an isometry, then either σ(T)⊆∂D\sigma (T) \subseteq \partial \mathbb {D} or σ(T)=cl D\sigma (T) = \text{cl}\, \mathbb {D}.

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Problem VII.6.8

Verify the statements made in the following example. Let {αn}∈ℓ∞\{ \alpha_n\} \in \ell^\infty, 1≤p≤∞1 \le p \le \infty, and define A:ℓp→ℓpA: \ell^p \to \ell^p by (Ax)(n)=αnx(n)(Ax)(n) = \alpha_n x(n). Then σ(A)=cl{αn}\sigma (A) = \text{cl}\{ \alpha_n\} and σp(A)={αn}\sigma_p(A) = \{ \alpha_n\}. For each kk, define Nk={n∈N:αn=αk}N_k = \left\{ n \in \mathbb {N} : \alpha_n = \alpha_k\right\} and define Pk:ℓp→ℓpP_k: \ell^p \to \ell^p by Pkx=χNkxP_k x = \chi_{N_k} x. If αk\alpha_k is an isolated point of σ(A)\sigma (A), then {αk}\{ \alpha_k\} is a clopen subset of σ(A)\sigma (A) and E({αk};A)=PkE(\{ \alpha_k\} ; A) = P_k.

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Problem VII.6.9

Let 1≤p≤∞1 \le p \le \infty and suppose 0<α1≤α2≤⋯0 < \alpha_1 \le \alpha_2 \le \cdots such that r=lim⁡αn<∞r = \lim \alpha_n < \infty. Define A:ℓp→ℓpA: \ell^p \to \ell^p by A(x1,x2,…)=(0,α1x1,α2x2,…)A(x_1, x_2, \ldots ) = (0, \alpha_1 x_1, \alpha_2 x_2, \ldots ). Show that σ(A)={z∈C:∣z∣≤r}\sigma (A) = \left\{ z \in \mathbb {C} : \left|z\right| \le r\right\} and σap(A)=∂σ(A)\sigma_{ap}(A) = \partial \sigma (A). If ∣λ∣<r\left|\lambda \right| < r, then ran(A−λ)\text{ran}(A - \lambda ) is closed and has codimension 11. Also, σp(A)=□\sigma_p(A) = \square.

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Problem VII.6.10

Verify the statements made in the following example. A measurable function k:[0,1]×[0,1]→Ck: [0,1] \times [0,1] \to \mathbb {C} is called a Volterra kernel if kk is bounded and k(x,y)=0k(x, y) = 0 when x<yx < y. If 1≤p≤∞1 \le p \le \infty and kk is a Volterra kernel, define Vk:Lp(0,1)→Lp(0,1)V_k: L^p(0,1) \to L^p(0,1) by

Vkf(x)=∫01k(x,y)f(y) dy=∫0xk(x,y)f(y) dy. V_k f(x) = \int _0^1 k(x, y) f(y) \, dy = \int _0^x k(x, y) f(y) \, dy.

Then Vk∈B(Lp)V_k \in \mathcal{B}(L^p) and ∥Vk∥≤∥k∥∞\left\| V_k\right\| \le \left\| k\right\|_\infty. If k,hk, h are Volterra kernels and (hk)(x,y)=∫01h(x,t)k(t,y) dt(hk)(x, y) = \int_0^1 h(x, t) k(t, y) \, dt, then hkhk is a Volterra kernel, ∥hk∥∞≤∥h∥∞∥k∥∞\left\| hk\right\|_\infty \le \left\| h\right\|_\infty \left\| k\right\|_\infty, and Vhk=VhVkV_{hk} = V_h V_k. If kk is the characteristic function of {(x,y)∈[0,1]×[0,1]:y<x}\left\{ (x,y) \in [0,1] \times [0,1] : y < x\right\}, then VkV_k is the Volterra operator. If kk is any Volterra kernel, then σ(Vk)={0}\sigma (V_k) = \{ 0\}.

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Problem VII.6.11

Let 1≤p≤∞1 \le p \le \infty and let (X,Ω,μ)(X, \Omega , \mu ) be a σ\sigma-finite measure space. For ϕ\phi in L∞(μ)L^\infty (\mu ), define MϕM_\phi on Lp(μ)L^p(\mu ) to be the multiplication operator Mϕf=ϕfM_\phi f = \phi f. Find σ(Mϕ)\sigma (M_\phi ), σap(Mϕ)\sigma_{ap}(M_\phi ), and σp(Mϕ)\sigma_p(M_\phi ).

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Problem VII.6.12

If A∈B(X)A \in \mathcal{B}(\mathcal{X}), f∈Hol(A)f \in \text{Hol}(A), and λ∈σp(A)\lambda \in \sigma_p(A), is f(λ)∈σp(f(A))f(\lambda ) \in \sigma_p(f(A))? If λ∈σap(A)\lambda \in \sigma_{ap}(A), is f(λ)∈σap(f(A))f(\lambda ) \in \sigma_{ap}(f(A))? Is there a relation between f(σap(A))f(\sigma_{ap}(A)) and σap(f(A))\sigma_{ap}(f(A))?

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Problem VII.6.13

If A∈B(X)A \in \mathcal{B}(\mathcal{X}), say that a complex number λ\lambda has finite index if there is a positive integer kk such that ker⁡(A−λ)k=ker⁡(A−λ)k+1\ker (A - \lambda )^k = \ker (A - \lambda )^{k+1}; the index of λ\lambda, denoted by ν(λ)\nu (\lambda ) or νA(λ)\nu_A(\lambda ), is the smallest such integer kk.

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(a)

Show that if λ\lambda is an isolated point of σ(A)\sigma (A) and a pole of order nn of (z−A)−1(z - A)^{-1}, then ν(λ)=n\nu (\lambda ) = n.

(b)

If ν(λ)<∞\nu (\lambda ) < \infty, show that ker⁡(A−λ)ν(λ)=ker⁡(A−λ)ν(λ)+k\ker (A - \lambda )^{\nu (\lambda )} = \ker (A - \lambda )^{\nu (\lambda ) + k} for all k≥0k \ge 0.

(c)

If X=Cn\mathcal{X} = \mathbb {C}^n and

A=[0101⋱⋱10], A = \begin{bmatrix} 0 & & & \\ 1 & 0 & & \\ & 1 & \ddots & \\ & & \ddots & \\ & & 1 & 0 \end{bmatrix},

then σ(A)={0}\sigma (A) = \{ 0\} and ν(0)=n\nu (0) = n.

Problem VII.6.14

If VV is the Volterra operator, show that 00 is an essential singularity of (z−V)−1(z - V)^{-1}.

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Problem VII.6.15

Let A\mathcal{A} be a Banach algebra with identity. If a∈Aa \in \mathcal{A}, define La,Ra∈B(A)L_a, R_a \in \mathcal{B}(\mathcal{A}) by La(x)=axL_a(x) = ax and Ra(x)=xaR_a(x) = xa. Show that σ(La)=σ(Ra)=σ(a)\sigma (L_a) = \sigma (R_a) = \sigma (a).

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Problem VII.6.16

If EE is a projection on a Hilbert space and EE is neither 00 nor 11, then σ(E)={0,1}\sigma (E) = \{ 0, 1\}.

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Problem VII.6.17

(McCabe) If X\mathcal{X} is a complex Banach space and T∈B(X)T \in \mathcal{B}(\mathcal{X}), show that the following statements are equivalent.

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(a)

r(T)<1r(T) < 1.

(b)

∥Tm∥<1\left\| T^m\right\| < 1 for some positive integer mm.

(c)

∑n∥Tn(x)∥<∞\sum_n \left\| T^n(x)\right\| < \infty for every xx in X\mathcal{X}.