Stopping times: definition, measurability and closure properties

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Give an example of a random variable TT and two filtrations {Fn}n≥1\left\{ \mathcal{F}_{n}\right\}_{n \geq 1} and {Gn}n≥1\left\{ \mathcal{G}_{n}\right\}_{n \geq 1} such that TT is a stopping time w.r.t. the filtration {Fn}n≥1\left\{ \mathcal{F}_{n}\right\}_{n \geq 1} but not w.r.t. {Gn}n≥1\left\{ \mathcal{G}_{n}\right\}_{n \geq 1}.

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Let T1T_{1} and T2T_{2} be stopping times w.r.t. a filtration {Fn}n≥1\left\{ \mathcal{F}_{n}\right\}_{n \geq 1}. Verify that min⁡(T1,T2),max⁡(T1,T2),T1+T2\min \left(T_{1}, T_{2}\right), \max \left(T_{1}, T_{2}\right), T_{1}+T_{2}, and T12T_{1}^{2} are stopping times w.r.t. {Fn}n≥1\left\{ \mathcal{F}_{n}\right\}_{n \geq 1}. Give an example to show that T1\sqrt{T_{1}} and T1−1T_{1}-1 need not be stopping times w.r.t. {Fn}n≥1\left\{ \mathcal{F}_{n}\right\}_{n \geq 1}.

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Let TT be a random variable taking values in {1,2,3,…}\left\{ 1,2,3, \ldots \right\}. Show that there is a filtration {Fn}n≥1\left\{ \mathcal{F}_{n}\right\}_{n \geq 1} w.r.t. which TT is a stopping time.

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Let {Fn}n≥1\left\{ \mathcal{F}_{n}\right\}_{n \geq 1} be a filtration.

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(a)

Show that TT is a stopping time w.r.t. {Fn}n≥1\left\{ \mathcal{F}_{n}\right\}_{n \geq 1} iff

{T≤n}∈Fn for all n≥1 \left\{ T \leq n\right\} \in \mathcal{F}_{n} \quad \text{ for all } \quad n \geq 1
(b)

Show by an example that if a random variable TT satisfies {T≥n}∈Fn\left\{ T \geq n\right\} \in \mathcal{F}_{n} for all n≥1n \geq 1, it need not be a stopping time w.r.t. {Fn}n≥1\left\{ \mathcal{F}_{n}\right\}_{n \geq 1}. (Hint: Consider a TT of the form

T=inf⁡{k:k≥1,Xk+1∈A} and Fn=σ⟨Xj:j≤n⟩. T = \inf \left\{ k: k \geq 1, X_{k+1} \in A\right\} \quad \text{ and } \quad \mathcal{F}_{n} = \sigma \left\langle X_{j}: j \leq n\right\rangle .

)

Show that FT\mathcal{F}_{T} defined in (2.6) is a σ\sigma-algebra.

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Prove all parts of Proposition 3.8.

Proposition 3.8: Suppose {Ft}\left\{ \mathcal{F}_{t}\right\} satisfies the usual conditions. Then

  1. TT is a stopping time if and only if (T≤t)∈Ft(T \leq t) \in \mathcal{F}_{t} for all tt.

  2. If T=tT=t, a.s., then TT is a stopping time.

  3. If SS and TT are stopping times, then so are S∨TS \vee T and S∧TS \wedge T.

  4. If Tn,n=1,2,…T_{n}, n=1,2, \ldots, are stopping times with T1≤T2≤⋯T_{1} \leq T_{2} \leq \cdots, then so is sup⁡nTn\sup_{n} T_{n}.

  5. If Tn,n=1,2,…T_{n}, n=1,2, \ldots, are stopping times with T1≥T2≥⋯T_{1} \geq T_{2} \geq \cdots, then so is inf⁡nTn\inf_{n} T_{n}.

  6. If s≥0s \geq 0 and SS is a stopping time, then so is S+sS+s.

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If TnT_{n} is defined by (3.2), show TnT_{n} is a stopping time for each nn and Tn↓TT_{n} \downarrow T.

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This exercise gives an alternate definition of FT\mathcal{F}_{T} which is more appealing, but not as useful. Suppose that {Ft}\left\{ \mathcal{F}_{t}\right\} satisfies the usual conditions. Show that FT\mathcal{F}_{T} is equal to the σ\sigma-field generated by the collection of random variables YTY_{T} such that YY is a bounded process with paths that are right continuous with left limits and YY is adapted to the filtration {Ft}\left\{ \mathcal{F}_{t}\right\}.

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Suppose {Ft}\left\{ \mathcal{F}_{t}\right\} is a filtration satisfying the usual conditions. Show that if TT is a stopping time, then TT is FT\mathcal{F}_{T} measurable.

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Suppose {Ft}\left\{ \mathcal{F}_{t}\right\} is a filtration satisfying the usual conditions and TT is a stopping time. Show that if SS is a FT\mathcal{F}_{T} measurable random variable with S≥TS \geq T, then SS is a stopping time.

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Suppose {Ft}\left\{ \mathcal{F}_{t}\right\} is a filtration satisfying the usual conditions. Show that if SS and TT are stopping times and XX is a bounded F∞\mathcal{F}_{\infty } measurable random variable, then

E[E[X∣FS]∣FT]=E[X∣FS∧T] \mathbb {E}\left[\mathbb {E}\left[X \mid \mathcal{F}_{S}\right] \mid \mathcal{F}_{T}\right]=\mathbb {E}\left[X \mid \mathcal{F}_{S \wedge T}\right]

Hint: Let Yt=E[X∣Ft]Y_{t}=\mathbb {E}\left[X \mid \mathcal{F}_{t}\right] and Zt=Yt∧SZ_{t}=Y_{t \wedge S}. Show the left-hand side is equal to YS∧TY_{S \wedge T}.

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Let WtW_{t} be a Brownian motion and {Ft}\left\{ \mathcal{F}_{t}\right\} be the minimal augmented filtration generated by WW. Let

T=inf⁡{t>0:Wt=sup⁡0≤s≤1Ws} T=\inf \left\{ t>0: W_{t}=\sup _{0 \leq s \leq 1} W_{s}\right\}

Show that TT is not a stopping time with respect to {Ft}\left\{ \mathcal{F}_{t}\right\}.

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Let XX be a bounded adapted right-continuous process, let ε>0\varepsilon >0, let U0=0U_{0}=0, a.s., and define UiU_{i} by (16.3) for i≥1i \geq 1. Show each UiU_{i} is a stopping time.

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Let (Ft)t⩾0\left(\mathscr {F}_{t}\right)_{t \geqslant 0} be a filtration and τ\tau an optional time with respect to it. Introduce the σ\sigma-algebra

Fτ+={A∈F:A∩{τ<t}∈Ft for every t⩾0}. \mathscr {F}_{\tau +} = \left\{ A \in \mathscr {F}: A \cap \left\{ \tau < t\right\} \in \mathscr {F}_{t} \text{ for every } t \geqslant 0\right\} .

Can one assert that in relation (51) the σ\sigma-algebra G=Fσ+\mathscr {G} = \mathscr {F}_{\sigma +}?

Relation (51) arises in the proof of Lemma 7. Lemma 7: let X=(Xt,Ft)t⩾0X = \left(X_{t}, \mathscr {F}_{t}\right)_{t \geqslant 0} be a martingale with a.s. right-continuous sample paths, and let σ\sigma and τ\tau be optional times (with respect to the filtration F=(Ft)t⩾0\mathbb {F} = \left(\mathscr {F}_{t}\right)_{t \geqslant 0}) such that σ⩽τ⩽c\sigma \leqslant \tau \leqslant c a.s., where cc is a positive constant; then E[Xτ]=E[Xσ]\mathbb {E}\left[X_{\tau }\right] = \mathbb {E}\left[X_{\sigma }\right]. In the proof one sets σ(n)=2−n[2nσ+1]\sigma (n) = 2^{-n}\left[2^{n} \sigma +1\right], n∈Nn \in \mathbb {N}, where [⋅][\cdot ] denotes the integer part of a number, and

G=⋂n=1∞F‾σ(n)(51) \mathscr {G} = \bigcap _{n = 1}^{\infty } \overline{\mathscr {F}}_{\sigma (n)} \tag {51}

where A‾=σ{A,N}\overline{\mathscr {A}} = \sigma \left\{ \mathscr {A}, \mathscr {N}\right\} for a σ\sigma-algebra A\mathscr {A}, and N\mathscr {N} is the class of P\mathbb {P}-null sets.

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(a)

Let JJ be a stopping rule and I{J≥n}\mathbb {I}_{\left\{ J \geq n\right\} } be the indicator rv of the event {J≥n}\left\{ J \geq n\right\}. Show that J=∑n≥1I{J≥n}J = \sum_{n \geq 1} \mathbb {I}_{\left\{ J \geq n\right\} }.

(b)

Show that I{J≥1}≥I{J≥2}≥…\mathbb {I}_{\left\{ J \geq 1\right\} } \geq \mathbb {I}_{\left\{ J \geq 2\right\} } \geq \ldots, i.e., show that for each n≥1n \geq 1, I{J≥n}(ω)≥I{J≥n+1}(ω)\mathbb {I}_{\left\{ J \geq n\right\} }(\omega ) \geq \mathbb {I}_{\left\{ J \geq n+1\right\} }(\omega ) for each ω∈Ω\omega \in \Omega (except perhaps for a set of probability 0).

This is a very simple exercise designed to clarify confusion about the roles of past, present, and future in stopping rules. Let {Xn;n≥1}\left\{ X_{n}; n \geq 1\right\} be a sequence of IID binary rv's, each with the pmf pX(1)=1/2\mathsf{p}_{X}(1) = 1/2, pX(0)=1/2\mathsf{p}_{X}(0) = 1/2. Let JJ be a positive integer-valued rv that takes on the sample value nn of the first trial for which Xn=1X_{n} = 1. That is, for each n≥1n \geq 1,

{J=n}={X1=0,  X2=0,…,Xn−1=0,  Xn=1}. \left\{ J = n\right\} = \left\{ X_{1} = 0, \; X_{2} = 0, \ldots , X_{n-1} = 0, \; X_{n} = 1\right\} .
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(a)

Use the definition of stopping trial, Definition 5.5.1 (a stopping trial, or stopping time, JJ for a sequence of rv's X1,X2,…X_{1}, X_{2}, \ldots is a positive, integer-valued rv such that the indicator function of the event {J=n}\left\{ J = n\right\} is a function of X1,…,XnX_{1}, \ldots , X_{n} for each n≥1n \geq 1), to show that JJ is a stopping trial for {Xn;n≥1}\left\{ X_{n}; n \geq 1\right\}.

(b)

Show that for any given nn, the rv's XnX_{n} and IJ=n\mathbb {I}_{J=n} are statistically dependent.

(c)

Show that for every m>nm>n, XnX_{n} and IJ=m\mathbb {I}_{J=m} are statistically dependent.

(d)

Show that for every m<nm<n, XnX_{n} and IJ=m\mathbb {I}_{J=m} are statistically independent.

(e)

Show that XnX_{n} and IJ≥n\mathbb {I}_{J \geq n} are statistically independent. Give the simplest characterization you can of the event {J≥n}\left\{ J \geq n\right\}.

(f)

Show that XnX_{n} and IJ>n\mathbb {I}_{J>n} are statistically dependent.

Let τ\tau be a stopping time for the natural filtration generated by a sequence of random variables {Zn:n∈N}\left\{ Z_{n}: n \in \mathbb {N}\right\}. Show that Fτ=σ{Zτ∧n:n∈N}\mathcal{F}_{\tau } = \sigma \left\{ Z_{\tau \wedge n}: n \in \mathbb {N}\right\}.

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Let {Xt:t∈R+}\left\{ X_{t}: t \in \mathbb {R}^{+}\right\} be a process with continuous sample paths, adapted to a filtration {Ft:t∈R+}\left\{ \mathcal{F}_{t}: t \in \mathbb {R}^{+}\right\}. Define τ(ω):=inf⁡{t∈R+:Xt(ω)∈F}\tau (\omega ): = \inf \left\{ t \in \mathbb {R}^{+}: X_{t}(\omega ) \in F\right\}, for some closed set FF. Show that {τ≤t}={ω:inf⁡s∈Qtd(Xs(ω),F)=0}\left\{ \tau \leq t\right\} = \left\{ \omega : \inf_{s \in Q_{t}} d\left(X_{s}(\omega ), F\right) = 0\right\}, where QtQ_{t} denotes the set of rational numbers in [0,t][0, t]. Deduce that τ\tau is a stopping time for the filtration.

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Let {Fn}\left\{ \mathscr {F}_{n}\right\} be a nondecreasing sequence of σ\sigma-algebras, {Xn}\left\{ X_{n}\right\} a sequence of random variables such that XnX_{n} is measurable with respect to Fn\mathscr {F}_{n}. Let BB be an arbitrary Borel set on the line. Prove that the first hitting time of the set BB: τB=inf⁡{n⩾0:Xn∈B}\tau_{B} = \inf \left\{ n \geqslant 0: X_{n} \in B\right\} is a Markov time.

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Let τ\tau and σ\sigma be Markov times. Prove that τ+σ\tau +\sigma, min⁡{τ,σ},max⁡{τ,σ}\min \left\{ \tau , \sigma \right\} , \max \left\{ \tau , \sigma \right\} are also Markov times with respect to the same sequence of σ\sigma-algebras as τ,σ\tau , \sigma.

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Let τ\tau and σ\sigma be Markov times. Is the random variable τ−σ\tau -\sigma a Markov time?

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Let (Bt)t⩾0\left(B_{t}\right)_{t \geqslant 0} be a BM1\mathrm{BM}^{1} and σ,τ\sigma , \tau be two stopping times such that Eτ,Eσ<∞\mathbb {E} \tau , \mathbb {E} \sigma < \infty.

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(a)

Show that σ∧τ\sigma \wedge \tau is a stopping time.

(b)

Show that {σ⩽τ}∈Fσ∧τ\left\{ \sigma \leqslant \tau \right\} \in \mathscr {F}_{\sigma \wedge \tau }.

(c)

Show that E[BτBσ]=E[τ∧σ]\mathbb {E}\left[B_{\tau } B_{\sigma }\right] = \mathbb {E}\left[\tau \wedge \sigma \right].

(d)

Deduce from c) that E[∣Bτ−Bσ∣2]=E[∣τ−σ∣]\mathbb {E}\left[\left|B_{\tau } - B_{\sigma }\right|^{2}\right] = \mathbb {E}\left[\left|\tau - \sigma \right|\right].

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