Irrationality and transcendence proofs

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{εk}\left\{ \varepsilon_{k}\right\} is an arbitrary sequence of +1+1's and −1-1's, and {nk}\left\{ n_{k}\right\} is a strictly increasing sequence of natural numbers. Prove that the sum of the series ∑εk2−nk\sum \varepsilon_{k} 2^{-n_{k}} is irrational if lim⁡‾(nk+1−nk)=+∞\overline{\lim }\left(n_{k+1}-n_{k}\right)=+\infty.

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{εk}\left\{ \varepsilon_{k}\right\} is an arbitrary sequence of +1+1's and −1-1's, and {nk}\left\{ n_{k}\right\} is a strictly increasing sequence of natural numbers. Let lim‾⁡nk+1n1n2…nk=+∞\varlimsup \frac{n_{k+1}}{n_{1} n_{2} \ldots n_{k}}=+\infty. Prove that

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(a)

the sum of the series ∑(−1)knk\sum \frac{(-1)^{k}}{n_{k}} is irrational;

(b)

if nk+1nk⩾2\frac{n_{k+1}}{n_{k}} \geqslant 2 for all k∈Nk \in \mathbb {N}, then the sum of the series ∑εknk\sum \frac{\varepsilon_{k}}{n_{k}} is irrational. Is this so in the case nk+1nk⩾Q>1\frac{n_{k+1}}{n_{k}} \geqslant Q>1?

{εk}\left\{ \varepsilon_{k}\right\} is an arbitrary sequence of +1+1's and −1-1's, and {nk}\left\{ n_{k}\right\} is a strictly increasing sequence of natural numbers. Let lim‾⁡ln⁡nk2k=+∞\varlimsup \frac{\ln n_{k}}{2^{k}}=+\infty. Prove that

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(a)

the sum of the series ∑(−1)knk\sum \frac{(-1)^{k}}{n_{k}} is irrational;

(b)

if nk+1nk⩾2\frac{n_{k+1}}{n_{k}} \geqslant 2 for all k∈Nk \in \mathbb {N}, then the sum of the series ∑εknk\sum \frac{\varepsilon_{k}}{n_{k}} is irrational.

{εk}\left\{ \varepsilon_{k}\right\} is an arbitrary sequence of +1+1's and −1-1's, and {nk}\left\{ n_{k}\right\} is a strictly increasing sequence of natural numbers.

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(a)

Prove that the sum of the series S=∑εkFkS=\sum \frac{\varepsilon_{k}}{F_{k}} is irrational, if Fk=22k+1F_{k}=2^{2^{k}}+1 are the Fermat numbers.

(b)

Let the sequence {nk}\left\{ n_{k}\right\} be such that

nk+1⩾nk2−nk+1 for all k∈N. n_{k+1} \geqslant n_{k}^{2}-n_{k}+1 \quad \text{ for all } \quad k \in \mathbb {N} .

Prove the rationality of the sum ∑1nk\sum \frac{1}{n_{k}}, if nk+1=nk2−nk+1n_{k+1}=n_{k}^{2}-n_{k}+1 for all sufficiently large kk.

Is the converse statement true? Is the number ∑122k−2\sum \frac{1}{2^{2^{k}}-2} rational?

{εk}\left\{ \varepsilon_{k}\right\} is an arbitrary sequence of +1+1's and −1-1's, and {nk}\left\{ n_{k}\right\} is a strictly increasing sequence of natural numbers. Let lim‾⁡ln⁡nk3k=+∞\varlimsup \frac{\ln n_{k}}{3^{k}}=+\infty. Prove that

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(a)

the number ∑(−1)knk\sum \frac{(-1)^{k}}{n_{k}} is not a quadratic irrational;

(b)

if nk+1nk⩾2\frac{n_{k+1}}{n_{k}} \geqslant 2 for all k∈Nk \in \mathbb {N}, then the number ∑εknk\sum \frac{\varepsilon_{k}}{n_{k}} is not a quadratic irrational.

{εk}\left\{ \varepsilon_{k}\right\} is an arbitrary sequence of +1+1's and −1-1's. Prove the transcendence of the numbers ∑εk2−k!\sum \varepsilon_{k} 2^{-k!}.

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{εk}\left\{ \varepsilon_{k}\right\} is an arbitrary sequence of +1+1's and −1-1's, and {nk}\left\{ n_{k}\right\} is a strictly increasing sequence of natural numbers. Let lim⁡‾ln⁡nkk!>0\overline{\lim } \frac{\ln n_{k}}{k!}>0. Prove that

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(a)

the number ∑(−1)knk\sum \frac{(-1)^{k}}{n_{k}} is transcendental;

(b)

if nk+1nk⩾2\frac{n_{k+1}}{n_{k}} \geqslant 2 for all k∈Nk \in \mathbb {N}, then the number ∑εknk\sum \frac{\varepsilon_{k}}{n_{k}} is transcendental.

Irrationality of the number ee. Using the expansions

e=∑n⩾01n! and 1e=∑n⩾0(−1)nn!, e=\sum _{n \geqslant 0} \frac{1}{n!} \quad \text{ and } \quad \frac{1}{e}=\sum _{n \geqslant 0} \frac{(-1)^{n}}{n!},

prove that

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(a)

the number ee is irrational;

(b)

Ae2+Be+C≠0A e^{2}+B e+C \neq 0, if A,B,CA, B, C are integers not all equal to zero.

Let σ(n)\sigma (n) be the sum of divisors of a natural number nn. Prove the irrationality of the sums of the series

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(a)

∑σ(n)n!\sum \frac{\sigma (n)}{n!};

(b)

∑(−1)nσ(n)n!\sum (-1)^{n} \frac{\sigma (n)}{n!}.

Irrationality of the number π\pi.

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(a)

Let Hn=1n!∫−π/2π/2(π24−t2)ncos⁡tdt(n=0,1,2,…)H_{n}=\frac{1}{n!} \int_{-\pi / 2}^{\pi / 2}\left(\frac{\pi^{2}}{4}-t^{2}\right)^{n} \cos t d t(n=0,1,2, \ldots ). Prove that Hn=Pn(π2)H_{n}=P_{n}\left(\pi^{2}\right), where PnP_{n} is an algebraic polynomial of degree at most nn with integer coefficients.

(b)

Deduce from this that π2\pi^{2} (and hence also π\pi) is an irrational number.

Irrationality of the values of the exponential function at rational points.

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(a)

Let Jn(x)=1n!∫−xx(x2−t2)netdt(n=0,1,2,…)J_{n}(x)=\frac{1}{n!} \int_{-x}^{x}\left(x^{2}-t^{2}\right)^{n} e^{t} d t \quad (n=0,1,2, \ldots ). Prove that Jn(x)=An(x)ex+Bn(x)e−xJ_{n}(x)=A_{n}(x) e^{x}+B_{n}(x) e^{-x}, where An,BnA_{n}, B_{n} are algebraic polynomials of degree at most nn with integer coefficients.

(b)

Deduce from this that er∉Qe^{r} \notin \mathbb {Q}, if r∈Q,r≠0r \in \mathbb {Q}, r \neq 0.

Irrationality of the values of the tangent at rational points.

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(a)

Let Hn(x)=1n!∫−xx(x2−t2)ncos⁡tdt(n=0,1,2,…)H_{n}(x)=\frac{1}{n!} \int_{-x}^{x}\left(x^{2}-t^{2}\right)^{n} \cos t d t(n=0,1,2, \ldots ). Prove that Hn(x)=Cn(x)cos⁡x+Sn(x)sin⁡xH_{n}(x)=C_{n}(x) \cos x+S_{n}(x) \sin x, where Cn,SnC_{n}, S_{n} are algebraic polynomials of degree at most nn with integer coefficients.

(b)

Deduce from this that tg⁡r∉Q\operatorname {tg} r \notin \mathbb {Q}, if r∈Q,r≠0r \in \mathbb {Q}, r \neq 0.

All three vertices of an equilateral triangle cannot be lattice points.

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The decimal fraction

0.23571113171923… 0.23571113171923\ldots

(formed by writing consecutively all the prime numbers) is irrational. [249, 110.]

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The number

e=1+11!+12!+13!+14!+⋯ e = 1+\frac{1}{1!}+\frac{1}{2!}+\frac{1}{3!}+\frac{1}{4!}+\cdots

is irrational.

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The number ee is not only irrational, but it is also not an algebraic number of the second degree, i.e. it cannot satisfy an equation of the form

ae+be−1+c=0, ae+be^{-1}+c=0 ,

where a,b,ca,b,c are integers and are not all =0=0.

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If the Euler (Mascheroni) constant C=−Γ′(1)C=-\Gamma '(1) were a rational number, then Γ′(n+1)\Gamma '(n+1) would have to be an integer for all integers nn from some point onward.

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If both ϑ/π\vartheta /\pi and cos⁡ϑ\cos \vartheta are rational, then cos⁡ϑ\cos \vartheta must have one of the following five values:

1,12,0,−12,−1. 1, \quad \tfrac 12, \quad 0, \quad -\tfrac 12, \quad -1 .
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Consider the interior angle included between two contiguous faces of a regular solid and call it

T,H,O,D,orI T, \quad H, \quad O, \quad D, \quad \text{or} \quad I

according as the solid is a tetra-, hexa-, octa-, dodeca-, or icosahedron (a hexahedron is a cube). Show that the ratios

TH,OH,DH,IH \frac TH, \quad \frac OH, \quad \frac DH, \quad \frac IH

are irrational.

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Remark.
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Show first, using appropriate spherical triangles, that cos⁡T=13\cos T=\tfrac 13, cos⁡H=0\cos H=0, cos⁡O=−13\cos O=-\tfrac 13, cos⁡2D=−35\cos 2D=-\tfrac 35, cos⁡2I=19\cos 2I=\tfrac 19.

The numbers α1,α2,…,αm\alpha_1,\alpha_2,\ldots ,\alpha_m are called linearly dependent if there exist rational integers a1,a2,…,ama_1,a_2,\ldots ,a_m not all zero such that a1α1+a2α2+⋯+amαm=0a_1\alpha_1+a_2\alpha_2+\cdots +a_m\alpha_m=0. If no relation of this kind exists then α1,α2,…,αm\alpha_1,\alpha_2,\ldots ,\alpha_m are called linearly independent. Thus, if β≠0\beta \neq 0, the numbers α\alpha and β\beta are linearly dependent or independent according as α/β\alpha /\beta is rational or irrational. The number α\alpha is algebraic if there exists an nn (a positive rational integer) such that 1,α,α2,…,αn1,\alpha ,\alpha^2,\ldots ,\alpha^n are linearly dependent.

The numbers (angles) T,HT,H and OO are linearly dependent; in fact

T−2H+O=0 T-2H+O=0

(see 197.2; it can be also proved by elementary geometry). Yet TT and OO are linearly independent.

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(continued). Show that T,H,DT,H,D and II are linearly independent. Also H,O,DH,O,D and II are linearly independent, and any linear homogeneous relation with rational coefficients between T,H,O,DT,H,O,D and II can differ only trivially (that is, only by a numerical factor) from the one given in 197.3.

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If both ϑ/π\vartheta /\pi and tan⁡2ϑ\tan^2\vartheta are rational then tan⁡2ϑ\tan^2\vartheta must have one of the following five values (regarding ∞=1/0\infty =1/0 as ``rational''):

0,13,1,3,10. 0, \quad \tfrac 13, \quad 1, \quad 3, \quad \tfrac 10 .
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With the exception of the four cases n=1,2,4n=1,2,4, and 8, tan⁡2π/n\tan 2\pi /n is irrational for all positive rational integers nn.

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(continued). From this result derive 197.1 [38.1].

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The number

λ=log⁡3log⁡2 \lambda = \frac{\log 3}{\log 2}

is irrational.

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The numbers aa and bb are positive; aa may be rational or irrational and the same holds for bb, and so there are four possible cases. Show by means of examples that aba^b can be rational or irrational in each of these four cases (eight examples are required).

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If rr is rational (r≠0)(r \neq 0) and xx is irrational, prove that r+xr+x and rxr x are irrational.

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Prove that there is no rational number whose square is 12.

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References

[МГЛ+04] Макаров Б.М., Голузина М.Г., Лодкин А.А., Подкорытов А.Н. Избранные задачи по вещественному анализу. 2-е изд., Невский Диалект; БХВ-Петербург, 2004.
[PóSz98] Pólya G., Szegő G. Problems and Theorems in Analysis. Springer, 1998.
[Rud76] Rudin W. Principles of Mathematical Analysis. 3rd ed., McGraw-Hill, 1976.