Lattice Points in Two and Three Dimensions
[13/100%]All three vertices of an equilateral triangle cannot be lattice points.
A polygon is equiangular, has sides, and all its vertices are lattice points. Then is either 4 or 8.
A regular polygon has sides and all its vertices are lattice points. Then .
How thick must the trunks of the trees in a regularly spaced circular forest grow if they are to block completely the view from the center?
Let be a given positive integer. Let every lattice point that satisfies the inequality be the center of a circle of radius . If is sufficiently small, there exist rays running from the point 0, 0 to infinity without meeting the circles described above (the forest is transparent); such rays no longer exist if is sufficiently large (for the circles touch). Let be the value of which divides the two cases (limit of transparency). Then we have
In the plane draw the widest possible infinite straight ``path'', contained between two parallels and avoiding all the lattice points, that makes an angle equal to with the -axis. Denoting the width of this path by , determine .
Two lattice points and are termed congruent mod , if
Among any distinct lattice points there are always that are congruent mod .
In the plane consider a domain of area (Jordan content) . It may contain no lattice points, but can always be moved parallel to itself so that lattice points lie in it.
The lattice points in the closed first quadrant are enumerable. I.e. there exist functions defined for ordered pairs of non-negative integers that combine the following two properties:
The values assumed by form the set of numbers .
The function takes different values at distinct points; i.e. if are integers, , , , , , then .
There even exist rational entire functions that enumerate the lattice points, i.e. that have the properties (1) (2). An example is the function
and the function arising from it by interchanging and [the lattice points are counted successively on the line segments
Let be a rational entire function of degree
where denotes a rational entire homogeneous function of degree . If enumerates the lattice points, then clearly for , . If for , , and enumerates the lattice points, then the degree of is
[The number of lattice points contained inside the contour line is related to the enclosed area.]]
Consider the square domain , as a chess board with $n^2$ squares'', i.e. by means of straight lines parallel to the axis divide it into $n^2$ squares of unit area. The problem of the queens'' requires us to choose from the lattice points that constitute the centers of the squares lattice points that satisfy the inequalities
where ; . Replace the inequalities by the more restrictive ``incongruence relations''
and show that these have a solution if and only if is relatively prime to 6.
A regular polygon has sides and all its vertices are lattice points. Then is equal to 3, 4 or 6.
(continued). Give examples showing that the three cases and 6 can actually occur.
All the vertices of a regular polyhedron are lattice points. Then the polyhedron is either a cube or a tetrahedron or an octahedron.
(continued). Give examples showing that the three cases mentioned above can actually occur.