Section 1.2

Functions

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Problem 1.2.1

Let f:X→Yf: X \rightarrow Y and A,B⊂XA, B \subset X. Prove that:

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(a)

f(A)\f(B)⊂f(A\B)f(A) \backslash f(B) \subset f(A \backslash B).

(b)

inclusion in (a) can be strict.

Problem 1.2.2

Let f:X→Yf: X \rightarrow Y, let A⊂XA \subset X, and B⊂YB \subset Y. Prove that:

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(a)

If ff is surjective then f(f−1(B))=Bf\left(f^{-1}(B)\right)=B.

(b)

If ff is injective then f−1(f(A))=Af^{-1}(f(A))=A.

Problem 1.2.3

Let f:X→Yf: X \rightarrow Y and A,B⊂XA, B \subset X. Prove that:

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(a)

ff is injective if and only if f(A∩B)=f(A)∩f(B)f(A \cap B)=f(A) \cap f(B) for all A,BA, B.

(b)

ff is surjective if and only if f(A)C⊂f(AC)f(A)^{C} \subset f\left(A^{C}\right) for all AA.

(c)

f(A)C=f(AC)f(A)^{C}=f\left(A^{C}\right) for all AA if and only ff is bijective.

Problem 1.2.4

Let f:X→Yf: X \rightarrow Y and A,B⊂YA, B \subset Y. Prove that

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(a)

A⊂BA \subset B implies that f−1(A)⊂f−1(B)f^{-1}(A) \subset f^{-1}(B).

(b)

f−1(A∪B)=f−1(A)∪f−1(B)f^{-1}(A \cup B)=f^{-1}(A) \cup f^{-1}(B).

(c)

f−1(BC)=(f−1(B))Cf^{-1}\left(B^{C}\right)=\left(f^{-1}(B)\right)^{C}.

Problem 1.2.5

Let f:X→Y,A⊂Xf: X \rightarrow Y, A \subset X, and B⊂YB \subset Y. Prove that f(A∩f−1(B))=f(A)∩Bf\left(A \cap f^{-1}(B)\right)= f(A) \cap B.

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Problem 1.2.6

Let f:X→Yf: X \rightarrow Y, let X0⊂XX_{0} \subset X, let f0f_{0} be the restriction of ff to X0X_{0}, and let E⊂YE \subset Y. Prove that:

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(a)

f0−1(E)=f−1(E)∩X0f_{0}^{-1}(E)=f^{-1}(E) \cap X_{0}.

(b)

f−1(E)=f0−1(E)∪(f−1(E)∩(X\X0))f^{-1}(E)=f_{0}^{-1}(E) \cup \left(f^{-1}(E) \cap \left(X \backslash X_{0}\right)\right).

Problem 1.2.7

Let f:X→Yf: X \rightarrow Y, let {Ai}i∈I\left\{ A_{i}\right\}_{i \in I} be a collection of subsets of XX, and let {Bi}i∈I\left\{ B_{i}\right\}_{i \in I} be a collection of subsets of YY. Prove that:

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(a)

f−1(∩i∈IBi)=∩i∈If−1(Bi)f^{-1}\left(\cap_{i \in I} B_{i}\right)=\cap_{i \in I} f^{-1}\left(B_{i}\right).

(b)

f(∩i∈IAi)⊂∩i∈If(Ai)f\left(\cap_{i \in I} A_{i}\right) \subset \cap_{i \in I} f\left(A_{i}\right).

(c)

The equality holds in (b) if and only if ff is injective.

(d)

f−1(∪i∈IBi)=∪i∈If−1(Bi)f^{-1}\left(\cup_{i \in I} B_{i}\right)=\cup_{i \in I} f^{-1}\left(B_{i}\right).

Problem 1.2.8

Let {Ai}i∈I\left\{ A_{i}\right\}_{i \in I} and {Bi}i∈I\left\{ B_{i}\right\}_{i \in I} be subsets of XX. Prove that

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(a)

(∪i∈IAi)\(∪i∈IBi)⊂∪i∈I(Ai\Bi)\left(\cup_{i \in I} A_{i}\right) \backslash \left(\cup_{i \in I} B_{i}\right) \subset \cup_{i \in I}\left(A_{i} \backslash B_{i}\right).

(b)

Inclusion in (a) can be strict.

Problem 1.2.9

Let f:X→Rf: X \rightarrow \mathbb {R} and let A,B⊂XA, B \subset X. Prove that:

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(a)

χA∩B=χAχB\chi_{A \cap B}=\chi_{A} \chi_{B}.

(b)

χA∪B=χA+χB−χAχB\chi_{A \cup B}=\chi_{A}+\chi_{B}-\chi_{A} \chi_{B}.

(c)

χA\B=χA−χAχB\chi_{A \backslash B}=\chi_{A}-\chi_{A} \chi_{B}.

(d)

χA∘f=χf−1(A)\chi_{A} \circ f=\chi_{f^{-1}(A)}.

(e)

∣χA−χB∣=χA△B\left|\chi_{A}-\chi_{B}\right|=\chi_{A \triangle B}.