Section 2.6

The classification theorem

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Problem 2.6.1

Let BB be the Möbius band. Construct a model of B#TB \# T (the connected sum of BB with the torus TT) and show that it is homeomorphic to B#KB \# K (the connected sum of BB with the Klein bottle KK).

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Remark.
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It will help if the cylinder used to form the connected sum is attached symmetrically, one-fourth and three-fourths of the way across the strip representing BB.

Problem 2.6.2

Here P(1)(k)P^{(k)}_{(1)} denotes the boundary connected sum of kk copies of the projective plane PP with one disk removed, and similarly T(1)(k)T^{(k)}_{(1)} for kk copies of the torus TT. Show that P(1)(k)∪‾T(1)≃P(1)(2k+1)P^{(k)}_{(1)} \mathbin {\overline{\cup }} T_{(1)} \simeq P^{(2k+1)}_{(1)}. Conclude from this that P(1)(l)∪‾T(1)(k)≃P(1)(2k+l)P^{(l)}_{(1)} \mathbin {\overline{\cup }} T^{(k)}_{(1)} \simeq P^{(2k+l)}_{(1)}.

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Problem 2.6.3

For each of the orientable surfaces (given by handle decompositions with a single 00-handle and disjoint 11-handles attached to its boundary) in Figure 2.46, use handle sliding to put it in standard form and identify the surface. Check your answer using the classification theorem (Theorem 2.6.2: a connected, orientable handlebody with 00- and 11-handles and Euler characteristic χ\chi and pp boundary circles is homeomorphic to the standard model for S(p)S_{(p)} or T(p)(g)T^{(g)}_{(p)}, where χ=2−2g−p\chi = 2 - 2g - p).

Surfaces for Exercise 2.6.3.Surfaces for Exercise 2.6.3.

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Remark.
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First find a torus pair (a pair of linked 11-handles which together create T(1)T_{(1)} when attached to a disk) and slide the other handles off of it.

Problem 2.6.4

For each of the nonorientable surfaces in Figure 2.47, use handle sliding to put it in standard form and identify the surface. Check your answer using the classification theorem (Theorem 2.6.2: a connected, nonorientable handlebody with 00- and 11-handles and Euler characteristic χ\chi and pp boundary circles is homeomorphic to the standard model for P(p)(h)P^{(h)}_{(p)}, where χ=2−h−p\chi = 2 - h - p).

Surfaces for Exercise 2.6.4.Surfaces for Exercise 2.6.4.

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Remark.
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First find a twisted handle (a 11-handle attached to a single boundary circle in a way that creates a Möbius band from the disk) and slide the other handles off of it.

Problem 2.6.5

Consider the step in the proof of the classification theorem (Theorem 2.6.2) for the orientable case where a new torus pair (a pair of linked 11-handles) is created by adding a new 11-handle to a handlebody H1H_{1} already in standard form T(p)(g)T^{(g)}_{(p)}, giving H=H1∪h1H = H_{1} \cup h^{1}. Show that, if we regard the 00-handle together with this new torus pair as giving us the torus-with-one-hole T(1)T_{(1)}, then we can remove this piece from the surface and replace it by a consistently oriented disk with the same boundary, to which the other handles (those of H1H_{1} besides its 00-handle) are attached. Considering this disk as the new 00-handle and the other 11-handles as attached to its boundary, forming a handlebody H1′H_{1}', show that H≃H1′#TH \simeq H_{1}' \# T. Then use induction to show that H≃T(p)(g+1)H \simeq T^{(g+1)}_{(p)} when H1′≃T(p)(g)H_{1}' \simeq T^{(g)}_{(p)}.

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Problem 2.6.6

Consider the step in the proof of the classification theorem (Theorem 2.6.2) for the orientable case where a new 11-handle is attached to a single boundary circle of a handlebody H1H_{1} (already in standard form) to form H=H1∪h1H = H_{1} \cup h^{1}. Show that if H1H_{1} is homeomorphic to T(p)(g)T^{(g)}_{(p)}, then we can add a 22-handle to HH so that H∪h2≃H1H \cup h^{2} \simeq H_{1}. Thus, removing this 22-handle shows that H≃T(p+1)(g)H \simeq T^{(g)}_{(p+1)}.

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Problem 2.6.7

Consider the step in the proof of the classification theorem (Theorem 2.6.2) for the nonorientable case where we attach a new 11-handle h1h^{1} to form HH from a handlebody H1H_{1}, which, by induction, may be assumed to be either T(p)(g)T^{(g)}_{(p)} or P(p)(h)P^{(h)}_{(p)} and already in standard form. Show that we can assume in either case that h1h^1 is attached away from the torus pairs or twisted handles of H1H_1, so it may be regarded as attached to S(p)S_{(p)} (the disk with p−1p-1 trivial handles). In the case where H1H_{1} is orientable, h1h^{1} will necessarily be attached to S(p)S_{(p)} so that S(p)∪h1S_{(p)} \cup h^{1} is nonorientable. Show that this is not necessarily the case when H1H_{1} is nonorientable.

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Problem 2.6.8

Show that if a 11-handle h1h^{1} is attached to a single boundary circle of H1≃S(p)H_{1} \simeq S_{(p)} as a twisted handle to form HH, then the union of the 00-handle and h1h^{1} forms a Möbius band P(1)P_{(1)}. Form a new handlebody H2H_{2} by replacing h0∪h1h^{0} \cup h^{1} by a disk with the same boundary and then attaching the other 11-handles (those of H1H_1 besides its 00-handle) to it. Show that H2≃S(p)H_{2} \simeq S_{(p)} and H≃P#H2≃P(p)H \simeq P \# H_{2} \simeq P_{(p)}.

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Problem 2.6.9

Show that if a 11-handle h11h^{1}_{1} is attached to two boundary circles of S(p)S_{(p)} in a twisted fashion to form HH, and we choose another 11-handle h21h^{1}_{2} so that h0∪h21h^{0} \cup h^{1}_{2} forms an annulus whose boundary consists of these two circles, then H1=h0∪h21∪h11H_{1} = h^{0} \cup h^{1}_{2} \cup h^{1}_{1} is a Klein bottle with a disk removed, K(1)K_{(1)}. Form a new handlebody H2H_{2} by removing h0∪h21∪h11h^{0} \cup h^{1}_{2} \cup h^{1}_{1} and replacing it with a disk (the new 00-handle), then adding in all of the other handles of the original standard handle decomposition of S(p)S_{(p)}. Show that H2≃S(p−1)H_{2} \simeq S_{(p-1)} and H≃K#S(p−1)H \simeq K \# S_{(p-1)}.

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Problem 2.6.10

Deduce the general induction step for the nonorientable case of the classification theorem (Theorem 2.6.2) from the constructions of the last three exercises (2.6.7--2.6.9), considering separately:

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(a)

the case where the handle is attached to S(p)S_{(p)} in an orientable fashion;

(b)

the case where the handle is attached to S(p)S_{(p)} in a nonorientable fashion.