Chapter 5

Interval Estimates of Parameters

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Problem 5.1

The sample {X1,…,Xn},n≫1\left\{ X_{1}, \ldots , X_{n}\right\} , n \gg 1 corresponds to the Poisson distribution Pois⁡(θ),θ>0\operatorname {Pois}\left(\theta \right), \theta > 0. Construct an asymptotic confidence interval for θ\theta of confidence level qq.

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Problem 5.2

The sample {X1,…,Xn}\left\{ X_{1}, \ldots , X_{n}\right\} corresponds to the distribution N(μ;θ),μ\mathcal{N}(\mu ; \theta ), \mu is known. Construct a central confidence interval of confidence level qq for the variance θ\theta.

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Problem 5.3

The sample {X1,…,Xn},n≫1\left\{ X_{1}, \ldots , X_{n}\right\} , n \gg 1 corresponds to the distribution Exp⁡(1θ)\operatorname {Exp}\left(\frac{1}{\theta }\right), θ>0\theta > 0. Construct an asymptotic confidence interval of confidence level qq for the parameter θ\theta.

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Problem 5.4

From the sample zn={−0,26;−0,36;1,83;0,54;−2,06}z_{n} = \left\{ -0,26 ;-0,36 ; 1,83 ; 0,54 ;-2,06\right\} corresponding to the distribution N(θ1;θ22)\mathcal{N}\left(\theta_{1} ; \theta_{2}^{2}\right), find confidence intervals of confidence level q=0,9q = 0,9 for θ1\theta_{1} and θ2\theta_{2}.

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Problem 5.5

The sample Zn={Xk,k=1,…,n},n≫1Z_{n} = \left\{ X_{k}, k = 1, \ldots , n\right\} , n \gg 1 corresponds to the uniform distribution R[0;a],a>0R[0 ; a], a > 0. Construct an asymptotic confidence interval of confidence level qq for the parameter θ=E[X1]\theta = \mathbb {E}\left[X_{1}\right].

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Problem 5.6

The sample Zn={X1,…,Xn},n≫1Z_{n} = \left\{ X_{1}, \ldots , X_{n}\right\} , n \gg 1 corresponds to the distribution with probability density p(x;θ)=exp⁡{θ−x},x⩾θp(x ; \theta ) = \exp \left\{ \theta -x\right\} , x \geqslant \theta, where θ>0\theta > 0. Show that [X(1)+ln⁡(1−q)n;X(1)]\left[X_{(1)}+\frac{\ln (1-q)}{n} ; X_{(1)}\right] is a confidence interval of confidence level qq for θ\theta.

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Problem 5.7

Under the conditions of Problem 6, construct a central confidence interval of confidence level qq for θ\theta.

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Problem 5.8

Let the sample {X1,…,Xn},n≫1\left\{ X_{1}, \ldots , X_{n}\right\} , n \gg 1 correspond to the distribution R[0;θ],θ>0R[0 ; \theta ], \theta > 0. Show that (X(n)θ)n\left(\frac{X_{(n)}}{\theta }\right)^{n} is a pivotal statistic, and construct a confidence interval for θ\theta of minimum length with confidence level qq.

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Problem 5.9

Let Zn(1)={X1,…,Xn}Z_{n}^{(1)} = \left\{ X_{1}, \ldots , X_{n}\right\} and Zn(2)={Y1,…,Yn}Z_{n}^{(2)} = \left\{ Y_{1}, \ldots , Y_{n}\right\} be two independent samples, where Zn(1)Z_{n}^{(1)} corresponds to the distribution N(θ1;σ12)\mathcal{N}\left(\theta_{1} ; \sigma_{1}^{2}\right), and Zn(2)Z_{n}^{(2)} to N(θ2;σ22)\mathcal{N}\left(\theta_{2} ; \sigma_{2}^{2}\right) (σ1\sigma_{1} and σ2\sigma_{2} are known). It is required to construct a confidence interval of confidence level qq for the parameter θ=θ1−θ2\theta = \theta_{1}-\theta_{2}.

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