Section 2.8

Menger's Theorem

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Problem 2.8.1

From every connected multigraph one can remove a vertex (together with all edges incident to it) so that it remains connected.

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Remark.
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A graph or multigraph is called 2-connected if it differs from K2K_{2} and remains connected after the removal of any vertex.

Problem 2.8.2
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(1)

A special case of the vertex version of Menger's theorem. Any two distinct vertices of a 2-connected multigraph that are not joined by an edge lie on some non-self-intersecting cycle.

(2)

Is it true that for any path PP in a multigraph having at least three vertices there exists another path in the same multigraph with the same endpoints that does not intersect PP anywhere except at the endpoints?

Problem 2.8.3

If a multigraph has at least one edge and, after the removal of any edge, there is still a path between the vertices aa and bb, then the multigraph contains two paths between the vertices aa and bb having no edges in common.

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Problem 2.8.4
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(1)

For any edge uu of a 2-connected graph GG different from K3K_{3}, at least one of the graphs G−uG-u and G/uG/u is 2-connected.

(2)

For any two vertices of a convex polyhedron there exist three paths along its edges from one vertex to the other that are disjoint (everywhere except at these vertices). (Such graphs are called 3-connected.)

(3)

For a 3-connected graph GG with an edge xyxy (whose vertices are x,yx,y), the graph G/xyG/xy is 3-connected if and only if the graph G−x−yG-x-y is 2-connected.

Problem 2.8.5
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(1)

Whitney's theorem (vertex version). A multigraph remains connected after the removal of any k−1k-1 vertices if and only if any two of its vertices can be joined by kk paths intersecting only at these two vertices.

(2)

Menger's theorem (vertex version). If vertices aa and bb of a multigraph GG that are not joined by an edge remain in the same connected component after the removal of any k−1k-1 other vertices, then aa and bb can be joined by kk paths intersecting only at these two vertices.

Problem 2.8.6

Call vertices AA and BB of a graph equivalent if there exists a sequence of vertices A=A0,A1,…,An=BA = A_{0}, A_{1}, \ldots , A_{n} = B such that any two consecutive vertices AiA_{i} and Ai+1A_{i+1} can be joined by kk paths having no common intermediate vertices. Then any two equivalent vertices can be joined by kk paths having no common edges.

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