Section 6

Plane and a line in space

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Problem 6.1

Write the equation of:

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(1)

the plane r=r0+au+bv\mathbf{r} = \mathbf{r}_{0} + \mathbf{a} u + \mathbf{b} v in the form (r,n)=D(a∦b)(\mathbf{r}, \mathbf{n}) = D(\mathbf{a} \nparallel \mathbf{b})

(2)

the line r=r0+at\mathbf{r} = \mathbf{r}_{0} + \mathbf{a} t in the form [r,a]=b\left[\mathbf{r}, \mathbf{a}\right] = \mathbf{b} (a≠0)(\mathbf{a} \neq 0)

(3)

the line [r,a]=b\left[\mathbf{r}, \mathbf{a}\right] = \mathbf{b} in the form r=r0+at\mathbf{r} = \mathbf{r}_{0} + \mathbf{a} t (a≠0)(\mathbf{a} \neq 0)

(4)

the line (r,ni)=Di,i=1,2\left(\mathbf{r}, \mathbf{n}_{i}\right) = D_{i}, i = 1, 2, in the form [r,a]=b(n1∦n2)\left[\mathbf{r}, \mathbf{a}\right] = \mathbf{b}\left(\mathbf{n}_{1} \nparallel \mathbf{n}_{2}\right)

(5)

the line (r,ni)=Di,i=1,2\left(\mathbf{r}, \mathbf{n}_{i}\right) = D_{i}, i = 1, 2, in the form r=r0+at\mathbf{r} = \mathbf{r}_{0} + \mathbf{a} t (a≠0)(\mathbf{a} \neq 0).

Problem 6.2

Find the necessary and sufficient condition under which the planes (r,n1)=D1\left(\mathbf{r}, \mathbf{n}_{1}\right) = D_{1} and (r,n2)=D2(ni≠0,i=1,2)\left(\mathbf{r}, \mathbf{n}_{2}\right) = D_{2} \quad \left(\mathbf{n}_{i} \neq 0, i = 1, 2\right):

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(1)

intersect along a line

(2)

are parallel but do not coincide

(3)

coincide.

Problem 6.3

Find the necessary and sufficient condition under which the lines r=r1+a1t\mathbf{r} = \mathbf{r}_{1} + \mathbf{a}_{1} t and r=r2+a2t(ai≠0,i=1,2)\mathbf{r} = \mathbf{r}_{2} + \mathbf{a}_{2} t\left(\mathbf{a}_{i} \neq 0, i = 1, 2\right):

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(1)

intersect (i.e. have a unique common point)

(2)

are skew

(3)

are parallel but do not coincide

(4)

coincide.

Problem 6.4

Given a line r=r0+at\mathbf{r} = \mathbf{r}_{0} + \mathbf{a} t (a≠0)(\mathbf{a} \neq 0) and a plane (r,n)=D(n≠0)(\mathbf{r}, \mathbf{n}) = D (\mathbf{n} \neq 0). Under what necessary and sufficient condition:

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(1)

do they intersect (have a unique common point)

(2)

are they parallel (have no common points)

(3)

does the line lie in the plane?

Problem 6.5

Find the position vector of the point of intersection of:

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(1)

the line r=r0+at\mathbf{r} = \mathbf{r}_{0} + \mathbf{a} t with the plane (r,n)=D(\mathbf{r}, \mathbf{n}) = D (if (a,n)≠0(\mathbf{a}, \mathbf{n}) \neq 0)

(2)

the line [r,a]=b\left[\mathbf{r}, \mathbf{a}\right] = \mathbf{b} with the plane (r,n)=D(\mathbf{r}, \mathbf{n}) = D (if (a,n)≠0)(\mathbf{a}, \mathbf{n}) \neq 0)).

Problem 6.6

Point M0M_{0} is determined by the position vector r0\mathbf{r}_{0}. Find the equations of:

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(1)

the line passing through the point M0M_{0} perpendicular to the plane (r,n)=D(\mathbf{r}, \mathbf{n}) = D

(2)

the plane passing through the point M0M_{0} perpendicular to the line r=r1+at\mathbf{r} = \mathbf{r}_{1} + \mathbf{at}.

Problem 6.7

Find the vector equation of the plane passing through the line r=r0+at\mathbf{r} = \mathbf{r}_{0} + \mathbf{a} t (a≠0)(\mathbf{a} \neq 0) and the point M1(r1)M_{1}\left(\mathbf{r}_{1}\right), not lying on this line.

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Problem 6.8

Given a point M0(r0)M_{0}\left(\mathbf{r}_{0}\right) and a plane (r,n)=D(\mathbf{r}, \mathbf{n}) = D (n≠0)(\mathbf{n} \neq 0). Find the position vector of:

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(1)

the projection of point M0M_{0} onto the plane

(2)

the point M1M_{1} symmetric to M0M_{0} with respect to the plane.

Problem 6.9

Given a point M0(r0)M_{0}\left(\mathbf{r}_{0}\right) and a line r=r1+at\mathbf{r} = \mathbf{r}_{1} + \mathbf{a} t (a≠0)(\mathbf{a} \neq 0). Find the position vector of:

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(1)

the projection of point M0M_{0} onto the line

(2)

the point M1M_{1} symmetric to M0M_{0} with respect to the line.

Problem 6.10

Find the equations of:

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(1)

the projection onto the plane (r,n)=D(\mathbf{r}, \mathbf{n}) = D (n≠0)(\mathbf{n} \neq 0) of the line r=r0+at\mathbf{r} = \mathbf{r}_{0} + \mathbf{a} t (a≠0)(\mathbf{a} \neq 0), not perpendicular to this plane

(2)

the line meeting the line r=r1+at\mathbf{r} = \mathbf{r}_{1} + \mathbf{a} t (a≠0)(\mathbf{a} \neq 0) at a right angle and passing through the point M0(r0)M_{0}\left(\mathbf{r}_{0}\right), not lying on the given line (the perpendicular dropped from the point M0(r0)M_{0}\left(\mathbf{r}_{0}\right) onto the line r=r1+at\mathbf{r} = \mathbf{r}_{1} + \mathbf{a} t)

(3)

the line meeting the two skew lines r=r1+a1t\mathbf{r} = \mathbf{r}_{1} + \mathbf{a}_{1} t and r=r2+a2t\mathbf{r} = \mathbf{r}_{2} + \mathbf{a}_{2} t (a≠0)(\mathbf{a} \neq 0) and passing through the point M0(r0)M_{0}\left(\mathbf{r}_{0}\right), not lying on either of these lines

(4)

the line meeting the two skew lines r=r1+a1t\mathbf{r} = \mathbf{r}_{1} + \mathbf{a}_{1} t and r=r2+a2t\mathbf{r} = \mathbf{r}_{2} + \mathbf{a}_{2} t (a≠0)(\mathbf{a} \neq 0) at right angles (the common perpendicular to these lines).

Problem 6.11

Find the distance:

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(1)

from the point M0(r0)M_{0}\left(\mathbf{r}_{0}\right) to the plane (r,n)=D(\mathbf{r}, \mathbf{n}) = D (n≠0)(\mathbf{n} \neq 0)

(2)

between the two parallel planes r=r1+au+bv\mathbf{r} = \mathbf{r}_{1} + \mathbf{a} u + \mathbf{b} v and r=r2+au+bv\mathbf{r} = \mathbf{r}_{2} + \mathbf{a} u + \mathbf{b} v (a≠0)(\mathbf{a} \neq 0)

(3)

between the two parallel planes (r,n)=D1(\mathbf{r}, \mathbf{n}) = D_{1} and (r,n)=D2(\mathbf{r}, \mathbf{n}) = D_{2} (n≠0)(\mathbf{n} \neq 0)

(4)

from the point M0(r0)M_{0}\left(\mathbf{r}_{0}\right) to the line r=r1+at\mathbf{r} = \mathbf{r}_{1} + \mathbf{a} t (a≠0)(\mathbf{a} \neq 0)

(5)

from the point M0(r0)M_{0}\left(\mathbf{r}_{0}\right) to the line [r,a]=b\left[\mathbf{r}, \mathbf{a}\right] = \mathbf{b} (a≠0)(\mathbf{a} \neq 0)

(6)

between the two parallel lines r=r1+at\mathbf{r} = \mathbf{r}_{1} + \mathbf{a} t and r=r2+at\mathbf{r} = \mathbf{r}_{2} + \mathbf{a} t (a≠0)(\mathbf{a} \neq 0)

(7)

between the two parallel lines [r,a]=b1\left[\mathbf{r}, \mathbf{a}\right] = \mathbf{b}_{1} and [r,a]=b2\left[\mathbf{r}, \mathbf{a}\right] = \mathbf{b}_{2} (a≠0)(\mathbf{a} \neq 0)

(8)

between the two skew lines r=r1+a1t\mathbf{r} = \mathbf{r}_{1} + \mathbf{a}_{1} t and r=r2+a2t\mathbf{r} = \mathbf{r}_{2} + \mathbf{a}_{2} t (a≠0)(\mathbf{a} \neq 0)

(9)

between the two skew lines [r,a1]=b1\left[\mathbf{r}, \mathbf{a}_{1}\right] = \mathbf{b}_{1} and [r,a2]=b2\left[\mathbf{r}, \mathbf{a}_{2}\right] = \mathbf{b}_{2} (a≠0)(\mathbf{a} \neq 0).

Problem 6.12

Given a line r=r0+at\mathbf{r} = \mathbf{r}_{0} + \mathbf{a} t (a≠0)(\mathbf{a} \neq 0) and a plane (r,n)=D(\mathbf{r}, \mathbf{n}) = D (n≠0)(\mathbf{n} \neq 0), not parallel to each other. Point MM lies on the line and is at distance ρ\rho from the plane. Find the position vector of point MM.

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Problem 6.13

Point MM lies in the plane Ax+By+Cz+D=0Ax + By + Cz + D = 0, the vector MM1→\overrightarrow {MM_{1}} has coordinates (A,B,C)(A, B, C). Prove that point M1M_{1} lies in the positive half-space relative to the given plane.

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Problem 6.14
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(1)

Given the parametric equations of a plane: x=1+u−v,y=2+u+2v,z=−1−u+2vx = 1 + u - v, y = 2 + u + 2v, z = - 1 - u + 2v, find its general equation.

(2)

Given the general equation of a plane 2x−3y+z+1=02x - 3y + z + 1 = 0, find its parametric equations.

Problem 6.15

Prove that a direction vector a\mathbf{a} of the line given as the intersection of two planes A1x+B1y+C1z+D1=0,A2x+B2y+C2z+D2=0A_{1} x + B_{1} y + C_{1} z + D_{1} = 0, A_{2} x + B_{2} y + C_{2} z + D_{2} = 0 can be found by the ``cross product'' rule

a=[B1C1B2C2]e1+[C1A1C2A2]e2+[A1B1A2B2]e3 \mathbf{a} =\left[\begin{smallmatrix} B_{1} & C_{1} \\ B_{2} & C_{2} \end{smallmatrix}\right] \mathbf{e}_{1} +\left[\begin{smallmatrix} C_{1} & A_{1} \\ C_{2} & A_{2} \end{smallmatrix}\right] \mathbf{e}_{2} +\left[\begin{smallmatrix} A_{1} & B_{1} \\ A_{2} & B_{2} \end{smallmatrix}\right] \mathbf{e}_{3}

not only in a right-handed rectangular system, but also in a general Cartesian coordinate system.

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Problem 6.16
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(1)

Write the equations of the line x=2+3t,y=3−tx = 2 + 3t, y = 3 - t, z=1+tz = 1 + t as the intersection of two planes and in canonical form.

(2)

Write the equations of the line x−y+2z+4=0,−2x+y+z+3=0x - y + 2z + 4 = 0, - 2x + y + z + 3 = 0 in parametric and canonical form.

Problem 6.17

Find the equation of the plane passing through the point A(1,−1,2)A(1, - 1, 2) and parallel to the plane:

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(1)

x−3y+2z+1=0x - 3y + 2z + 1 = 0

(2)

x=5x = 5

(3)

y=4y = 4

(4)

z=3z = 3

(5)

x=4−u+v,y=2+u+2v,z=−1+7u+3vx = 4 - u + v, \quad y = 2 + u + 2v, \quad z = - 1 + 7u + 3v.

Problem 6.18

Find the equations of the line passing through the point A(1,3,1)A(1, 3, 1) and parallel to the line:

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(1)

x+y−z+2=0,2x+3y+z=0x + y - z + 2 = 0, 2x + 3y + z = 0

(2)

x+13=y−24=z+221\frac{x + 1}{3} = \frac{y - 2}{4} = \frac{z + 2}{21}

(3)

x=2,y=3x = 2, y = 3

(4)

x=0,z=0x = 0, z = 0

(5)

y=−1,z=2y = - 1, z = 2.

Problem 6.19

Find the equations of the line passing through two given points:

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(1)

A(1,3,−1)A(1, 3, - 1) and B(4,2,1)B(4, 2, 1)

(2)

A(3,2,5)A(3, 2, 5) and B(4,1,5)B(4, 1, 5)

(3)

A(−1,1,2)A(- 1, 1, 2) and B(5,1,2)B(5, 1, 2).

Problem 6.20

Find the equation of the plane passing through three given points (if these points determine a plane):

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(1)

A(2,1,3),B(−1,2,5),C(3,0,1)A(2, 1, 3), B(- 1, 2, 5), C(3, 0, 1)

(2)

A(1,−1,3),B(2,3,4),C(−1,1,2)A(1, - 1, 3), B(2, 3, 4), C(- 1, 1, 2)

(3)

A(3,0,0),B(0,−1,0),C(0,0,4)A(3, 0, 0), B(0, - 1, 0), C(0, 0, 4)

(4)

A(2,1,1),B(2,0,−1),C(2,4,3)A(2, 1, 1), B(2, 0, - 1), C(2, 4, 3)

(5)

A(1,1,2),B(2,3,3),C(−1,−3,0)A(1, 1, 2), B(2, 3, 3), C(- 1, - 3, 0).

Problem 6.21

Given two planes. Determine whether they intersect, are parallel, or coincide. If the planes intersect, find the canonical equations of the line of intersection. The planes are given by the equations:

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(1)

3x+y−z+1=03x + y - z + 1 = 0 and 5x+3y+z+2=05x + 3y + z + 2 = 0

(2)

x+y−2z+1=0x + y - 2z + 1 = 0 and 6z−3x−3y−3=06z - 3x - 3y - 3 = 0

(3)

−x+y+z=1- x + y + z = 1 and x−y−z=2x - y - z = 2

(4)

x=3+u+v,y=2−u+v,z=3u−2vx = 3 + u + v, \quad y = 2 - u + v, \quad z = 3u - 2v\quad and x=5−u\quad x = 5 - u, y=3+v,z=u+2vy = 3 + v, \quad z = u + 2v.

Problem 6.22

For which aa do the planes x+ay+z−1=0x + ay + z - 1 = 0 and ax+9y+a39z+3=0ax + 9y + \frac{a^{3}}{9} z + 3 = 0

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(1)

intersect

(2)

are parallel

(3)

coincide?

Problem 6.23

Check whether the given line lies in the plane x−3y+z+1=0x - 3y + z + 1 = 0, is parallel to this plane, or meets it at a single point; in the last case find the coordinates of the point of intersection. The line is given by the equations:

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(1)

x−15=y−14=z−17\frac{x - 1}{5} = \frac{y - 1}{4} = \frac{z - 1}{7}

(2)

x=2+3t,y=7+t,z=1+tx = 2 + 3t, y = 7 + t, z = 1 + t

(3)

x−y+2z=0,x+y−3z+2=0x - y + 2z = 0, x + y - 3z + 2 = 0

(4)

3x−2y−1=0,7y−3z−4=03x - 2y - 1 = 0, 7y - 3z - 4 = 0

(5)

x=2,y=5+t,z=4+3tx = 2, y = 5 + t, z = 4 + 3t.

Problem 6.24

For which aa does the line x1=ya=z−2−1\frac{x}{1} = \frac{y}{a} = \frac{z - 2}{ - 1}:

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(1)

intersect the plane 3a2x+ay+z−4a=03a^{2} x + ay + z - 4a = 0

(2)

is parallel to this plane

(3)

lie in this plane?

Problem 6.25

Given two lines. Determine whether they intersect, are skew, are parallel, or coincide. If the lines intersect or are parallel, find the equation of the plane in which they lie. If the lines intersect, also find the coordinates of their point of intersection. The lines are given by the equations:

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(1)

x+z−1=0,3x+y−z+13=0x + z - 1 = 0, 3x + y - z + 13 = 0 and x−2y+3=0,y+2z−8=0x - 2y + 3 = 0, y + 2z - 8 = 0;

(2)

x=3+t,y=−1+2t,z=4x = 3 + t, y = - 1 + 2t, z = 4 and x+y−z=0,2x−y+,+2z=0x + y - z = 0, 2x - y +, + 2z = 0;

(3)

x=2+4t,y=−6t,z=−1−8tx = 2 + 4t, y = - 6t, z = - 1 - 8t and x=7−6t,y=2+9t,z=12tx = 7 - 6t, y = 2 + 9t, z = 12t;

(4)

x=9t,y=5t,z=−3+tx = 9t, y = 5t, z = - 3 + t and 2x−3y−3z−9=0,x−2y+z+3=02x - 3y - 3z - 9 = 0, x - 2y + z + 3 = 0;

(5)

x=1+2t,y=7+t,z=3+4tx = 1 + 2t, y = 7 + t, z = 3 + 4t and x=6+3t,y=−1−2t,z=−2+tx = 6 + 3t, y = - 1 - 2t, z = - 2 + t.

Problem 6.26

For which aa do the lines x−1a=y−11=z−(a−2)2a\frac{x - 1}{a} = \frac{y - 1}{1} = \frac{z - (a - 2)^{2}}{a} and x1=ya=z1\frac{x}{1} = \frac{y}{a} = \frac{z}{1}:

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(1)

intersect

(2)

are skew

(3)

are parallel

(4)

coincide?

Problem 6.27

Investigate the mutual position of three planes; if there exist points belonging to all three planes simultaneously, find the coordinates of these points. The planes are given by the equations:

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(1)

2x+3y−4z−1=0,−x+5y−z−3=0,3x−10y+7z=02x + 3y - 4z - 1 = 0, - x + 5y - z - 3 = 0, 3x - 10y + 7z = 0;

(2)

x+y−2z+1=0,−x−y+2z+1=0,2x+2y−4z=0x + y - 2z + 1 = 0, - x - y + 2z + 1 = 0, 2x + 2y - 4z = 0

(3)

x+2y−z−1=0,−2x−4y+2z+2=0,4+4z−4x−8y=0x + 2y - z - 1 = 0, \quad - 2x - 4y + 2z + 2 = 0, \quad 4 + 4z - 4x - 8y = 0

(4)

5x−2y+4=0,3x+z−5=0,8x−2y+z+7=05x - 2y + 4 = 0, \quad 3x + z - 5 = 0, \quad 8x - 2y + z + 7 = 0

(5)

5x−2y+4=0,3x+z−5=0,8x−2y+z−1=05x - 2y + 4 = 0, 3x + z - 5 = 0, 8x - 2y + z - 1 = 0.

Problem 6.28

Find the equation of the plane passing through the point A(1,3,0)A(1, 3, 0) and parallel to the lines x+y−z+3=0x + y - z + 3 = 0, 2x−y+5z+1=02x - y + 5z + 1 = 0 and −x+y=1,5x+y−z+2=0- x + y = 1, 5x + y - z + 2 = 0.

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Problem 6.29

Find the equation of the plane:

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(1)

passing through the line x−13=y+24=z−12\frac{x - 1}{3} = \frac{y + 2}{4} = \frac{z - 1}{2} and parallel to the line x5=y−14=z+13\frac{x}{5} = \frac{y - 1}{4} = \frac{z + 1}{3}

(2)

passing through the line x=3+t,y=2+5t,z=−1+3tx = 3 + t, y = 2 + 5t, z = - 1 + 3t and parallel to the line x=4−2t,y=−8+t,z=5+2tx = 4 - 2t, y = - 8 + t, z = 5 + 2t.

Problem 6.30

Find the equation of the plane passing through the point A(−1,1,2)A(- 1, 1, 2) and the line given by the equations:

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(1)

x=1+5t,y=−1+t,z=2tx = 1 + 5t, \quad y = - 1 + t, \quad z = 2t

(2)

x+5y−7z+1=0,3x−y+2z+3=0x + 5y - 7z + 1 = 0, \quad 3x - y + 2z + 3 = 0.

Problem 6.31

Find the equation of the plane passing through the two parallel lines x−15=y+23=z−11\frac{x - 1}{5} = \frac{y + 2}{3} = \frac{z - 1}{1} and x−25=y3=z+31\frac{x - 2}{5} = \frac{y}{3} = \frac{z + 3}{1}

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Problem 6.32

Prove that the two given lines intersect and find the equation of the plane containing them:

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(1)

x+1−2=y−21=z−54\frac{x + 1}{ - 2} = \frac{y - 2}{1} = \frac{z - 5}{4} and x+52=y+83=z−4−1\frac{x + 5}{2} = \frac{y + 8}{3} = \frac{z - 4}{ - 1}

(2)

x=1+3t,y=−1+4t,z=2+5tx = 1 + 3t, y = - 1 + 4t, \quad z = 2 + 5t and x=1−t,y=−1+2t,z=2+4tx = 1 - t, y = - 1 + 2t, \quad z = 2 + 4t

Problem 6.33

A line is projected onto the plane OyzOyz parallel to the axis OxOx. Find the equations of the projection, if the line is given by the equations:

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(1)

x=1+2t,y=3t,z=1−tx = 1 + 2t, \quad y = 3t, \quad z = 1 - t

(2)

x+y+z−1=0,x+2y−3z+2=0x + y + z - 1 = 0, \quad x + 2y - 3z + 2 = 0.

Problem 6.34

A line is projected onto the plane x+2y−3z+2=0x + 2y - 3z + 2 = 0 parallel to the vector l(2,1,−1)\mathbf{l}(2, 1, - 1). Find the equations of the projection, if the line is given by the equations:

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(1)

x=1+2t,y=3t,z=−6−tx = 1 + 2t, y = 3t, \quad z = - 6 - t

(2)

x+y+z−1=0,y−3z+4=0x + y + z - 1 = 0, \quad y - 3z + 4 = 0.

Problem 6.35

Three faces of a parallelepiped lie in the planes x−3z+18=0,2x−4y+5z−21=0,6x+y+z−30=0x - 3z + 18 = 0, 2x - 4y + 5z - 21 = 0, 6x + y + z - 30 = 0, and one of its vertices AA has coordinates (−1,3,1)(- 1, 3, 1). Find the equations of the remaining faces of the parallelepiped and of its diagonal passing through vertex AA.

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Problem 6.36

Points A(1,0,3)A(1, 0, 3) and B(−1,2,1)B(- 1, 2, 1) are vertices of tetrahedron ABCDABCD, point K(−1,5,2)K(- 1, 5, 2) is the midpoint of edge BCBC, and point M(0,1,4)M(0, 1, 4) is the intersection point of the medians of face BCDBCD. Find the equations of the planes in which the faces of the tetrahedron lie.

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Problem 6.37

Find the equations of the line passing through the point O(0,0,0)O(0, 0, 0) and meeting the two given lines:

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(1)

x−y+z+2=0,x−2y+3z−8=0x - y + z + 2 = 0, x - 2y + 3z - 8 = 0 and y−z+1=0,x+y−2z+4=0y - z + 1 = 0, x + y - 2z + 4 = 0

(2)

x=1+2t,y=2+3t,z=−tx = 1 + 2t, \quad y = 2 + 3t, \quad z = - t and x=4t,y=5−5t,z=3+2tx = 4t, \quad y = 5 - 5t, \quad z = 3 + 2t.

Problem 6.38

Find the equations of the line passing through the point A(−1,1,−1)A(- 1, 1, - 1) and meeting the two given lines:

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(1)

x−y+z+2=0,x−2y+3z−8=0x - y + z + 2 = 0, x - 2y + 3z - 8 = 0 and y−z=0,x+y−2z+4=0y - z = 0, x + y - 2z + 4 = 0

(2)

x−12=y−23=z−1\frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z}{ - 1} and x4=y+5−5=z−32\frac{x}{4} = \frac{y + 5}{ - 5} = \frac{z - 3}{2}.

Problem 6.39

Find the equations of the line meeting the two lines x+32=y−53=z1\frac{x + 3}{2} = \frac{y - 5}{3} = \frac{z}{1} and x−105=y+74=z1\frac{x - 10}{5} = \frac{y + 7}{4} = \frac{z}{1} and parallel to the line x+28=y−17=z−31\frac{x + 2}{8} = \frac{y - 1}{7} = \frac{z - 3}{1}.

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Problem 6.40

Find the equations of the planes passing through the line x−13=y−15=z+24\frac{x - 1}{3} = \frac{y - 1}{5} = \frac{z + 2}{4} and equidistant from the points A(1,2,5)A(1, 2, 5) and BB(3,0,−1)\stackrel{B}{B}(3, 0, - 1).

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Problem 6.41

Find the equations of the planes passing through the point A(1,0,4)A(1, 0, 4) and equidistant from the three points B(2,1,6)B(2, 1, 6), C(−2,3,2)C(- 2, 3, 2) and D(8,1,0)D(8, 1, 0).

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Problem 6.42

Find the equations of the planes equidistant from the four points A(1,−1,3),B(3,3,5),C(1,7,3)A(1, - 1, 3), B(3, 3, 5), C(1, 7, 3) and D(5,1,5)D(5, 1, 5).

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Problem 6.43

Plane mm contains the points A,B,C,SA, B, C, S and meets the coordinate axes Ox,Oy,OzOx, Oy, Oz at the points P,Q,RP, Q, R, while the coordinate planes Oxy,Oxz,OyzOxy, Oxz, Oyz meet it along the lines l1,l2,l3l_{1}, l_{2}, l_{3}. In plane mm the coordinate system A,AB→,AC→A, \overrightarrow {AB}, \overrightarrow {AC} is chosen. It is known that point SS has coordinates (3,4)(3, 4) in this coordinate system, and points AA, B,CB, C have respectively the following coordinates in the original spatial coordinate system:

(1) (1,2,1),(−1,3,2),(1,4,0)(1, 2, 1), (- 1, 3, 2), (1, 4, 0);

(2) (2,1,1),(2,3,0),(1,1,2)(2, 1, 1), (2, 3, 0), (1, 1, 2);

(3) (1,−1,0),(1,0,−1),(0,1,1)(1, - 1, 0), (1, 0, - 1), (0, 1, 1).

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(1)

Find the coordinates of the points P,Q,R,SP, Q, R, S and the equations of the lines l1,l2,l3l_{1}, l_{2}, l_{3} in the original spatial coordinate system.

(2)

Find the coordinates of the points P,Q,RP, Q, R and the equations of the lines l1,l2,l3l_{1}, l_{2}, l_{3} in the coordinate system A,AB→,AC→A, \overrightarrow {AB}, \overrightarrow {AC}.

Problem 6.44

Through vertex C1C_{1} of parallelepiped ABCDA1B1C1D1ABCDA_{1} B_{1} C_{1} D_{1} a plane is drawn meeting the extensions of edges AB,ADAB, AD and AA1AA_{1} respectively at points B0,D0B_{0}, D_{0} and A0A_{0} such that ∣AB0∣∣AB∣=∣AD0∣∣AD∣=3∣AA0∣∣AA1∣\frac{\left|AB_{0}\right|}{\left|AB\right|} = \frac{\left|AD_{0}\right|}{\left|AD\right|} = 3\frac{\left|AA_{0}\right|}{\left|AA_{1}\right|}. Find the ratio of the volume of the parallelepiped to the volume of tetrahedron AB0D0A0AB_{0} D_{0} A_{0}.

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Problem 6.45

Find a normal vector of the plane:

?
(1)

Ax+By+Cz+D=0Ax + By + Cz + D = 0

(2)

x=x0+a1u+a2v,y=y0+b1u+b2v,z=z0+c1u+c2vx = x_{0} + a_{1} u + a_{2} v, y = y_{0} + b_{1} u + b_{2} v, z = z_{0} + c_{1} u + c_{2} v.

Problem 6.46

Find the equations of the line passing through the point A(1,−1,2)A(1, - 1, 2) and perpendicular to the plane:

?
(1)

x−3y+2z+1=0x - 3y + 2z + 1 = 0

(2)

x=5x = 5

(3)

y=4y = 4

(4)

z=3z = 3

(5)

x=4−u+v,y=2+u+2v,z=−1+7u+3vx = 4 - u + v, \quad y = 2 + u + 2v, \quad z = - 1 + 7u + 3v.

Problem 6.47

Find the equation of the plane passing through the point A(1,3,1)A(1, 3, 1) and perpendicular to the line:

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(1)

x+y−z+2=0,2x+3y+z−1=0x + y - z + 2 = 0, \quad 2x + 3y + z - 1 = 0

(2)

x+13=y−24=z+221\frac{x + 1}{3} = \frac{y - 2}{4} = \frac{z + 2}{21}

(3)

x=2,y=3x = 2, \quad y = 3

(4)

x=0,z=0x = 0, z = 0

(5)

y=−1,z=2y = - 1, \quad z = 2.

Problem 6.48

Find the equation of the plane passing through the point A(2,1,−1)A(2, 1, - 1) and perpendicular to the two planes: x−y+5z+1=0x - y + 5z + 1 = 0 and 2x+y=32x + y = 3.

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Problem 6.49

Find the equation of the plane perpendicular to the plane x+3y−z+2=0x + 3y - z + 2 = 0 and passing through the line:

?
(1)

x−12=y−13=z−14\frac{x - 1}{2} = \frac{y - 1}{3} = \frac{z - 1}{4}

(2)

2x−y+z=0,x+2y+z−3=02x - y + z = 0, x + 2y + z - 3 = 0.

Problem 6.50

In the pencil determined by the planes x+2y−3z+5=0x + 2y - 3z + 5 = 0 and 4x−y+3z+5=04x - y + 3z + 5 = 0, find two mutually perpendicular planes, one of which passes through the point M(1,3,1)M(1, 3, 1).

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Problem 6.51

Point AA lies on the line x−32=y3=z−1−1\frac{x - 3}{2} = \frac{y}{3} = \frac{z - 1}{ - 1}, and AA is equidistant from the points B(3,0,−2)B(3, 0, - 2) and C(−1,1,5)C(- 1, 1, 5). Find the coordinates of point AA.

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Problem 6.52

Find the distance from the point A(3,1,−1)A(3, 1, - 1) to the plane:

?
(1)

x−y−5z+2=0x - y - 5z + 2 = 0

(2)

x−2y+2z−2=0x - 2y + 2z - 2 = 0

(3)

x−2y+2z+7=0x - 2y + 2z + 7 = 0

(4)

x−2y+2z=0x - 2y + 2z = 0

(5)

x−2y+2z+1=0x - 2y + 2z + 1 = 0

(6)

x=1x = 1

(7)

y=5y = 5

(8)

z=0z = 0

Problem 6.53

Find the distance between the parallel planes:

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(1)

6x−3y+2z+5=06x - 3y + 2z + 5 = 0 and 6x−3y+2z−9=06x - 3y + 2z - 9 = 0

(2)

2x+2y−z+3=02x + 2y - z + 3 = 0 and 2x+2y−z+18=02x + 2y - z + 18 = 0

(3)

3x+4z+1=03x + 4z + 1 = 0 and 6x+8z−1=06x + 8z - 1 = 0.

Problem 6.54
?
(1)

Find the equations of the planes parallel to the plane 6x−3y+2z+5=06x - 3y + 2z + 5 = 0 and at distance 3 from it.

(2)

Find the equations of the planes parallel to the plane x+3y−z+11=0x + 3y - z + \sqrt{11} = 0 and at distance 3 from it.

(3)

Find the equations of the planes parallel to the plane 2x+2y−z+3=02x + 2y - z + 3 = 0 and at distance 3 from the point A(1,2,−1)A(1, 2, - 1).

(4)

Find the equations of the planes parallel to the plane 3x+4z+1=03x + 4z + 1 = 0 and at distance 3 from the origin.

Problem 6.55

Point AA lies on the line x−12=y3=z+11\frac{x - 1}{2} = \frac{y}{3} = \frac{z + 1}{1}. The distance from point AA to the plane x+y+z+3=0x + y + z + 3 = 0 equals 3\sqrt{3}. Find the coordinates of point AA.

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Problem 6.56

Point AA lies on the line x−11=y−33=z+4−5\frac{x - 1}{1} = \frac{y - 3}{3} = \frac{z + 4}{ - 5}, and AA is equidistant from the point B(0,1,1)B(0, 1, 1) and from the plane 2x−y+2z+1=02x - y + 2z + 1 = 0. Find the coordinates of point AA.

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Problem 6.57

Points A(1,−1,2)A(1, - 1, 2) and B(3,0,4)B(3, 0, 4) are vertices of a cube ABCDA1B1C1D1ABCDA_{1} B_{1} C_{1} D_{1}. The vector AD→\overrightarrow {AD} is perpendicular to the line x=0,y−z=0x = 0, y - z = 0, and the orientation of the triple of vectors AB→,AD→\overrightarrow {AB}, \overrightarrow {AD}. AA1→\overrightarrow {AA_{1}} coincides with the orientation of the triple of basis vectors of the coordinate system, and the sum of the coordinates of the vector AA1→\overrightarrow {AA_{1}} is negative. Find the equations of the faces of the cube.

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Problem 6.58

Points A(−3,0,0)A(- 3, 0, 0) and B(3,0,0)B(3, 0, 0) are vertices of a regular tetrahedron ABCDABCD, the vertex CC is at distance 323\sqrt{2} from the coordinate plane OxyOxy, and all coordinates of the point CC are nonnegative. The orientation of the triple of vectors AB→,AC→,AD→\overrightarrow {AB}, \overrightarrow {AC}, \overrightarrow {AD} coincides with the orientation of the triple of basis vectors of the coordinate system. Find the equations of the faces of the tetrahedron.

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Problem 6.59

Given the point A(3,−1,1)A(3, - 1, 1). Find:

?
(1)

the coordinates of the projections of the point AA onto the coordinate planes and the coordinates of the points symmetric to AA with respect to the coordinate planes

(2)

the coordinates of the projection of the point AA onto the plane x+2y+2z+6=0x + 2y + 2z + 6 = 0 and the coordinates of the point symmetric to AA with respect to this plane

(3)

the coordinates of the projection of the point AA onto the plane 2x+3y+6z+40=02x + 3y + 6z + 40 = 0 and the coordinates of the point symmetric to AA with respect to this plane.

Problem 6.60

Find the equations of the line symmetric to the line x−23=y+11=z−24\frac{x - 2}{3} = \frac{y + 1}{1} = \frac{z - 2}{4} with respect to the plane 5x−y+z−4=05x - y + z - 4 = 0.

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Problem 6.61

Find the equations of the projections onto the plane x+5y−z−25=0x + 5y - z - 25 = 0 of the following lines:

?
(1)

x+14=y2=z−13\frac{x + 1}{4} = \frac{y}{2} = \frac{z - 1}{3}

(2)

x−y+2z−1=0,3x−y+2z+2=0x - y + 2z - 1 = 0, \quad 3x - y + 2z + 2 = 0

(3)

x+11=y5=z−1−1\frac{x + 1}{1} = \frac{y}{5} = \frac{z - 1}{ - 1}.

Problem 6.62

Find the angle between the planes:

?
(1)

x+4y−z+1=0x + 4y - z + 1 = 0 and x+y−z−3=0x + y - z - 3 = 0

(2)

x+2y−z=1x + 2y - z = 1 and x−y=3x - y = 3

(3)

x+2y−2z=0x + 2y - 2z = 0 and z=5z = 5

(4)

x+2y−z−1=0x + 2y - z - 1 = 0 and 3x−5y−7z=03x - 5y - 7z = 0

(5)

x+3y−z+1=0x + 3y - z + 1 = 0 and x=1−u,y=2−3u−v,z=7+u+vx = 1 - u, \quad y = 2 - 3u - v, \quad z = 7 + u + v

(6)

x−3y+2z+1=0x - 3y + 2z + 1 = 0 and 6z−9y+3x+5=06z - 9y + 3x + 5 = 0.

Problem 6.63

Find the angle between the lines:

?
(1)

2x+y−z+1=0,x+3y+z+2=02x + y - z + 1 = 0, x + 3y + z + 2 = 0 and x+3y−z+2=0x + 3y - z + 2 = 0, x+y+z−1=0x + y + z - 1 = 0

(2)

x−12=y−23=z+3−1\frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z + 3}{ - 1} and x+1−3=y4=z−106\frac{x + 1}{ - 3} = \frac{y}{4} = \frac{z - 10}{6}

(3)

x=5−2t,y=6+4t,z=8tx = 5 - 2t, \quad y = 6 + 4t, \quad z = 8t and x=1+t,y=−2t,z=3−4tx = 1 + t, \quad y = - 2t, \quad z = 3 - 4t.

Problem 6.64

Find the angle between the plane 4x+4y−7z+1=04x + 4y - 7z + 1 = 0 and the line:

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(1)

x+y+z+1=0,2x+y+3z+2=0x + y + z + 1 = 0, 2x + y + 3z + 2 = 0

(2)

x−13=y+22=z−6\frac{x - 1}{3} = \frac{y + 2}{2} = \frac{z}{ - 6}

(3)

x−24=y−14=z+3−7\frac{x - 2}{4} = \frac{y - 1}{4} = \frac{z + 3}{ - 7}

(4)

x−111=y+1−4=z+34\frac{x - 1}{11} = \frac{y + 1}{ - 4} = \frac{z + 3}{4}.

Problem 6.65

Find the equations of the line passing through the point A(1,3,2)A(1, 3, 2) parallel to the plane OxyOxy and making:

?
(1)

an angle of 45∘45^{\circ } with the line x=y,z=0x = y, z = 0

(2)

an angle of arcsin⁡(1/10)\arcsin (1 / \sqrt{10}) with the plane x−y=1x - y = 1.

Problem 6.66

Find the equation of the plane passing through the point A(−1,2,1)A(- 1, 2, 1) parallel to the line x2=−y3=−z\frac{x}{2} = - \frac{y}{3} = - z and making an angle of 60∘60^{\circ } with the line x=y,z=0x = y, z = 0.

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Problem 6.67

Find the equation of the plane passing through the line x+5y+z=0,x−z+4=0x + 5y + z = 0, \quad x - z + 4 = 0 and making an angle 45∘c45^{\circ } \mathrm{c} the plane x−4y−8z+1=0x - 4y - 8z + 1 = 0.

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Problem 6.68

Prove that the two given lines intersect, and find the equations of the bisectors of the acute and obtuse angles between them:

?
(1)

x=4−4t,y=1+4t,z=−5+7tx = 4 - 4t, y = 1 + 4t, z = - 5 + 7t and x=−3+t,y=−1+2t,z=−4+2tx = - 3 + t, y = - 1 + 2t, \quad z = - 4 + 2t

(2)

x=4+t,y=1−t,z=5+4tx = 4 + t, y = 1 - t, \quad z = 5 + 4t and x=−3−3t,y=8+3tx = - 3 - 3t, \quad y = 8 + 3t, z=1z = 1

(3)

x=1+2t,y=2+3t,z=11−6tx = 1 + 2t, \quad y = 2 + 3t, \quad z = 11 - 6t and x=1+t,y=3+tx = 1 + t, \quad y = 3 + t, z=7−tz = 7 - t.

Problem 6.69

The legs of an isosceles triangle have a common vertex A(3,4,5)A(3, 4, 5), the other two vertices lie on the axes OxOx and OyOy, and the plane of the triangle is parallel to the axis OzOz. Find the angles of the triangle and find the equation of its plane.

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Problem 6.70

Given a point A(2,−1,0)A(2, - 1, 0) and a line ll. Compute the distance from the point AA to the line ll; find the coordinates of the projection of the point AA onto ll and the coordinates of the point BB symmetric to AA with respect to ll; find the equations of the line passing through the point AA and meeting the given line at a right angle ("drop a perpendicular" from the point AA to ll). The line ll is given by the equations:

?
(1)

x−73=y−14=z−32\frac{x - 7}{3} = \frac{y - 1}{4} = \frac{z - 3}{2}

(2)

x=1+2t,y=2−2t,z=−3+tx = 1 + 2t, \quad y = 2 - 2t, \quad z = - 3 + t

(3)

2x+y−z+1=0,x+y+z+2=02x + y - z + 1 = 0, x + y + z + 2 = 0.

Problem 6.71

The point AA lies on the line x−y−3=0,2y+z=0x - y - 3 = 0, 2y + z = 0. The distance from the point AA to the line x=y=zx = y = z equals 6\sqrt{6}. Find the coordinates of the point AA.

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Problem 6.72

Find the distance between the lines:

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(1)

x−43=y+16=z−1−2\frac{x - 4}{3} = \frac{y + 1}{6} = \frac{z - 1}{ - 2} and x−5−6=y−12=z4\frac{x - 5}{ - 6} = \frac{y}{ - 12} = \frac{z}{4}

(2)

x=3+2t,y=10−3t,z=3+4tx = 3 + 2t, y = 10 - 3t, z = 3 + 4t and x=1+3t,y=1−2tx = 1 + 3t, y = 1 - 2t, z=1+3tz = 1 + 3t

(3)

x+y+z−1=0,x+3y−z+2=0x + y + z - 1 = 0, x + 3y - z + 2 = 0 and x+3y+z+2=0x + 3y + z + 2 = 0, x+2y−z+1=0x + 2y - z + 1 = 0.

Problem 6.73

Given lines l1l_{1} and l2l_{2}. Find the equations of their common perpendicular (i.e., the line meeting l1l_{1} and l2l_{2} at a right angle); find the points of intersection of the common perpendicular with the given lines; compute the distance between l1l_{1} and l2l_{2}. The lines are given by the equations:

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(1)

x=5+t,y=3−t,z=13+tx = 5 + t, \quad y = 3 - t, \quad z = 13 + t and x=6+t,y=1+2t,z=10−tx = 6 + t, \quad y = 1 + 2t, z = 10 - t;

(2)

2x+7y−13=0,3y−2z−1=02x + 7y - 13 = 0, \quad 3y - 2z - 1 = 0 and x+y−8=0,2x+y−z=0x + y - 8 = 0, 2x + y - z = 0;

(3)

x−61=y−12=z−10−1\frac{x - 6}{1} = \frac{y - 1}{2} = \frac{z - 10}{ - 1} and x+4−7=y−32=z−43\frac{x + 4}{ - 7} = \frac{y - 3}{2} = \frac{z - 4}{3}.

Problem 6.74

Points A(−1,−3,1),B(5,3,8),C(−1,−3,5),D(2A(- 1, - 3, 1), B(5, 3, 8), C(- 1, - 3, 5), D(2, 1,−4)1, - 4) are vertices of a tetrahedron. Find:

?
(1)

the length of the altitude of the tetrahedron dropped from the vertex DD to the face ABCABC

(2)

the length of the altitude of the base ABCABC dropped from the vertex CC to the side ABAB

(3)

the distance between the skew edges ADAD and BCBC

(4)

the angle between the skew edges ADAD and BCBC

(5)

the angle between the edge ADAD and the face ABCABC.

Problem 6.75

The length of the edge of the cube ABCDA1B1C1D1ABCDA_{1} B_{1} C_{1} D_{1} equals 1. Find:

?
(1)

the distance from the vertex AA to the plane B1CD1B_{1} CD_{1}

(2)

the distance between the diagonal of the cube AC1AC_{1} and the diagonal of the lateral face CD1CD_{1} skew to it

(3)

the ratios in which the points of intersection of the common perpendicular to the lines AC1AC_{1} and CD1CD_{1} with these lines divide the segments AC1AC_{1} and CD1CD_{1}.

Problem 6.76

Three faces ABCD,ABB1A1ABCD, ABB_{1} A_{1} and ADD1A1ADD_{1} A_{1} of a parallelepiped ABCDA1B1C1D1ABCDA_{1} B_{1} C_{1} D_{1} lie respectively in the planes 2x+3y+4z+8=0,x+3y−6=0,z+5=02x + 3y + 4z + 8 = 0, x + 3y - 6 = 0, z + 5 = 0; the vertex C1C_{1} has coordinates 6,−5,16, - 5, 1. Find:

?
(1)

the distance from the vertex A1A_{1} to the plane B1BDB_{1} BD

(2)

the distance from the vertex DD to the line ABAB

(3)

the distance between the lines ACAC and A1C1A_{1} C_{1}

(4)

the distance between the lines AA1AA_{1} and BCBC

(5)

the angle between the lines ACAC and C1D1C_{1} D_{1}

(6)

the angle between the planes BDD1BDD_{1} and ACC1ACC_{1}

(7)

the angle between the line CA1CA_{1} and the plane DCC1DCC_{1}.

Problem 6.77

Find the necessary and sufficient conditions for the one of the four dihedral angles, formed by two intersecting non-perpendicular planes A1x+B1y+C1z+D1=0A_{1} x + B_{1} y + C_{1} z + D_{1} = 0 and A2x+B2y+C2z+D2=0A_{2} x + B_{2} y + C_{2} z + D_{2} = 0, that contains the point M0(x0,y0,z0)M_{0}\left(x_{0}, y_{0}, z_{0}\right), to be:

?
(1)

acute

(2)

obtuse.

Problem 6.78

Given two planes x+2y+2z=0x + 2y + 2z = 0 and 7x+4y+4z=07x + 4y + 4z = 0. A third plane mm passes through the origin OO so that the endpoint of its normal vector, laid off from the point OO, lies in the obtuse dihedral angle formed by the given planes. The cosines of the acute dihedral angles between mm and the given planes equal 2/152 / 15 and 4 / 45 respectively. Find the equation of the plane mm.

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Problem 6.79

Consider the dihedral angle between the planes x−2y+z+3=0x - 2y + z + 3 = 0 and x+y+2z=1x + y + 2z = 1, inside which the point A(−1,0,0)A(- 1, 0, 0) lies. Prove that the set of points lying inside this angle and at distances 6\sqrt{6} and 262\sqrt{6} from the given planes respectively is a line. Find the equations of this line.

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Problem 6.80

Find the equation of the bisector plane of the dihedral angle between the planes x−z−5=0x - z - 5 = 0 and 3x+5y+4z=03x + 5y + 4z = 0 inside which the point A(1,1,1)A(1, 1, 1) lies.

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Problem 6.81

Find the equation of the bisector plane of the acute dihedral angle between the planes x−z−5=0x - z - 5 = 0 and 3x+5y+4z=03x + 5y + 4z = 0.

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Problem 6.82

The faces of a tetrahedron are given by the equations x+2y−2z+3=0,4x−4y+7z−9=0,8x+4y+z−3=0,y−z=0x + 2y - 2z + 3 = 0, 4x - 4y + 7z - 9 = 0, 8x + 4y + z - 3 = 0, y - z = 0. Find the equations of:

?
(1)

the bisector plane of the interior dihedral angle between the first two faces

(2)

the line lying in the interior trihedral angle between the first three faces, all points of which are equidistant from these three faces.

Problem 6.83

The vertices of a tetrahedron are the points A(1,2,3)A(1, 2, 3), B(−2,8,9),C(5,0,7),D(3,4,2)B(- 2, 8, 9), C(5, 0, 7), D(3, 4, 2). Find the radii and the coordinates of the centers of the inscribed and circumscribed spheres.

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Problem 6.84

Find the radius and the coordinates of the center of the sphere passing through the point A(0,1,0)A(0, 1, 0) and tangent to the planes x+y=0x + y = 0, x−y=0,x+y+4z=0x - y = 0, \quad x + y + 4z = 0.

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Problem 6.85

Find the coordinates of the center OO and the radius rr of the sphere tangent to the planes 5x−y+z−17=05x - y + z - 17 = 0 and x+y−z+11=0x + y - z + 11 = 0 and passing through the points A(−7,−1,−1)A(- 7, - 1, - 1) and B(1,1,1)B(1, 1, 1).

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Problem 6.86

Find the coordinates of the center OO and the radius rr of the sphere tangent to the plane x+5y+z−33=0x + 5y + z - 33 = 0 and passing through the points A(2,3,−2),B(−2,3,4)A(2, 3, - 2), B(- 2, 3, 4) and C(0,−1,2)C(0, - 1, 2).

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Problem 6.87

The vertices of a triangle are the points A(1,2,3)A(1, 2, 3), B(1,5,−1),C(5,3,−5)B(1, 5, - 1), C(5, 3, - 5). Find the radii and the coordinates of the centers of the inscribed and circumscribed circles.

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Problem 6.88

Prove that the three planes x−2y+2z+3=0x - 2y + 2z + 3 = 0, 2x+2y+z−6=0,5x+14y−2z−21=02x + 2y + z - 6 = 0, 5x + 14y - 2z - 21 = 0 have no common points, but the three lines formed by the intersection of each pair of these planes are parallel, i.e., the planes form a prism. Find the radius and the equations of the axis of the right circular cylindrical surface:

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(1)

inscribed in this prism;

(2)

circumscribed about it.

Problem 6.89

In a regular quadrilateral pyramid SMNPQ(SSMNPQ (S is the apex), points HH and FF are the midpoints of the edges MNMN and NPNP respectively. The point EE lies on the segment SHSH, with ∣SH∣=3\left|SH\right| = 3, ∣SE∣=9/4\left|SE\right| = 9 / 4. The distance from the point SS to the line EFEF equals 5\sqrt{5}. Find the volume of the pyramid.

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Problem 6.90

The base of a right prism ABCDA1B1C1D1ABCDA_{1} B_{1} C_{1} D_{1} is a rhombus ABCDABCD with angle ∠A=60∘\angle A = 60^{\circ }. The length of the side of the base of the prism equals aa, the length of the lateral edge equals 3a\sqrt{3} a. The point EE is the orthogonal projection of the vertex C1C_{1} onto the plane AB1D1AB_{1} D_{1}, and the point FF is the orthogonal projection of the point EE onto the plane AA1D1DAA_{1} D_{1} D. Find the volume of the pyramid ADEFADEF.

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Problem 6.91

In a regular prism ABCA1B1C1ABCA_{1} B_{1} C_{1} the length of the lateral edge equals 3. The point MM is the midpoint of the edge ACAC, the point NN lies on the edge B1C1B_{1} C_{1}, and the point PP belongs to the face AA1B1BAA_{1} B_{1} B and is at distance 1 from the plane ABCABC. It is known that each of the lines PMPM and PNPN makes an angle of 30∘30^{\circ } with the plane AA1B1BAA_{1} B_{1} B, and the line PNPN makes an angle of 30∘30^{\circ } with the plane BB1C1CBB_{1} C_{1} C. Find the volume of the prism.

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Problem 6.92

In a regular prism ABCA1B1C1ABCA_{1} B_{1} C_{1} the length of the side of the base equals 2a2a, the length of the lateral edge equals aa. Through the vertex AA a plane is drawn perpendicular to the line AB1AB_{1}, through the vertex BB a plane perpendicular to the line BC1BC_{1}, and through the vertex CC a plane perpendicular to the line CA1CA_{1}. Find the volume of the polyhedron bounded by these three planes and the plane A1B1C1A_{1} B_{1} C_{1}.

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Problem 6.93

Given two coordinate systems O,e1,e2,e3O, \mathbf{e}_{1}, \mathbf{e}_{2}, \mathbf{e}_{3} and O′,e1′O^{\prime }, \mathbf{e}_{1}^{\prime }, e2′,e3′\mathbf{e}_{2}^{\prime }, \mathbf{e}_{3}^{\prime }. The origin of the second coordinate system has coordinates a10,a20,a30a_{10}, a_{20}, a_{30} in the first system, and the basis vectors of the second system have coordinates (a11,a21,a31)\left(a_{11}, a_{21}, a_{31}\right), (a12,a22,a32),(a13,a23,a33)\left(a_{12}, a_{22}, a_{32}\right), \left(a_{13}, a_{23}, a_{33}\right) respectively in the basis of the first system. In the first coordinate system a plane is given by the equation Ax+By+Cz+D=0Ax + By + Cz + D = 0. Find the equation of this plane in the second system.

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Problem 6.94

In space, four points A(1,2,1)A(1, 2, 1), B(−1,3,0),C(2,5,3),D(−2,3,4)B(- 1, 3, 0), C(2, 5, 3), D(- 2, 3, 4) and a plane 2x+y−3z+2=02x + y - 3z + 2 = 0 are given. Find the equation of this plane in the new coordinate system A,AB→,AC→,AD→A, \overrightarrow {AB}, \overrightarrow {AC}, \overrightarrow {AD}.

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Problem 6.95

The planes x−2y+3z−6=0,2x+y−z=0,4x+z−5=0x - 2y + 3z - 6 = 0, 2x + y - z = 0, 4x + z - 5 = 0 are respectively the planes O′y′z′,O′z′x′O^{\prime } y^{\prime } z^{\prime }, O^{\prime } z^{\prime } x^{\prime }, O′x′y′O^{\prime } x^{\prime } y^{\prime } of a new coordinate system, and the point A(2,0,1)A(2, 0, 1) has coordinates 1,1,11, 1, 1 in the new system.

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(1)

Find the coordinates of a point in the original coordinate system, if its coordinates x′,y′,z′x^{\prime }, y^{\prime }, z^{\prime } in the new system are known.

(2)

Find, in the new coordinate system, the canonical equations of the line which in the original system is given by the equations x−11=y+1−4=z−2−1\frac{x - 1}{1} = \frac{y + 1}{ - 4} = \frac{z - 2}{ - 1}.

Problem 6.96

In a rectangular coordinate system O,e1,e2,e3O, \mathbf{e}_{1}, \mathbf{e}_{2}, \mathbf{e}_{3} a plane is given by the equation 3x+5y+2z+2=03x + 5y + \sqrt{2} z + \sqrt{2} = 0. The origin of the new rectangular coordinate system is at the point O′(1,1,−1)O^{\prime }(1, 1, - 1), the basis vector e3′\mathbf{e}_{3}^{\prime } is opposite to the vector e3\mathbf{e}_{3}, and the basis vectors e1′\mathbf{e}_{1}^{\prime } and e2′\mathbf{e}_{2}^{\prime } are obtained from the vectors e1\mathbf{e}_{1} and e2\mathbf{e}_{2} respectively by a rotation, in the plane containing e1\mathbf{e}_{1} and e2\mathbf{e}_{2}, through an angle of 45∘45^{\circ } in the direction of the shortest rotation from e1\mathbf{e}_{1} to e2\mathbf{e}_{2}.

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(1)

Find the coordinates of a point in the original coordinate system, if its coordinates x′,y′,z′x^{\prime }, y^{\prime }, z^{\prime } in the new system are known.

(2)

Find the equation of the given plane in the new coordinate system.

Problem 6.97

Three planes, given in a rectangular coordinate system by the equations x+2y−2z+3=0,2x+y+2z=0x + 2y - 2z + 3 = 0, 2x + y + 2z = 0, 2x−2y−z+3=02x - 2y - z + 3 = 0 (verify that they are pairwise perpendicular), are respectively the planes O′y′z′,O′z′x′O^{\prime } y^{\prime } z^{\prime }, O^{\prime } z^{\prime } x^{\prime }, O′x′y′O^{\prime } x^{\prime } y^{\prime } of a new rectangular coordinate system, and the point A(−1,0,0)A(- 1, 0, 0) has positive coordinates in the new system.

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(1)

Find the coordinates of a point in the original coordinate system, if its coordinates x′,y′,z′x^{\prime }, y^{\prime }, z^{\prime } in the new system are known.

(2)

Find, in the new coordinate system, the canonical equations of the lines given in the original system by the equations x−12=y−11=z−31\frac{x - 1}{2} = \frac{y - 1}{1} = \frac{z - 3}{1} and x=y=zx = y = z. Compute, in both coordinate systems, the angle and the distance between these lines; verify that the results agree.