Elements of pseudo-orthogonal, pseudo-unitary and symplectic groups

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Prove that any pseudo-orthogonal matrix of type (1,1)(1,1) (see problem 1625) has the form

±(11−β2±β1−β2β1−β2±11−β2) \pm \left(\begin{smallmatrix} \frac{1}{\sqrt{1-\beta ^{2}}} & \pm \frac{\beta }{\sqrt{1-\beta ^{2}}} \\ \frac{\beta }{\sqrt{1-\beta ^{2}}} & \pm \frac{1}{\sqrt{1-\beta ^{2}}} \end{smallmatrix}\right)

(the Lorentz parametrization of the group O(1,1)O(1,1)).

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Prove that any pseudo-orthogonal matrix of type (1,1)(1,1) (see problem 1625) has the form

±(ch⁡φ±sh⁡φsh⁡φ±ch⁡φ) \pm \left(\begin{smallmatrix} \operatorname {ch} \varphi & \pm \operatorname {sh} \varphi \\ \operatorname {sh} \varphi & \pm \operatorname {ch} \varphi \end{smallmatrix}\right)

(hyperbolic rotations).

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Find all 2×22 \times 2 matrices gg over C\mathbb {C} such that det⁡(g)=1\operatorname {det}\left(g\right) = 1, ηg∗η=g−1\eta g^{*} \eta = g^{-1}, where η\eta is the diagonal matrix η=diag⁡(1,−1)\eta = \operatorname {diag}(1,-1).

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Consider the matrix (ζ∈R\zeta \in \mathbb {R})

S(ζ)=(cosh⁡(ζ)00sinh⁡(ζ)0cosh⁡(ζ)sinh⁡(ζ)00sinh⁡(ζ)cosh⁡(ζ)0sinh⁡(ζ)00cosh⁡(ζ)). S(\zeta ) = \begin{pmatrix} \cosh (\zeta ) & 0 & 0 & \sinh (\zeta ) \\ 0 & \cosh (\zeta ) & \sinh (\zeta ) & 0 \\ 0 & \sinh (\zeta ) & \cosh (\zeta ) & 0 \\ \sinh (\zeta ) & 0 & 0 & \cosh (\zeta ) \end{pmatrix}.
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(i)

Show that the matrix is invertible, i.e. find the determinant.

(ii)

Calculate the inverse of S(ζ)S(\zeta ).

(iii)

Calculate

A:=ddζS(ζ)∣ζ=0 A := \frac{d}{d\zeta }S(\zeta )\bigg|_{\zeta =0}

and then calculate exp⁡(ζA)\exp (\zeta A).

(iv)

Do the matrices S(ζ)S(\zeta ) form a group under matrix multiplication?

Let JJ be the 2n×2n2n \times 2n matrix

J:=(0nIn−In0n). J := \begin{pmatrix} 0_{n} & I_{n} \\ -I_{n} & 0_{n} \end{pmatrix}.

Show that the 2n×2n2n \times 2n matrices AA satisfying ATJA=JA^{T}JA = J form a group under matrix multiplication. This group is called the symplectic group Sp(2n)Sp(2n).

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The Lie group SU(1,1)SU(1,1) consists of all 2×22 \times 2 matrices TT over the complex numbers with

TMT∗=M,M=(100−1),det⁡(T)=1. TMT^{*} = M, \qquad M = \begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix}, \qquad \operatorname {det}\left(T\right) = 1.

Show that the conditions on ξ0,ξ1,ξ2,ξ3∈R\xi_{0}, \xi_{1}, \xi_{2}, \xi_{3} \in \mathbb {R} such that

T=(ξ0+iξ3ξ1+iξ2ξ1−iξ2ξ0−iξ3) T = \begin{pmatrix} \xi _{0}+i\xi _{3} & \xi _{1}+i\xi _{2} \\ \xi _{1}-i\xi _{2} & \xi _{0}-i\xi _{3} \end{pmatrix}

is an element of SU(1,1)SU(1,1) is given by det⁡(T)=ξ02+ξ32−ξ12−ξ22=1\operatorname {det}\left(T\right) = \xi_{0}^{2}+\xi_{3}^{2}-\xi_{1}^{2}-\xi_{2}^{2} = 1.

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(i)

Can any element of the Lie group SU(1,1)SU(1,1) be written as

(eiα/200e−iα/2)(cosh⁡(ζ/2)sinh⁡(ζ/2)sinh⁡(ζ/2)cosh⁡(ζ/2))(eiβ/200e−iβ/2)? \begin{pmatrix} e^{i\alpha /2} & 0 \\ 0 & e^{-i\alpha /2} \end{pmatrix} \begin{pmatrix} \cosh (\zeta /2) & \sinh (\zeta /2) \\ \sinh (\zeta /2) & \cosh (\zeta /2) \end{pmatrix} \begin{pmatrix} e^{i\beta /2} & 0 \\ 0 & e^{-i\beta /2} \end{pmatrix}?

Each element in the this product is an element of the Lie group SU(1,1)SU(1,1).

(ii)

Can any element of the compact Lie group SU(2)SU(2) be written as

(cos⁡(α/2)−sin⁡(α/2)sin⁡(α/2)cos⁡(α/2))(eiγ/200e−iγ/2)(cos⁡(β/2)sin⁡(β/2)−sin⁡(β/2)cos⁡(β/2))? \begin{pmatrix} \cos (\alpha /2) & -\sin (\alpha /2) \\ \sin (\alpha /2) & \cos (\alpha /2) \end{pmatrix} \begin{pmatrix} e^{i\gamma /2} & 0 \\ 0 & e^{-i\gamma /2} \end{pmatrix} \begin{pmatrix} \cos (\beta /2) & \sin (\beta /2) \\ -\sin (\beta /2) & \cos (\beta /2) \end{pmatrix}?

Let nn be an integer with n≥2n \geq 2. Let p,qp, q be integers with p,q≥1p, q \geq 1 and n=p+qn = p+q. Let IpI_{p} be the p×pp \times p identity matrix and IqI_{q} be the q×qq \times q identity matrix. Let

Ip,q=(Ip00−Iq)≡Ip⊕(−Iq). I_{p,q} = \begin{pmatrix} I_{p} & 0 \\ 0 & -I_{q} \end{pmatrix} \equiv I_{p} \oplus (-I_{q}).

The Lie group O(p,q)O(p,q) is the set of all n×nn \times n matrices defined by

O(p,q):={A∈GL(n,R):ATIp,qA=Ip,q}. O(p,q) := \left\{ A \in GL(n, \mathbb {R}) : A^{T}I_{p,q}A = I_{p,q}\right\} .

Show that this is the group of all invertible linear maps of Rn\mathbb {R}^{n} that preserves the quadratic form

∑j=1pxjyj−∑j=p+1nxjyj. \sum _{j=1}^{p} x_{j}y_{j} - \sum _{j=p+1}^{n} x_{j}y_{j}.
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The Lie group SU(2,2)SU(2,2) is defined as the group of transformation on the four dimensional complex space C4\mathbb {C}^{4} leaving invariant the indefinite quadratic form

∣z1∣2+∣z2∣2−∣z3∣2−∣z4∣2. \left|z_{1}\right|^{2}+\left|z_{2}\right|^{2}-\left|z_{3}\right|^{2}-\left|z_{4}\right|^{2}.

The Lie algebra su(2,2)su(2,2) is defined as the 4×44 \times 4 matrices XX with trace 0 and X∗L+LX=04X^{*}L+LX = 0_{4}, where LL is the 4×44 \times 4 matrix

L=(−I20202I2). L = \begin{pmatrix} -I_{2} & 0_{2} \\ 0_{2} & I_{2} \end{pmatrix}.

Is

X=(0110)⊗(0110) X = \begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix} \otimes \begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix}

an element of the Lie algebra su(2,2)su(2,2)? Find exp(zX)\mathrm{exp}\left(zX\right). Discuss.

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(i)

Consider the non-compact Lie group SO(1,1,R)SO(1, 1, \mathbb {R}) with the element

A(α)=(cosh⁡(α)sinh⁡(α)sinh⁡(α)cosh⁡(α)). A(\alpha ) = \begin{pmatrix} \cosh (\alpha ) & \sinh (\alpha ) \\ \sinh (\alpha ) & \cosh (\alpha ) \end{pmatrix}.

Show that the inverse of A(α)A(\alpha ) is given by

A−1(α)=A(−α)=(cosh⁡(α)−sinh⁡(α)−sinh⁡(α)cosh⁡(α)). A^{-1}(\alpha ) = A(-\alpha ) = \begin{pmatrix} \cosh (\alpha ) & -\sinh (\alpha ) \\ -\sinh (\alpha ) & \cosh (\alpha ) \end{pmatrix}.

Show that the eigenvalues of A(α)A(\alpha ) are given by eαe^{\alpha } and e−αe^{-\alpha }.

(ii)

Let ⊕\oplus be the direct sum. Find the determinant, eigenvalues and normalized eigenvectors of the 3×33 \times 3 matrix (1)⊕A(α)(1) \oplus A(\alpha ).

The Lie group SU(2,2)SU(2,2) is defined as the group of transformation on the four dimensional complex space C4\mathbb {C}^{4} leaving invariant the indefinite quadratic form

∣z1∣2+∣z2∣2−∣z3∣2−∣z4∣2. \left|z_{1}\right|^{2}+\left|z_{2}\right|^{2}-\left|z_{3}\right|^{2}-\left|z_{4}\right|^{2}.

The Lie algebra su(2,2)\mathfrak {su}(2,2) is defined as the 4×44 \times 4 matrices XX with trace 0 and X∗L+LX=04X^{*}L+LX = 0_{4}, where LL is the 4×44 \times 4 matrix

L=(−I20202I2). L = \begin{pmatrix} -I_{2} & 0_{2} \\ 0_{2} & I_{2} \end{pmatrix}.

Is

X=(0001001001001000) X = \begin{pmatrix} 0 & 0 & 0 & 1 \\ 0 & 0 & 1 & 0 \\ 0 & 1 & 0 & 0 \\ 1 & 0 & 0 & 0 \end{pmatrix}

an element of the Lie algebra su(2,2)\mathfrak {su}(2,2)? Find exp(zX)\mathrm{exp}\left(zX\right). Discuss.

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The Lie group SU(1,1)SU(1,1) consists of the set of all 2×22 \times 2 pseudo-unitary matrices (of determinant 11) preserving the quadratic form

∣z1∣2−∣z2∣2,(z1,z2∈C). \left|z_{1}\right|^{2} - \left|z_{2}\right|^{2}, \quad (z_{1}, z_{2} \in \mathbb {C}) .
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(i)

Show that the 2×22 \times 2 matrix

U(τ,α,β)=(cosh⁡(τ/2)e−iαsinh⁡(τ/2)e−iβsinh⁡(τ/2)eiβcosh⁡(τ/2)eiα)(1) U(\tau , \alpha , \beta ) = \begin{pmatrix} \cosh (\tau /2) e^{-i\alpha } & \sinh (\tau /2) e^{-i\beta } \\ \sinh (\tau /2) e^{i\beta } & \cosh (\tau /2) e^{i\alpha } \end{pmatrix} \tag {1}

preserves the quadratic form ∣z1∣2−∣z2∣2\left|z_{1}\right|^{2} - \left|z_{2}\right|^{2} (z1,z2∈C)(z_{1}, z_{2} \in \mathbb {C}), where τ,α,β∈R\tau , \alpha , \beta \in \mathbb {R}.

(ii)

Show that det⁡(U(τ,α,β))=1\operatorname {det}\left(U(\tau , \alpha , \beta )\right) = 1.

(iii)

Give the inverse of U(τ,α,β)U(\tau , \alpha , \beta ).

(iv)

Show that U1(τ1,α1,β1)U2(τ2,α2,β2)U_{1}(\tau_{1}, \alpha_{1}, \beta_{1}) U_{2}(\tau_{2}, \alpha_{2}, \beta_{2}) with α1+α2=β1−β2\alpha_{1} + \alpha_{2} = \beta_{1} - \beta_{2} is again a matrix of the form (1).

Given the invertible 4×44 \times 4 matrix

G=(−1000010000100001). G = \begin{pmatrix} -1 & 0 & 0 & 0 \\ 0 & 1 & 0 & 0 \\ 0 & 0 & 1 & 0 \\ 0 & 0 & 0 & 1 \end{pmatrix} .

Find two non-diagonal matrices LL over R\mathbb {R} such that LTGL=GL^{T}GL = G. Such transformations are known as Lorentz transformations.

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Consider the Lie group SO(1,1,R)SO(1,1,\mathbb {R}). Let

A(ϕ)=(cosh⁡ϕsinh⁡ϕsinh⁡ϕcosh⁡ϕ) A(\phi ) = \begin{pmatrix} \cosh \phi & \sinh \phi \\ \sinh \phi & \cosh \phi \end{pmatrix}

be an element of SO(1,1,R)SO(1,1,\mathbb {R}). Find a 2×22 \times 2 matrix BB such that B−1A(ϕ)BB^{-1}A(\phi )B is diagonal. To find BB calculate the eigenvalues and normalized eigenvectors of A(ϕ)A(\phi ). Is BB an element of the Lie group SO(1,1,R)SO(1,1,\mathbb {R})?

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One natural parameterization of the Lie algebra su(1,1)su(1,1) as a sub Lie algebra of sp(2,2)sp(2,2) is given by the 4×44 \times 4 matrices

R1=(0001001001001000),R2=(i0000−i0000i0000−i),R3=(000i00−i00i00−i000) R_{1} = \begin{pmatrix} 0 & 0 & 0 & 1 \\ 0 & 0 & 1 & 0 \\ 0 & 1 & 0 & 0 \\ 1 & 0 & 0 & 0 \end{pmatrix}, \qquad R_{2} = \begin{pmatrix} i & 0 & 0 & 0 \\ 0 & -i & 0 & 0 \\ 0 & 0 & i & 0 \\ 0 & 0 & 0 & -i \end{pmatrix}, \qquad R_{3} = \begin{pmatrix} 0 & 0 & 0 & i \\ 0 & 0 & -i & 0 \\ 0 & i & 0 & 0 \\ -i & 0 & 0 & 0 \end{pmatrix}

with [R1,R2]=−2R3[R_{1}, R_{2}] = -2R_{3}, [R3,R1]=2R2[R_{3}, R_{1}] = 2R_{2}, [R2,R3]=−2R1[R_{2}, R_{3}] = -2R_{1}. Find g2g1g2g_{2}g_{1}g_{2}, where g1=exp(αR1)g_{1} = \mathrm{exp}\left(\alpha R_{1}\right) and g2=exp(βR2/2)g_{2} = \mathrm{exp}\left(\beta R_{2}/2\right).

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(i)

Let t∈Rt \in \mathbb {R}. Show that the matrix

gt=(cosh⁡tisinh⁡t−isinh⁡tcosh⁡t) g_{t} = \begin{pmatrix} \cosh t & i\sinh t \\ -i\sinh t & \cosh t \end{pmatrix}

has an inverse and find gt−1g_{t}^{-1}. gtg_{t} is an element of SO(1,1)SO(1,1).

(ii)

The symmetric space SL(2,C)/SU(2)SL(2, \mathbb {C})/SU(2) can be identified with the space H3H^{3} of positive 2×22 \times 2 matrices with determinant 11

A=(a+bx+iyx−iya−b),a,b,c,d∈R A = \begin{pmatrix} a+b & x+iy \\ x-iy & a-b \end{pmatrix}, \qquad a,b,c,d \in \mathbb {R}

i.e. det⁡A=a2−b2−x2−y2=1\det A = a^{2}-b^{2}-x^{2}-y^{2} = 1. The group action is defined by

gt⋅A:=gtAgt∗. g_{t} \cdot A := g_{t}Ag_{t}^{*} .

Find gt⋅Ag_{t} \cdot A.

(iii)

Show that on the hyperboloid a2=1+b2+x2+y2a^{2} = 1+b^{2}+x^{2}+y^{2}, the matrix gtg_{t} only changes the coordinates yy and aa.

We consider the Lie groups U(2,2)U(2,2), SU(2,2)SU(2,2) and the corresponding Lie algebras u(2,2)u(2,2), su(2,2)su(2,2), respectively. We define the matrix

L:=(−10000−10000100001). L := \begin{pmatrix} -1 & 0 & 0 & 0 \\ 0 & -1 & 0 & 0 \\ 0 & 0 & 1 & 0 \\ 0 & 0 & 0 & 1 \end{pmatrix} .

Then

U(2,2):={G∈GL(4,C):G∗LG=L}SU(2,2):={G∈U(2,2):det⁡G=1}u(2,2):={X∈M4(C):XL+LX=04}su(2,2):={X∈u(2,2):\tr(X)=0} \begin{align} U(2,2) & := \left\{ G \in GL(4, \mathbb {C}) : G^{*}LG = L\right\} \\ SU(2,2) & := \left\{ G \in U(2,2) : \det G = 1\right\} \\ u(2,2) & := \left\{ X \in M_{4}(\mathbb {C}) : XL+LX = 0_{4}\right\} \\ su(2,2) & := \left\{ X \in u(2,2) : \tr (X) = 0\right\} \end{align}

where M4(C)M_{4}(\mathbb {C}) is the vector space of the 4×44 \times 4 matrices over the complex numbers.

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(i)

Show that

X=(0001001001001000) X = \begin{pmatrix} 0 & 0 & 0 & 1 \\ 0 & 0 & 1 & 0 \\ 0 & 1 & 0 & 0 \\ 1 & 0 & 0 & 0 \end{pmatrix}

is an element of u(2,2)u(2,2) and su(2,2)su(2,2).

(ii)

Let t∈Rt \in \mathbb {R}. Calculate exp(tX)\mathrm{exp}\left(tX\right) to find an element of SU(2,2)SU(2,2).

Let α∈R\alpha \in \mathbb {R}. Given the matrix

A(α)=(cosh⁡α00sinh⁡α0cos⁡αsin⁡α00−sin⁡αcos⁡α0sinh⁡α00cosh⁡α). A(\alpha ) = \begin{pmatrix} \cosh \alpha & 0 & 0 & \sinh \alpha \\ 0 & \cos \alpha & \sin \alpha & 0 \\ 0 & -\sin \alpha & \cos \alpha & 0 \\ \sinh \alpha & 0 & 0 & \cosh \alpha \end{pmatrix} .

Write a SymbolicC++ program that calculates the vector

A(α)(x0x1x2x3) A(\alpha ) \begin{pmatrix} x_{0} \\ x_{1} \\ x_{2} \\ x_{3} \end{pmatrix}

and shows that x02+x12+x22−x32x_{0}^{2}+x_{1}^{2}+x_{2}^{2}-x_{3}^{2} is invariant.

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References

[Сми16] Смирнов Ю.М. Сборник задач по аналитической геометрии и линейной алгебре. МЦНМО, 2016.
[StHa17] Steeb W., Hardy Y. Problems and Solutions in Introductory and Advanced Matrix Calculus. 2nd ed., World Scientific Publishing, 2017.
[STH12] Steeb W., Tanski I., Hardy Y. Problems and Solutions for Groups, Lie Groups, Lie Algebras with Applications. World Scientific Publishing, 2012.