Hellinger-Toeplitz theorem

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Prove that if TT is an operator on a Hilbert space VV such that ⟨Tf,g⟩=⟨f,Tg⟩\langle T f, g\rangle = \langle f, T g\rangle for all f,g∈Vf, g \in V, then TT is a bounded operator.

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Let A,BA, B be linear operators in the Hilbert space HH such that (Ax,y)=(x,By)(A x, y) = (x, B y) for all x,y∈Hx, y \in H. Prove that A,B∈L(H)A, B \in \mathcal{L}(H).

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Let A,BA, B be linear operators in Hilbert space HH such that (Ax,y)=(x,By),x,y∈H(A x, y) = (x, B y), x, y \in H. Prove that A∈L(H)A \in \mathcal{L}(H) and B=A∗B = A^{*}.

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(E. Hellinger, O. Toeplitz, 1910). Let A:H→HA: H \rightarrow H be a linear operator in a Hilbert space HH. Prove that if for all x,y∈Hx, y \in H the equality (Ax,y)=(x,Ay)(A x, y) = (x, A y) holds, then the operator AA is bounded. 1

Definition 8.3: An operator A∈B(H)A \in \mathcal{B}(H) is called self-adjoint if A=A∗A = A^{*}.

Footnotes

  1. Operators satisfying such a relation are called self-adjoint (see Definition 8.3 below). ↩

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(a)

Is a symmetric linear transformation on an inner-product space H\mathbf{H} necessarily bounded?

(b)

What if H\mathbf{H} is a Hilbert space?

Remark.
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A linear transformation AA (not necessarily bounded) on an inner-product space H\mathbf{H} (not necessarily complete) is called symmetric if ⟨Af,g⟩=⟨f,Ag⟩\left\langle Af, g \right\rangle = \left\langle f, Ag \right\rangle for all ff and gg in H\mathbf{H}. (This neutral term is used rather than "Hermitian" or "self-adjoint," because in the customary approach to Hermitian operators, A=A∗A = A^{*}, boundedness is an assumption necessary for the very formulation of the definition.)

Let HH be a Hilbert space and T:H→HT: H \rightarrow H a linear operator which is symmetric, i.e.,

⟨Tx,y⟩=⟨x,Ty⟩,∀x,y∈H \langle T x, y\rangle = \langle x, T y\rangle , \forall x, y \in H

Prove that TT is continuous.

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Let H\mathcal{H} be Hilbert space and let A,B:H→HA, B: \mathcal{H} \rightarrow \mathcal{H} be linear operators satisfying ⟨Bx,y⟩=⟨x,Ay⟩\left\langle B x, y \right\rangle = \left\langle x, A y \right\rangle for all x,y∈Hx, y \in \mathcal{H}. Prove that AA and BB are both bounded.

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Let H\mathcal{H} be Hilbert space, let T:H→HT: \mathcal{H} \rightarrow \mathcal{H} be a linear operator that is symmetric, i.e., ⟨Tx,y⟩=⟨x,Ty⟩\left\langle T x, y \right\rangle = \left\langle x, T y \right\rangle, for all x,y∈Hx, y \in \mathcal{H}. Prove that TT is bounded. Give an example to show that the assertion is not true if DD is a dense subspace of H\mathcal{H} and T:D→HT: D \rightarrow \mathcal{H} is symmetric.

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Let H\mathcal{H} be Hilbert space, let T:H→HT: \mathcal{H} \rightarrow \mathcal{H} be a linear operator such that ⟨Tx,x⟩≥0\left\langle T x, x \right\rangle \geq 0, for all x∈Hx \in \mathcal{H}. Prove that TT is bounded.

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Let HH be a Hilbert space and the linear operator T:H→HT: H \rightarrow H have the property that ⟨T(u),v⟩=⟨u,T(v)⟩\left\langle T(u), v \right\rangle = \left\langle u, T(v) \right\rangle for all u,v∈Hu, v \in H. Show that TT belongs to L(H)\mathcal{L}(H), that is, TT is bounded.

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References

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[BCK+24] Brayman V.B., Chaikovskyi A.V., Konstantinov O.Y., Kukush A.G., Mishura Y.S., Nesterenko O.N. Functional Analysis and Operator Theory. Springer, 2024.
[БСШ17] Бородин П.А., Савчук А.М., Шейпак И.А. Задачи по функциональному анализу. МЦНМО, 2017.
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[Le13] Le A. Functional Analysis Problems with Solutions. 2013.
[Pet25] Petrovic J.S. Measure and Integral: Theory and Practice. CRC Press, 2025.
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