Martingales from harmonic and excessive functions of Markov processes
[7/29%]Let be a Markov chain with state space , and transition probability matrix . That is, for each ,
for all . Let and be such that
and
Verify that has the Markov property, namely, for all ,
Verify that is a martingale w.r.t. the filtration .
Suppose and is bounded below and attains its lower bound. Suppose also that is irreducible and recurrent. That is, for all . Show that is a constant function. (Hint: Use the optional stopping theorem II.)
Suppose is a Markov process with transition probabilities is a bounded Borel measurable function, , and we define for . Show that is a -martingale for each .
Let be an excessive function for a strong Markov process . Let and . Let . Prove that is a supermartingale with respect to the -fields and with respect to for each .
Suppose that is a finite-state Markov chain with transition matrix . Suppose that for all (the are the components of a right eigenvector of the transition matrix). Put and show that is a martingale.
(see [12; p. 166]). Let be an -dimensional Brownian motion and a continuous superharmonic function in , i.e., , for any , is not less than the integral of this function over any sphere centered at . Prove that the process is a supermartingale with respect to the natural filtration of the Brownian motion if for all .
Let be a discrete-time Markov chain with countable state space and transition matrix . Suppose that is bounded and satisfies for some and all . Show that constitutes a supermartingale.
Let be a continuous-time Markov chain with finite state space and generator . Let be a root of the equation . Show that constitutes a martingale with respect to .