Complete analytic functions defined by multivalued formulas

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Let UU be a connected and simply connected open subset of the complex plane, and let ff be a holomorphic function on UU. Suppose aa is a point of UU such that the Taylor series of ff at aa converges on an open disc DD that intersects the complement of UU. Does it follow that ff extends to a holomorphic function on U∪DU \cup D? Give a proof or a counterexample.

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Let ff be the analytic function defined in the disk Δ={z:∣z−4∣<4}\Delta = \left\{ z : \left|z-4\right| < 4\right\} so that f(z)=z1/3(z+1)1/2f(z) = z^{1/3}(z+1)^{1/2} in Δ\Delta and f(x)f(x) is positive for 0<x<80 < x < 8. An analytic function gg in Δ\Delta is obtained from ff by analytic continuation along the path starting and ending at z=4z = 4 (see Fig. 5.2). Express gg in terms of ff.

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(a)

Let D⊂CD \subset \mathbb {C} be the complement of the simply connected closed set {eθ+iθ:θ∈R}∪{0}\left\{ e^{\theta +i\theta } : \theta \in \mathbb {R}\right\} \cup \left\{ 0\right\}. Let log⁡\log be a branch of the logarithm on DD such that log⁡e=1\log e = 1. Find log⁡e15\log e^{15}. Justify your answer.

(b)

Let γ\gamma denote the unit circle, oriented counterclockwise. By lifting the integration to an appropriate covering space, give a precise meaning to the integral ∫γ(log⁡z)2 dz\int_\gamma (\log z)^2\, dz and find all possible values which can be assigned to it.

Prove that the function ln⁡z\ln z, defined for real positive values of zz, can be regularly continued to the entire complex plane with a cut along the negative part of the real axis, and, denoting this regular continuation by the symbol h(z)h(z), obtain for it the formula

h(z)=ln⁡∣z∣+iarg⁡z(∣arg⁡z∣<π). h(z) = \ln \left|z\right|+i \arg z \quad (\left|\arg z\right| < \pi ).
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Let α\alpha be an arbitrary real number. Prove that the function zαz^{\alpha }, defined for real positive zz, can be regularly continued to the entire complex plane with a cut along the negative part of the real axis, and, denoting this regular continuation by the symbol (zα)\left(z^{\alpha }\right), obtain for it the formula

(zα)=∣z∣αeiαarg⁡z(∣arg⁡z∣<π). \left(z^{\alpha }\right) = \left|z\right|^{\alpha } e^{i \alpha \arg z} \quad (\left|\arg z\right| < \pi ).
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For every point a∈C\{0}a \in \mathbb {C} \backslash \left\{ 0\right\} and every piecewise-smooth oriented curve γa\gamma_{a} starting at the point 1 and ending at the point aa, such that 0∉γa0 \notin \gamma_{a}, let us define the quantity

hγa(a)=∫γadζζ h_{\gamma a}(a) = \int _{\gamma a} \frac{d \zeta }{\zeta }

and the function hγa:B∣a∣(a)→Ch_{\gamma a}: B_{\left|a\right|}(a) \rightarrow \mathbb {C} of the form

hγa(z)=hγa(a)+∫azdζζ,z∈B∣a∣(a) h_{\gamma a}(z) = h_{\gamma a}(a)+\int _{a}^{z} \frac{d \zeta }{\zeta }, \quad z \in B_{\left|a\right|}(a)

Prove that the family of elements

(B∣a∣(a),hγa),a∈C\{0} \left(B_{\left|a\right|}(a), h_{\gamma a}\right), \quad a \in \mathbb {C} \backslash \left\{ 0\right\}

forms a function (denoted by Ln⁡z\operatorname {Ln} z) analytic in the entire complex plane with the point z=0z = 0 deleted.

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Let α\alpha be an arbitrary complex number. Prove that the family of elements

(B∣a∣(a),eαhγa(z)),a∈C\{0} \left(B_{\left|a\right|}(a), e^{\alpha h_{\gamma a}(z)}\right), \quad a \in \mathbb {C} \backslash \left\{ 0\right\}

where the function hγah_{\gamma a} is defined in Problem 6, forms the function zαz^{\alpha }, analytic in C\{0}\mathbb {C} \backslash \left\{ 0\right\}.

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For every point a∈C,a≠i,a≠−ia \in \mathbb {C}, a \neq i, a \neq -i, and every piecewise-smooth oriented curve γa\gamma_{a} starting at the point 0 and ending at the point aa, such that i∉γa,−i∉γai \notin \gamma_{a},-i \notin \gamma_{a}, let us define the quantity

gγa(a)=∫γadζ1+ζ2 g_{\gamma _{a}}(a) = \int _{\gamma _{a}} \frac{d \zeta }{1+\zeta ^{2}}

and the function gγa:Bra(a)→Cg_{\gamma_{a}}: B_{r_{a}}(a) \rightarrow \mathbb {C} of the form

gγa(z)=gγa(a)+∫azdζ1+ζ2,z∈Bra(a),ra=min⁡{∣a−i∣,∣a+i∣} g_{\gamma _{a}}(z) = g_{\gamma _{a}}(a)+\int _{a}^{z} \frac{d \zeta }{1+\zeta ^{2}}, \quad z \in B_{r_{a}}(a), \quad r_{a} = \min \left\{ \left|a-i\right|,\left|a+i\right|\right\}

Prove that the family of elements

(Bra(a),gγa),a≠±i \left(B_{r_{a}}(a), g_{\gamma _{a}}\right), \quad a \neq \pm i

forms a function (denoted by Arctg⁡z)\operatorname {Arctg} z), analytic in C‾\({i}∪{−i})\overline{\mathbb {C}} \backslash (\left\{ i\right\} \cup \left\{ -i\right\} ).

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Let the function φ(z)\varphi (z) be regular in a domain GG and let z0z_{0} be some point of this domain. For every point a∈Ga \in G and every piecewise-smooth curve γa⊂G\gamma_{a} \subset G starting at the point z0z_{0} and ending at the point aa, define the quantity

fγa(a)=∫γaφ(ζ)dζ f_{\gamma _{a}}(a) = \int _{\gamma _{a}} \varphi (\zeta ) d \zeta

and the function fγa:Br(a)→Cf_{\gamma_{a}}: B_{r}(a) \rightarrow \mathbb {C} of the form

fγa(z)=fγa(a)+∫azφ(ζ)dζ,z∈Bra(a) f_{\gamma _{a}}(z) = f_{\gamma _{a}}(a)+\int _{a}^{z} \varphi (\zeta ) d \zeta , \quad z \in B_{r_{a}}(a)

where ra>0r_{a} > 0 is such that Bra(a)⊂GB_{r_{a}}(a) \subset G. Prove that the family of elements

(Bra(a),fγa),a∈G, \left(B_{r_{a}}(a), f_{\gamma _{a}}\right), \quad a \in G,

forms a function analytic in the domain GG.

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Prove that the set of values taken by the elements of the analytic function Ln⁡z\operatorname {Ln} z (see Problem 6) at an arbitrary point a∈C\{0}a \in \mathbb {C} \backslash \left\{ 0\right\} coincides with the set of values of the expression

Ln⁡a=ln⁡∣a∣+iArg⁡a. \operatorname {Ln} a = \ln \left|a\right|+i \operatorname {Arg} a.
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Prove that the set of values taken by the elements of the analytic function zαz^{\alpha } (see Problem 7) at an arbitrary point a∈C\{0}a \in \mathbb {C} \backslash \left\{ 0\right\} coincides with the set of values of the expression

{aα}=eαLn⁡a. \left\{ a^{\alpha }\right\} = e^{\alpha \operatorname {Ln} a}.
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Prove that the set of values taken by the elements of the analytic function Arctg⁡z\operatorname {Arctg} z (see Example 8) at an arbitrary point aa of the domain G={z∈C:z≠±i}G = \left\{ z \in \mathbb {C}: z \neq \pm i\right\} coincides with the set of values of the expression

12iLn⁡1+ia1−ia. \frac{1}{2 i} \operatorname {Ln} \frac{1+i a}{1-i a}.
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For the following multivalued expressions and domains GG, find the functions analytic in the domain GG that are represented by these expressions:

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(1)

{zz}\left\{ z^{z}\right\}, where G={z∈C:z≠0}G = \left\{ z \in \mathbb {C}: z \neq 0\right\};

(2)

{z2Ln⁡2z}\left\{ z^{2} \operatorname {Ln}^{2} z\right\}, where G={z∈C:z≠0}G = \left\{ z \in \mathbb {C}: z \neq 0\right\};

(3)

Ln⁡(1−z2)\operatorname {Ln}\left(1-z^{2}\right), where G={z∈C:z≠1,z≠−1}G = \left\{ z \in \mathbb {C}: z \neq 1, z \neq -1\right\};

(4)

{1+z23}\left\{ \sqrt[3]{1+z^{2}}\right\}, where G={z∈C:z≠i,z≠−i}G = \left\{ z \in \mathbb {C}: z \neq i, z \neq -i\right\};

(5)

{1−z4}\left\{ \sqrt{1-z^{4}}\right\}, where G={z∈C:z≠±i,z≠±1}G = \left\{ z \in \mathbb {C}: z \neq \pm i, z \neq \pm 1\right\};

(6)

Ln z2−1z2+1\frac{z^{2}-1}{z^{2}+1}, where G={z∈C‾:z≠±i,z≠±1}G = \left\{ z \in \overline{\mathbb {C}}: z \neq \pm i, z \neq \pm 1\right\}.

(7)

{z2−1}\left\{ \sqrt{z^{2}-1}\right\}, where G={z∈C:z≠±1}G = \left\{ z \in \mathbb {C}: z \neq \pm 1\right\};

(8)

Ln⁡z−1z+1\operatorname {Ln} \frac{z-1}{z+1}, where G={z∈C:z≠±1}G = \left\{ z \in \mathbb {C}: z \neq \pm 1\right\}.

Prove that there exists a function analytic in the entire complex plane with the points z=0z = 0 and z=1z = 1 deleted, which is represented by the formula LnLn⁡z\operatorname {LnLn} z.

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Prove the existence of functions represented by the following multivalued formulas and analytic in the given domains GG:

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(1)

{(z+1)α(Ln⁡z)β}\left\{ (z+1)^{\alpha }(\operatorname {Ln} z)^{\beta }\right\}, where G={z∈C:z≠0,z≠±1}G = \left\{ z \in \mathbb {C}: z \neq 0, z \neq \pm 1\right\};

(2)

Ln⁡(z+z2+1)\operatorname {Ln}\left(z+\sqrt{z^{2}+1}\right), where G={z∈C:z≠±i}G = \left\{ z \in \mathbb {C}: z \neq \pm i\right\};

(3)

Ln⁡(1−z4)\operatorname {Ln}(1-\sqrt[4]{z}), where G={z∈C:z≠0,z≠1}G = \left\{ z \in \mathbb {C}: z \neq 0, z \neq 1\right\};

(4)

{z+z}\left\{ \sqrt{z+\sqrt{z}}\right\}, where G={z∈C:z≠0,z≠1}G = \left\{ z \in \mathbb {C}: z \neq 0, z \neq 1\right\};

(5)

{πi+Ln⁡z3}\left\{ \sqrt[3]{\pi i+\operatorname {Ln} z}\right\}, where G={z∈C:z≠0,z≠−1}G = \left\{ z \in \mathbb {C}: z \neq 0, z \neq -1\right\};

(6)

{1+Ln⁡z}\left\{ \sqrt{1+\sqrt{\operatorname {Ln} z}}\right\}, where G={z∈C:z≠0,z≠e}G = \left\{ z \in \mathbb {C}: z \neq 0, z \neq e\right\}.

References

[deSi04] de Souza P.N., Silva J. Berkeley Problems in Mathematics. 3rd ed., Springer, 2004.
[CJP+11] Chen J., Jiang G., Pan Y., Qin T., Tong Y., Wu Q., Xu S., Li T. Problems and Solutions in Mathematics. 2nd ed., World Scientific, 2011.
[ШПК15] Шабунин М.И., Половинкин Е.С., Карлов М.И. Сборник задач по теории функций комплексного переменного. 4-е изд., БИНОМ. Лаборатория знаний, 2015.