Section 9

The Uniqueness Theorem. Regular Continuation.

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Problem 9.1

Let the function f(z)f(z) be regular in the closure Gˉ\bar{G} of a domain GG, and f(z)≢f(z) \not\equiv const. Prove that only a finite number of solutions of the equation f(z)=af(z) = a (for an arbitrary fixed value aa) lie in the domain GG.

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Problem 9.2

Does there exist a function f(z)f(z), regular in some neighborhood of the point z=0z = 0 and satisfying one of the following conditions (for all n=1,2,…)n = 1,2, \ldots ):

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(1)

f(1n)=sin⁡πn2f\left(\frac{1}{n}\right) = \sin \frac{\pi n}{2};

(2)

f(1n)=1ncos⁡πnf\left(\frac{1}{n}\right) = \frac{1}{n} \cos \pi n;

(3)

f(1n)=12n+1f\left(\frac{1}{n}\right) = \frac{1}{2 n+1};

(4)

f(1n)=cos⁡2πn2n+1f\left(\frac{1}{n}\right) = \frac{\cos^{2} \pi n}{2 n+1};

(5)

f(1n)=12n+cos⁡πnf\left(\frac{1}{n}\right) = \frac{1}{2 n+\cos \pi n};

(6)

f(1n)=f(−1n)=1n2f\left(\frac{1}{n}\right) = f\left(-\frac{1}{n}\right) = \frac{1}{n^{2}};

(7)

f(1n)=f(−1n)=12n+1f\left(\frac{1}{n}\right) = f\left(-\frac{1}{n}\right) = \frac{1}{2 n+1};

(8)

f(1n)=e−nf\left(\frac{1}{n}\right) = e^{-n};

(9)

f(1n)=f(−1n)=1n3f\left(\frac{1}{n}\right) = f\left(-\frac{1}{n}\right) = \frac{1}{n^{3}};

(10)

f(1n)=f(−1n)=sin⁡πn2n3f\left(\frac{1}{n}\right) = f\left(-\frac{1}{n}\right) = \frac{\sin \frac{\pi n}{2}}{n^{3}};

(11)

f(1n)=f(−1n)=cos⁡2(πn)n2f\left(\frac{1}{n}\right) = f\left(-\frac{1}{n}\right) = \frac{\cos^{2}(\pi n)}{n^{2}};

(12)

f(1n)=f(−1n)=sin⁡2πn2n2f\left(\frac{1}{n}\right) = f\left(-\frac{1}{n}\right) = \frac{\sin^{2} \frac{\pi n}{2}}{n^{2}};

(13)

∣f(1n)∣<e−n\left|f\left(\frac{1}{n}\right)\right| < e^{-n};

(14)

2−n<∣f(1n)∣<21−n2^{-n} < \left|f\left(\frac{1}{n}\right)\right| < 2^{1-n};

(15)

n−5/2<∣f(1n)∣<2n−5/2n^{-5 / 2} < \left|f\left(\frac{1}{n}\right)\right| < 2 n^{-5 / 2};

(16)

∣f(1n)−cos⁡πn2n+1∣<1n2\left|f\left(\frac{1}{n}\right)-\frac{\cos \pi n}{2 n+1}\right| < \frac{1}{n^{2}}.

Problem 9.3

Let the functions f1(z)f_{1}(z) and f2(z)f_{2}(z) be regular in a domain DD and satisfy in this domain the differential equation f′(z)=P(z,f(z))f^{\prime }(z) = P(z, f(z)), where P(z,w)P(z, w) is a polynomial in its variables. Prove that if at some point z0∈Dz_{0} \in D the equality f1(z0)=f2(z0)f_{1}\left(z_{0}\right) = f_{2}\left(z_{0}\right) holds, then f1(z)≡f2(z)f_{1}(z) \equiv f_{2}(z).

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Problem 9.4

Let the functions f1(z)f_{1}(z) and f2(z)f_{2}(z) be regular in a domain DD and satisfy in this domain the differential equation

f(m)(z)=P(z,f,f′,…,f(m−1)), f^{(m)}(z) = P\left(z, f, f^{\prime }, \ldots , f^{(m-1)}\right),

where PP is a polynomial in its variables. Prove that if at some point z0∈Dz_{0} \in D the equalities

f1(z0)=f2(z0),…,f1(m−1)(z0)=f2(m−1)(z0) f_{1}\left(z_{0}\right) = f_{2}\left(z_{0}\right), \ldots , f_{1}^{(m-1)}\left(z_{0}\right) = f_{2}^{(m-1)}\left(z_{0}\right)

hold, then f1(z)≡f2(z)f_{1}(z) \equiv f_{2}(z).

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Problem 9.5

Prove that the functional equation f(z)=f(2z)f(z) = f(2 z) has no solutions regular at the point z=0z = 0 and not identically constant.

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Problem 9.6

Let q=e2πiαq = e^{2 \pi i \alpha }, where α\alpha is an irrational number. Prove that the functional equation f(z)=f(qz)f(z) = f(q z) has no solutions f(z)f(z) regular for 1/2<∣z∣<21 / 2 < \left|z\right| < 2 and not identically constant.

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Problem 9.7

Let f(z)f(z) be a periodic function, regular in some domain containing the point z=∞z = \infty. Prove that f(z)=f(z) = const throughout the domain of regularity.

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Problem 9.8

Prove that the functions ez,cos⁡z,sin⁡z,ch⁡z,sh⁡ze^{z}, \cos z, \sin z, \operatorname {ch} z, \operatorname {sh} z, originally defined only for real values of the variable, can be regularly continued to the entire complex plane by expanding these functions in a Taylor series.

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Problem 9.9

Find the widest possible domain into which the following functions can be regularly continued from the real axis:

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(1)

tg⁡z\operatorname {tg} z;

(2)

ctg⁡z\operatorname {ctg} z;

(3)

th⁡z\operatorname {th} z;

(4)

e1/cos⁡ze^{1 / \cos z};

(5)

e−tg⁡ze^{-\operatorname {tg} z};

(6)

sin⁡(th⁡z)\sin (\operatorname {th} z);

(7)

cos⁡(ez2)\cos \left(e^{z^{2}}\right);

(8)

th⁡(ez)\operatorname {th}\left(e^{z}\right);

(9)

ctg⁡(ch⁡z)\operatorname {ctg}(\operatorname {ch} z).

Problem 9.10

Prove that the function ln⁡z\ln z, defined for real positive values of zz, can be regularly continued to the entire complex plane with a cut along the negative part of the real axis, and, denoting this regular continuation by the symbol h(z)h(z), obtain for it the formula

h(z)=ln⁡∣z∣+iarg⁡z(∣arg⁡z∣<π). h(z) = \ln \left|z\right|+i \arg z \quad (\left|\arg z\right| < \pi ).
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Problem 9.11

Let α\alpha be an arbitrary real number. Prove that the function zαz^{\alpha }, defined for real positive zz, can be regularly continued to the entire complex plane with a cut along the negative part of the real axis, and, denoting this regular continuation by the symbol (zα)\left(z^{\alpha }\right), obtain for it the formula

(zα)=∣z∣αeiαarg⁡z(∣arg⁡z∣<π). \left(z^{\alpha }\right) = \left|z\right|^{\alpha } e^{i \alpha \arg z} \quad (\left|\arg z\right| < \pi ).
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Problem 9.12

Let the function Φ(z1,…,zn)\Phi \left(z_{1}, \ldots , z_{n}\right) be defined when

zk∈Dk(k=1,2,…,n) z_{k} \in D_{k} \quad (k = 1,2, \ldots , n)

and be regular in each variable zkz_{k} in the domain DkD_{k} for arbitrary fixed values of the remaining variables. Prove that if each domain DkD_{k} contains a nonempty interval (ak,bk)\left(a_{k}, b_{k}\right) of the real axis, and if

Φ(z1,…,zn)=0(z1∈(a1,b1),…,zn∈(an,bn)), \Phi \left(z_{1}, \ldots , z_{n}\right) = 0 \quad \left(z_{1} \in \left(a_{1}, b_{1}\right), \ldots , z_{n} \in \left(a_{n}, b_{n}\right)\right),

then Φ(z1,…,zn)≡0\Phi \left(z_{1}, \ldots , z_{n}\right) \equiv 0.

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Problem 9.13

Relying on the validity of the formulas given below for real values of the variables, prove their validity also for arbitrary complex values of these variables:

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(1)

ez1+z2=ez1⋅ez2e^{z_{1}+z_{2}} = e^{z_{1}} \cdot e^{z_{2}};

(2)

cos⁡2z+sin⁡2z=1\cos^{2} z+\sin^{2} z = 1;

(3)

sin⁡2z=2sin⁡zcos⁡z\sin 2 z = 2 \sin z \cos z;

(4)

ch⁡2z=ch⁡2z+sh⁡2z\operatorname {ch} 2 z = \operatorname {ch}^{2} z+\operatorname {sh}^{2} z;

(5)

sin⁡(z1+z2)=sin⁡z1cos⁡z2+cos⁡z1sin⁡z2\sin \left(z_{1}+z_{2}\right) = \sin z_{1} \cos z_{2}+\cos z_{1} \sin z_{2};

(6)

ch⁡(z1+z2)=ch⁡z1ch⁡z2+sh⁡z1sh⁡z2\operatorname {ch}\left(z_{1}+z_{2}\right) = \operatorname {ch} z_{1} \operatorname {ch} z_{2}+\operatorname {sh} z_{1} \operatorname {sh} z_{2};

(7)

cos⁡z1+cos⁡z2=2cos⁡z1+z22cos⁡z1−z22\cos z_{1}+\cos z_{2} = 2 \cos \frac{z_{1}+z_{2}}{2} \cos \frac{z_{1}-z_{2}}{2};

(8)

sh⁡z1+sh⁡z2=2sh⁡z1+z22ch⁡z1−z22\operatorname {sh} z_{1}+\operatorname {sh} z_{2} = 2 \operatorname {sh} \frac{z_{1}+z_{2}}{2} \operatorname {ch} \frac{z_{1}-z_{2}}{2}.

Problem 9.14

Let the function f(z)f(z) be regular in some domain containing the segment [0,1][0,1] and satisfy the condition f(z+1)=f(z)f(z+1) = f(z). Prove that the function f(z)f(z) can be regularly continued into some strip −δ<Im(z)<δ-\delta < \mathrm{Im}\left(z\right) < \delta, δ>0\delta > 0.

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Problem 9.15

Let the function f(z)f(z) be regular in some domain containing the segment [0,1][0,1] and satisfy the condition

f(z+1)=zf(z)+p(z), f(z+1) = z f(z)+p(z),

where p(z)p(z) is a polynomial. Prove that the function f(z)f(z) can be regularly continued into some strip −δ<Im(z)<δ,δ>0-\delta < \mathrm{Im}\left(z\right) < \delta , \delta > 0.

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Problem 9.16

Let the function f(z)f(z) be regular in some domain containing the segment [1,2][1,2] and satisfy the condition

f(2z)=f(z)+p(z), f(2 z) = f(z)+p(z),

where p(z)p(z) is a polynomial. Prove that the function f(z)f(z) can be regularly continued into some angle −δ<arg⁡z<δ,δ>0-\delta < \arg z < \delta , \delta > 0.

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Problem 9.17

Let the function f(z)f(z) be regular in the annulus ρ<∣z∣<1,ρ>0\rho < \left|z\right| < 1, \rho > 0, and satisfy in it the functional equation

f(z)=f(z2)+g(z), f(z) = f\left(z^{2}\right)+g(z),

where g(z)g(z) is some given function, regular in the disk ∣z∣<1\left|z\right| < 1. Prove that the function f(z)f(z) can be regularly continued into the annulus 0<∣z∣<10 < \left|z\right| < 1.

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Problem 9.18

Euler's gamma function Γ(z)\Gamma (z) is defined for real z>0z > 0 by the equality

Γ(z)=∫0∞tz−1e−tdt \Gamma (z) = \int _{0}^{\infty } t^{z-1} e^{-t} d t

Prove that the function Γ(z)\Gamma (z) can be regularly continued to the entire complex plane, with the exception of the points z=0,−1,−2,…z = 0,-1,-2, \ldots.

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Problem 9.19

Euler's beta function B(z,ζ)\mathrm{B}(z, \zeta ) is defined for real z>0z > 0 and ζ>0\zeta > 0 by the equality

B(z,ζ)=∫01tz−1(1−t)ζ−1dt \mathrm{B}(z, \zeta ) = \int _{0}^{1} t^{z-1}(1-t)^{\zeta -1} d t

Prove that the function B(z,ζ)\mathrm{B}(z, \zeta ) can be regularly continued in each of the variables to the entire complex plane, with the exception of the points z=0,−1,−2,…(z = 0,-1,-2, \ldots ( respectively ζ=0,−1,−2,…)\zeta = 0,-1,-2, \ldots ).

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Problem 9.20

Let the function φ(ζ)\varphi (\zeta ) be regular in the annulus r⩽∣ζ∣⩽Rr \leqslant \left|\zeta \right| \leqslant R. Prove that the function f(z)f(z), given in the disk ∣z∣<r\left|z\right| < r by the formula

f(z)=12πi∮∣ζ∣=r(ζ−z)mφ(ζ)dζ(∣z∣<r) f(z) = \frac{1}{2 \pi i} \oint _{\left|\zeta \right| = r}(\zeta -z)^{m} \varphi (\zeta ) d \zeta \quad (\left|z\right| < r)

(mm an integer) can be regularly continued into the disk ∣z∣<R\left|z\right| < R, and that this regular continuation g(z)g(z) is given by the formula

g(z)=12πi∮∣ζ∣=R(ζ−z)mφ(ζ)dζ(∣z∣<R) g(z) = \frac{1}{2 \pi i} \oint _{\left|\zeta \right| = R}(\zeta -z)^{m} \varphi (\zeta ) d \zeta \quad (\left|z\right| < R)
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Problem 9.21

Prove that the following functions can be regularly continued to the domains GG indicated in parentheses:

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(1)

f(z)=∮∣ζ∣=1e(ζ+1ζ)dζζ−z,∣z∣<1(G={z:∣z∣<∞});f(z) = \oint_{\left|\zeta \right| = 1} e^{\left(\zeta +\frac{1}{\zeta }\right)} \frac{d \zeta }{\zeta -z},\left|z\right| < 1 \quad (G = \left\{ z:\left|z\right| < \infty \right\} ) ;

(2)

f(z)=∮∣ζ∣=1e(ζ+1ζ)dζζ−z,∣z∣>1(G={z:∣z∣>0})f(z) = \oint_{\left|\zeta \right| = 1} e^{\left(\zeta +\frac{1}{\zeta }\right)} \frac{d \zeta }{\zeta -z},\left|z\right| > 1 \quad (G = \left\{ z:\left|z\right| > 0\right\} );

(3)

f(z)=∮∣ζ∣=2cos⁡(ζ+1ζ)ζ2+1dζ(ζ−z)2,∣z∣<2(G={z:∣z∣<∞})f(z) = \oint_{\left|\zeta \right| = 2} \frac{\cos \left(\zeta +\frac{1}{\zeta }\right)}{\zeta^{2}+1} \frac{d \zeta }{(\zeta -z)^{2}}, \quad \left|z\right| < 2 \quad (G = \left\{ z:\left|z\right| < \infty \right\} );

(4)

f(z)=∮∣ζ∣=2cos⁡(ζ+1ζ)ζ2+1dζ(ζ−z)2,∣z∣>2(G={z:z≠0,i,−i})f(z) = \oint_{\left|\zeta \right| = 2} \frac{\cos \left(\zeta +\frac{1}{\zeta }\right)}{\zeta^{2}+1} \frac{d \zeta }{(\zeta -z)^{2}},\left|z\right| > 2 \quad (G = \left\{ z: z \neq 0, i,-i\right\} );

(5)

f(z)=∮∣ζ∣=1sh⁡(ζ+1ζ)dζζ2+z2,∣z∣<1(G={z:∣z∣<∞})f(z) = \oint_{\left|\zeta \right| = 1} \operatorname {sh}\left(\zeta +\frac{1}{\zeta }\right) \frac{d \zeta }{\zeta^{2}+z^{2}},\left|z\right| < 1 \quad (G = \left\{ z:\left|z\right| < \infty \right\} );

(6)

f(z)=∮∣ζ∣=1e−1/ζch⁡ζdζζ2+z2,∣z∣<1(G={z:z≠±πi/2,±3πi/2,…})f(z) = \oint_{\left|\zeta \right| = 1} \frac{e^{-1 / \zeta }}{\operatorname {ch} \zeta } \frac{d \zeta }{\zeta^{2}+z^{2}},\left|z\right| < 1 \quad (G = \left\{ z: z \neq \pm \pi i / 2, \pm 3 \pi i / 2, \ldots \right\} ).

Problem 9.22

Let the function φ(ζ)\varphi (\zeta ) be regular in the strip −a⩽Re(ζ)⩽0-a \leqslant \mathrm{Re}\left(\zeta \right) \leqslant 0 and satisfy the condition

∣φ(ζ)∣⩽M(1+∣ζ∣)−α,α>0(−a⩽Re(ζ)⩽0) \left|\varphi (\zeta )\right| \leqslant M(1+\left|\zeta \right|)^{-\alpha }, \quad \alpha > 0 \quad (-a \leqslant \mathrm{Re}\left(\zeta \right) \leqslant 0)

Prove that the function

f(z)=∫−i∞+i∞φ(ζ)ζ−zdζ(Re(z)>0) f(z) = \int _{-i \infty }^{+i \infty } \frac{\varphi (\zeta )}{\zeta -z} d \zeta \quad (\mathrm{Re}\left(z\right) > 0)

admits a regular continuation into the half-plane Re(z)>−a\mathrm{Re}\left(z\right) > -a, and that this continuation g(z)g(z) is given by the formula

g(z)=∫−a−i∞−a+i∞φ(ζ)ζ−zdζ(Re(z)>−a) g(z) = \int _{-a-i \infty }^{-a+i \infty } \frac{\varphi (\zeta )}{\zeta -z} d \zeta \quad (\mathrm{Re}\left(z\right) > -a)
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Problem 9.23

Prove that for the regular continuation g(z)g(z), constructed in Problem 22, the formula also holds

g(z)=∫−i∞i∞φ(ζ)ζ−zdζ−2πiφ(z)(−a⩽Re(z)<0) g(z) = \int _{-i \infty }^{i \infty } \frac{\varphi (\zeta )}{\zeta -z} d \zeta -2 \pi i \varphi (z) \quad (-a \leqslant \mathrm{Re}\left(z\right) < 0)
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