Korovkin's theorem

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Let Bn,n≥1B_{n}, n \geq 1, be Bernstein operators:

(Bnx)(t)=∑k=0n(nk)x(kn)tk(1−t)n−k,t∈[0,1],x∈C([0,1]). \left(B_{n} x\right)(t) = \sum _{k = 0}^{n}\binom {n}{k} x\left(\frac{k}{n}\right) t^{k}(1-t)^{n-k}, t \in [0,1], x \in C(\left[0,1\right]).

Is it true that Bn⇉IB_{n} \rightrightarrows I?

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Let {fn:n≥1}\left\{ f_{n}: n \geq 1\right\} be a sequence of linear nonnegative functionals on a real space C([a,b])C(\left[a, b\right]) (see problem 3.42), and f(x)=x(c),x∈C([a,b])f(x) = x(c), x \in C(\left[a, b\right]), where c∈[a,b]c \in \left[a, b\right] is fixed. Denote ek(t)=tk,t∈[a,b],k=0,1,2,y(t)=(t−c)2,t∈[a,b]e_{k}(t) = t^{k}, t \in [a, b], k = 0,1,2, y(t) = (t-c)^{2}, t \in [a, b]. Prove that

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(1)

for each x∈C([a,b])x \in C(\left[a, b\right]) and each ε>0\varepsilon > 0 the following inequality holds:

−2∥x∥δ2y(t)−ε≤x(t)−x(c)≤2∥x∥δ2y(t)+ε,t∈[a,b] -\frac{2\left\| x\right\| }{\delta ^{2}} y(t)-\varepsilon \leq x(t)-x(c) \leq \frac{2\left\| x\right\| }{\delta ^{2}} y(t)+\varepsilon , t \in [a, b]

where the number δ=δ(x,ε)>0\delta = \delta (x, \varepsilon ) > 0 is such that ∣x(t)−x(c)∣<ε\left|x(t)-x(c)\right| < \varepsilon for all t∈[a,b]t \in [a, b], for which ∣t−c∣<δ\left|t-c\right| < \delta.

(2)

(Korovkin) fn→w−∗ff_{n} \xrightarrow {w-*} f, if one of the following conditions is fulfilled:

(a) fn(e0)→f(e0)f_{n}\left(e_{0}\right) \rightarrow f\left(e_{0}\right) and fn(y)→f(y),n→∞f_{n}(y) \rightarrow f(y), n \rightarrow \infty;

(b) fn(ek)→f(ek),n→∞f_{n}\left(e_{k}\right) \rightarrow f\left(e_{k}\right), n \rightarrow \infty, for k=0,1,2k = 0,1,2.

A linear operator A:C([a,b])→C([a,b])A: C(\left[a, b\right]) \rightarrow C(\left[a, b\right]), where C([a,b])C(\left[a, b\right]) is a real space, is called nonnegative if for all x∈C([a,b])x \in C(\left[a, b\right]) such that x(t)≥0x(t) \geq 0 for all t∈[a,b]t \in [a, b], we have (Ax)(t)≥0(A x)(t) \geq 0 for all t∈[a,b]t \in [a, b]. Prove that

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(1)

The nonnegative operator is continuous, and ∥A∥=∥Ae0∥\left\| A\right\| = \left\| A e_{0}\right\|, where e0(t)=1e_{0}(t) = 1, t∈[a,b]t \in [a, b].

(2)

(Korovkin) If {An:n≥1}\left\{ A_{n}: n \geq 1\right\} is a sequence of nonnegative operators, then An→sIA_{n} \xrightarrow {s} I in C([a,b])C(\left[a, b\right]) if and only if the convergence Anek→ek,n→∞A_{n} e_{k} \rightarrow e_{k}, n \rightarrow \infty, holds for ek(t)=tk,t∈[a,b],k=0,1,2e_{k}(t) = t^{k}, t \in [a, b], k = 0,1,2.

Is the analogous criterion of weak convergence of nonnegative operators valid?

Let X=Lp([0,1])X = L_{p}(\left[0,1\right]) or X=C([0,1])X = C(\left[0,1\right]), the operator Kn:X→XK_{n}: X \rightarrow X assigns to each function x∈Xx \in X the Kantorovich polynomial

(Knx)(t)=∑k=0n(nk)xnktk(1−t)n−k,t∈[0,1] \left(K_{n} x\right)(t) = \sum _{k = 0}^{n}\binom {n}{k} x_{n k} t^{k}(1-t)^{n-k}, t \in [0,1]

where xnk=(n+1)∫kn+1k+1n+1x(t)dt,0≤k≤n,n≥1x_{n k} = (n+1) \int_{\frac{k}{n+1}}^{\frac{k+1}{n+1}} x(t) d t, 0 \leq k \leq n, n \geq 1. Prove that

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(1)

Kn→sIK_{n} \xrightarrow {s} I in C([0,1])C(\left[0,1\right]);

(2)

Kn→sIK_{n} \xrightarrow {s} I in Lp([0,1]),1≤p<+∞L_{p}(\left[0,1\right]), 1 \leq p < +\infty.

Is this statement true for p=+∞p = +\infty?

(P. P. Korovkin, 1959). Let Ln∈B(C[0,1]),n∈NL_{n} \in \mathcal{B}(C[0,1]), n \in \mathbb {N}, be positive operators (i.e., for any nonnegative function x∈C[0,1]x \in C[0,1] its images LnxL_{n} x are also nonnegative functions). Prove that if Ln(1)→1,Ln(t)→tL_{n}(1) \rightarrow 1, L_{n}(t) \rightarrow t, and Ln(t2)→t2L_{n}\left(t^{2}\right) \rightarrow t^{2}, then Lnx→xL_{n} x \rightarrow x for any function x∈C[0,1]x \in C[0,1] (i.e., Ln→sIL_{n} \xrightarrow {s} I).

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References

[BCK+24] Brayman V.B., Chaikovskyi A.V., Konstantinov O.Y., Kukush A.G., Mishura Y.S., Nesterenko O.N. Functional Analysis and Operator Theory. Springer, 2024.
[БСШ17] Бородин П.А., Савчук А.М., Шейпак И.А. Задачи по функциональному анализу. МЦНМО, 2017.