Section 7.2

Problems to Solve

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Problem 7.4

Prove the following statements:

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(1)

if the limit exists, then it is unique for any operator convergence;

(2)

uniform convergence implies strong convergence;

(3)

strong convergence implies weak convergence;

(4)

the converse statements to the statements (2) and (3) are not true;

(5)

in a finite-dimensional space uniform, strong and weak convergences are equivalent.

Problem 7.5

What does the uniform, strong and weak operator convergence look like for operators from L(X,K)\mathcal{L}(X, \mathbb {K}), where XX is an NLS, i.e., for functionals?

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Problem 7.6

Let X1X_{1} and X2X_{2} be normed linear spaces, {An:n≥1}⊂L(X1,X2),A∈L(X1,X2)\left\{ A_{n}: n \geq 1\right\} \subset \mathcal{L}\left(X_{1}, X_{2}\right), A \in \mathcal{L}\left(X_{1}, X_{2}\right). Prove that for the convergence An→sA,n→∞A_{n} \xrightarrow {s} A, n \rightarrow \infty, it is sufficient, and if X1X_{1} is a Banach space, then it is also necessary, that the following conditions are fulfilled:

(a) the sequence {∥An∥:n≥1}\left\{ \left\| A_{n}\right\| : n \geq 1\right\} is bounded;

(b) there exists a total set M⊂X1M \subset X_{1} such that Anx→Ax,n→∞A_{n} x \rightarrow A x, n \rightarrow \infty, in X2X_{2} for all x∈Mx \in M.

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Problem 7.7

Formulate and prove theorems, analogous to problem 7.6∘7.6^{\circ }, for weak operator convergence.

Problem 7.6: Let X1X_{1} and X2X_{2} be normed linear spaces, {An:n≥1}⊂L(X1,X2),A∈L(X1,X2)\left\{ A_{n}: n \geq 1\right\} \subset \mathcal{L}\left(X_{1}, X_{2}\right), A \in \mathcal{L}\left(X_{1}, X_{2}\right). Prove that for the convergence An→sA,n→∞A_{n} \xrightarrow {s} A, n \rightarrow \infty, it is sufficient, and if X1X_{1} is a Banach space, then it is also necessary, that the following conditions are fulfilled:

(a) the sequence {∥An∥:n≥1}\left\{ \left\| A_{n}\right\| : n \geq 1\right\} is bounded;

(b) there exists a total set M⊂X1M \subset X_{1} such that Anx→Ax,n→∞A_{n} x \rightarrow A x, n \rightarrow \infty, in X2X_{2} for all x∈Mx \in M.

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Problem 7.8

Examine the sequence of operators An:lp→lp,n≥1A_{n}: l_{p} \rightarrow l_{p}, n \geq 1, for uniform, strong and weak convergence.

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(1)

Anx=(0,…,0⏟n,x1,x2,…),1≤p<+∞A_{n} x = (\underbrace{0, \ldots , 0}_{n}, x_{1}, x_{2}, \ldots ), 1 \leq p < +\infty;

(2)

Anx=(xn+1,xn+2,…),1≤p≤+∞;A_{n} x = \left(x_{n+1}, x_{n+2}, \ldots \right), 1 \leq p \leq +\infty ;

(3)

Anx=(0,…,0⏟n−1,xn,0,0,…),1≤p<+∞A_{n} x = (\underbrace{0, \ldots , 0}_{n-1}, x_{n}, 0,0, \ldots ), 1 \leq p < +\infty;

(4)

Anx=(0,…,0⏟n−1,xn,xn+1,…),1≤p<+∞A_{n} x = (\underbrace{0, \ldots , 0}_{n-1}, x_{n}, x_{n+1}, \ldots ), 1 \leq p < +\infty;

(5)

Anx=(xn,xn−1,x2,…x1,0,0,…),1≤p≤+∞;A_{n} x = \left(x_{n}, x_{n-1}, x_{2}, \ldots x_{1}, 0,0, \ldots \right), 1 \leq p \leq +\infty ;

(6)

Anx=(x1n,x2n−1,…,xn1,0,0,…),1≤p<+∞;A_{n} x = \left(\frac{x_{1}}{n}, \frac{x_{2}}{n-1}, \ldots , \frac{x_{n}}{1}, 0,0, \ldots \right), 1 \leq p < +\infty ;

(7)

Anx=(0,…,0⏟n−1,nx2n,0,0,…),1≤p≤+∞;A_{n} x = (\underbrace{0, \ldots , 0}_{n-1}, \sqrt{n} x_{2 n}, 0,0, \ldots ), 1 \leq p \leq +\infty ;

(8)

Anx=(∑m=1nxm,0,0,…),1≤p≤+∞;A_{n} x = \left(\sum_{m = 1}^{n} x_{m}, 0,0, \ldots \right), 1 \leq p \leq +\infty ;

(9)

Anx=(1+n1+nx1,1+n1+2nx2,1+n1+3nx3,…,1+n1+n2xn,0,0,…),1≤p≤+∞;A_{n} x = \left(\frac{1+n}{1+n} x_{1}, \frac{1+n}{1+2 n} x_{2}, \frac{1+n}{1+3 n} x_{3}, \ldots , \frac{1+n}{1+n^{2}} x_{n}, 0,0, \ldots \right), 1 \leq p \leq +\infty ;

(10)

Anx=(nnx1,nnx2,…,nnxn,…),1≤p≤+∞;A_{n} x = \left(\sqrt[n]{n} x_{1}, \sqrt[n]{n} x_{2}, \ldots , \sqrt[n]{n} x_{n}, \ldots \right), 1 \leq p \leq +\infty ;

(11)

Anx=(nnx1,nnx2,…,nnxn,0,0,…),1≤p<+∞;A_{n} x = \left(\sqrt[n]{n} x_{1}, \sqrt[n]{n} x_{2}, \ldots , \sqrt[n]{n} x_{n}, 0,0, \ldots \right), 1 \leq p < +\infty ;

(12)

Anx=(xn2n,xn+12n+1,…,x2n3n,0,0,…),1≤p≤+∞;A_{n} x = \left(\frac{x_{n}}{2 n}, \frac{x_{n+1}}{2 n+1}, \ldots , \frac{x_{2 n}}{3 n}, 0,0, \ldots \right), 1 \leq p \leq +\infty ;

(13)

Anx=(1+n1+nx1,1+n1+2nx2,1+n1+3nx3,…,1+n1+knxk,…),1≤p≤+∞;A_{n} x = \left(\frac{1+n}{1+n} x_{1}, \frac{1+n}{1+2 n} x_{2}, \frac{1+n}{1+3 n} x_{3}, \ldots , \frac{1+n}{1+k n} x_{k}, \ldots \right), 1 \leq p \leq +\infty ;

(14)

Anx=(1+n1+nx1,1+n1+2nx2,1+n1+3nx3,…,1+n1+knxk,0,0,…),1≤p≤+∞A_{n} x = \left(\frac{1+n}{1+n} x_{1}, \frac{1+n}{1+2 n} x_{2}, \frac{1+n}{1+3 n} x_{3}, \ldots , \frac{1+n}{1+k n} x_{k}, 0,0, \ldots \right), 1 \leq p \leq +\infty, where k∈Nk \in \mathbb {N} is fixed.

Problem 7.9

Examine the sequence of operators from items (3), (6) and (11) of problem 7.8∘7.8^{\circ } for uniform, strong or weak convergence in the case of p=+∞p = +\infty.

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Problem 7.10

Find the necessary and sufficient conditions for the sequence of complex numbers {αn:n≥1}\left\{ \alpha_{n}: n \geq 1\right\}, under which the sequence of operators An:lp→lpA_{n}: l_{p} \rightarrow l_{p}, 1≤p≤+∞,n≥11 \leq p \leq +\infty , n \geq 1, converges uniformly, strongly, weakly, if

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(1)

Anx=(αnx1,0,0,…)A_{n} x = \left(\alpha_{n} x_{1}, 0,0, \ldots \right);

(2)

Anx=(0,0,…,0⏟n−1,αnx1,0,0,…)A_{n} x = (\underbrace{0,0, \ldots , 0}_{n-1}, \alpha_{n} x_{1}, 0,0, \ldots );

(3)

Anx=(α1x1,α2x2,…,αnxn,0,0,…)A_{n} x = \left(\alpha_{1} x_{1}, \alpha_{2} x_{2}, \ldots , \alpha_{n} x_{n}, 0,0, \ldots \right);

(4)

Anx=(αnx1,αnx2,…,αnxn,0,0,…)A_{n} x = \left(\alpha_{n} x_{1}, \alpha_{n} x_{2}, \ldots , \alpha_{n} x_{n}, 0,0, \ldots \right);

(5)

Anx=(0,0,…,0⏟n−1,α1x1,α2x2,…,αnxn,0,0,…)A_{n} x = (\underbrace{0,0, \ldots , 0}_{n-1}, \alpha_{1} x_{1}, \alpha_{2} x_{2}, \ldots , \alpha_{n} x_{n}, 0,0, \ldots );

(6)

Anx=(0,0,…,0⏟n−1,αnx1,αn−1x2,…,α1xn,0,0,…)A_{n} x = (\underbrace{0,0, \ldots , 0}_{n-1}, \alpha_{n} x_{1}, \alpha_{n-1} x_{2}, \ldots , \alpha_{1} x_{n}, 0,0, \ldots );

(7)

Anx=(αnxn,αn−1xn+1,…,α1x2n−1,0,0,…)A_{n} x = \left(\alpha_{n} x_{n}, \alpha_{n-1} x_{n+1}, \ldots , \alpha_{1} x_{2 n-1}, 0,0, \ldots \right);

(8)

Anx=(αnx1,αn+1x2,…)A_{n} x = \left(\alpha_{n} x_{1}, \alpha_{n+1} x_{2}, \ldots \right);

(9)

Anx=(αnx1,αn+1x2,…,α2n−1xn,0,0,…)A_{n} x = \left(\alpha_{n} x_{1}, \alpha_{n+1} x_{2}, \ldots , \alpha_{2 n-1} x_{n}, 0,0, \ldots \right);

(10)

Anx=(αnx1,αn−1x2,…,α1xn,0,0,…)A_{n} x = \left(\alpha_{n} x_{1}, \alpha_{n-1} x_{2}, \ldots , \alpha_{1} x_{n}, 0,0, \ldots \right).

Problem 7.11

Examine the sequence of operators An:C([0,1])→C([0,1])A_{n}: C(\left[0,1\right]) \rightarrow C(\left[0,1\right]) for uniform, strong, and weak convergence.

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(1)

(Anx)(t)=tn(1−t)x(t);\left(A_{n} x\right)(t) = t^{n}(1-t) x(t) ;

(2)

(Anx)(t)=tnx(t)\left(A_{n} x\right)(t) = t^{n} x(t);

(3)

(Anx)(t)=e−ntx(t)\left(A_{n} x\right)(t) = e^{-n t} x(t);

(4)

(Anx)(t)=x(t)⋅sin⁡nt\left(A_{n} x\right)(t) = x(t) \cdot \sin n t;

(5)

(Anx)(t)=∫01(tn+sn)x(s)ds\left(A_{n} x\right)(t) = \int_{0}^{1}\left(t^{n}+s^{n}\right) x(s) d s;

(6)

(Anx)(t)=x(t)⋅sin⁡tn\left(A_{n} x\right)(t) = x(t) \cdot \sin \frac{t}{n};

(7)

(Anx)(t)=∫01(t+s)n3x(s)ds\left(A_{n} x\right)(t) = \int_{0}^{1} \frac{(t+s)^{n}}{3} x(s) d s;

(8)

(Anx)(t)=∫01(t+s)n3nx(s)ds\left(A_{n} x\right)(t) = \int_{0}^{1} \frac{(t+s)^{n}}{3^{n}} x(s) d s;

(9)

(Anx)(t)=∫0t(∑k=0n(−1)ks2k+1(2k+1)!)x(s)ds;\left(A_{n} x\right)(t) = \int_{0}^{t}\left(\sum_{k = 0}^{n} \frac{(-1)^{k} s^{2 k+1}}{(2 k+1)!}\right) x(s) d s ;

(10)

(Anx)(t)=x(t1+1n)\left(A_{n} x\right)(t) = x\left(t^{1+\frac{1}{n}}\right);

(11)

(Anx)(t)=(t10n−t2n)x(t);\left(A_{n} x\right)(t) = \left(t^{10 n}-t^{2 n}\right) x(t) ;

(12)

(Anx)(t)=t∫01x(sin⁡nπ2s)ds\left(A_{n} x\right)(t) = t \int_{0}^{1} x\left(\sin^{n} \frac{\pi }{2} s\right) d s;

(13)

(Anx)(t)=t∫01x(s)sin⁡nπ2sds\left(A_{n} x\right)(t) = t \int_{0}^{1} x(s) \sin^{n} \frac{\pi }{2} s d s;

(14)

(Anx)(t)=∫01t1+(2s)n1+(2s)2nx(s)ds\left(A_{n} x\right)(t) = \int_{0}^{1} t \frac{1+(2 s)^{n}}{1+(2 s)^{2 n}} x(s) d s;

(15)

(Anx)(t)=ln⁡(1+nt)1+ntx(t)\left(A_{n} x\right)(t) = \frac{\ln (1+n t)}{1+n t} x(t);

(16)

(Anx)(t)=ln⁡(1+t)1+ntx(t)\left(A_{n} x\right)(t) = \frac{\ln (1+t)}{1+n t} x(t);

(17)

(Anx)(t)=∫01t2ln⁡(1+ns)1+nsx(s)ds\left(A_{n} x\right)(t) = \int_{0}^{1} t^{2} \frac{\ln (1+n s)}{1+n s} x(s) d s;

(18)

(Anx)(t)=∫0tn2nx(s)ds;\left(A_{n} x\right)(t) = \int_{0}^{\frac{t^{n}}{2^{n}}} x(s) d s ;

(19)

(Anx)(t)=∫0tnx(s)ds;\left(A_{n} x\right)(t) = \int_{0}^{t^{n}} x(s) d s ;

(20)

(Anx)(t)=(1−t)n∫0tnx(s)ds\left(A_{n} x\right)(t) = (1-t)^{n} \int_{0}^{t^{n}} x(s) d s;

(21)

(Anx)(t)=n∫tt+1nx(s)ds\left(A_{n} x\right)(t) = n \int_{t}^{t+\frac{1}{n}} x(s) d s, where x(s)=x(1)x(s) = x(1) for s>1s > 1.

Problem 7.12

Examine the sequence of operators An:Lp(T)→Lp(T)A_{n}: L_{p}(T) \rightarrow L_{p}(T) for uniform, strong, and weak convergence.

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(1)

T=R,(Anx)(t)=x(t+n),1≤p<+∞;T = \mathbb {R},\left(A_{n} x\right)(t) = x(t+n), 1 \leq p < +\infty ;

(2)

T=R,(Anx)(t)={x(t),t≥n,0,t<n,1≤p<+∞;T = \mathbb {R},\left(A_{n} x\right)(t) = \begin{cases} x(t), & t \geq n, \\ 0, & t < n, \end{cases} \quad 1 \leq p < +\infty ;

(3)

T=R,(Anx)(t)=11+∣t−n∣x(t),1≤p<+∞;T = \mathbb {R},\left(A_{n} x\right)(t) = \frac{1}{1+\left|t-n\right|} x(t), 1 \leq p < +\infty ;

(4)

T=[0,1],(Anx)(t)=tn∫01snx(s)ds,1≤p<+∞;T = \left[0,1\right],\left(A_{n} x\right)(t) = t^{n} \int_{0}^{1} s^{n} x(s) d s, 1 \leq p < +\infty ;

(5)

T=[0,1],(Anx)(t)=x(t)cos⁡nt,p=2T = \left[0,1\right],\left(A_{n} x\right)(t) = x(t) \cos n t, p = 2;

(6)

T=[0,1],(Anx)(t)=x(t)cos⁡ent,p=2T = \left[0,1\right],\left(A_{n} x\right)(t) = x(t) \cos e^{n} t, p = 2;

(7)

T=[0,1],(Anx)(t)=x(t)cos⁡net,p=2T = \left[0,1\right],\left(A_{n} x\right)(t) = x(t) \cos n e^{t}, p = 2;

(8)

T=[0,1],(Anx)(t)=x(t)cos⁡ent,p=2T = \left[0,1\right],\left(A_{n} x\right)(t) = x(t) \cos e^{n t}, p = 2;

(9)

T=R,(Anx)(t)=x(t)⋅χ[ln⁡n,2ln⁡n](t),1≤p<+∞;T = \mathbb {R},\left(A_{n} x\right)(t) = x(t) \cdot \chi_{\left[\ln n, 2 \ln n\right]}(t), 1 \leq p < +\infty ;

(10)

T=[0,1],(Anx)(t)=tnx(t),p=1T = \left[0,1\right],\left(A_{n} x\right)(t) = \sqrt[n]{t} x(t), p = 1;

(11)

T=[0,1],(Anx)(t)=∫01t2(sn−s2n)x(s)ds,1≤p<+∞T = \left[0,1\right],\left(A_{n} x\right)(t) = \int_{0}^{1} t^{2}\left(s^{n}-s^{2 n}\right) x(s) d s, 1 \leq p < +\infty.

Problem 7.13

Let {pn:n≥1}⊂C([a,b])\left\{ p_{n}: n \geq 1\right\} \subset C(\left[a, b\right]) be a fixed sequence,

(Anx)(t)=pn(t)x(t),t∈[a,b],x∈C([a,b]). \left(A_{n} x\right)(t) = p_{n}(t) x(t), t \in [a, b], x \in C(\left[a, b\right]).

Under what conditions on the sequence {pn:n≥1}\left\{ p_{n}: n \geq 1\right\} the sequence of operators {An:n≥1}\left\{ A_{n}: n \geq 1\right\} converges

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(1)

uniformly;

(2)

strongly;

(3)

weakly? Determine the form of the limit operator.

Problem 7.14

Let X1,X2X_{1}, X_{2} be Banach spaces.

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(1)

Prove that the space L(X1,X2)\mathcal{L}\left(X_{1}, X_{2}\right) is complete with respect to the strong convergence of operators, i.e., every sequence {An:n≥1}⊂L(X1,X2)\left\{ A_{n}: n \geq 1\right\} \subset \mathcal{L}\left(X_{1}, X_{2}\right), for which {Anx:n≥1}\left\{ A_{n} x: n \geq 1\right\} is a Cauchy sequence of elements from X2X_{2} for each x∈X1x \in X_{1}, converges strongly to some operator A∈L(X1,X2)A \in \mathcal{L}\left(X_{1}, X_{2}\right).

(2)

Under what conditions on the Banach spaces X1X_{1} and X2X_{2} is the space L(X1,X2)\mathcal{L}\left(X_{1}, X_{2}\right) complete with respect to weak convergence?

Problem 7.15

In Lp(R),1≤p<+∞L_{p}(\mathbb {R}), 1 \leq p < +\infty, define the shift operator

(Asx)(t)=x(t+s),t∈R,x∈Lp(R),s∈R \left(A_{s} x\right)(t) = x(t+s), t \in \mathbb {R}, x \in L_{p}(\mathbb {R}), s \in \mathbb {R}

Let sn→s,n→∞s_{n} \rightarrow s, n \rightarrow \infty, and sn≠s,n≥1s_{n} \neq s, n \geq 1. Prove that Asn→sAsA_{s_{n}} \xrightarrow {s} A_{s}, but Asn⇏AsA_{s_{n}} \nRightarrow A_{s}.

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Problem 7.16

Let XX be the space C1([0,1])C^{1}(\left[0,1\right]) with the norm ∥x∥=max⁡t∈[0,1]∣x(t)∣,x∈C1([0,1])\left\| x\right\| = \max_{t \in [0,1]}\left|x(t)\right|, x \in C^{1}(\left[0,1\right]). Define the operator An:X→C([0,1])A_{n}: X \rightarrow C(\left[0,1\right]) by the formula (Anx)(t)=n(x(t+1n)−x(t)),t∈[0,1],x∈X,n≥1\left(A_{n} x\right)(t) = n\left(x\left(t+\frac{1}{n}\right)-x(t)\right), \quad t \in [0,1], \quad x \in X, \quad n \geq 1 (if t>1t > 1, put x(t)=x(1)+x−′(1)(t−1)x(t) = x(1)+x_{-}^{\prime }(1)(t-1).) Prove that

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(1)

for every x∈Xx \in X the sequence {Anx:n≥1}\left\{ A_{n} x: n \geq 1\right\} converges in norm in C([0,1])C(\left[0,1\right]);

(2)

the sequence {∥An∥:n≥1}\left\{ \left\| A_{n}\right\| : n \geq 1\right\} is not bounded;

(3)

the space L(X,C([0,1]))\mathcal{L}(X, C(\left[0,1\right])) is not complete with respect to the strong operator topology.

Do these statements contradict the Uniform Boundedness Principle?

Problem 7.17

Denote by C~\widetilde{C} the space of all 2π2 \pi-periodic continuous functions on R\mathbb {R}. It can be identified with a subspace in C([−π,π])C(\left[-\pi , \pi \right]), which consists of functions xx such that x(−π)=x(π)x(-\pi ) = x(\pi ). For any n≥1n \geq 1 and t∈[−π,π]t \in [-\pi , \pi ] put

(Snx)(t)=1π∫−ππDn(t−s)x(s)ds \left(S_{n} x\right)(t) = \frac{1}{\pi } \int _{-\pi }^{\pi } D_{n}(t-s) x(s) d s

where Dn(t)=12+∑k=1ncos⁡kt=sin⁡2n+12t2sin⁡t2D_{n}(t) = \frac{1}{2}+\sum_{k = 1}^{n} \cos k t = \frac{\sin \frac{2 n+1}{2} t}{2 \sin \frac{t}{2}} is the Dirichlet kernel. Prove that

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(1)

Sn→sI,Sn⇏IS_{n} \xrightarrow {s} I, S_{n} \nRightarrow I in L2([−π,π])L_{2}(\left[-\pi , \pi \right]);

(2)

∫−ππ∣Dn(t)∣dt>Aln⁡n,n≥1\int_{-\pi }^{\pi }\left|D_{n}(t)\right| d t > A \ln n, n \geq 1, for some constant A>0A > 0;

(3)

there exist functions x∈C~(x∈L1([−π,π]))x \in \widetilde{C}\left(x \in L_{1}(\left[-\pi , \pi \right])\right), for which the Fourier series with respect to the trigonometric system does not converge to xx in C~\widetilde{C} (in L1([−π,π])L_{1}(\left[-\pi , \pi \right]), respectively);

(4)

for any t0∈[−π,π]t_{0} \in [-\pi , \pi ] there exists a function x∈C~x \in \widetilde{C}, for which the Fourier series at the point t0t_{0} does not converge to x(t0)x\left(t_{0}\right);

(5)

there exist functions x∈C([−π,π])x \in C(\left[-\pi , \pi \right]) and y∈L1([−π,π])y \in L_{1}(\left[-\pi , \pi \right]) such that the series

a0α02+∑n=1∞(anαn+bnβn) \frac{a_{0} \alpha _{0}}{2}+\sum _{n = 1}^{\infty }\left(a_{n} \alpha _{n}+b_{n} \beta _{n}\right)

diverges, where {a0,an,bn:n≥1},{α0,αn,βn:n≥1}\left\{ a_{0}, a_{n}, b_{n}: n \geq 1\right\} ,\left\{ \alpha_{0}, \alpha_{n}, \beta_{n}: n \geq 1\right\} are the Fourier coefficients of the functions xx and yy, respectively.

Problem 7.18

Let X1X_{1} be a Banach space, X2X_{2} be an NLS and the mapping B:X1×X1→X2B: X_{1} \times X_{1} \rightarrow X_{2} be linear and continuous in each variable. Prove that BB is joint continuous.

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Problem 7.19

Let XX be an NLS which consists of algebraic polynomials of one variable with a norm ∥x∥=∫01∣x(t)∣dt\left\| x\right\| = \int_{0}^{1}\left|x(t)\right| d t, and B(x,y)=∫01x(t)y(t)dtB(x, y) = \int_{0}^{1} x(t) y(t) d t. Prove that the functional BB is linear and continuous in each variable, but is not continuous on X×XX \times X.

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Problem 7.20

Let XX be a Banach space and {A,B,An,Bn:n≥1}⊂L(X)\left\{ A, B, A_{n}, B_{n}: n \geq 1\right\} \subset \mathcal{L}(X). Prove that

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(1)

An→sA,Bn→sB⇒AnBn→sABA_{n} \xrightarrow {s} A, B_{n} \xrightarrow {s} B \Rightarrow A_{n} B_{n} \xrightarrow {s} A B;

(2)

An⇉A,Bn⇉B⇒AnBn⇉ABA_{n} \rightrightarrows A, B_{n} \rightrightarrows B \Rightarrow A_{n} B_{n} \rightrightarrows A B;

(3)

An→wA,Bn→wB⇏AnBn→wABA_{n} \xrightarrow {w} A, B_{n} \xrightarrow {w} B \nRightarrow A_{n} B_{n} \xrightarrow {w} A B.

Problem 7.21

Let XX be a Banach space, {x,xn:n≥1}⊂X\left\{ x, x_{n}: n \geq 1\right\} \subset X and {A,An:n≥1}⊂L(X)\left\{ A, A_{n}: n \geq 1\right\} \subset \mathcal{L}(X). Prove that

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(1)

An→sA,xn→x⇒Anxn→AxA_{n} \xrightarrow {s} A, x_{n} \rightarrow x \Rightarrow A_{n} x_{n} \rightarrow A x;

(2)

An⇉A,xn→wx⇒Anxn→wAxA_{n} \rightrightarrows A, x_{n} \xrightarrow {w} x \Rightarrow A_{n} x_{n} \xrightarrow {w} A x;

(3)

An→sA,xn→wx⇏Anxn→wAxA_{n} \xrightarrow {s} A, x_{n} \xrightarrow {w} x \nRightarrow A_{n} x_{n} \xrightarrow {w} A x.

Problem 7.22

Let HH be a Hilbert space, {An:n≥1}⊂L(H),sup⁡n≥1∥An∥<+∞\left\{ A_{n}: n \geq 1\right\} \subset \mathcal{L}(H), \sup_{n \geq 1}\left\| A_{n}\right\| < +\infty, and ∃L⊂H,Lˉ=H,∀x,y∈L:∃lim⁡n→∞(Anx,y)\exists L \subset H, \bar{L} = H, \forall x, y \in L: \exists \lim_{n \rightarrow \infty }\left(A_{n} x, y\right).

Prove that there exists A∈L(H)A \in \mathcal{L}(H) such that An→wAA_{n} \xrightarrow {w} A.

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Problem 7.23

Let HH be a separable Hilbert space. Prove that any closed ball in L(H)\mathcal{L}(H) is a weakly compact set (i.e., every bounded sequence in L(H)\mathcal{L}(H) contains a weakly convergent subsequence).

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Problem 7.24

Let XX be a Banach space, A∈L(X),{λk:k≥0}⊂R,φ(t)=∑n=1∞λntnA \in \mathcal{L}(X),\left\{ \lambda_{k}: k \geq 0\right\} \subset \mathbb {R}, \varphi (t) = \sum_{n = 1}^{\infty } \lambda_{n} t^{n}, t∈Rt \in \mathbb {R}, be the sum of a power series which converges on R\mathbb {R}. Prove that the sequence {φn(A):n≥0}\left\{ \varphi_{n}(A): n \geq 0\right\}, where φn(A)=∑k=0nλkAk,n≥0,A0=I\varphi_{n}(A) = \sum_{k = 0}^{n} \lambda^{k} A^{k}, n \geq 0, A^{0} = I, converges in L(X)\mathcal{L}(X) to some operator φ(A)∈L(X)\varphi (A) \in \mathcal{L}(X).

Prove that under the condition λk≥0,k≥0\lambda_{k} \geq 0, k \geq 0, the inequality ∥φ(A)∥≤φ(∥A∥)\left\| \varphi (A)\right\| \leq \varphi (\left\| A\right\| ) holds.

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Problem 7.25

Prove that for a bounded operator A∈L(X)A \in \mathcal{L}(X), where XX is a Banach space, the operators

eA=∑k=0∞Akk!,sin⁡A=∑k=0∞(−1)kA2k+1(2k+1)!,cos⁡A=∑k=0∞(−1)kA2k(2k)!, e^{A} = \sum _{k = 0}^{\infty } \frac{A^{k}}{k!}, \sin A = \sum _{k = 0}^{\infty } \frac{(-1)^{k} A^{2 k+1}}{(2 k+1)!}, \cos A = \sum _{k = 0}^{\infty } \frac{(-1)^{k} A^{2 k}}{(2 k)!},

are well-defined, and eA,sin⁡A,cos⁡A∈L(X)e^{A}, \sin A, \cos A \in \mathcal{L}(X).

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Problem 7.26

Let XX be a Banach space, A∈L(X)A \in \mathcal{L}(X). Prove that the series ∑n=0∞An\sum_{n = 0}^{\infty } A^{n} converges in L(X)\mathcal{L}(X) if and only if for some k∈Nk \in \mathbb {N} the inequality ∥Ak∥<1\left\| A^{k}\right\| < 1 holds.

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Problem 7.27

Prove that every linear bounded operator in a Hilbert space is a strong limit of a sequence of bounded finite-dimensional operators if and only if the space is separable.

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Problem 7.28

Denote by TnT_{n} the subspace of the space C~\widetilde{C} (see problem 7.17*) which consists of trigonometric polynomials of degree at most nn. An operator U∈L(C~)U \in \mathcal{L}(\tilde{C}) is called a polynomial (trigonometric) operator of degree nn, if Ux∈TnU x \in T_{n} for all x∈C~x \in \widetilde{C} and Ux=xU x = x for all x∈Tnx \in T_{n}. Prove the following statements:

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(1)

The following operators are polynomial: the operator SnS_{n} from problem 7.17*; an operator that maps each function to its interpolation (trigonometric) polynomial, constructed for a fixed set of nodes.

(2)

(Zigmund-Marcinkiewicz-Berman) If UU is a polynomial operator of degree nn, then 12π∫−ππ(Uxτ)(s−τ)dτ=(Snx)(s),s∈R,x∈C~\frac{1}{2 \pi } \int_{-\pi }^{\pi }\left(U x^{\tau }\right)(s-\tau ) d \tau = \left(S_{n} x\right)(s), s \in \mathbb {R}, x \in \widetilde{C}, where xτ(t)=x(t+τ),t∈R,τ∈Rx^{\tau }(t) = x(t+\tau ), \quad t \in \mathbb {R}, \quad \tau \in \mathbb {R}, and for each s∈Rs \in \mathbb {R} the integrand is a continuous function of τ\tau.

(3)

If UU is a polynomial operator of degree nn, then ∥U∥≥∥Sn∥>Aln⁡n,n≥1\left\| U\right\| \geq \left\| S_{n}\right\| > A \ln n, n \geq 1, for some constant A>0A > 0.

(4)

The sequence {Un:n≥1}\left\{ U_{n}: n \geq 1\right\} of polynomial operators, where UnU_{n} is an operator of degree nn, does not converge strongly in C~\widetilde{C}.

Problem 7.29

A linear operator A:C([a,b])→C([a,b])A: C(\left[a, b\right]) \rightarrow C(\left[a, b\right]), where C([a,b])C(\left[a, b\right]) is a real space, is called nonnegative if for all x∈C([a,b])x \in C(\left[a, b\right]) such that x(t)≥0x(t) \geq 0 for all t∈[a,b]t \in [a, b], we have (Ax)(t)≥0(A x)(t) \geq 0 for all t∈[a,b]t \in [a, b]. Prove that

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(1)

The nonnegative operator is continuous, and ∥A∥=∥Ae0∥\left\| A\right\| = \left\| A e_{0}\right\|, where e0(t)=1e_{0}(t) = 1, t∈[a,b]t \in [a, b].

(2)

(Korovkin) If {An:n≥1}\left\{ A_{n}: n \geq 1\right\} is a sequence of nonnegative operators, then An→sIA_{n} \xrightarrow {s} I in C([a,b])C(\left[a, b\right]) if and only if the convergence Anek→ek,n→∞A_{n} e_{k} \rightarrow e_{k}, n \rightarrow \infty, holds for ek(t)=tk,t∈[a,b],k=0,1,2e_{k}(t) = t^{k}, t \in [a, b], k = 0,1,2.

Is the analogous criterion of weak convergence of nonnegative operators valid?

Problem 7.30

Let X=Lp([0,1])X = L_{p}(\left[0,1\right]) or X=C([0,1])X = C(\left[0,1\right]), the operator Kn:X→XK_{n}: X \rightarrow X assigns to each function x∈Xx \in X the Kantorovich polynomial

(Knx)(t)=∑k=0n(nk)xnktk(1−t)n−k,t∈[0,1] \left(K_{n} x\right)(t) = \sum _{k = 0}^{n}\binom {n}{k} x_{n k} t^{k}(1-t)^{n-k}, t \in [0,1]

where xnk=(n+1)∫kn+1k+1n+1x(t)dt,0≤k≤n,n≥1x_{n k} = (n+1) \int_{\frac{k}{n+1}}^{\frac{k+1}{n+1}} x(t) d t, 0 \leq k \leq n, n \geq 1. Prove that

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(1)

Kn→sIK_{n} \xrightarrow {s} I in C([0,1])C(\left[0,1\right]);

(2)

Kn→sIK_{n} \xrightarrow {s} I in Lp([0,1]),1≤p<+∞L_{p}(\left[0,1\right]), 1 \leq p < +\infty.

Is this statement true for p=+∞p = +\infty?