Section 8.7

More Convergence Concepts

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Problem 8.7.1

Prove the following simple claims.

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(a)

Let {fn}n=1∞\left\{ f_{n}\right\}_{n=1}^{\infty } denote a Cauchy sequence in LpL^{p}, where 0<p<∞0<p<\infty. Show that {fn}n=1∞\left\{ f_{n}\right\}_{n=1}^{\infty } is a Cauchy sequence in measure: for every ε>0\varepsilon >0 and δ>0\delta >0 there is N∈NN \in \mathbb {N} such that for every n,m⩾Nn, m \geqslant N we have μ({ω∈Ω:∣fn(ω)−fm(ω)∣>δ})<ε\mu \left(\left\{ \omega \in \Omega :\left|f_{n}(\omega )-f_{m}(\omega )\right|>\delta \right\} \right)<\varepsilon.

(b)

Let f,f1,f2,…∈Lpf, f_{1}, f_{2}, \ldots \in L^{p} and suppose that fn→Lpff_{n} \xrightarrow {L^{p}} f, where 0<p<∞0<p<\infty. If g∈L∞g \in L^{\infty }, then fg,f1g,f2g,…∈Lpf g, f_{1} g, f_{2} g, \ldots \in L^{p} and fng→Lpfgf_{n} g \xrightarrow {L^{p}} f g.

Problem 8.7.2

While convergence in pth mean implies convergence in measure, it is not the case that convergence in measure implies convergence in pthe mean.

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Problem 8.7.3

It is possible for a sequence {fn}n=1∞\left\{ f_{n}\right\}_{n=1}^{\infty } in LpL^{p} to converge μ\mu-a. e. to some f∈Lpf \in L^{p} but not in pth mean. That is, convergence μ\mu-a. e. does not force convergence in pp th mean.

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Problem 8.7.4

It is possible for a sequence {fn}n=1∞\left\{ f_{n}\right\}_{n=1}^{\infty } in LpL^{p} to converge in pth mean to zero, but {fn}n=1∞\left\{ f_{n}\right\}_{n=1}^{\infty } converges at no point of Ω\Omega.

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Problem 8.7.5

It is possible to have functions f,f1,f2,…∈Lp1∩Lp2f, f_{1}, f_{2}, \ldots \in L^{p_{1}} \cap L^{p_{2}} such that fn→Lp1ff_{n} \xrightarrow {L^{p_{1}}} f but fn̸→Lp2ff_{n} \not\xrightarrow {L^{p_{2}}} f.

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Problem 8.7.6

Let 1<p0<+∞1<p_{0}<+\infty. There is a sequence {fn}n=1∞\left\{ f_{n}\right\}_{n=1}^{\infty } in LpL^{p} for all 1⩽p<p01 \leqslant p<p_{0} with fn→Lp0f_{n} \xrightarrow {L^{p}} 0 for all 1⩽p<p01 \leqslant p<p_{0}, but fnf_{n} fails to converge in p0p_{0}th mean.

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Problem 8.7.7

Let 1⩽p,q<+∞1 \leqslant p, q<+\infty, and let {fn}n=1∞\left\{ f_{n}\right\}_{n=1}^{\infty } denote a sequence in Lp∩LqL^{p} \cap L^{q}. Suppose that there is g∈Lpg \in L^{p} and h∈Lqh \in L^{q} with fn→Lpgf_{n} \xrightarrow {L^{p}} g and fn→Lqhf_{n} \xrightarrow {L^{q}} h. Then g=hg=h μ\mu-a.e. on Ω\Omega.

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Problem 8.7.8

Suppose that {fn}n=1∞\left\{ f_{n}\right\}_{n=1}^{\infty } is a sequence in LpL^{p}, where 1<p<+∞1<p<+\infty. Suppose that h∈L1h \in L^{1} with fn⩽hf_{n} \leqslant h μ\mu-a.e. on Ω\Omega. If fnf_{n} converges in measure to some ff, then f∈Lpf \in L^{p} and fn→Lpff_{n} \xrightarrow {L^{p}} f.

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Problem 8.7.9

If f,f1,f2,…∈Lpf, f_{1}, f_{2}, \ldots \in L^{p} are such that fn→ff_{n} \rightarrow f uniformly, then fn→Lpff_{n} \xrightarrow {L^{p}} f.

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Remark.
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Here 0<p<+∞0<p<+\infty.

Problem 8.7.10

Let f,f1,f2,…∈Lpf, f_{1}, f_{2}, \ldots \in L^{p}, where 1⩽p⩽+∞1 \leqslant p \leqslant +\infty, and suppose that ∥fn∥p→∥f∥p\left\| f_{n}\right\|_{p} \rightarrow \left\| f\right\|_{p}. Then either of the conditions fn→ff_{n} \rightarrow f μ\mu-a.e. on Ω\Omega and fn→ff_{n} \rightarrow f in measure is sufficient for the conclusion fn→Lpff_{n} \xrightarrow {L^{p}} f.

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Problem 8.7.11

Consider the measure space ([0,1],B,λ)\left(\left[0,1\right], \mathscr {B}, \lambda \right), where here B\mathscr {B} denotes the Borel subsets of [0,1]\left[0,1\right] and λ\lambda denotes Lebesgue measure restricted to B\mathscr {B}. Let fn=n  1[0,n−1]f_{n}=n \; \mathbb {1}_{\left[0, n^{-1}\right]} for each n∈Nn \in \mathbb {N}. Then each fnf_{n} is in LpL^{p} for 1⩽p<+∞1 \leqslant p<+\infty, fn→0f_{n} \rightarrow 0 μ\mu-a.e. on [0,1]\left[0,1\right] and in measure, but ∫fng↛∫0g\int f_{n} g \not\rightarrow \int 0 g when g=1g=1, and hence fn↛0f_{n} \not\rightarrow 0 weakly.

Definition. Consider a generic measure space (Ω,F,μ)\left(\Omega , \mathcal{F}, \mu \right), and let 1⩽p<+∞1 \leqslant p<+\infty. Let f,f1,f2,…∈Lpf, f_{1}, f_{2}, \ldots \in L^{p}. We will say that fn→ff_{n} \rightarrow f weakly [in LpL^{p}] iff

lim⁡n∫fng=∫fgfor every g∈Lp′. \lim _{n} \int f_{n} g = \int f g \quad \text{for every } g \in L^{p^{\prime }}.

Here p′p^{\prime } denotes the conjugate exponent of pp: p′=pp−1p^{\prime }=\frac{p}{p-1} for 1<p<+∞1<p<+\infty, and 1′=+∞1^{\prime }=+\infty.

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Problem 8.7.12

Consider the measure space (R,B,λ)\left(\mathbb {R}, \mathscr {B}, \lambda \right). Let fn=n−1  1[1,en]f_{n}=n^{-1} \; \mathbb {1}_{\left[1, e^{n}\right]} for every n∈Nn \in \mathbb {N}. Then each fnf_{n} is in LpL^{p} for 1⩽p<+∞1 \leqslant p<+\infty, fn→0f_{n} \rightarrow 0 uniformly, but fn↛0f_{n} \not\rightarrow 0 weakly in LpL^{p}.

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Remark.
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Consider the function g(ω)=ω−1  1[1,+∞)(ω)g(\omega )=\omega^{-1} \; \mathbb {1}_{[1,+\infty )}(\omega ). We have that g∈Lp′g \in L^{p^{\prime }} for each 1<p<+∞1<p<+\infty, gg is bounded, and ∫fng=1\int f_{n} g=1 for every n∈Nn \in \mathbb {N}, while ∫0g=0\int 0 g=0.

Problem 8.7.13

Consider the measure space ([0,2π],B,λ)\left(\left[0,2 \pi \right], \mathscr {B}, \lambda \right), where here B\mathscr {B} denotes the Borel subsets of [0,2π]\left[0,2 \pi \right] and λ\lambda denotes Lebesgue measure restricted to B\mathscr {B}. For each n∈Nn \in \mathbb {N} and 0⩽ω⩽2π0 \leqslant \omega \leqslant 2 \pi, define fn(ω)=cos⁡nωf_{n}(\omega )=\cos n \omega. Then each fnf_{n} is in L1L^{1}, and fn→0f_{n} \rightarrow 0 weakly in L1L^{1}. However, fn↛0f_{n} \not\rightarrow 0. In fact, we have fn̸→μ0f_{n} \not\xrightarrow {\mu } 0 and fn↛0f_{n} \not\rightarrow 0 μ\mu-a.e. on Ω\Omega.

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Remark.
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This exercise might be difficult.

Problem 8.7.14

Refer to the Vitali Convergence Theorem. Prove that conditions (i) and (ii) imply that f∈Lpf \in L^{p} and fn→ff_{n} \rightarrow f in pth mean when μ(Ω)=+∞\mu (\Omega )=+\infty.

Vitali Convergence Theorem (finite-measure case). Let (Ω,F,μ)\left(\Omega , \mathcal{F}, \mu \right) denote a measure space with μ(Ω)<+∞\mu (\Omega )<+\infty, and let 1⩽p<+∞1 \leqslant p<+\infty. Let {fn}n=1∞\left\{ f_{n}\right\}_{n=1}^{\infty } denote a sequence of functions in LpL^{p}. Let ff denote an F/B∗\mathcal{F} / \mathscr {B}^{*}-measurable function on Ω\Omega such that fn→ff_{n} \rightarrow f μ\mu-a.e. on Ω\Omega and ff is finite μ\mu-a.e. on Ω\Omega. Then the condition f∈Lpf \in L^{p} and fn→Lpff_{n} \xrightarrow {L^{p}} f is equivalent to the dual conditions (i) for every ε>0\varepsilon >0 there is A∈FA \in \mathcal{F} [depending on ε\varepsilon] with μ(A)<+∞\mu (A)<+\infty and ∫Ac∣fn∣p<ε\int_{A^{c}} \left|f_{n}\right|^{p}<\varepsilon for every n∈Nn \in \mathbb {N}, and (ii) for every ε>0\varepsilon >0 there is δ>0\delta >0 [depending only on ε\varepsilon, not nn] such that whenever μ(E)<δ\mu (E)<\delta we have ∫E∣fn∣p<ε\int_{E} \left|f_{n}\right|^{p}<\varepsilon for every n∈Nn \in \mathbb {N}.

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Problem 8.7.15

Let (Ω,F,μ)\left(\Omega , \mathcal{F}, \mu \right) denote a measure space with 1⩽p<+∞1 \leqslant p<+\infty. Let {fn}n=1∞\left\{ f_{n}\right\}_{n=1}^{\infty } denote a sequence in LpL^{p}, and let ff denote an F/B∗\mathcal{F} / \mathscr {B}^{*}-measurable function that is finite μ\mu-a.e. on Ω\Omega with fn→ff_{n} \rightarrow f μ\mu-a.e. on Ω\Omega. For every n,k∈Nn, k \in \mathbb {N}, let Bn,k={ω∈Ω:∣fn(ω)∣p⩾k}B_{n, k}=\left\{ \omega \in \Omega :\left|f_{n}(\omega )\right|^{p} \geqslant k\right\}. Make the following additional assumption (a): for every ε>0\varepsilon >0 there is a set A∈FA \in \mathcal{F} [depending on ε\varepsilon] such that μ(A)<+∞\mu (A)<+\infty and ∫Ac∣fn∣p<ε\int_{A^{c}} \left|f_{n}\right|^{p}<\varepsilon for every n∈Nn \in \mathbb {N}.

Then the following four statements are logically equivalent:

  1. f∈Lpf \in L^{p} and fn→Lpff_{n} \xrightarrow {L^{p}} f

  2. If {Ek}k=1∞\left\{ E_{k}\right\}_{k=1}^{\infty } is a nonincreasing sequence of F\mathcal{F}-sets with limit ∅\varnothing, then for every ε>0\varepsilon >0 there is K∈NK \in \mathbb {N} such that k⩾Kk \geqslant K forces ∫Ek∣fn∣p<ε\int_{E_{k}} \left|f_{n}\right|^{p}<\varepsilon for every n∈Nn \in \mathbb {N}.

  3. For every ε>0\varepsilon >0 there is K∈NK \in \mathbb {N} such that k⩾Kk \geqslant K forces ∫Bn,k∣fn∣p<ε\int_{B_{n, k}} \left|f_{n}\right|^{p}<\varepsilon for every n∈Nn \in \mathbb {N}.

  4. For every ε>0\varepsilon >0 there is δ>0\delta >0 such that μ(E)<δ\mu (E)<\delta forces ∫E∣fn∣p<ε\int_{E} \left|f_{n}\right|^{p}<\varepsilon for every n∈Nn \in \mathbb {N}.

Vitali Convergence Theorem (finite-measure case). Let (Ω,F,μ)\left(\Omega , \mathcal{F}, \mu \right) denote a measure space with μ(Ω)<+∞\mu (\Omega )<+\infty, and let 1⩽p<+∞1 \leqslant p<+\infty. Let {fn}n=1∞\left\{ f_{n}\right\}_{n=1}^{\infty } denote a sequence of functions in LpL^{p}. Let ff denote an F/B∗\mathcal{F} / \mathscr {B}^{*}-measurable function on Ω\Omega such that fn→ff_{n} \rightarrow f μ\mu-a.e. on Ω\Omega and ff is finite μ\mu-a.e. on Ω\Omega. Then the condition f∈Lpf \in L^{p} and fn→Lpff_{n} \xrightarrow {L^{p}} f is equivalent to the dual conditions (i) for every ε>0\varepsilon >0 there is A∈FA \in \mathcal{F} with μ(A)<+∞\mu (A)<+\infty and ∫Ac∣fn∣p<ε\int_{A^{c}} \left|f_{n}\right|^{p}<\varepsilon for every n∈Nn \in \mathbb {N}, and (ii) for every ε>0\varepsilon >0 there is δ>0\delta >0 such that whenever μ(E)<δ\mu (E)<\delta we have ∫E∣fn∣p<ε\int_{E} \left|f_{n}\right|^{p}<\varepsilon for every n∈Nn \in \mathbb {N}.

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Remark.
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The following outline is useful. By the Vitali Convergence Theorem and Exercise 8.7.14, it is immediate that (i) and (iv) are logically equivalent.

We show that (i) implies (ii). Let ε>0\varepsilon >0. Find N∈NN \in \mathbb {N} such that n⩾Nn \geqslant N implies ∥fn−f∥p<ε\left\| f_{n}-f\right\|_{p}<\varepsilon. For n⩾Nn \geqslant N and k∈Nk \in \mathbb {N}, Minkowski's Inequality gives

(∫Ek∣fn∣p)1/p⩽(∫Ek∣f∣p)1/p+(∫Ek∣fn−f∣p)1/p<(∫Ek∣f∣p)1/p+ε. \left(\int _{E_{k}} \left|f_{n}\right|^{p}\right)^{1 / p} \leqslant \left(\int _{E_{k}} \left|f\right|^{p}\right)^{1 / p}+\left(\int _{E_{k}} \left|f_{n}-f\right|^{p}\right)^{1 / p} <\left(\int _{E_{k}} \left|f\right|^{p}\right)^{1 / p}+\varepsilon .

Apply DCT to {∣f∣p  1Ek}k=1∞\left\{ \left|f\right|^{p} \; \mathbb {1}_{E_{k}}\right\}_{k=1}^{\infty } to show that (∫Ek∣fn∣p)1/p<ε\left(\int_{E_{k}} \left|f_{n}\right|^{p}\right)^{1 / p}<\varepsilon for large enough kk, say k⩾Kk \geqslant K. Then for every n∈Nn \in \mathbb {N} and k⩾Kk \geqslant K, we have (∫Ek∣fn∣p)1/p<2ε\left(\int_{E_{k}} \left|f_{n}\right|^{p}\right)^{1 / p}<2 \varepsilon. For n∈{1,…,N−1}n \in \left\{ 1, \ldots , N-1\right\}, observe for every k∈Nk \in \mathbb {N} that we have

∫Ek∣fn∣p⩽∫Ekmax⁡{∣f1∣p,…,∣fN−1∣p}<+∞, \int _{E_{k}} \left|f_{n}\right|^{p} \leqslant \int _{E_{k}} \max \left\{ \left|f_{1}\right|^{p}, \ldots , \left|f_{N-1}\right|^{p}\right\} <+\infty ,

and therefore DCT can be used to obtain (ii).

Now assume (ii), picking ε>0\varepsilon >0. For each k∈Nk \in \mathbb {N}, define Ek=⋃n=k∞Bn,kE_{k}=\bigcup_{n=k}^{\infty } B_{n, k}. Then E1⊇E2⊇⋯E_{1} \supseteq E_{2} \supseteq \cdots and lim⁡‾n∣fn(ω)∣=+∞\overline{\lim }_{n} \left|f_{n}(\omega )\right|=+\infty on ⋂k=1∞Ek\bigcap_{k=1}^{\infty } E_{k}; from this we have μ(⋂k=1∞Ek)=0\mu \left(\bigcap_{k=1}^{\infty } E_{k}\right)=0. Next, write Fk=Ek−⋂j=1∞EjF_{k}=E_{k}-\bigcap_{j=1}^{\infty } E_{j} for every k∈Nk \in \mathbb {N}. We have that F1⊇F2⊇⋯F_{1} \supseteq F_{2} \supseteq \cdots and lim⁡kFk=∅\lim_{k} F_{k}=\varnothing. Choose KK such that k⩾Kk \geqslant K implies ∫Fk∣fn∣p<ε\int_{F_{k}} \left|f_{n}\right|^{p}<\varepsilon for every n∈Nn \in \mathbb {N}. For every n⩾Kn \geqslant K we have Bn,K⊆EKB_{n, K} \subseteq E_{K}. Therefore, if n,k⩾Kn, k \geqslant K, then

∫Bn,k∣fn∣p⩽∫Bn,K∣fn∣p⩽∫EK∣fn∣p=∫FK∣fn∣p<ε. \int _{B_{n, k}} \left|f_{n}\right|^{p} \leqslant \int _{B_{n, K}} \left|f_{n}\right|^{p} \leqslant \int _{E_{K}} \left|f_{n}\right|^{p}=\int _{F_{K}} \left|f_{n}\right|^{p}<\varepsilon .

For n∈{1,…,K−1}n \in \left\{ 1, \ldots , K-1\right\}, we have ∣fn∣p⩽max⁡{∣f1∣p,…,∣fK−1∣p}=g\left|f_{n}\right|^{p} \leqslant \max \left\{ \left|f_{1}\right|^{p}, \ldots , \left|f_{K-1}\right|^{p}\right\} =g, say, and hence ∫Bn,k∣fn∣p⩽∫Bkg<+∞\int_{B_{n, k}} \left|f_{n}\right|^{p} \leqslant \int_{B_{k}} g<+\infty, where Bk=⋃n=1K−1Bn,k={ω∈Ω:g(ω)⩾k}B_{k}=\bigcup_{n=1}^{K-1} B_{n, k}=\left\{ \omega \in \Omega : g(\omega ) \geqslant k\right\}. Use DCT to derive (iii) in direct fashion.

Now assume (iii). Pick K∈NK \in \mathbb {N} such that k⩾Kk \geqslant K forces ∫Bn,k∣fn∣p<εp\int_{B_{n, k}} \left|f_{n}\right|^{p}<\varepsilon^{p} for every n∈Nn \in \mathbb {N}. Argue that μ(E)<K−1εp\mu (E)<K^{-1} \varepsilon^{p} implies

(∫E∣fn∣p)1/p⩽(∫E∩Bn,K∣fn∣p)1/p+(∫E∩Bn,Kc∣fn∣p)1/p<2ε. \left(\int _{E} \left|f_{n}\right|^{p}\right)^{1 / p} \leqslant \left(\int _{E \cap B_{n, K}} \left|f_{n}\right|^{p}\right)^{1 / p}+\left(\int _{E \cap B_{n, K}^{c}} \left|f_{n}\right|^{p}\right)^{1 / p}<2 \varepsilon .

Therefore we may deduce (iv) from (iii).

Problem 8.7.16

Assume everything in Exercise 8.7.15, including (a). Assume further that (ii) holds. Argue that (i) and (ii) of the Vitali Convergence Theorem follow as consequences.

Vitali Convergence Theorem (finite-measure case). Let (Ω,F,μ)\left(\Omega , \mathcal{F}, \mu \right) denote a measure space with μ(Ω)<+∞\mu (\Omega )<+\infty, and let 1⩽p<+∞1 \leqslant p<+\infty. Let {fn}n=1∞\left\{ f_{n}\right\}_{n=1}^{\infty } denote a sequence of functions in LpL^{p}. Let ff denote an F/B∗\mathcal{F} / \mathscr {B}^{*}-measurable function on Ω\Omega such that fn→ff_{n} \rightarrow f μ\mu-a.e. on Ω\Omega and ff is finite μ\mu-a.e. on Ω\Omega. Then the condition f∈Lpf \in L^{p} and fn→Lpff_{n} \xrightarrow {L^{p}} f is equivalent to the dual conditions (i) for every ε>0\varepsilon >0 there is A∈FA \in \mathcal{F} with μ(A)<+∞\mu (A)<+\infty and ∫Ac∣fn∣p<ε\int_{A^{c}} \left|f_{n}\right|^{p}<\varepsilon for every n∈Nn \in \mathbb {N}, and (ii) for every ε>0\varepsilon >0 there is δ>0\delta >0 such that whenever μ(E)<δ\mu (E)<\delta we have ∫E∣fn∣p<ε\int_{E} \left|f_{n}\right|^{p}<\varepsilon for every n∈Nn \in \mathbb {N}.

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Remark.
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The particular form of the Vitali Convergence Theorem as presented in this text and the previous two exercises [and the outlines of the solution] owe their existence and form to the most excellent presentation of Hewitt and Stromberg, pp. 203-205.