Section 8.5

Containment Relations for Lp\boldsymbol{L}^{\boldsymbol{p}} Spaces

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Problem 8.5.1

Consider the measure space (R,B,λ)(\mathbb {R}, \mathfrak {B}, \lambda ). Let 1⩽p<q<∞1 \leqslant p<q< \infty, and let rr be such that 1/q<r<1/p1 / q<r<1 / p.

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(a)

Define ff on R\mathbb {R} by writing f(x)=x−r  1(0,1)(x)f(x)=x^{-r} \; \mathbb {1}_{(0,1)}(x) for each x∈Rx \in \mathbb {R}. Then f∈Lpf \in L^{p} but f∉Lqf \notin L^{q}. Therefore, we do not in general have Lp⊆LqL^{p} \subseteq L^{q} when p<qp<q.

(b)

Let g(x)=x−r  1(1,∞)(x)g(x)=x^{-r} \; \mathbb {1}_{(1, \infty )}(x) for every x∈Rx \in \mathbb {R}. Then g∈Lqg \in L^{q} but g∉Lpg \notin L^{p}. Therefore, we do not in general have Lq⊆LpL^{q} \subseteq L^{p} when p<qp<q.

Problem 8.5.2

Let 0<p<r<∞0<p<r<\infty. Then Lp∩L∞⊆LrL^{p} \cap L^{\infty } \subseteq L^{r}, and for any f∈Lp∩L∞f \in L^{p} \cap L^{\infty } we have ∥f∥r⩽∥f∥pp/r∥f∥∞1−p/r\left\| f\right\|_{r} \leqslant \left\| f\right\|_{p}^{p / r}\left\| f\right\|_{\infty }^{1-p / r}.

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Problem 8.5.3

For any 0<p<∞0<p<\infty and 0<M<∞0<M<\infty we have

(∫∣f∣p)1/p⩾Mμ({ω∈Ω:∣f(ω)∣⩾M})1/p. \left(\int \left|f\right|^{p}\right)^{1 / p} \geqslant M \mu (\left\{ \omega \in \Omega :\left|f(\omega )\right| \geqslant M\right\} )^{1 / p} .
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Problem 8.5.4

Let 0<r<∞0<r<\infty and assume that f∈Lr∩L∞f \in L^{r} \cap L^{\infty }, so that f∈Lpf \in L^{p} for every r<p<∞r<p<\infty by Exercise 8.5.2. We wish to show that lim⁡p→∞∥f∥p=∥f∥∞\lim_{p \rightarrow \infty }\left\| f\right\|_{p}=\left\| f\right\|_{\infty }. Follow this outline:

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(a)

Ignoring the trivial case where f=0μf=0 \mu-a.e. on Ω\Omega, let f≠0f \neq 0 on a set of positive measure, so that ∥f∥∞>0\left\| f\right\|_{\infty }>0. Show that lim inf⁡p→∞∥f∥p⩾∥f∥∞\liminf_{p \rightarrow \infty }\left\| f\right\|_{p} \geqslant \left\| f\right\|_{\infty }.

(b)

Show that lim sup⁡p→∞∥f∥p⩽∥f∥∞\limsup_{p \rightarrow \infty }\left\| f\right\|_{p} \leqslant \left\| f\right\|_{\infty }.

(c)

Put (a) and (b) together to prove the claim.

Problem 8.5.5

Let μ(Ω)=1\mu (\Omega )=1 and 1⩽p⩽q⩽∞1 \leqslant p \leqslant q \leqslant \infty. Show for arbitrary ff that

∫∣f∣⩽(∫∣f∣p)1/p=(∫∣f∣q)1/q⩽ess⁡sup⁡f \int \left|f\right| \leqslant \left(\int \left|f\right|^{p}\right)^{1 / p}=\left(\int \left|f\right|^{q}\right)^{1 / q} \leqslant \operatorname {ess} \sup f

so that ∥f∥1⩽∥f∥p⩽∥f∥q⩽∥f∥∞\left\| f\right\|_{1} \leqslant \left\| f\right\|_{p} \leqslant \left\| f\right\|_{q} \leqslant \left\| f\right\|_{\infty }.

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Problem 8.5.6

We know that lp⊆lq⊆l∞l^{p} \subseteq l^{q} \subseteq l^{\infty } when 0<p<q<+∞0<p<q<+\infty by Claim 5. Show further that

ess⁡sup⁡f⩽(∑ω∈Ω∣f(ω)∣q)1/q⩽(∑ω∈Ω∣f(ω)∣p)1/p \operatorname {ess} \sup f \leqslant \left(\sum _{\omega \in \Omega }\left|f(\omega )\right|^{q}\right)^{1 / q} \leqslant \left(\sum _{\omega \in \Omega }\left|f(\omega )\right|^{p}\right)^{1 / p}

for arbitrary f∈lpf \in l^{p}, so that ∥f∥∞⩽∥f∥q⩽∥f∥p\left\| f\right\|_{\infty } \leqslant \left\| f\right\|_{q} \leqslant \left\| f\right\|_{p} for every f∈lpf \in l^{p}.

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Remark.
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Claim 5: For every 0<p<q<+∞0<p<q<+\infty we have lp⊆lq⊆l∞l^{p} \subseteq l^{q} \subseteq l^{\infty }.

Problem 8.5.7

Consider (R,B,λ)\left(\mathbb {R}, \mathfrak {B}, \lambda \right).

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(a)

Find ff such that f∈Lpf \in L^{p} but f∉Lqf \notin L^{q} for every p<q<+∞p<q<+\infty.

(b)

Find ff such that f∈Lqf \in L^{q} for every 0<q<p0<q<p, but f∉Lpf \notin L^{p}.

(c)

Find a nonnegative finite-valued function ff with f∉Lpf \notin L^{p} for every 0<p<+∞0<p<+\infty.

(d)

Find ff such that f∈Lpf \in L^{p} but f∉Lqf \notin L^{q} for every q∈(0,∞)−{p}q \in (0, \infty )-\left\{ p\right\}.

Problem 8.5.8

Let (Ω,F,μ)(\Omega , \mathcal{F}, \mu ) be such that μ(A)>0\mu (A)>0 forces μ(A)⩾1\mu (A) \geqslant 1 for each A∈FA \in \mathcal{F}. Let 1⩽p⩽q<+∞1 \leqslant p \leqslant q<+\infty. Then Lp⊆Lq⊆L∞L^{p} \subseteq L^{q} \subseteq L^{\infty } and ∥f∥∞⩽∥f∥q⩽∥f∥p\left\| f\right\|_{\infty } \leqslant \left\| f\right\|_{q} \leqslant \left\| f\right\|_{p}.

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