Section 5.2

Combining Measurable Functions

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Problem 5.2.1

If f:Ω→R‾f: \Omega \rightarrow \overline{\mathbb {R}} is F/B∗\mathcal{F} / \mathcal{B}^{*}-measurable, then ∣f∣\left|f\right| is F/B∗\mathcal{F} / \mathcal{B}^{*} measurable. However, if ∣f∣\left|f\right| is F/B∗\mathcal{F} / \mathscr {B}^{*}-measurable, then ff is not necessarily F/B∗\mathcal{F} / \mathfrak {B}^{*}-measurable.

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Problem 5.2.2

Let n∈Nn \in \mathbb {N}, and let f1,…,fnf_{1}, \ldots , f_{n} denote F/B∗\mathcal{F} / \mathcal{B}^{*}-measurable functions with common domain A∈FA \in \mathscr {F}.

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(a)

Both max⁡{f1,f2}\max \left\{ f_{1}, f_{2}\right\} and min⁡{f1,f2}\min \left\{ f_{1}, f_{2}\right\} are F/B∗\mathcal{F} / \mathscr {B}^{*}-measurable functions.

(b)

Both max⁡{f1,…,fn}\max \left\{ f_{1}, \ldots , f_{n}\right\} and min⁡{f1,…,fn}\min \left\{ f_{1}, \ldots , f_{n}\right\} are F/B∗\mathcal{F} / \mathscr {B}^{*}-measurable functions.

Problem 5.2.3

Let ( Ω,F,μ\Omega , \mathcal{F}, \mu ) denote a measure space, and let f:Ω→R‾f: \Omega \rightarrow \overline{\mathbb {R}} denote a F/B∗\mathcal{F} / \mathfrak {B}^{*}-measurable mapping. Let ν:B∗→R‾\nu : \mathfrak {B}^{*} \rightarrow \overline{\mathbb {R}} be such that ν(B)=μ(f−1(B))\nu (B)= \mu \left(f^{-1}(B)\right) for every B∈B∗B \in \mathscr {B}^{*}. That is, ν=μ∘f−1\nu =\mu \circ f^{-1}. Then ( R‾,B∗,ν\overline{\mathbb {R}}, \mathscr {B}^{*}, \nu ) is a measure space. Furthermore, even if μ\mu is σ\sigma-finite, ν\nu is not necessarily σ\sigma-finite.

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Problem 5.2.4

This exercise concerns itself with (MF9).

(MF9): Let y∈R‾y \in \overline{\mathbb {R}}, let A∈FA \in \mathcal{F} be nonempty, and let f:A→R‾f: A \rightarrow \overline{\mathbb {R}} and g:A→R‾g: A \rightarrow \overline{\mathbb {R}} be F/B∗\mathcal{F} / \mathfrak {B}^{*}-measurable. (a) Let h:A→R‾h: A \rightarrow \overline{\mathbb {R}} be such that, for every ω∈A\omega \in A, h(ω)=f(ω)+g(ω)h(\omega ) = f(\omega )+g(\omega ) if f(ω)+g(ω)f(\omega )+g(\omega ) is defined and h(ω)=yh(\omega ) = y if f(ω)+g(ω)f(\omega )+g(\omega ) is undefined. Then hh is F/B∗\mathcal{F} / \mathfrak {B}^{*}-measurable. (b) Let h:A→R‾h: A \rightarrow \overline{\mathbb {R}} be such that, for every ω∈A\omega \in A, h(ω)=f(ω)−g(ω)h(\omega ) = f(\omega )-g(\omega ) if f(ω)−g(ω)f(\omega )-g(\omega ) is defined and h(ω)=yh(\omega ) = y if f(ω)−g(ω)f(\omega )-g(\omega ) is undefined. Then hh is F/B∗\mathcal{F} / \mathfrak {B}^{*}-measurable.

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(a)

Prove part (b) of (MF9) by suitably adapting the proof of (a).

(b)

Prove part (b) of (MF9) by using (a) of (MF9) and (MF7).

(c)

Show that {ω∈A:f(ω)+g(ω)<x}=⋃r1,r2∈Q;r1+r2<x{ω∈A:f(ω)<r1}∩{ω∈A:g(ω)<r2}\left\{ \omega \in A: f(\omega )+g(\omega )<x\right\} =\bigcup_{r_{1}, r_{2} \in \mathbb {Q} ; r_{1}+r_{2}<x}\left\{ \omega \in A: f(\omega )<r_{1}\right\} \cap \left\{ \omega \in A: g(\omega )<r_{2}\right\}.

(d)

Repeat part (c) for f−gf-g by proving an analogous identity.

(e)

Let y∈R‾,n⩾2y \in \overline{\mathbb {R}}, n \geqslant 2, and for i=1,…,ni=1, \ldots , n, let fi:A→R‾f_{i}: A \rightarrow \overline{\mathbb {R}} denote a F/B∗\mathcal{F} / \mathcal{B}^{*} measurable function. Let h:A→R‾h: A \rightarrow \overline{\mathbb {R}} be defined for all ω∈A\omega \in A by the rule

h(ω)={f1(ω)+⋯+fn(ω) if f1(ω)+⋯+fn(ω) is defined y if f1(ω)+⋯+fn(ω) is undefined.  h(\omega )= \begin{cases} f_{1}(\omega )+\cdots +f_{n}(\omega ) & \text{ if } f_{1}(\omega )+\cdots +f_{n}(\omega ) \text{ is defined } \\ y & \text{ if } f_{1}(\omega )+\cdots +f_{n}(\omega ) \text{ is undefined. }\end{cases}

Show that hh is F/B∗\mathcal{F} / \mathscr {B}^{*}-measurable.

Problem 5.2.5

This exercise concerns itself with (MF10).

(MF10): Let A∈F−{∅}A \in \mathcal{F} - \left\{ \varnothing \right\}, and let f:A→R‾f: A \rightarrow \overline{\mathbb {R}} and g:A→R‾g: A \rightarrow \overline{\mathbb {R}} denote F/B∗\mathcal{F} / \mathfrak {B}^{*}-measurable functions. The following hold: (a) fgfg is F/B∗\mathcal{F} / \mathfrak {B}^{*}-measurable. (b) Let y∈R‾y \in \overline{\mathbb {R}} and h:A→R‾h: A \rightarrow \overline{\mathbb {R}} be such that, for each ω∈A\omega \in A, h(ω)=f(ω)/g(ω)h(\omega ) = f(\omega )/g(\omega ) if ω∈A\omega \in A is such that f(ω)/g(ω)f(\omega )/g(\omega ) is defined, and h(ω)=yh(\omega ) = y otherwise. Then hh is F/B∗\mathcal{F} / \mathfrak {B}^{*}-measurable.

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(a)

Directly prove (a) of (MF10) assuming that ff and gg are real valued instead of extended real valued.

(b)

Prove (b) of (MF10) assuming that ff and gg are real valued and that gg is nonzero on AA.

(c)

Using the previous part, now prove (b) of (MF10) in full generality.