Section 3.8

Approximations

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Problem 3.8.1

The assumption v(B)=+∞v(B)=+\infty is not superfluous in Claim 4, and the assumption v(A)<+∞v(A)<+\infty is not superfluous in Claim 6.

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Problem 3.8.2

Let v:Bk→R‾v: \mathscr {B}^{k} \rightarrow \overline{\mathbb {R}} be nonnegative and finitely additive with v(Rk)<+∞v\left(\mathbb {R}^{k}\right)<+\infty. Suppose that v(A)=\sup \left\{ v(K): K \subseteq A, K compact for each A∈BkA \in \mathscr {B}^{k}. Then vv is a finite measure.

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Problem 3.8.3

Let v:Bk→R‾v: \mathcal{B}^{k} \rightarrow \overline{\mathbb {R}} be a measure such that v(B)<+∞v(B)<+\infty for every bounded B∈BkB \in \mathcal{B}^{k}. Let A⊆RkA \subseteq \mathbb {R}^{k}, where AA is not necessarily in Bk\mathcal{B}^{k}. There exist sets FF and GG such that F⊆A⊆GF \subseteq A \subseteq G, FF is a countable union of closed sets, and GG is a countable intersection of open sets, and v(G−F)=0v(G-F)=0.

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Problem 3.8.4

Suppose that v:Bk→Rkv: \mathcal{B}^{k} \rightarrow \mathbb {R}^{k} is a finite measure such that if A∈BkA \in \mathcal{B}^{k} and v(A)>0v(A)>0, then there exists B∈BkB \in \mathcal{B}^{k} with B⊆AB \subseteq A and 0<v(B)<v(A)0<v(B)<v(A). Then there exists an uncountable compact set KK such that K⊆AK \subseteq A and v(K)=0v(K)=0.

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Problem 3.8.5

Let A\mathcal{A} denote a field on Ω\Omega, and let μ\mu and vv denote measures with domain σ(A)\sigma (\mathcal{A}) that are σ\sigma-finite on A\mathcal{A}. Let E∈σ(A)E \in \sigma (\mathcal{A}) be such that μ(E),v(E)<+∞\mu (E), v(E)<+\infty, and let ε>0\varepsilon >0 be given. Then there exists E0∈AE_{0} \in \mathcal{A} such that μ(E△E0),v(E△E0)<ε\mu \left(E \triangle E_{0}\right), v\left(E \triangle E_{0}\right)<\varepsilon.

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