Chapter 8

Decomposition of Matrices

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Problem 8.1.1

Find the LULU-decomposition of the 3×33 \times 3 matrix

A=(36−925−3−4110). A = \begin{pmatrix} 3 & 6 & -9 \\ 2 & 5 & -3 \\ -4 & 1 & 10 \end{pmatrix} .

The triangular matrices LL and UU are not uniquely determined by the matrix equation A=LUA = LU. These two matrices together contain n2+nn^{2}+n unknown elements. Thus when comparing elements on the left- and right-hand side of A=LUA = LU we have n2n^{2} equations and n2+nn^{2}+n unknowns. We require a further nn conditions to uniquely determine the matrices. There are three additional sets of nn conditions that are commonly used. These are Doolittle’s method with ℓjj=1\ell_{jj} = 1, j=1,…,nj = 1, \ldots , n; Choleski’s method with ℓjj=ujj\ell_{jj} = u_{jj}, j=1,…,nj = 1, \ldots , n; Crout’s method with ujj=1u_{jj} = 1, j=1,…,nj = 1, \ldots , n. Apply Crout's method.

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Problem 8.1.2

Let AA be an n×nn \times n matrix over R\mathbb {R}. Consider the LULU-decomposition A=LUA = LU, where LL is a unit lower triangular matrix and UU is an upper triangular matrix. The LDULDU-decomposition is defined as A=LDUA = LDU, where LL is unit lower triangular, DD is diagonal and UU is unit upper triangular. Let

A=(24−249−3−2−37). A = \begin{pmatrix} 2 & 4 & -2 \\ 4 & 9 & -3 \\ -2 & -3 & 7 \end{pmatrix} .

Find the LDULDU-decomposition via the LULU-decomposition.

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Problem 8.1.3

Find the QRQR-decomposition of the 3×33 \times 3 matrix

A=(213−1070−1−1). A = \begin{pmatrix} 2 & 1 & 3 \\ -1 & 0 & 7 \\ 0 & -1 & -1 \end{pmatrix} .
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Problem 8.1.4

We consider 3×33 \times 3 matrices over R\mathbb {R}. An orthogonal matrix QQ such that det⁡(Q)=1\operatorname {det}\left(Q\right) = 1 is called a rotation matrix. Let 1≤p<r≤31 \leq p < r \leq 3 and ϕ\phi be a real number. An orthogonal 3×33 \times 3 matrix Qpr(ϕ)=(qij)1≤i,j≤3Q_{pr}(\phi ) = (q_{ij})_{1 \leq i, j \leq 3} given by

qpp=qrr=cos⁡(ϕ)qii=1if i≠p,rqpr=−qrp=−sin⁡(ϕ)qip=qpi=qir=qri=0i≠p,rqij=0if i≠p,r and j≠p,r \begin{aligned} q_{pp} = q_{rr} & = \cos (\phi ) \\ q_{ii} & = 1 \quad \text{if } i \neq p, r \\ q_{pr} = -q_{rp} & = -\sin (\phi ) \\ q_{ip} = q_{pi} = q_{ir} = q_{ri} & = 0 \quad i \neq p, r \\ q_{ij} & = 0 \quad \text{if } i \neq p, r \text{ and } j \neq p, r \end{aligned}

will be called a plane rotation through ϕ\phi in the plane span (ep,er)(e_{p}, e_{r}). Let Q=(qij)1≤i,j≤3Q = (q_{ij})_{1 \leq i, j \leq 3} be a rotation matrix. Show that there exist angles ϕ∈[0,π)\phi \in [0, \pi ), θ,ψ∈(−π,π]\theta , \psi \in (-\pi , \pi ] called the Euler angles of QQ such that

Q=Q12(ϕ)Q23(θ)Q12(ψ).(1) Q = Q_{12}(\phi ) Q_{23}(\theta ) Q_{12}(\psi ) . \tag {1}
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Problem 8.1.5

Consider a square non-singular square matrix AA over C\mathbb {C}, i.e. A−1A^{-1} exists. The polar decomposition theorem states that AA can be written as A=UHA = UH, where UU is a unitary matrix and HH is a hermitian positive definite matrix. Show that AA has a unique polar decomposition.

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Problem 8.1.6

For any n×nn \times n matrix AA over C\mathbb {C}, there exists a positive semi-definite matrix HH and a unitary matrix such that A=HUA = HU. If AA is nonsingular, then HH is positive definite and UU and HH are unique.

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(i)

Find the polar decomposition for the invertible 3×33 \times 3 matrix

A=(10−4054−443). A = \begin{pmatrix} 1 & 0 & -4 \\ 0 & 5 & 4 \\ -4 & 4 & 3 \end{pmatrix} .

The positive definite matrix HH is the unique square root of the positive definite matrix A∗AA^{*}A and then UU is defined by U=AH−1U = AH^{-1}.

(ii)

Apply the polar decomposition to the nonnormal matrix AA

A=(1101)⇒A∗=(1011) A = \begin{pmatrix} 1 & 1 \\ 0 & 1 \end{pmatrix} \quad \Rightarrow \quad A^{*} = \begin{pmatrix} 1 & 0 \\ 1 & 1 \end{pmatrix}

which is an element of the Lie group SL(2,R)SL(2, \mathbb {R}).

Problem 8.1.7

Let AA be an arbitrary m×nm \times n matrix over R\mathbb {R}, i.e. A∈Rm×nA \in \mathbb {R}^{m \times n}. Then AA can be written as

A=UΣVT A = U \Sigma V^{T}

where UU is an m×mm \times m orthogonal matrix, VV is an n×nn \times n orthogonal matrix, Σ\Sigma is an m×nm \times n diagonal matrix with nonnegative entries and the superscript TT denotes the transpose. This is called the singular value decomposition. An algorithm to find the singular value decomposition is as follows.

  1. Find the eigenvalues λj\lambda_{j} (j=1,…,nj = 1, \ldots , n) of the n×nn \times n matrix ATAA^{T}A. Arrange the eigenvalues λ1,…,λn\lambda_{1}, \ldots , \lambda_{n} in descending order.

  2. Find the number of nonzero eigenvalues of the matrix ATAA^{T}A. We call this number rr.

  3. Find the orthogonal eigenvectors v→j\overrightarrow {v}_{j} of the matrix ATAA^{T}A corresponding to the obtained eigenvalues, and arrange them in the same order to form the column-vectors of the n×nn \times n matrix VV.

  4. Form an m×nm \times n diagonal matrix Σ\Sigma placing on the leading diagonal of it the square root σj:=λj\sigma_{j} := \sqrt{\lambda_{j}} of p=min⁡(m,n)p = \min (m, n) first eigenvalues of the matrix ATAA^{T}A found in 1) in descending order.

  5. Find the first rr column vectors of the m×mm \times m matrix UU

u→j=1σjAv→j,j=1,2,…,r. \overrightarrow {u}_{j} = \frac{1}{\sigma _{j}} A \overrightarrow {v}_{j}, \quad j = 1, 2, \ldots , r .
  1. Add to the matrix UU the rest of the m−rm-r vectors using the Gram-Schmidt orthogonalization process.

We have Av→j=σju→jA \overrightarrow {v}_{j} = \sigma_{j} \overrightarrow {u}_{j}, ATu→j=σjv→jA^{T} \overrightarrow {u}_{j} = \sigma_{j} \overrightarrow {v}_{j} and therefore ATAv→j=σj2v→jA^{T}A \overrightarrow {v}_{j} = \sigma_{j}^{2} \overrightarrow {v}_{j}, AATu→j=σj2u→jAA^{T} \overrightarrow {u}_{j} = \sigma_{j}^{2} \overrightarrow {u}_{j}. Apply the algorithm to the matrix

A=(0.961.722.280.96). A = \begin{pmatrix} 0.96 & 1.72 \\ 2.28 & 0.96 \end{pmatrix} .
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Problem 8.1.8

Find the singular value decomposition A=UΣVTA = U \Sigma V^{T} of the matrix (row vector) A=(2 1 −2)A = (2 \ 1 \ -2).

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Problem 8.1.9
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(i)

Let n≥2n \geq 2 and n=2kn = 2k. Let AA be an n×kn \times k matrix and A∗A=IkA^{*}A = I_{k}. Find the n×nn \times n matrix AA∗AA^{*} using the singular value decomposition. Calculate tr⁡(AA∗)\operatorname {tr}(AA^{*}).

(ii)

Let n≥2n \geq 2 and n=2kn = 2k. Let AA be an n×kn \times k matrix and A∗A=IkA^{*}A = I_{k}. Let SS be a positive definite n×nn \times n matrix. Show that

1≤tr⁡(A∗S2A)tr⁡((A∗SA)2). 1 \leq \frac{\operatorname {tr}(A^{*}S^{2}A)}{\operatorname {tr}((A^{*}SA)^{2})} .
Problem 8.1.10

Let AA be an n×nn \times n matrix over R\mathbb {R}. Assume that A−1A^{-1} exists. Given the singular value decomposition of AA, i.e. A=UWVTA = UWV^{T}. Find the singular value decomposition for A−1A^{-1}.

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Problem 8.1.11

Find the Moore-Penrose pseudo inverses of

(1001−10),(10),(1 1) \begin{pmatrix} 1 & 0 \\ 0 & 1 \\ -1 & 0 \end{pmatrix} , \qquad \begin{pmatrix} 1 \\ 0 \end{pmatrix} , \qquad (1 \ 1)

applying the singular value decomposition.

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Problem 8.1.12

Any unitary 2n×2n2^{n} \times 2^{n} matrix UU can be decomposed as

U=(U100U2)(CS−SC)(U300U4) U = \begin{pmatrix} U_{1} & 0 \\ 0 & U_{2} \end{pmatrix} \begin{pmatrix} C & S \\ -S & C \end{pmatrix} \begin{pmatrix} U_{3} & 0 \\ 0 & U_{4} \end{pmatrix}

where U1,U2,U3,U4U_{1}, U_{2}, U_{3}, U_{4} are 2n−1×2n−12^{n-1} \times 2^{n-1} unitary matrices and CC and SS are the 2n−1×2n−12^{n-1} \times 2^{n-1} diagonal matrices

C=diag⁡(cos⁡(α1),cos⁡(α2),…,cos⁡(α2n/2)),S=diag⁡(sin⁡(α1),sin⁡(α2),…,sin⁡(α2n/2)) \begin{aligned} C & = \operatorname {diag}(\cos (\alpha _{1}), \cos (\alpha _{2}), \ldots , \cos (\alpha _{2^{n}/2})) , \\ S & = \operatorname {diag}(\sin (\alpha _{1}), \sin (\alpha _{2}), \ldots , \sin (\alpha _{2^{n}/2})) \end{aligned}

where αj∈R\alpha_{j} \in \mathbb {R}. This decomposition is called cosine-sine decomposition.

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(i)

Consider the unitary 2×22 \times 2 matrix

U=(0i−i0). U = \begin{pmatrix} 0 & i \\ -i & 0 \end{pmatrix} .

Show that UU can be written as

U=(u100u2)(cos⁡(α)sin⁡(α)−sin⁡(α)cos⁡(α))(u300u4) U = \begin{pmatrix} u_{1} & 0 \\ 0 & u_{2} \end{pmatrix} \begin{pmatrix} \cos (\alpha ) & \sin (\alpha ) \\ -\sin (\alpha ) & \cos (\alpha ) \end{pmatrix} \begin{pmatrix} u_{3} & 0 \\ 0 & u_{4} \end{pmatrix}

where α∈R\alpha \in \mathbb {R} and u1,u2,u3,u4∈U(1)u_{1}, u_{2}, u_{3}, u_{4} \in U(1) (i.e. u1,u2,u3,u4u_{1}, u_{2}, u_{3}, u_{4} are complex numbers with length 1). Find α\alpha, u1u_{1}, u2u_{2}, u3u_{3}, u4u_{4}.

(ii)

Find the cosine-sine decomposition of the unitary matrix

U=12(111−1). U = \frac{1}{\sqrt{2}} \begin{pmatrix} 1 & 1 \\ 1 & -1 \end{pmatrix} .
Problem 8.1.13

Find the cosine-sine decomposition of the 4×44 \times 4 unitary matrix (Bell matrix)

12(1001011001−10100−1). \frac{1}{\sqrt{2}} \begin{pmatrix} 1 & 0 & 0 & 1 \\ 0 & 1 & 1 & 0 \\ 0 & 1 & -1 & 0 \\ 1 & 0 & 0 & -1 \end{pmatrix} .
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Problem 8.1.14

Let AA be an n×nn \times n matrix over C\mathbb {C}. Then there exists an n×nn \times n unitary matrix (U∗=U−1)(U^{*} = U^{-1}) such that

U∗AU=T(1) U^{*}AU = T \tag {1}

where TT is an n×nn \times n matrix in upper triangular form. Equation (1) is called a Schur decomposition. The diagonal elements of TT are the eigenvalues of AA. Note that such a decomposition is not unique. An iterative algorithm to find a Schur decomposition for an n×nn \times n matrix is as follows.

It generates at each step matrices UkU_{k} and TkT_{k} (k=1,…,n−1k = 1, \ldots , n-1) with the properties: each UkU_{k} is unitary, and each TkT_{k} has only zeros below its main diagonal in its first kk columns. Tn−1T_{n-1} is in upper triangular form, and U=U1U2⋯Un−1U = U_{1}U_{2} \cdots U_{n-1} is the unitary matrix that transforms AA into Tn−1T_{n-1}. We set T0=AT_{0} = A. The kk-th step in the iteration is as follows.

Step 1. Denote as AkA_{k} the (n−k+1)×(n−k+1)(n-k+1) \times (n-k+1) submatrix in the lower right portion of Tk−1T_{k-1}.

Step 2. Determine an eigenvalue and the corresponding normalized eigenvector for AkA_{k}.

Step 3. Construct a unitary matrix NkN_{k} which has as its first column the normalized eigenvector found in step 2.

Step 4. For k=1k = 1, set U1=N1U_{1} = N_{1}, for k>1k > 1, set

Uk=(Ik−100Nk) U_{k} = \begin{pmatrix} I_{k-1} & 0 \\ 0 & N_{k} \end{pmatrix}

where Ik−1I_{k-1} is the (k−1)×(k−1)(k-1) \times (k-1) identity matrix.

Step 5. Calculate Tk=Uk∗Tk−1UkT_{k} = U_{k}^{*}T_{k-1}U_{k}.

Apply the algorithm to the 3×33 \times 3 symmetric matrix

A=(101010101). A = \begin{pmatrix} 1 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \end{pmatrix} .
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Problem 8.1.15

Let AA be an n×nn \times n matrix over C\mathbb {C}. Then there exists an n×nn \times n unitary matrix QQ, such that

Q∗AQ=D+N Q^{*}AQ = D + N

where D=diag⁡(λ1,λ2,…,λn)D = \operatorname {diag}(\lambda_{1}, \lambda_{2}, \ldots , \lambda_{n}) is the diagonal matrix composed of the eigenvalues of AA and NN is a strictly upper triangular matrix (i.e. NN has zero entries on the diagonal). The matrix QQ is said to provide a Schur decomposition of AA. Let

A=(38−23),Q=15(2i1−1−2i). A = \begin{pmatrix} 3 & 8 \\ -2 & 3 \end{pmatrix} , \qquad Q = \frac{1}{\sqrt{5}} \begin{pmatrix} 2i & 1 \\ -1 & -2i \end{pmatrix} .

Show that QQ provides a Schur decomposition of AA.

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Problem 8.1.16

We say that a matrix is upper triangular if all their entries below the main diagonal are 0, and that it is strictly upper triangular if in addition all the entries on the main diagonal are equal to 1. Any invertible real n×nn \times n matrix AA can be written as the product of three real n×nn \times n matrices

A=ODN A = ODN

where NN is strictly upper triangular, DD is diagonal with positive entries, and OO is orthogonal. This is known as the Iwasawa decomposition of the matrix AA. The decomposition is unique. In other words, that if A=O′D′N′A = O'D'N', where O′O', D′D' and N′N' are orthogonal, diagonal with positive entries and strictly upper triangular, respectively, then O′=OO' = O, D=D′D = D' and N′=NN' = N.

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(i)

Find the Iwasawa decomposition of the matrix

A=(0112). A = \begin{pmatrix} 0 & 1 \\ 1 & 2 \end{pmatrix} .
(ii)

Consider the 2×22 \times 2 matrix

M=(abcd) M = \begin{pmatrix} a & b \\ c & d \end{pmatrix}

where a,b,c,d∈Ca, b, c, d \in \mathbb {C} and ad−bc=1ad-bc = 1. Thus MM is an element of the Lie group SL(2,C)SL(2, \mathbb {C}). The Iwasawa decomposition is given by

(abcd)=(αβ−β‾α‾)(δ−1/200δ1/2)(1η01) \begin{pmatrix} a & b \\ c & d \end{pmatrix} = \begin{pmatrix} \alpha & \beta \\ -\overline{\beta } & \overline{\alpha } \end{pmatrix} \begin{pmatrix} \delta ^{-1/2} & 0 \\ 0 & \delta ^{1/2} \end{pmatrix} \begin{pmatrix} 1 & \eta \\ 0 & 1 \end{pmatrix}

where α,β,η∈C\alpha , \beta , \eta \in \mathbb {C} and δ∈R+\delta \in \mathbb {R}^{+}. Find α,β,δ\alpha , \beta , \delta and η\eta.

Problem 8.1.17

Let AA be a unitary n×nn \times n matrix. Let PP be an invertible n×nn \times n matrix. Let B:=APB := AP. Show that PB−1PB^{-1} is unitary.

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Problem 8.1.18

Show that every 2×22 \times 2 matrix AA of determinant 1 is the product of three elementary matrices. This means that matrix AA can be written as

(a11a12a21a22)=(1x01)(10y1)(1z01).(1) \begin{pmatrix} a_{11} & a_{12} \\ a_{21} & a_{22} \end{pmatrix} = \begin{pmatrix} 1 & x \\ 0 & 1 \end{pmatrix} \begin{pmatrix} 1 & 0 \\ y & 1 \end{pmatrix} \begin{pmatrix} 1 & z \\ 0 & 1 \end{pmatrix} . \tag {1}
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Problem 8.1.19

Almost any 2×22 \times 2 matrix AA can be factored (Gaussian decomposition) as

(a11a12a21a22)=(1α01)(λ00μ)(10β1). \begin{pmatrix} a_{11} & a_{12} \\ a_{21} & a_{22} \end{pmatrix} = \begin{pmatrix} 1 & \alpha \\ 0 & 1 \end{pmatrix} \begin{pmatrix} \lambda & 0 \\ 0 & \mu \end{pmatrix} \begin{pmatrix} 1 & 0 \\ \beta & 1 \end{pmatrix} .

Find the decomposition of the matrix

A=(1111). A = \begin{pmatrix} 1 & 1 \\ 1 & 1 \end{pmatrix} .
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Problem 8.1.20

Consider the symmetric 3×33 \times 3 matrix AA over R\mathbb {R} and the orthogonal matrix OO, respectively

A=(2−10−12−10−12),O=(cos⁡(ϕ)−sin⁡(ϕ)0sin⁡(ϕ)cos⁡(ϕ)0001). A = \begin{pmatrix} 2 & -1 & 0 \\ -1 & 2 & -1 \\ 0 & -1 & 2 \end{pmatrix} , \qquad O = \begin{pmatrix} \cos (\phi ) & -\sin (\phi ) & 0 \\ \sin (\phi ) & \cos (\phi ) & 0 \\ 0 & 0 & 1 \end{pmatrix} .

Calculate A~=O−1AO\widetilde{A} = O^{-1}AO. Can we find an angle ϕ\phi such that a~12=a~21=0\widetilde{a}_{12} = \widetilde{a}_{21} = 0?

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Problem 8.1.21

Let AA be an m×mm \times m matrix. Let BB be an n×nn \times n matrix. Let XX be an m×nm \times n matrix such that

AX=XB.(1) AX = XB . \tag {1}

We can find non-singular matrices VV and WW such that V−1AV=JAV^{-1}AV = J_{A}, W−1BW=JBW^{-1}BW = J_{B}, where JAJ_{A}, JBJ_{B} are the Jordan canonical form of AA and BB, respectively. Show that from (1) it follows that JAY=YJBJ_{A}Y = YJ_{B}, where Y:=V−1XWY := V^{-1}XW.

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Problem 8.1.22
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(i)

Let AA be a square nonsingular matrix of order nAn_{A} with LULU factorization A=PATLAUAA = P_{A}^{T}L_{A}U_{A} and BB be a square nonsingular matrix of order nBn_{B} with LULU factorization B=PBTLBUBB = P_{B}^{T}L_{B}U_{B}. Find the LULU factorization for A⊗BA \otimes B.

(ii)

Let AA be a positive definite matrix of order nAn_{A} with Cholesky factor GAG_{A} and BB be a positive definite matrix of order nBn_{B} with Cholesky factor GBG_{B}. Find the Cholesky factorization for A⊗BA \otimes B.

(iii)

Let AA be an mA×nAm_{A} \times n_{A} matrix with linear independent columns and QRQR factorization A=QARAA = Q_{A}R_{A}, where QAQ_{A} is an mA×nAm_{A} \times n_{A} matrix with orthonormal columns and RAR_{A} is an nA×nAn_{A} \times n_{A} upper triangular matrix. BB is similar defined with B=QBRBB = Q_{B}R_{B} as its QRQR factorization. Find the QRQR factorization for A⊗BA \otimes B.

(iv)

Let AA be a square matrix of order nAn_{A} with Schur decomposition A=UATAUATA = U_{A}T_{A}U_{A}^{T}, where UAU_{A} is unitary and TAT_{A} is upper triangular. Let BB be a square matrix of order nBn_{B} with Schur decomposition B=UBTBUBTB = U_{B}T_{B}U_{B}^{T}, where UBU_{B} is unitary and TBT_{B} is upper triangular. Find the Schur decomposition for A⊗BA \otimes B.

(v)

Let AA be an mA×nAm_{A} \times n_{A} matrix with singular value decomposition A=UAΣAVATA = U_{A}\Sigma_{A}V_{A}^{T} and BB be an mB×nBm_{B} \times n_{B} matrix with singular value decomposition B=UBΣBVBTB = U_{B}\Sigma_{B}V_{B}^{T}. Find the singular value decomposition for A⊗BA \otimes B.

Problem 8.1.23

Write the matrix

H=(11111−i−1i1−11−11i−1−i) H = \begin{pmatrix} 1 & 1 & 1 & 1 \\ 1 & -i & -1 & i \\ 1 & -1 & 1 & -1 \\ 1 & i & -1 & -i \end{pmatrix}

as the product of two 4×44 \times 4 matrices AA and BB such that each of these matrices has precisely two non-zero entries in each row.

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Problem 8.1.24

An n×nn \times n matrix AA is persymmetric if JnAJn=ATJ_{n}AJ_{n} = A^{T} and skew persymmetric if JnAJn=ATJ_{n}AJ_{n} = A^{T}, where JnJ_{n} is the n×nn \times n exchange matrix, i.e. the matrix with 1's on the counter diagonal and 0's otherwise. Hence Jn2=InJ_{n}^{2} = I_{n}. Let BB be an n×nn \times n symmetric matrix.

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(i)

Show that B+JnBJnB + J_{n}BJ_{n} is persymmetric.

(ii)

Show that B−JnBJnB - J_{n}BJ_{n} is skew persymmetric.

(iii)

Show that BB can be written as a sum of a persymmetric matrix and a skew persymmetric matrix.

Problem 8.1.25

Decompose the 3×33 \times 3 matrix

(10100010−1) \begin{pmatrix} 1 & 0 & 1 \\ 0 & 0 & 0 \\ 1 & 0 & -1 \end{pmatrix}

as the sum of a persymmetric and a skew persymmetric matrix.

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Problem 8.2.1

If A∈Rn×nA \in \mathbb {R}^{n \times n}, then there exists an orthogonal Q∈Rn×nQ \in \mathbb {R}^{n \times n} such that

QTAQ=(R11R12R1m0R22R2m⋮⋮⋮00…Rmn) Q^{T}AQ = \begin{pmatrix} R_{11} & R_{12} & & R_{1m} \\ 0 & R_{22} & & R_{2m} \\ \vdots & \vdots & & \vdots \\ 0 & 0 & \ldots & R_{mn} \end{pmatrix}

where each RiiR_{ii} is either a 1×11 \times 1 matrix or a 2×22 \times 2 matrix having complex conjugate eigenvalues. Find QQ for the 3×33 \times 3 matrix

A=(010203040). A = \begin{pmatrix} 0 & 1 & 0 \\ 2 & 0 & 3 \\ 0 & 4 & 0 \end{pmatrix} .

Then calculate QTAQQ^{T}AQ.

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Problem 8.2.2

Find a cosine-sine decomposition of the matrices

12(iii−i),12(iii−i)⊗12(iii−i). \frac{1}{\sqrt{2}} \begin{pmatrix} i & i \\ i & -i \end{pmatrix} , \qquad \frac{1}{\sqrt{2}} \begin{pmatrix} i & i \\ i & -i \end{pmatrix} \otimes \frac{1}{\sqrt{2}} \begin{pmatrix} i & i \\ i & -i \end{pmatrix} .
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Problem 8.2.3
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(i)

Consider the 4×44 \times 4 matrices

Ω=(0100−10100−10100−10),Ω~=(00100001−10000−100). \Omega = \begin{pmatrix} 0 & 1 & 0 & 0 \\ -1 & 0 & 1 & 0 \\ 0 & -1 & 0 & 1 \\ 0 & 0 & -1 & 0 \end{pmatrix} , \qquad \widetilde{\Omega } = \begin{pmatrix} 0 & 0 & 1 & 0 \\ 0 & 0 & 0 & 1 \\ -1 & 0 & 0 & 0 \\ 0 & -1 & 0 & 0 \end{pmatrix} .

Can one find 4×44 \times 4 permutation matrices P,QP, Q such that Ω=PΩ~Q\Omega = P \widetilde{\Omega } Q?

(ii)

Consider the 2n×2n2n \times 2n matrices

Ω=(010…000−101…000−10…000⋱000−1010000−10),Ω~=(0nIn−In0n). \Omega = \begin{pmatrix} 0 & 1 & 0 & \ldots & 0 & 0 & 0 \\ -1 & 0 & 1 & \ldots & 0 & 0 & \\ 0 & -1 & 0 & \ldots & 0 & 0 & 0 \\ & & & \ddots & & & \\ 0 & 0 & 0 & & -1 & 0 & 1 \\ 0 & 0 & 0 & & 0 & -1 & 0 \end{pmatrix} , \qquad \widetilde{\Omega } = \begin{pmatrix} 0_{n} & I_{n} \\ -I_{n} & 0_{n} \end{pmatrix} .

Can one find 2n×2n2n \times 2n permutation matrices P,QP, Q such that Ω=PΩ~Q\Omega = P \widetilde{\Omega } Q?

Problem 8.2.4
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(i)

Given the 3×23 \times 2 matrix

A=(011110). A = \begin{pmatrix} 0 & 1 \\ 1 & 1 \\ 1 & 0 \end{pmatrix} .

Find the singular value decomposition of AA.

(ii)

Let α∈R\alpha \in \mathbb {R}. Find the singular value decomposition of the 2×32 \times 3 matrix

X(α)=(cos⁡(α)sin⁡(α)00cos⁡(α)sin⁡(α)). X(\alpha ) = \begin{pmatrix} \cos (\alpha ) & \sin (\alpha ) & 0 \\ 0 & \cos (\alpha ) & \sin (\alpha ) \end{pmatrix} .
Problem 8.2.5

The Cholesky decomposition of the a positive semi-definite matrix MM is the decomposition into a product of a lower triangular matrix LL and its conjugate transpose L∗L^{*}, i.e. M=LL∗M = LL^{*}. Find the Cholesky decomposition for the density matrix (pure state)

ρ=13(1−ii)13(1  i  −i)≡13(1i−i−i1−1i−11). \rho = \frac{1}{\sqrt{3}} \begin{pmatrix} 1 \\ -i \\ i \end{pmatrix} \frac{1}{\sqrt{3}} (1 \ \ i \ \ -i) \equiv \frac{1}{3} \begin{pmatrix} 1 & i & -i \\ -i & 1 & -1 \\ i & -1 & 1 \end{pmatrix} .
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Problem 8.2.6

Show that (cosine-sine decomposition)

(0110)=(100i)(01−10)(i001). \begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix} = \begin{pmatrix} 1 & 0 \\ 0 & i \end{pmatrix} \begin{pmatrix} 0 & 1 \\ -1 & 0 \end{pmatrix} \begin{pmatrix} i & 0 \\ 0 & 1 \end{pmatrix} .
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Problem 8.2.7

Let UU be an n×nn \times n unitary matrix. The matrix UU can always be diagonalized by a unitary matrix VV such that

U=V(eiθ10⋮0eiθn)V∗ U = V \begin{pmatrix} e^{i\theta _{1}} & & 0 \\ & \vdots & \\ 0 & & e^{i\theta _{n}} \end{pmatrix} V^{*}

where eiθje^{i\theta_{j}}, θj∈[0,2π)\theta_{j} \in [0, 2\pi ) are the eigenvalues of UU. Let n=2n = 2 and

U=(0110). U = \begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix} .

Thus the eigenvalues of UU are 1 and −1-1. Show that

U=V(100−1)V∗withV=V∗=12(111−1). U = V \begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix} V^{*} \quad \text{with} \quad V = V^{*} = \frac{1}{\sqrt{2}} \begin{pmatrix} 1 & 1 \\ 1 & -1 \end{pmatrix} .
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Problem 8.2.8

If A∈SL(2,R)A \in SL(2, \mathbb {R}), then it can be uniquely be written in the form

(cos⁡(ϕ)sin⁡(ϕ)−sin⁡(ϕ)cos⁡(ϕ))exp⁡(abb−a). \begin{pmatrix} \cos (\phi ) & \sin (\phi ) \\ -\sin (\phi ) & \cos (\phi ) \end{pmatrix} \exp \begin{pmatrix} a & b \\ b & -a \end{pmatrix} .

Find this decomposition for the 2×22 \times 2 nonnormal matrix

A=(1101). A = \begin{pmatrix} 1 & 1 \\ 0 & 1 \end{pmatrix} .
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