Section 24.1

Chapter Problems

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Problem 24.1.1

(i) Consider the 2×22 \times 2 rotation matrix

R(α)=(cos⁡(α)−sin⁡(α)sin⁡(α)cos⁡(α)) R(\alpha ) = \begin{pmatrix} \cos (\alpha ) & -\sin (\alpha ) \\ \sin (\alpha ) & \cos (\alpha ) \end{pmatrix}

with det⁡(R(α))=1\operatorname {det}\left(R(\alpha )\right) = 1. Is the determinant preserved under repeated differentiation of R(α)R(\alpha ) with respect to α\alpha? (ii) Consider the 2×22 \times 2 matrix

S(α)=(cos⁡(α)sin⁡(α)sin⁡(α)−cos⁡(α)) S(\alpha ) = \begin{pmatrix} \cos (\alpha ) & \sin (\alpha ) \\ \sin (\alpha ) & -\cos (\alpha ) \end{pmatrix}

with det⁡(S(α))=−1\operatorname {det}\left(S(\alpha )\right) = -1. Is the determinant preserved under repeated differentiation of S(α)S(\alpha ) with respect to α\alpha?

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Problem 24.1.2

Let fjk:R→Rf_{jk} : \mathbb {R} \rightarrow \mathbb {R} be analytic functions, where j,k=1,2j, k = 1, 2 and F(ϵ)=(fjk(ϵ))F(\epsilon ) = (f_{jk}(\epsilon )). Find the differential equations for F(ϵ)F(\epsilon ) such that

F(ϵ)dF(ϵ)dϵ=dF(ϵ)dϵF(ϵ). F(\epsilon ) \frac{dF(\epsilon )}{d\epsilon } = \frac{dF(\epsilon )}{d\epsilon } F(\epsilon ).
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Problem 24.1.3

Consider the invertible 2×22 \times 2 matrix

A(x)=(cos⁡(x)sin⁡(x)−sin⁡(x)cos⁡(x)). A(x) = \begin{pmatrix} \cos (x) & \sin (x) \\ -\sin (x) & \cos (x) \end{pmatrix}.

Show that d(ln⁡(det⁡(A(x))))=tr⁡(A−1(x)dA(x))d(\ln (\operatorname {det}\left(A(x)\right))) = \operatorname {tr}(A^{-1}(x) dA(x)) where dd denotes the exterior derivative.

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Problem 24.1.4

(i) Consider the analytic function f→:R2→R2\overrightarrow {f} : \mathbb {R}^{2} \rightarrow \mathbb {R}^{2}

f1(x1,x2)=sinh⁡(x2),f2(x1,x2)=sinh⁡(x1). f_{1}(x_{1}, x_{2}) = \sinh (x_{2}), \quad f_{2}(x_{1}, x_{2}) = \sinh (x_{1}).

Show that this function admits the (only) fixed point (0,0)(0,0). Find the functional matrix at the fixed point

(∂f1/∂x1∂f1/∂x2∂f2/∂x1∂f2/∂x2)∣(0,0). \left. \begin{pmatrix} \partial f_{1}/\partial x_{1} & \partial f_{1}/\partial x_{2} \\ \partial f_{2}/\partial x_{1} & \partial f_{2}/\partial x_{2} \end{pmatrix} \right|_{(0,0)}.

(ii) Consider the analytic function g→:R2→R2\overrightarrow {g} : \mathbb {R}^{2} \rightarrow \mathbb {R}^{2}

g1(x1,x2)=sinh⁡(x1),g2(x1,x2)=−sinh⁡(x2). g_{1}(x_{1}, x_{2}) = \sinh (x_{1}), \quad g_{2}(x_{1}, x_{2}) = -\sinh (x_{2}).

Show that this function admits the (only) fixed point (0,0)(0,0). Find the functional matrix at the fixed point

(∂g1/∂x1∂g1/∂x2∂g2/∂x1∂g2/∂x2)∣(0,0). \left. \begin{pmatrix} \partial g_{1}/\partial x_{1} & \partial g_{1}/\partial x_{2} \\ \partial g_{2}/\partial x_{1} & \partial g_{2}/\partial x_{2} \end{pmatrix} \right|_{(0,0)}.

(iii) Multiply the two matrices found in (i) and (ii). (iv) Find the composite function h→:R2→R2\overrightarrow {h} : \mathbb {R}^{2} \rightarrow \mathbb {R}^{2}

h→(x→)=(f→∘g→)(x→)=f→(g→(x→)). \overrightarrow {h}(\overrightarrow {x}) = (\overrightarrow {f} \circ \overrightarrow {g})(\overrightarrow {x}) = \overrightarrow {f}(\overrightarrow {g}(\overrightarrow {x})).

Show that this function also admits the fixed point (0,0)(0,0). Find the functional matrix at this fixed point

(∂h1/∂x1∂h1/∂x2∂h2/∂x1∂h2/∂x2)∣(0,0). \left. \begin{pmatrix} \partial h_{1}/\partial x_{1} & \partial h_{1}/\partial x_{2} \\ \partial h_{2}/\partial x_{1} & \partial h_{2}/\partial x_{2} \end{pmatrix} \right|_{(0,0)}.

Compare this matrix with the matrix found in (iii).

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Problem 24.1.5

Consider the 2×22 \times 2 matrix

V(t)=(cos⁡(ωt)sin⁡(ωt)−sin⁡(ωt)cos⁡(ωt)). V(t) = \begin{pmatrix} \cos (\omega t) & \sin (\omega t) \\ -\sin (\omega t) & \cos (\omega t) \end{pmatrix}.

Calculate dV(t)/dtdV(t)/dt and then find the commutator [dV(t)/dt,V(t)][dV(t)/dt, V(t)]. Discuss.

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Problem 24.1.6

Let AA be an n×nn \times n matrix. Assume that the inverse of AA exists, i.e. det⁡(A)≠0\operatorname {det}\left(A\right) \neq 0. Then the inverse B=A−1B = A^{-1} can be calculated as

∂∂ajkln⁡(det⁡(A))=bkj. \frac{\partial }{\partial a_{jk}} \ln (\operatorname {det}\left(A\right)) = b_{kj}.

Apply this formula to the 2×22 \times 2 matrix AA with det⁡(A)=a11a22−a12a21≠0\operatorname {det}\left(A\right) = a_{11} a_{22} - a_{12} a_{21} \neq 0.

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Problem 24.1.7

Let QQ and PP be n×nn \times n symmetric matrices over R\mathbb {R}, i.e. Q=QTQ = Q^{T} and P=PTP = P^{T}. Assume that P−1P^{-1} exists. Find the maximum of the function f:Rn→Rf : \mathbb {R}^{n} \rightarrow \mathbb {R}

f(x→)=x→TQx→ f(\overrightarrow {x}) = \overrightarrow {x}^{T} Q \overrightarrow {x}

subject to x→TPx→=1\overrightarrow {x}^{T} P \overrightarrow {x} = 1. Use the Lagrange multiplier method.

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Problem 24.1.8

Let Φ:Rn×Rn→R\Phi : \mathbb {R}^{n} \times \mathbb {R}^{n} \rightarrow \mathbb {R} be an analytic function, where (x→,y→)=(x1,…,xn,y1,…,yn)∈Rn×Rn(\overrightarrow {x}, \overrightarrow {y}) = (x_{1}, \ldots , x_{n}, y_{1}, \ldots , y_{n}) \in \mathbb {R}^{n} \times \mathbb {R}^{n}. The Monge-Ampere determinant M(Φ)M(\Phi ) is defined by

M(Φ):=det⁡(Φ∂Φ/∂x1⋯∂Φ/∂xn∂Φ/∂y1∂2Φ/∂x1∂y1⋯∂2Φ/∂xn∂y1⋮⋮⋮∂Φ/∂yn∂2Φ/∂x1∂yn⋯∂2Φ/∂xn∂yn). M(\Phi ) := \det \begin{pmatrix} \Phi & \partial \Phi /\partial x_{1} & \cdots & \partial \Phi /\partial x_{n} \\ \partial \Phi /\partial y_{1} & \partial ^{2} \Phi /\partial x_{1} \partial y_{1} & \cdots & \partial ^{2} \Phi /\partial x_{n} \partial y_{1} \\ \vdots & \vdots & & \vdots \\ \partial \Phi /\partial y_{n} & \partial ^{2} \Phi /\partial x_{1} \partial y_{n} & \cdots & \partial ^{2} \Phi /\partial x_{n} \partial y_{n} \end{pmatrix}.

Let n=2n = 2 and

Φ(x1,x2,y1,y2)=x12+x22+(x1y1)2+(x2y2)2+y12+y22. \Phi (x_{1}, x_{2}, y_{1}, y_{2}) = x_{1}^{2} + x_{2}^{2} + (x_{1} y_{1})^{2} + (x_{2} y_{2})^{2} + y_{1}^{2} + y_{2}^{2}.

Find the Monge-Ampere determinant and the conditions on x1,x2,y1,y2x_{1}, x_{2}, y_{1}, y_{2} such that M(Φ)=0M(\Phi ) = 0.

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Problem 24.1.9

Consider the m×mm \times m matrix F(x→)=(fjk(x→))F(\overrightarrow {x}) = (f_{jk}(\overrightarrow {x})) (j,k=1,…,mj, k = 1, \ldots , m), where fjk:Rn→Rf_{jk} : \mathbb {R}^{n} \rightarrow \mathbb {R} are analytic functions. Assume that F(x→)F(\overrightarrow {x}) is invertible for all x→∈Rn\overrightarrow {x} \in \mathbb {R}^{n}. Then we have the identities (j=1,…,mj = 1, \ldots , m)

∂(det⁡(F(x→)))∂xj≡det⁡(F(x→))tr⁡(F−1(x→)∂F(x→)∂xj) \frac{\partial (\operatorname {det}\left(F(\overrightarrow {x})\right))}{\partial x_{j}} \equiv \operatorname {det}\left(F(\overrightarrow {x})\right) \operatorname {tr}\left( F^{-1}(\overrightarrow {x}) \frac{\partial F(\overrightarrow {x})}{\partial x_{j}} \right)

and

∂F−1(x→)∂xj≡−F−1(x→)∂F(x→)∂xjF−1(x→). \frac{\partial F^{-1}(\overrightarrow {x})}{\partial x_{j}} \equiv -F^{-1}(\overrightarrow {x}) \frac{\partial F(\overrightarrow {x})}{\partial x_{j}} F^{-1}(\overrightarrow {x}).

The differentiation is understood entrywise. Apply the identities to the matrix (m=2,n=1m = 2, n = 1)

F(x)=(cos⁡(x)sin⁡(x)−sin⁡(x)cos⁡(x)). F(x) = \begin{pmatrix} \cos (x) & \sin (x) \\ -\sin (x) & \cos (x) \end{pmatrix}.
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Problem 24.1.10

Let AA be an invertible n×nn \times n matrix over R\mathbb {R}. Consider the functions

Ej=12(Ac→j−e→j)T(Ac→j−e→j) E_{j} = \frac{1}{2} (A \overrightarrow {c}_{j} - \overrightarrow {e}_{j})^{T} (A \overrightarrow {c}_{j} - \overrightarrow {e}_{j})

where j=1,…,nj = 1, \ldots , n, c→j\overrightarrow {c}_{j} is the jj-th column of the inverse matrix of AA, e→j\overrightarrow {e}_{j} is the jj-th column of the n×nn \times n identity matrix. This means e→1,…,e→n\overrightarrow {e}_{1}, \ldots , \overrightarrow {e}_{n} is the standard basis (as column vectors) in Rn\mathbb {R}^{n}. The c→j\overrightarrow {c}_{j} are determined by minimizing the EjE_{j} with respect to the c→j\overrightarrow {c}_{j}. Apply this method to find the inverse of the 3×33 \times 3 matrix

A=(10101010−1). A = \begin{pmatrix} 1 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & -1 \end{pmatrix}.
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Problem 24.1.11

Let f→\overrightarrow {f} be a function from UU, an open subset of Rm\mathbb {R}^{m}, to Rn\mathbb {R}^{n}. Assume that the component function fjf_{j} (j=1,…,nj = 1, \ldots , n) possess first order partial derivatives. Then we can associate the n×mn \times m matrix

(∂fj∂xk∣p→),j=1,…,nk=1,…,m \left( \left. \frac{\partial f_{j}}{\partial x_{k}} \right|_{\overrightarrow {p}} \right), \quad j = 1, \ldots , n \quad k = 1, \ldots , m

where p→∈U\overrightarrow {p} \in U. The matrix is called the Jacobian matrix of f→\overrightarrow {f} at the point p→\overrightarrow {p}. When m=nm = n the determinant of the square matrix f→\overrightarrow {f} is called the Jacobian of f→\overrightarrow {f}. Let

A={r∈R:r>0},B={θ∈R:0≤θ<2π} A = \left\{ r \in \mathbb {R} : r > 0\right\} , \quad B = \left\{ \theta \in \mathbb {R} : 0 \leq \theta < 2\pi \right\}

and f→:A×B→R2\overrightarrow {f} : A \times B \rightarrow \mathbb {R}^{2} with f1(r,θ)=rcos⁡(θ)f_{1}(r, \theta ) = r \cos (\theta ), f2(r,θ)=rsin⁡(θ)f_{2}(r, \theta ) = r \sin (\theta ). Find the Jacobian matrix and the Jacobian.

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Problem 24.1.12

Consider the rotation matrix

R(t)=(cos⁡(ωt)sin⁡(ωt)−sin⁡(ωt)cos⁡(ωt)) R(t) = \begin{pmatrix} \cos (\omega t) & \sin (\omega t) \\ -\sin (\omega t) & \cos (\omega t) \end{pmatrix}

where ω\omega is a fixed frequency. Find the 2×22 \times 2 matrix

H(t)=iℏdR(t)dtRT(t) H(t) = i \hbar \frac{dR(t)}{dt} R^{T}(t)

and show it is hermitian.

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Problem 24.1.13

Let GL(m,C)GL(m, \mathbb {C}) be the general linear group over C\mathbb {C}. This Lie group consists of all nonsingular m×mm \times m matrices. Let GG be a Lie subgroup of GL(m,C)GL(m, \mathbb {C}). Suppose u1,u2,…,unu_{1}, u_{2}, \ldots , u_{n} is a coordinate system on GG in some neighborhood of ImI_{m}, the m×mm \times m identity matrix, and that X(u1,u2,…,um)X(u_{1}, u_{2}, \ldots , u_{m}) is a point in this neighborhood. The matrix dXdX of differential one-forms contains nn linearly independent differential one-forms since the nn-dimensional Lie group GG is smoothly embedded in GL(m,C)GL(m, \mathbb {C}). Consider the matrix of differential one forms

Ω:=X−1dX,X∈G. \Omega := X^{-1} dX, \quad X \in G.

The matrix Ω\Omega of differential one forms contains nn-linearly independent ones.

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(i)

Let AA be any fixed element of GG. The left-translation by AA is given by

X→AX. X \rightarrow AX.

Show that Ω=X−1dX\Omega = X^{-1} dX is left-invariant.

(ii)

Show that

dΩ+Ω∧Ω=0 d\Omega + \Omega \wedge \Omega = 0

where ∧\wedge denotes the exterior product for matrices, i.e. we have matrix multiplication together with the exterior product. The exterior product is linear and satisfies

duj∧duk=−duk∧duj. du_{j} \wedge du_{k} = -du_{k} \wedge du_{j}.

Therefore duj∧duj=0du_{j} \wedge du_{j} = 0 for j=1,…,nj = 1, \ldots , n. The exterior product is also associative.

(iii)

Find dX−1dX^{-1} using XX−1=ImX X^{-1} = I_{m}.

Problem 24.1.14

Consider GL(m,R)GL(m, \mathbb {R}) and a Lie subgroup of it. We interpret each element XX of GG as a linear transformation on the vector space Rm\mathbb {R}^{m} of row vectors v→=(v1,v2,…,vn)\overrightarrow {v} = (v_{1}, v_{2}, \ldots , v_{n}). Thus v→→w→=v→X\overrightarrow {v} \rightarrow \overrightarrow {w} = \overrightarrow {v} X. Show that dw→=w→Ωd\overrightarrow {w} = \overrightarrow {w} \Omega.

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Problem 24.1.15

Consider the compact Lie group SO(2)SO(2) consisting of the matrices

X(u)=(cos⁡(u)−sin⁡(u)sin⁡(u)cos⁡(u)). X(u) = \begin{pmatrix} \cos (u) & -\sin (u) \\ \sin (u) & \cos (u) \end{pmatrix}.

Calculate dXdX and X−1dXX^{-1} dX.

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Problem 24.1.16

Let nn be the dimension of the Lie group GG. Since the vector space of differential one-forms at the identity element is an nn-dimensional vector space, there are exactly nn linearly independent left invariant differential one-forms in GG. Let σ1,σ2,…,σn\sigma_{1}, \sigma_{2}, \ldots , \sigma_{n} be such a system. Consider the Lie group

G:={(u1u201):u1,u2∈R, u1>0}. G := \left\{ \begin{pmatrix} u_{1} & u_{2} \\ 0 & 1 \end{pmatrix} : u_{1}, u_{2} \in \mathbb {R}, \ u_{1} > 0 \right\} .

Let

X=(u1u201). X = \begin{pmatrix} u_{1} & u_{2} \\ 0 & 1 \end{pmatrix}.
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(i)

Find X−1X^{-1} and X−1dXX^{-1} dX. Calculate the left-invariant differential one-forms. Calculate the left-invariant volume element.

(ii)

Find the right-invariant forms.

Problem 24.1.17

Consider the Lie group consisting of the matrices

X=(u1u20u1),u1,u2∈R,u1>0. X = \begin{pmatrix} u_{1} & u_{2} \\ 0 & u_{1} \end{pmatrix}, \quad u_{1}, u_{2} \in \mathbb {R}, \quad u_{1} > 0.

Calculate X−1X^{-1} and X−1dXX^{-1} dX. Find the left-invariant differential one-forms and the left-invariant volume element.

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Problem 24.1.18

Let AA be a 2×22 \times 2 symmetric matrix

A=(a11a12a12a22) A = \begin{pmatrix} a_{11} & a_{12} \\ a_{12} & a_{22} \end{pmatrix}

over R\mathbb {R}. We define

∂∂a12A:=(0110). \frac{\partial }{\partial a_{12}} A := \begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix}.

Show that

∂∂a12tr⁡(A2)=tr⁡(∂∂a12A2)=tr⁡(2A∂A∂a12). \frac{\partial }{\partial a_{12}} \operatorname {tr}(A^{2}) = \operatorname {tr}\left( \frac{\partial }{\partial a_{12}} A^{2} \right) = \operatorname {tr}\left( 2 A \frac{\partial A}{\partial a_{12}} \right).
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Problem 24.1.19

Consider the matrix

A=(0−ii0). A = \begin{pmatrix} 0 & -i \\ i & 0 \end{pmatrix}.

Find the function (characteristic polynomial) p(λ)=det⁡(A−λI2)p(\lambda ) = \operatorname {det}\left(A - \lambda I_{2}\right). Find the eigenvalues of AA by solving p(λ)=0p(\lambda ) = 0. Find the minima of the function f(λ)=∣p(λ)∣f(\lambda ) = \left|p(\lambda )\right|. Discuss.

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Problem 24.1.20

Let α,β∈R\alpha , \beta \in \mathbb {R}. Consider the 2×22 \times 2 matrix

B=(−iα−β−βiα). B = \begin{pmatrix} -i\alpha & -\beta \\ -\beta & i\alpha \end{pmatrix}.

Find exp⁡(tB)\exp (tB), where t∈Rt \in \mathbb {R} and thus solve the initial value problem of the matrix differential equation

dAdt=BA(t). \frac{dA}{dt} = BA(t).
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Problem 24.1.21

The Fréchet derivative of a matrix function f:Cn×nf : \mathbb {C}^{n \times n} at a point X∈Cn×nX \in \mathbb {C}^{n \times n} is a linear mapping LX:Cn×n→Cn×nL_{X} : \mathbb {C}^{n \times n} \rightarrow \mathbb {C}^{n \times n} such that for all Y∈Cn×nY \in \mathbb {C}^{n \times n}

f(X+Y)−f(X)−LX(Y)=o(∥Y∥). f(X+Y) - f(X) - L_{X}(Y) = o(\left\| Y\right\| ).

Calculate the Fréchet derivative of f(X)=X2f(X) = X^{2}.

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