3.5 Maximum Likelihood Estimation, 3.6 Orthogonal Columns in the Regression Matrix
[5/100%]Prove the statement above that the minimum is given by ).
It is required to fit a regression model of the form
where is a second-degree polynomial. If , and , find such that the design matrix has mutually orthogonal columns.
Suppose that has linearly independent columns.
Using A.9.5, prove that
Deduce that
and hence show that with equality if and only if .
What modifications in the statement of Example 3.3 proved above can be made if the term is omitted?
Suppose that we wish to find the weights of objects. One method is to weigh each object times and take the average; this requires a total of weighings, and the variance of each average is ( being the variance of the weighing error). Another method is to weigh the objects in combinations; some of the objects are distributed between the two pans and weights are placed in one pan to achieve equilibrium. The regression model for such a scheme is
where , or -1 according as the th object is not used, placed in the left pan or in the right pan, is the weighing error (assumed to be the same for all weighings), and is the weight required for equilibrium ( is regarded as negative if placed in the left pan). After such weighing operations we can find the least squares estimates of the weights.
Show that the estimates of the weights have maximum precision (i.e., minimum variance) when each entry in the design matrix is and the columns of are mutually orthogonal.
If the objects are weighed individually, show that weighings are required to achieve the same precision as that given by the optimal design with weighings.