Chapter 16

Stochastic integrals: localization

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Problem 16.1

Let T<∞T < \infty. Do we have LT0=LT, loc 2\mathcal{L}_{T}^{0} = \mathcal{L}_{T, \text{ loc }}^{2} ?

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Problem 16.2

Let τ\tau be a stopping time. Show that   1[0,τ)\; \mathbb {1}_{[0, \tau )} is P\mathscr {P} measurable.

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Problem 16.3

If σn\sigma_{n} is localizing for a local martingale, so is τn:=σn∧n\tau_{n}: = \sigma_{n} \wedge n.

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Remark.
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Consequence: this yields the maximal inequality E[sup⁡s⩽T∣M(s∧τn)∣2]⩽Doob4E[∣M(τn)∣2]⩽4E[∣M(n)∣2]\mathbb {E}\left[\sup_{s\leqslant T}\left|M(s\wedge \tau_{n})\right|^{2}\right] \overset {\text{Doob}}{\leqslant } 4\mathbb {E}\left[\left|M(\tau_{n})\right|^{2}\right] \leqslant 4\mathbb {E}\left[\left|M(n)\right|^{2}\right].

Problem 16.4

The factor   1{σn>0}\; \mathbb {1}_{\left\{ \sigma_{n} > 0\right\} } is used in the definition of a local martingale, in order to avoid integrability requirements for M0M_{0}. More precisely, if (σn)n⩾1\left(\sigma_{n}\right)_{n \geqslant 1} is a localizing sequence, then we have

M0∈L1(P)&(Mt)t⩾0M_{0} \in L^{1}(\mathbb {P}) \& \left(M_{t}\right)_{t \geqslant 0} is a local martingale ⟺(Mσn∧t)t⩾0\Longleftrightarrow \left(M_{\sigma_{n} \wedge t}\right)_{t \geqslant 0} is a martingale.

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Problem 16.5

Let (It,Ft)t⩾0\left(I_{t}, \mathscr {F}_{t}\right)_{t \geqslant 0} be a continuous adapted process with values in [0,∞)[0, \infty ) and a.s. increasing sample paths. Set for u⩾0u \geqslant 0

σu(ω):=inf⁡{t⩾0:It(ω)>u} and τu(ω):=inf⁡{t⩾0:It(ω)⩾u} \sigma _{u}(\omega ): = \inf \left\{ t \geqslant 0: I_{t}(\omega ) > u\right\} \quad \text{ and } \quad \tau _{u}(\omega ): = \inf \left\{ t \geqslant 0: I_{t}(\omega ) \geqslant u\right\}

Show that

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(a)

σu⩾t⟺It⩽u\sigma_{u} \geqslant t \Longleftrightarrow I_{t} \leqslant u and τu>t⟺It<u\tau_{u} > t \Longleftrightarrow I_{t} < u.

(b)

τu\tau_{u} is an Ft\mathscr {F}_{t} stopping time and σu\sigma_{u} is an Ft+\mathscr {F}_{t+} stopping time.

(c)

u↦σuu \mapsto \sigma_{u} is right continuous and u↦τuu \mapsto \tau_{u} is left continuous.

(d)

τu=σu−=lim⁡ϵ↓0σu−ϵ\tau_{u} = \sigma_{u - } = \lim_{\epsilon \downarrow 0} \sigma_{u - \epsilon }.

(e)

u↦τu,u↦σuu \mapsto \tau_{u}, u \mapsto \sigma_{u} are continuous, if t↦Itt \mapsto I_{t} is strictly increasing.