Chapter 1

Robert Brown’s new thing

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Problem 1.1

Let X,Y,Xn,Yn:Ω→R,n⩾1X, Y, X_{n}, Y_{n}: \Omega \rightarrow \mathbb {R}, n \geqslant 1, be random variables.

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(a)

If, for all n⩾1,Xn  ⊥ ⁣ ⁣ ⁣⊥  Ynn \geqslant 1, X_{n} \; \perp \! \! \! \perp \; Y_{n} and if (Xn,Yn)→d(X,Y)\left(X_{n}, Y_{n}\right) \xrightarrow {d}(X, Y), then X  ⊥ ⁣ ⁣ ⁣⊥  YX \; \perp \! \! \! \perp \; Y.

(b)

Let X  ⊥ ⁣ ⁣ ⁣⊥  YX \; \perp \! \! \! \perp \; Y such that X,Y∼β1/2:=12(δ0+δ1)X, Y \sim \beta_{1 / 2}: = \frac{1}{2}\left(\delta_{0}+\delta_{1}\right) are Bernoulli random variables. We set Xn:=X+1nX_{n}: = X+\frac{1}{n} and Yn:=1−XnY_{n}: = 1 - X_{n}. Then Xn→dX,Yn→dY,Xn+Yn→d1X_{n} \xrightarrow {d} X, Y_{n} \xrightarrow {d} Y, X_{n}+Y_{n} \xrightarrow {d} 1 but (Xn,Yn)\left(X_{n}, Y_{n}\right) does not converge weakly to (X,Y)(X, Y).

(c)

Assume that Xn→dXX_{n} \xrightarrow {d} X and Yn→dYY_{n} \xrightarrow {d} Y. Is it true that Xn+Yn→dX+YX_{n}+Y_{n} \xrightarrow {d} X+Y ?

Problem 1.2

Let Xn,Yn:Ω→Rd,n⩾1X_{n}, Y_{n}: \Omega \rightarrow \mathbb {R}^{d}, n \geqslant 1, be two sequences of random variables such that Xn→dXX_{n} \xrightarrow {d} X and Xn−Yn→P0X_{n} - Y_{n} \xrightarrow {\mathbb {P}} 0. Then Yn→dXY_{n} \xrightarrow {d} X.

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Problem 1.3

Let Xn,Yn:Ω→R,n⩾1X_{n}, Y_{n}: \Omega \rightarrow \mathbb {R}, n \geqslant 1, be two sequences of random variables.

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(a)

If Xn→dXX_{n} \xrightarrow {d} X and Yn→PcY_{n} \xrightarrow {\mathbb {P}} c, then XnYn→dcXX_{n} Y_{n} \xrightarrow {d} c X. Is this still true if Yn→dcY_{n} \xrightarrow {d} c ?

(b)

If Xn→dXX_{n} \xrightarrow {d} X and Yn→P0Y_{n} \xrightarrow {\mathbb {P}} 0, then Xn+Yn→dXX_{n}+Y_{n} \xrightarrow {d} X. Is this still true if Yn→d0Y_{n} \xrightarrow {d} 0 ?

Remark.
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The direct approach to (a) is possible but relatively ugly. Part (b) has a relatively simple direct proof: fix ξ∈R\xi \in \mathbb {R},

E[eiξ(Xn+Yn)]−E[eiξX]=(E[eiξ(Xn+Yn)]−E[eiξXn])+(E[eiξXn]−E[eiξX])⏟→0 by d-convergence. \mathbb {E}\left[e^{i \xi (X_{n}+Y_{n})}\right] - \mathbb {E}\left[e^{i \xi X}\right] = \left(\mathbb {E}\left[e^{i \xi (X_{n}+Y_{n})}\right] - \mathbb {E}\left[e^{i \xi X_{n}}\right]\right)+\underbrace{\left(\mathbb {E}\left[e^{i \xi X_{n}}\right] - \mathbb {E}\left[e^{i \xi X}\right]\right)}_{\to 0 \text{ by } d\text{-convergence}}.

For the first term, using the uniform-continuity argument from Problem 1.2, for any ε>0\varepsilon > 0 there is δ=δ(ε,ξ)>0\delta = \delta (\varepsilon , \xi ) > 0 with

∣E[eiξ(Xn+Yn)]−E[eiξXn]∣⩽E[∣eiξXn(eiξYn−1)∣]=E[∣eiξYn−1∣]⩽ε+P(∣Yn∣>δ)→n→∞ε→ε→00, \left|\mathbb {E}\left[e^{i \xi (X_{n}+Y_{n})}\right] - \mathbb {E}\left[e^{i \xi X_{n}}\right]\right| \leqslant \mathbb {E}\left[\left|e^{i \xi X_{n}}\left(e^{i \xi Y_{n}} - 1\right)\right|\right] = \mathbb {E}\left[\left|e^{i \xi Y_{n}} - 1\right|\right] \leqslant \varepsilon +\mathbb {P}\left(\left|Y_{n}\right| > \delta \right) \xrightarrow [n \rightarrow \infty ]{} \varepsilon \xrightarrow [\varepsilon \rightarrow 0]{} 0,

using Yn→P0Y_{n} \xrightarrow {\mathbb {P}} 0 in the penultimate step.

Problem 1.4

Let Xn,X,Y:Ω→R,n⩾1X_{n}, X, Y: \Omega \rightarrow \mathbb {R}, n \geqslant 1, be random variables. If

lim⁡n→∞E[f(Xn)g(Y)]=E[f(X)g(Y)] for all f∈Cb(R),g∈Bb(R),  \lim _{n \rightarrow \infty } \mathbb {E}\left[f\left(X_{n}\right) g(Y)\right] = \mathbb {E}\left[f(X) g(Y)\right] \quad \text{ for all } f \in \mathcal{C}_{b}(\mathbb {R}), g \in \mathcal{B}_{b}(\mathbb {R}) \text{, }

then (Xn,Y)→d(X,Y)\left(X_{n}, Y\right) \xrightarrow {d}(X, Y). If X=ϕ(Y)X = \phi (Y) for some ϕ∈B(R)\phi \in \mathcal{B}(\mathbb {R}), then Xn→PXX_{n} \xrightarrow {\mathbb {P}} X.

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Problem 1.5

Let δj,j⩾1\delta_{j}, j \geqslant 1, be iid Bernoulli random variables with P(δj=±1)=1/2\mathbb {P}\left(\delta_{j} = \pm 1\right) = 1 / 2. We set

S0:=0,Sn:=δ1+⋯+δn and Xtn:=1nS⌊nt⌋ S_{0}: = 0, \quad S_{n}: = \delta _{1}+\cdots +\delta _{n} \quad \text{ and } \quad X_{t}^{n}: = \frac{1}{\sqrt{n}} S_{\left\lfloor n t\right\rfloor }

A one - dimensional random variable GG is Gaussian if it has the characteristic function E[eiξG]=exp⁡(imξ−12σ2ξ2)\mathbb {E}\left[e^{i \xi G}\right] = \exp \left(i m \xi - \frac{1}{2} \sigma^{2} \xi^{2}\right) with m∈Rm \in \mathbb {R} and σ⩾0\sigma \geqslant 0. Prove that

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(a)

Xtn→dGtX_{t}^{n} \xrightarrow {d} G_{t} where t>0t > 0 and GtG_{t} is a Gaussian random variable.

(b)

Xtn−Xsn→dGt−sX_{t}^{n} - X_{s}^{n} \xrightarrow {d} G_{t - s} where t⩾s⩾0t \geqslant s \geqslant 0 and GuG_{u} is a Gaussian random variable. Do we have Gt−s=Gt−GsG_{t - s} = G_{t} - G_{s} ?

(c)

Let 0⩽t1⩽…⩽tm,m⩾10 \leqslant t_{1} \leqslant \ldots \leqslant t_{m}, m \geqslant 1. Determine the limit as n→∞n \rightarrow \infty of the random vector (Xtmn−Xtm−1n,…,Xt2n−Xt1n,Xt1n)\left(X_{t_{m}}^{n} - X_{t_{m - 1}}^{n}, \ldots , X_{t_{2}}^{n} - X_{t_{1}}^{n}, X_{t_{1}}^{n}\right).

Problem 1.6

Consider the condition for all s<ts < t the random variables B(t)−B(s)t−s\frac{B(t) - B(s)}{\sqrt{t - s}} are identically distributed, centred and have variance 1.

Show that (B0), (B1), (B2), (B3) and (B0), (B1), (B2), (B3') are equivalent.

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Problem 1.7

Let GG and G′G^{\prime } be two independent real N (0,1)(0,1) - random variables. Show that

Γ±:=G±G′2∼N(0,1) and Γ−  ⊥ ⁣ ⁣ ⁣⊥  Γ+ \Gamma ^{ \pm }: = \frac{G \pm G^{\prime }}{\sqrt{2}} \sim \mathrm{N}(0,1) \quad \text{ and } \quad \Gamma ^{ - } \; \perp \! \! \! \perp \; \Gamma ^{+}
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Problem 1.8

Let (Xt)t⩾0\left(X_{t}\right)_{t \geqslant 0} be a stochastic process on the measure space (Ω,A,P)(\Omega , \mathscr {A}, \mathbb {P}) satisfying (B1)(B3). Assume further that there is some measurable set Ω0⊂Ω,P(Ω0)=1\Omega_{0} \subset \Omega , \mathbb {P}\left(\Omega_{0}\right) = 1, such that for all ω∈Ω0\omega \in \Omega_{0} we have X0(ω)=0X_{0}(\omega ) = 0 and t↦Xt(ω)t \mapsto X_{t}(\omega ) is continuous. Show that

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(a)

Bt(ω):=Xt(ω)  1Ω0(ω)B_{t}(\omega ): = X_{t}(\omega ) \; \mathbb {1}_{\Omega_{0}}(\omega ) is a Brownian motion on (Ω,A,P)(\Omega , \mathscr {A}, \mathbb {P});

(b)

XtX_{t} is a Brownian motion on the space (Ω0,Ω0∩A,P0:=P(⋅∩Ω0))\left(\Omega_{0}, \Omega_{0} \cap \mathscr {A}, \mathbb {P}_{0}: = \mathbb {P}\left(\cdot \cap \Omega_{0}\right)\right).

Notation. Ω0∩A:={Ω0∩A:A∈A}\Omega_{0} \cap \mathscr {A}: = \left\{ \Omega_{0} \cap A: A \in \mathscr {A}\right\} is the trace σ\sigma - algebra.

Remark.
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Method (b) also works if Ω0\Omega_{0} is not measurable, see Problem 1.9.

Problem 1.9

Let (Ω,A,P)(\Omega , \mathscr {A}, \mathbb {P}) be a probability space and let P∗(Q):=inf⁡{P(A):A⊃Q,A∈A}\mathbb {P}^{*}\left(Q\right): = \inf \left\{ \mathbb {P}\left(A\right): A \supset Q, A \in \mathscr {A}\right\} be the outer measure. If Ω0⊂Ω\Omega_{0} \subset \Omega is such that P∗(Ω0)=1\mathbb {P}^{*}\left(\Omega_{0}\right) = 1, then (Ω0,A0,P0)\left(\Omega_{0}, \mathscr {A}_{0}, \mathbb {P}_{0}\right) with A0:=Ω0∩A\mathscr {A}_{0}: = \Omega_{0} \cap \mathscr {A} and P0(A0):=P(A)\mathbb {P}_{0}\left(A_{0}\right): = \mathbb {P}\left(A\right) for every A0∈A0A_{0} \in \mathscr {A}_{0} of the form A0=Ω0∩AA_{0} = \Omega_{0} \cap A, defines a new probability space.

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Problem 1.10

Let (Ω,A,P)(\Omega , \mathscr {A}, \mathbb {P}) be a probability space. The completion (Ω,A′,P′)\left(\Omega , \mathscr {A}^{\prime }, \mathbb {P}^{\prime }\right) is the smallest extension such that A′\mathscr {A}^{\prime } contains all subsets of A\mathscr {A} measurable null sets. Show that

A′:={A′⊂Ω:∃A1,A2∈A,A1⊂A′⊂A2,P(A2\A1)=0},P′(A′):=P(A2)(A2 is as in the definition of A′). \begin{aligned} \mathscr {A}^{\prime }: = & \left\{ A^{\prime } \subset \Omega : \exists A_{1}, A_{2} \in \mathscr {A}, A_{1} \subset A^{\prime } \subset A_{2}, \mathbb {P}\left(A_{2} \backslash A_{1}\right) = 0\right\} , \\ & \mathbb {P}^{\prime }\left(A^{\prime }\right): = \mathbb {P}\left(A_{2}\right) \quad \left(A_{2} \text{ is as in the definition of } \mathscr {A}^{\prime }\right) . \end{aligned}
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