Chapter 3

Lie Algebras

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Problem 3.1

Let LL be a Lie algebra and a,b,h∈La, b, h \in L. Assume that

[a,h]=0,[b,h]=0. [a,h] = 0, \qquad [b,h] = 0.

Calculate [[a,b],h][[a,b],h].

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Problem 3.2

Let e1,e2,e3e_{1}, e_{2}, e_{3} be the generators of a three dimensional Lie algebra with the commutation relation

[e1,e3]=e1,[e2,e3]=e1+e2,[e1,e2]=0 . [e_{1},e_{3}] = e_{1}, \qquad [e_{2},e_{3}] = e_{1}+e_{2}, \qquad [e_{1},e_{2}] = 0 \, .

Find

[e1,[e2,e3]]+[e3,[e1,e2]] . [e_{1},[e_{2},e_{3}]] + [e_{3},[e_{1},e_{2}]] \, .
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Problem 3.3

Let LL be a three dimensional Lie algebra with basis a,b,ca, b, c and commutation relations (solvable Lie algebra)

[a,b]=0,[b,c]=a+kb,[c,a]=−ka+b,k>0 . [a,b] = 0, \qquad [b,c] = a+kb, \qquad [c,a] = -ka+b, \qquad k > 0 \, .
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(i)

Find the commutator [[b,c],[c,a]][[b,c],[c,a]].

(ii)

Check the Jacobi identity

[[a,b],c]+[[c,a],b]+[[b,c],a]=0 . [[a,b],c] + [[c,a],b] + [[b,c],a] = 0 \, .
Problem 3.4

Let LL be a Lie algebra and let II be an ideal of LL. We define the bracket [ , ]:L/I→L/I[\, , \, ] : L/I \to L/I by

[a+I,b+I]:=[a,b]+I [a+I, b+I] := [a,b] + I

where a,b∈La, b \in L. Show that the quotient vector space becomes a Lie algebra under this bracket.

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Problem 3.5

Let LL be a Lie algebra. A linear map D:L→LD : L \to L is called a derivation if

D[a,b]=[Da,b]+[a,Db] D[a,b] = [Da,b] + [a,Db]

for all a,b∈La, b \in L. The collection of all derivatives of LL is denoted by Der⁡(L)\operatorname {Der}(L). Let n∈Nn \in \mathbb {N}. Show that (Leibniz rule)

Dn[a,b]=∑j=0nnCj[Dja,Dn−jb] D^{n}[a,b] = \sum _{j=0}^{n} {}^{n}C_{j} [D^{j}a, D^{n-j}b]

where the binomial coefficients nCj{}^{n}C_{j} are defined for an arbitrary field F\mathbb {F}

nC0=nCn=1,nCj=n−1Cj−1+n−1Cjfor0<j<n . {}^{n}C_{0} = {}^{n}C_{n} = 1, \qquad {}^{n}C_{j} = {}^{n-1}C_{j-1} + {}^{n-1}C_{j} \quad \text{for} \quad 0 < j < n \, .
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Problem 3.6

A Lie algebra LL is called simple if LL is non-abelian and has no proper ideals. Show that for a simple Lie algebra the derived Lie algebra L(1)=[L,L]L^{(1)} = [L,L] is equal to LL, i.e.L(1)=LL^{(1)} = L.

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Problem 3.7

A Lie algebra LL is called semisimple if L≠0L \neq 0 and LL has no abelian ideals ≠0\neq 0. Show that a finite dimensional Lie algebra LL is semisimple if and only if rad⁡L=0\operatorname {rad}L = 0.

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Problem 3.8

Show that the adjoint representation of a semisimple Lie algebra is faithful. A faithful representation of a Lie algebra is a linear representation in which different elements of LL are represented by distinct linear mappings.

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Problem 3.9

Consider the Lie algebra with basis {e1,e2,e3}\{ e_{1}, e_{2}, e_{3}\} and the commutators

[e1,e2]=e3,[e2,e3]=e1,[e3,e1]=e2 . [e_{1},e_{2}] = e_{3}, \qquad [e_{2},e_{3}] = e_{1}, \qquad [e_{3},e_{1}] = e_{2} \, .

Find the adjoint representation.

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Problem 3.10

Apply the Levi decomposition theorem to the finite dimensional Lie algebra gl(2,R)\mathfrak {gl}(2,\mathbb {R}). Consider as basis

X=(0100),Y=(0010),H=(100−1),I2=(1001) . X = \begin{pmatrix} 0 & 1 \\ 0 & 0 \end{pmatrix}, \qquad Y = \begin{pmatrix} 0 & 0 \\ 1 & 0 \end{pmatrix}, \qquad H = \begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix}, \qquad I_{2} = \begin{pmatrix} 1 & 0 \\ 0 & 1 \end{pmatrix} \, .
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Problem 3.11

Consider a finite dimensional Lie algebra with basis elements {Xα:α=1,…,r}\{ X_{\alpha } : \alpha = 1, \ldots , r \}. The commutator may be expanded in terms of the basis

[Xα,Xβ]=∑γ=1rCαβγXγ(1) [X_{\alpha }, X_{\beta }] = \sum _{\gamma =1}^{r} C_{\alpha \beta }^{\gamma } X_{\gamma } \tag {1}

(α,β=1,…,r\alpha , \beta = 1, \ldots , r) where CαβγC_{\alpha \beta }^{\gamma } are called the structure constants. The structure constants CαβγC_{\alpha \beta }^{\gamma } in (1) are constants. The structure constants, defined by the commutation relations (1) satisfy the relations

Cαβγ=−Cβαγ C_{\alpha \beta }^{\gamma } = -C_{\beta \alpha }^{\gamma } ∑ρ=1r(CαβρCργδ+CβγρCραδ+CγαρCρβδ)=0 \sum _{\rho =1}^{r} \left( C_{\alpha \beta }^{\rho } C_{\rho \gamma }^{\delta } + C_{\beta \gamma }^{\rho } C_{\rho \alpha }^{\delta } + C_{\gamma \alpha }^{\rho } C_{\rho \beta }^{\delta } \right) = 0

where α,β,γ=1,…,r\alpha , \beta , \gamma = 1, \ldots , r. This is the Third Fundamental Theorem of Lie.

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Problem 3.12

The Lie algebra sl(2,R)\mathfrak {sl}(2,\mathbb {R}) is spanned by the 2×22 \times 2 matrices

h=(100−1),e=(0100),f=(0010) h = \begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix}, \qquad e = \begin{pmatrix} 0 & 1 \\ 0 & 0 \end{pmatrix}, \qquad f = \begin{pmatrix} 0 & 0 \\ 1 & 0 \end{pmatrix}

with

[e,f]=h,[h,e]=2e,[h,f]=−2f . [e,f] = h, \qquad [h,e] = 2e, \qquad [h,f] = -2f \, .
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(i)

Let xx be a linear combination of the basis h,e,fh, e, f

x=c1h+c2e+c3f x = c_{1}h + c_{2}e + c_{3}f

where c1,c2,c3∈Rc_{1}, c_{2}, c_{3} \in \mathbb {R}. Calculate the commutators [h,x],[e,x],[f,x][h,x], [e,x], [f,x].

(ii)

Show that the Lie algebra sl(2,R)\mathfrak {sl}(2,\mathbb {R}) is simple.

Problem 3.13

The Lie algebra sl(2,R)\mathfrak {sl}(2,\mathbb {R}) is simple. Study the Lie algebra sl(2,F)\mathfrak {sl}(2,\mathbb {F}), where char⁡F=2\operatorname {char}\mathbb {F} = 2.

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Problem 3.14

Show that for a simple Lie algebra LL the derived algebra L(1)=[L,L]L^{(1)} = [L,L] is equal to LL.

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Problem 3.15

The Lie algebra gl(n,R)\mathfrak {gl}(n,\mathbb {R}) can be represented by n×nn \times n matrices over R\mathbb {R}. Consider the standard basis for the vector space of all n×nn \times n matrices over R\mathbb {R} consisting of the matrices MijM_{ij} (having 1 in the (i,j)(i,j)-position and 0 elsewhere). Find the commutator

[Mij,Mkℓ] . [M_{ij}, M_{k\ell }] \, .
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Problem 3.16

The semisimple Lie algebra sl(3,R)\mathfrak {sl}(3,\mathbb {R}) has dimension 8. The standard basis is given by

h1=(1000−10000),h2=(00001000−1), h_{1} = \begin{pmatrix} 1 & 0 & 0 \\ 0 & -1 & 0 \\ 0 & 0 & 0 \end{pmatrix}, \qquad h_{2} = \begin{pmatrix} 0 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & -1 \end{pmatrix}, e1=(010000000),e2=(000001000), e_{1} = \begin{pmatrix} 0 & 1 & 0 \\ 0 & 0 & 0 \\ 0 & 0 & 0 \end{pmatrix}, \qquad e_{2} = \begin{pmatrix} 0 & 0 & 0 \\ 0 & 0 & 1 \\ 0 & 0 & 0 \end{pmatrix}, f1=(000100000),f2=(000000010), f_{1} = \begin{pmatrix} 0 & 0 & 0 \\ 1 & 0 & 0 \\ 0 & 0 & 0 \end{pmatrix}, \qquad f_{2} = \begin{pmatrix} 0 & 0 & 0 \\ 0 & 0 & 0 \\ 0 & 1 & 0 \end{pmatrix}, e13=(001000000),f13=(000000100) . e_{13} = \begin{pmatrix} 0 & 0 & 1 \\ 0 & 0 & 0 \\ 0 & 0 & 0 \end{pmatrix}, \qquad f_{13} = \begin{pmatrix} 0 & 0 & 0 \\ 0 & 0 & 0 \\ 1 & 0 & 0 \end{pmatrix} \, .

Find the commutator table. Find the rank of the Lie algebra.

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Problem 3.17

Give a Lie algebra which is semisimple, but not simple. Provide a matrix representation.

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Problem 3.18
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(i)

Classify all real two-dimensional Lie algebras, where F=R\mathbb {F} = \mathbb {R}. Denote the basis elements by XX and YY.

(ii)

Find a representation of the non-abelian two-dimensional Lie algebra using differential operators.

(iii)

Find a representation of the non-abelian two-dimensional Lie algebra using 2×22 \times 2 matrices.

Problem 3.19

Let InI_{n} be the n×nn \times n identity matrix. Can one find n×nn \times n matrices A,BA, B over C\mathbb {C} such that [A,B]=In[A,B] = I_{n}?

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Problem 3.20
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(i)

Let AA be an associative algebra over a field F\mathbb {F}. We define the commutator

[a,b]:=ab−ba [a,b] := ab - ba

for all a,b∈Aa, b \in A. Show that with this definition of the commutator we have a Lie algebra.

(ii)

Give an example.

Problem 3.21

A finite-dimensional Lie algebra over a field F\mathbb {F} of characteristic 0 (for example R\mathbb {R} and C\mathbb {C}) is called reductive if its adjoint representation is completely reducible. Give an example of a Lie algebra which is reductive but not semisimple.

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Problem 3.22

Consider the vector space of analytic functions f:R→Rf : \mathbb {R} \to \mathbb {R}. We define the bracket

[f,g]:=fdgdx−dfdxg . [f,g] := f\frac{dg}{dx} - \frac{df}{dx}g \, .
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(i)

Show that this defines an infinite dimensional Lie algebra.

(ii)

Consider the analytic functions

f(x)=sin⁡(x),g(x)=cos⁡(x),h(x)=1 . f(x) = \sin (x), \qquad g(x) = \cos (x), \qquad h(x) = 1 \, .

Show that these function for a basis of a finite dimensional Lie algebra. Is the Lie algebra semisimple?

(iii)

Let m,n∈Zm, n \in \mathbb {Z}. Consider

p(x)=xm,q(x)=xn . p(x) = x^{m}, \qquad q(x) = x^{n} \, .

Find [p,q][p,q].

Problem 3.23

Let f,g,p,q:R→Rf, g, p, q : \mathbb {R} \to \mathbb {R} be analytic functions. Consider the differential operators

f(x)ddx+p(x),g(x)ddx+q(x) . f(x)\frac{d}{dx} + p(x), \qquad g(x)\frac{d}{dx} + q(x) \, .

Calculate the commutator

[f(x)ddx+p(x), g(x)ddx+q(x)]h(x) \left[ f(x)\frac{d}{dx} + p(x), \, g(x)\frac{d}{dx} + q(x) \right] h(x)

where hh is an analytic function. Discuss.

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Problem 3.24

Let f,g:W→Wf, g : W \to W be two maps, where WW is a topological vector space (u∈Wu \in W). Assume that the Gateaux derivative of ff and gg exists, i.e.

f′(u)[v]:=∂f(u+ϵv)∂ϵ∣ϵ=0,g′(u)[v]:=∂g(u+ϵv)∂ϵ∣ϵ=0 .(1) f'(u)[v] := \left. \frac{\partial f(u+\epsilon v)}{\partial \epsilon } \right|_{\epsilon =0}, \qquad g'(u)[v] := \left. \frac{\partial g(u+\epsilon v)}{\partial \epsilon } \right|_{\epsilon =0} \, . \tag {1}

The Lie product (or commutator) of ff and gg is defined by

[f,g](u):=f′(u)[g(u)]−g′(u)[f(u)] .(2) [f,g](u) := f'(u)[g(u)] - g'(u)[f(u)] \, . \tag {2}

Let

f(u):=∂u∂t−u∂u∂x−∂3u∂x3,g(u):=∂u∂t−∂2u∂x2 .(3) f(u) := \frac{\partial u}{\partial t} - u\frac{\partial u}{\partial x} - \frac{\partial ^{3} u}{\partial x^{3}}, \qquad g(u) := \frac{\partial u}{\partial t} - \frac{\partial ^{2} u}{\partial x^{2}} \, . \tag {3}

Calculate the commutator [f,g](u)[f,g](u).

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Problem 3.25

Let LL be the real vector space R3\mathbb {R}^{3}. Let a→,b→∈L\overrightarrow {a}, \overrightarrow {b} \in L. Define

a→×b→:=(a2b3−a3b2a3b1−a1b3a1b2−a2b1) .(1) \overrightarrow {a} \times \overrightarrow {b} := \begin{pmatrix} a_{2}b_{3}-a_{3}b_{2} \\ a_{3}b_{1}-a_{1}b_{3} \\ a_{1}b_{2}-a_{2}b_{1} \end{pmatrix} \, . \tag {1}

Equation (1) is the cross or vector product.

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(i)

Show that LL is a Lie algebra.

(ii)

Show that in general

a→×(b→×c→)≠(a→×b→)×c→ . \overrightarrow {a} \times (\overrightarrow {b} \times \overrightarrow {c}) \neq (\overrightarrow {a} \times \overrightarrow {b}) \times \overrightarrow {c} \, .
Problem 3.26

The simple Lie algebra sl(2,R)\mathfrak {sl}(2,\mathbb {R}) is spanned by the 2×22 \times 2 matrices

h=(100−1),e=(0100),f=(0010) h = \begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix}, \qquad e = \begin{pmatrix} 0 & 1 \\ 0 & 0 \end{pmatrix}, \qquad f = \begin{pmatrix} 0 & 0 \\ 1 & 0 \end{pmatrix}

with [e,f]=h[e,f] = h, [h,e]=2e[h,e] = 2e, [h,f]=−2f[h,f] = -2f. Show that the bracket relations are also satisfied by the matrices

ρ2(h)=(20000000−2), \rho _{2}(h) = \begin{pmatrix} 2 & 0 & 0 \\ 0 & 0 & 0 \\ 0 & 0 & -2 \end{pmatrix}, ρ2(e)=(020001000),ρ2(f)=(000100020) \rho _{2}(e) = \begin{pmatrix} 0 & 2 & 0 \\ 0 & 0 & 1 \\ 0 & 0 & 0 \end{pmatrix}, \qquad \rho _{2}(f) = \begin{pmatrix} 0 & 0 & 0 \\ 1 & 0 & 0 \\ 0 & 2 & 0 \end{pmatrix}

and

ρ3(h)=(3000010000−10000−3), \rho _{3}(h) = \begin{pmatrix} 3 & 0 & 0 & 0 \\ 0 & 1 & 0 & 0 \\ 0 & 0 & -1 & 0 \\ 0 & 0 & 0 & -3 \end{pmatrix}, ρ3(e)=(0300002000010000),ρ3(f)=(0000100002000030) . \rho _{3}(e) = \begin{pmatrix} 0 & 3 & 0 & 0 \\ 0 & 0 & 2 & 0 \\ 0 & 0 & 0 & 1 \\ 0 & 0 & 0 & 0 \end{pmatrix}, \qquad \rho _{3}(f) = \begin{pmatrix} 0 & 0 & 0 & 0 \\ 1 & 0 & 0 & 0 \\ 0 & 2 & 0 & 0 \\ 0 & 0 & 3 & 0 \end{pmatrix} \, .
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Problem 3.27

Consider as a basis for the simple Lie algebra sl(2,R)\mathfrak {sl}(2,\mathbb {R}) the invertible matrices with trace 0

A=(01−10),B=(100−1),C=(0110) . A = \begin{pmatrix} 0 & 1 \\ -1 & 0 \end{pmatrix}, \qquad B = \begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix}, \qquad C = \begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix} \, .
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(i)

Find the commutators.

(ii)

Show that the eigenvalues of these matrices form a group under multiplication.

Problem 3.28

The Lie algebra su(n)\mathfrak {su}(n) are the n×nn \times n matrices XX with the conditions X∗=−XX^{*} = -X, \trX=0\tr X = 0. Find a basis for su(3)\mathfrak {su}(3) under the condition that the elements of the basis are orthogonal to each other with respect to the scalar product

⟨X,Y⟩:=\tr(XY∗) . \left\langle X, Y \right\rangle := \tr (XY^{*}) \, .
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Problem 3.29

The Lie algebra su(4)\mathfrak {su}(4) consists of all 4×44 \times 4 matrices over C\mathbb {C} such that A∗=−AA^{*} = -A, \trA=0\tr A = 0. The first condition is that the matrices are skew-hermitian. Give a basis for the Lie algebra under the condition that the elements of the basis are orthogonal to each other with respect to the scalar product

⟨A,B⟩:=\tr(AB∗) . \left\langle A, B \right\rangle := \tr (AB^{*}) \, .
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Problem 3.30

Let XX be a 2×22 \times 2 matrix over C\mathbb {C}. Let

L=(−1001) . L = \begin{pmatrix} -1 & 0 \\ 0 & 1 \end{pmatrix} \, .
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(i)

Find the condition on XX such that X∗L+LX=02X^{*}L + LX = 0_{2}. Then XX is an element of the Lie algebra u(1,1)\mathfrak {u}(1,1).

(ii)

Give a basis of the Lie algebra. Is the Lie algebra semisimple?

Problem 3.31

There is only one simple complex Lie algebra of rank 1. If α=λe1\alpha = \lambda e_{1} is a nonzero root, −λe1-\lambda e_{1} is the other. The canonical choice for λ\lambda is 1/21/\sqrt{2}. The commutators for the basis

E−1/2,H1,E+1/2 E_{-1/\sqrt{2}}, \quad H_{1}, \quad E_{+1/\sqrt{2}}

are

[H1,E±1/2]=±12E±1/2,[E+1/2,E−1/2]=12H1 . [H_{1}, E_{\pm 1/\sqrt{2}}] = \pm \frac{1}{\sqrt{2}} E_{\pm 1/\sqrt{2}}, \qquad [E_{+1/\sqrt{2}}, E_{-1/\sqrt{2}}] = \frac{1}{\sqrt{2}} H_{1} \, .

Find a 2×22 \times 2 matrix representation for this semisimple Lie algebra.

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Problem 3.32

Consider the Lie algebra gl(2,R)\mathfrak {gl}(2,\mathbb {R}). The 2×22 \times 2 matrices

e1=(1000),e2=(0100),e3=(0010),e4=(0001) e_{1} = \begin{pmatrix} 1 & 0 \\ 0 & 0 \end{pmatrix}, \qquad e_{2} = \begin{pmatrix} 0 & 1 \\ 0 & 0 \end{pmatrix}, \qquad e_{3} = \begin{pmatrix} 0 & 0 \\ 1 & 0 \end{pmatrix}, \qquad e_{4} = \begin{pmatrix} 0 & 0 \\ 0 & 1 \end{pmatrix}

form a basis of gl(2,R)\mathfrak {gl}(2,\mathbb {R}).

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(i)

Find the adjoint representation.

(ii)

Find the Killing form and the metric tensor for the Lie algebra. From these results decide whether the Lie algebra is semisimple.

Problem 3.33

Let e1,e2,e3e_{1}, e_{2}, e_{3} be the generators of a three-dimensional Lie algebra with the commutation relation

[e1,e3]=e1,[e2,e3]=e1+e2,[e1,e2]=0 . [e_{1},e_{3}] = e_{1}, \qquad [e_{2},e_{3}] = e_{1}+e_{2}, \qquad [e_{1},e_{2}] = 0 \, .

Find the adjoint representation. Is the Lie algebra semisimple?

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Problem 3.34

Let InI_{n} be the n×nn \times n unit matrix. Consider the 2n×2n2n \times 2n matrices

E1=12(In0n0n−In),E2=12(0nInIn0n),E3=12(0nIn−In0n) . E_{1} = \frac{1}{2} \begin{pmatrix} I_{n} & 0_{n} \\ 0_{n} & -I_{n} \end{pmatrix}, \qquad E_{2} = \frac{1}{2} \begin{pmatrix} 0_{n} & I_{n} \\ I_{n} & 0_{n} \end{pmatrix}, \qquad E_{3} = \frac{1}{2} \begin{pmatrix} 0_{n} & I_{n} \\ -I_{n} & 0_{n} \end{pmatrix} \, .

Find the commutators [E1,E2],[E1,E3],[E3,E2][E_{1},E_{2}], [E_{1},E_{3}], [E_{3},E_{2}]. Discuss.

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Problem 3.35

Consider the Lie algebra u(1,1)\mathfrak {u}(1,1). A basis using 2×22 \times 2 matrices is given by

τ0=12(i00−i),τ1=12(0110), \tau _{0} = \frac{1}{2} \begin{pmatrix} i & 0 \\ 0 & -i \end{pmatrix}, \qquad \tau _{1} = \frac{1}{2} \begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix}, τ2=12(0−ii0),τ3=12(i00i) . \tau _{2} = \frac{1}{2} \begin{pmatrix} 0 & -i \\ i & 0 \end{pmatrix}, \qquad \tau _{3} = \frac{1}{2} \begin{pmatrix} i & 0 \\ 0 & i \end{pmatrix} \, .

Find the commutators. Find the 4×44 \times 4 matrix

(Ajk):=\tr(τjτk)j,k=0,1,2,3 . (A_{jk}) := \tr (\tau _{j}\tau _{k}) \qquad j,k = 0,1,2,3 \, .

Is the matrix invertible?

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Problem 3.36

Let HH be a nonzero n×nn \times n hermitian matrix. Let EE be a nonzero n×nn \times n matrix. Assume that [H,E]=aE[H,E] = aE, where a∈Ra \in \mathbb {R} and a≠0a \neq 0. Show that the matrix EE cannot be hermitian.

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Problem 3.37

Consider the vectors in R2\mathbb {R}^{2}

α=123(1,3),β=123(1,−3) . \alpha = \frac{1}{2\sqrt{3}}(1,\sqrt{3}), \qquad \beta = \frac{1}{2\sqrt{3}}(1,-\sqrt{3}) \, .

Then

α+β=13(1,0) . \alpha + \beta = \frac{1}{\sqrt{3}}(1,0) \, .

Find eight 3×33 \times 3 matrices

H1,  H2,  Eα,  E−α,  Eβ,  E−β,  Eα+β,  E−(α+β) H_{1}, \; H_{2}, \; E_{\alpha }, \; E_{-\alpha }, \; E_{\beta }, \; E_{-\beta }, \; E_{\alpha +\beta }, \; E_{-(\alpha +\beta )}

such that the following commutation relations are satisfied

[H1,E±α]=±123E±α,[H2,E±α]=±12E±α [H_{1}, E_{\pm \alpha }] = \pm \frac{1}{2\sqrt{3}}E_{\pm \alpha }, \qquad [H_{2}, E_{\pm \alpha }] = \pm \frac{1}{2}E_{\pm \alpha } [H1,E±β]=±123E±β,[H2,E±β]=±12E±β [H_{1}, E_{\pm \beta }] = \pm \frac{1}{2\sqrt{3}}E_{\pm \beta }, \qquad [H_{2}, E_{\pm \beta }] = \pm \frac{1}{2}E_{\pm \beta } [H1,E±(α+β)]=13E±(α+β),[H2,E±(α+β)]=0 [H_{1}, E_{\pm (\alpha +\beta )}] = \frac{1}{\sqrt{3}}E_{\pm (\alpha +\beta )}, \qquad [H_{2}, E_{\pm (\alpha +\beta )}] = 0 [Eα,E−α]=H123+H22,[Eβ,E−β]=H123−H22, [E_{\alpha }, E_{-\alpha }] = \frac{H_{1}}{2\sqrt{3}} + \frac{H_{2}}{2}, \qquad [E_{\beta }, E_{-\beta }] = \frac{H_{1}}{2\sqrt{3}} - \frac{H_{2}}{2}, [Eα+β,E−(α+β)]=H13,[Eα,Eβ]=16Eα+β, [E_{\alpha +\beta }, E_{-(\alpha +\beta )}] = \frac{H_{1}}{\sqrt{3}}, \qquad [E_{\alpha }, E_{\beta }] = \frac{1}{\sqrt{6}}E_{\alpha +\beta }, [Eα,Eα+β]=0,[Eβ,Eα+β]=0 [E_{\alpha }, E_{\alpha +\beta }] = 0, \qquad [E_{\beta }, E_{\alpha +\beta }] = 0 [Eα,E−(α+β)]=−16E−β,[Eβ,E−(α+β)]=16E−α [E_{\alpha }, E_{-(\alpha +\beta )}] = -\frac{1}{\sqrt{6}}E_{-\beta }, \qquad [E_{\beta }, E_{-(\alpha +\beta )}] = \frac{1}{\sqrt{6}}E_{-\alpha }

and [H1,H2]=0[H_{1},H_{2}] = 0. We can assume that H1,H2H_{1}, H_{2} are diagonal matrices.

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Problem 3.38

The Lie algebra su(5)\mathfrak {su}(5) consists of all 5×55 \times 5 matrices with

X∗=−X,\trX=0 X^{*} = -X, \qquad \tr X = 0

for X∈su(5)X \in \mathfrak {su}(5). Give a basis of su(5)\mathfrak {su}(5). The basis elements should be orthogonal with respect to the scalar product \tr(XjXk∗)\tr (X_{j}X_{k}^{*}).

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Problem 3.39
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(i)

Is the three dimensional Heisenberg algebra with the basis {x,y,z}\{ x,y,z\} and the commutators [x,y]=z[x,y] = z, [x,z]=0[x,z] = 0, [y,z]=0[y,z] = 0 nilpotent?

(ii)

Find a matrix representation with 3×33 \times 3 matrices.

Problem 3.40

If a Lie algebra is nilpotent, then the Killing form vanishes. Can we conclude that if the Killing form vanishes then the Lie algebra is nilpotent?

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Problem 3.41

Show that the Lie algebra consisting of 3×33 \times 3 matrices over R\mathbb {R} (or C\mathbb {C}) with zeros on and below the main diagonal is nilpotent.

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Problem 3.42

Consider the vector space of 3×33 \times 3 matrices over R\mathbb {R} and the two linearly independent matrices

A=(011000000),B=(000001001) . A = \begin{pmatrix} 0 & 1 & 1 \\ 0 & 0 & 0 \\ 0 & 0 & 0 \end{pmatrix}, \qquad B = \begin{pmatrix} 0 & 0 & 0 \\ 0 & 0 & 1 \\ 0 & 0 & 1 \end{pmatrix} \, .

Construct a Lie algebra by calculating the commutators. Thus AA and BB would be the generators of the Lie algebra.

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Problem 3.43

Let z∈Cz \in \mathbb {C}. Consider the vector fields

V1=−∂∂z−∂∂zˉ,V2=i∂∂zˉ−i∂∂z,V3=2i(z∂∂zˉ−zˉ∂∂z) . V_{1} = -\frac{\partial }{\partial z} - \frac{\partial }{\partial \bar{z}}, \qquad V_{2} = i\frac{\partial }{\partial \bar{z}} - i\frac{\partial }{\partial z}, \qquad V_{3} = \frac{2}{i}\left( z\frac{\partial }{\partial \bar{z}} - \bar{z}\frac{\partial }{\partial z} \right) \, .

Find the commutators and show that we have a basis of a Lie algebra.

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Problem 3.44

Consider the vector fields

V12=x1∂∂x2−x2∂∂x1,V31=x3∂∂x1−x1∂∂x3,V23=x2∂∂x3−x3∂∂x2 . V_{12} = x_{1}\frac{\partial }{\partial x_{2}} - x_{2}\frac{\partial }{\partial x_{1}}, \qquad V_{31} = x_{3}\frac{\partial }{\partial x_{1}} - x_{1}\frac{\partial }{\partial x_{3}}, \qquad V_{23} = x_{2}\frac{\partial }{\partial x_{3}} - x_{3}\frac{\partial }{\partial x_{2}} \, .

Find the commutators [V12,V31],[V31,V23],[V23,V12][V_{12},V_{31}], [V_{31},V_{23}], [V_{23},V_{12}] and show that V12,V31,V23V_{12}, V_{31}, V_{23} form a basis of a Lie algebra. Is the Lie algebra semisimple?

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Problem 3.45

As an extension of the previous problem we can consider the vector fields (n≥3n \geq 3)

Vjk=−xj∂∂xk+xk∂∂xj,j=1,2,…,n,j<k . V_{jk} = -x_{j}\frac{\partial }{\partial x_{k}} + x_{k}\frac{\partial }{\partial x_{j}}, \qquad j = 1,2,\ldots ,n, \quad j < k \, .

There are 12n(n−1)\frac{1}{2}n(n-1) such vector fields. Find the commutator [Vjk,Vkℓ][V_{jk}, V_{k\ell }].

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Problem 3.46

The Lie algebra o(2,1)\mathfrak {o}(2,1) admits the basis

D12=−x1∂∂x2+x2∂∂x1,E23=x2∂∂x3+x3∂∂x2,E31=x3∂∂x1+x1∂∂x3 . D_{12} = -x_{1}\frac{\partial }{\partial x_{2}} + x_{2}\frac{\partial }{\partial x_{1}}, \qquad E_{23} = x_{2}\frac{\partial }{\partial x_{3}} + x_{3}\frac{\partial }{\partial x_{2}}, \qquad E_{31} = x_{3}\frac{\partial }{\partial x_{1}} + x_{1}\frac{\partial }{\partial x_{3}} \, .

Find the commutators.

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Problem 3.47

Let n≥2n \geq 2 and 0≤p≤n0 \leq p \leq n. The real semisimple Lie algebra o(p,n−p)\mathfrak {o}(p,n-p) is of dimension 12n(n−1)\frac{1}{2}n(n-1) and is spanned by the vector fields

Dkj=−Djk,Ekj=Ejk D_{kj} = -D_{jk}, \qquad E_{kj} = E_{jk} Djk=−xj∂∂xk+xk∂∂xj,1≤j<k≤p,p<j<k≤n D_{jk} = -x_{j}\frac{\partial }{\partial x_{k}} + x_{k}\frac{\partial }{\partial x_{j}}, \qquad 1 \leq j < k \leq p, \quad p < j < k \leq n Ejk=xj∂∂xk+xk∂∂xj,1≤j≤p,p<k≤n . E_{jk} = x_{j}\frac{\partial }{\partial x_{k}} + x_{k}\frac{\partial }{\partial x_{j}}, \qquad 1 \leq j \leq p, \quad p < k \leq n \, .

Find the commutators.

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Problem 3.48

Let z,w∈Cz, w \in \mathbb {C}. Consider the vector fields

T1=−w2i∂∂z−z2i∂∂w,T2=−w2∂∂z+z2∂∂w,T3=z2∂∂z−w2∂∂w . T_{1} = -\frac{w}{2i}\frac{\partial }{\partial z} - \frac{z}{2i}\frac{\partial }{\partial w}, \qquad T_{2} = -\frac{w}{2}\frac{\partial }{\partial z} + \frac{z}{2}\frac{\partial }{\partial w}, \qquad T_{3} = \frac{z}{2}\frac{\partial }{\partial z} - \frac{w}{2}\frac{\partial }{\partial w} \, .

Find the commutators [T1,T2],[T2,T3],[T3,T1][T_{1},T_{2}], [T_{2},T_{3}], [T_{3},T_{1}]. Let

T+:=T1+iT2,T−:=T1−iT2 . T_{+} := T_{1} + iT_{2}, \qquad T_{-} := T_{1} - iT_{2} \, .

Find T+T_{+} and T−T_{-}. Consider the function zmwnz^{m}w^{n}, where mm is a nonnegative integer and nn is a negative integer with n<−mn < -m. Show that zmwnz^{m}w^{n} is an eigenfunction of T3T_{3}. Find the eigenvalue. Find T+(zmwn)T_{+}(z^{m}w^{n}) and T−(zmwn)T_{-}(z^{m}w^{n}).

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Problem 3.49

Consider the operators

Lx=i(cos⁡(ϕ)cot⁡(α)∂∂ϕ+sin⁡(ϕ)∂∂α) L_{x} = i\left( \cos (\phi )\cot (\alpha )\frac{\partial }{\partial \phi } + \sin (\phi )\frac{\partial }{\partial \alpha } \right) Ly=i(sin⁡(ϕ)cot⁡(α)∂∂ϕ−cos⁡(ϕ)∂∂α) L_{y} = i\left( \sin (\phi )\cot (\alpha )\frac{\partial }{\partial \phi } - \cos (\phi )\frac{\partial }{\partial \alpha } \right) Lz=−i∂∂ϕ . L_{z} = -i\frac{\partial }{\partial \phi } \, .

By calculating the commutators [Lx,Ly],[Ly,Lz],[Lz,Lx][L_{x},L_{y}], [L_{y},L_{z}], [L_{z},L_{x}] show that we have a basis of a Lie algebra.

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Problem 3.50

Consider the linear differential operators

Sz=−xddx+ℓ,S−=x,S+=−xd2dx2+2ℓddx S_{z} = -x\frac{d}{dx} + \ell , \qquad S_{-} = x, \qquad S_{+} = -x\frac{d^{2}}{dx^{2}} + 2\ell \frac{d}{dx}

acting on an analytic function ff. Find the commutators [S+,S−],[S+,Sz],[S−,Sz][S_{+},S_{-}], [S_{+},S_{z}], [S_{-},S_{z}]. Discuss.

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Problem 3.51

Let σ1,σ2,σ3\sigma_{1}, \sigma_{2}, \sigma_{3} be the Pauli spin matrices with the commutation relation

[σ1,σ2]=2iσ3,[σ2,σ3]=2iσ1,[σ3,σ1]=2iσ2 . [\sigma _{1},\sigma _{2}] = 2i\sigma _{3}, \qquad [\sigma _{2},\sigma _{3}] = 2i\sigma _{1}, \qquad [\sigma _{3},\sigma _{1}] = 2i\sigma _{2} \, .

Thus we have

su(2)=⟨iσ1,iσ2,iσ3⟩ . \mathfrak {su}(2) = \left\langle i\sigma _{1}, i\sigma _{2}, i\sigma _{3}\right\rangle \, .

Let ⊗\otimes be the Kronecker product. Find the three commutators

[σ1⊗I2+I2⊗σ2,  σ2⊗I2+I2⊗σ3] [\sigma _{1} \otimes I_{2} + I_{2} \otimes \sigma _{2}, \; \sigma _{2} \otimes I_{2} + I_{2} \otimes \sigma _{3}] [σ2⊗I2+I2⊗σ3,  σ3⊗I2+I2⊗σ1] [\sigma _{2} \otimes I_{2} + I_{2} \otimes \sigma _{3}, \; \sigma _{3} \otimes I_{2} + I_{2} \otimes \sigma _{1}] [σ3⊗I2+I2⊗σ1,  σ2⊗I2+I2⊗σ3] . [\sigma _{3} \otimes I_{2} + I_{2} \otimes \sigma _{1}, \; \sigma _{2} \otimes I_{2} + I_{2} \otimes \sigma _{3}] \, .

Discuss.

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Problem 3.52

The Pauli spin matrices are given by

σ1:=(0110),σ2:=(0−ii0),σ3:=(100−1) . \sigma _{1} := \begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix}, \qquad \sigma _{2} := \begin{pmatrix} 0 & -i \\ i & 0 \end{pmatrix}, \qquad \sigma _{3} := \begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix} \, .

Their multiplication table is

σ1σ2=−σ2σ1=iσ3,σ2σ3=−σ3σ2=iσ1,σ3σ1=−σ1σ3=iσ2 . \sigma _{1}\sigma _{2} = -\sigma _{2}\sigma _{1} = i\sigma _{3}, \qquad \sigma _{2}\sigma _{3} = -\sigma _{3}\sigma _{2} = i\sigma _{1}, \qquad \sigma _{3}\sigma _{1} = -\sigma _{1}\sigma _{3} = i\sigma _{2} \, .

Let

A:=σ1⊗I2,B:=σ2⊗I2,C:=σ3⊗I2 . A := \sigma _{1} \otimes I_{2}, \qquad B := \sigma _{2} \otimes I_{2}, \qquad C := \sigma _{3} \otimes I_{2} \, .

Find the commutators [A,B],[B,C],[C,A][A,B], [B,C], [C,A].

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Problem 3.53

Consider the Pauli spin matrices σ1,σ2,σ3\sigma_{1}, \sigma_{2}, \sigma_{3} and the 4×44 \times 4 matrices

σ1⊗σ2,σ2⊗σ3,σ3⊗σ2 . \sigma _{1} \otimes \sigma _{2}, \qquad \sigma _{2} \otimes \sigma _{3}, \qquad \sigma _{3} \otimes \sigma _{2} \, .

Find the commutators

[σ1⊗σ2,σ2⊗σ3],[σ2⊗σ3,σ3⊗σ1],[σ3⊗σ1,σ1⊗σ2] . [\sigma _{1} \otimes \sigma _{2}, \sigma _{2} \otimes \sigma _{3}], \qquad [\sigma _{2} \otimes \sigma _{3}, \sigma _{3} \otimes \sigma _{1}], \qquad [\sigma _{3} \otimes \sigma _{1}, \sigma _{1} \otimes \sigma _{2}] \, .

Discuss.

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Problem 3.54

Consider the 4×44 \times 4 matrices

S1=(0110)⊗I2,S2=I2⊗(100ω) S_{1} = \begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix} \otimes I_{2}, \qquad S_{2} = I_{2} \otimes \begin{pmatrix} 1 & 0 \\ 0 & \omega \end{pmatrix}

where ω=exp(iπ)=−1\omega = \mathrm{exp}\left(i\pi \right) = -1. Find S12,S22,S1S2S1−1S2−1S_{1}^{2}, S_{2}^{2}, S_{1}S_{2}S_{1}^{-1}S_{2}^{-1} and the commutator [S1,S2][S_{1},S_{2}].

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Problem 3.55

Let ω=exp(2πi/4)≡exp(πi/2)=i\omega = \mathrm{exp}\left(2\pi i/4\right) \equiv \mathrm{exp}\left(\pi i/2\right) = i. Consider the four 64×6464 \times 64 invertible matrices

S1=(10000ω0000ω20000ω3)⊗(10000ω30000ω20000ω)⊗I4 S_{1} = \begin{pmatrix} 1 & 0 & 0 & 0 \\ 0 & \omega & 0 & 0 \\ 0 & 0 & \omega ^{2} & 0 \\ 0 & 0 & 0 & \omega ^{3} \end{pmatrix} \otimes \begin{pmatrix} 1 & 0 & 0 & 0 \\ 0 & \omega ^{3} & 0 & 0 \\ 0 & 0 & \omega ^{2} & 0 \\ 0 & 0 & 0 & \omega \end{pmatrix} \otimes I_{4} S2=I4⊗(0100001000011000)⊗I4 S_{2} = I_{4} \otimes \begin{pmatrix} 0 & 1 & 0 & 0 \\ 0 & 0 & 1 & 0 \\ 0 & 0 & 0 & 1 \\ 1 & 0 & 0 & 0 \end{pmatrix} \otimes I_{4} S3=I4⊗(10000ω0000ω20000ω3)⊗(10000ω30000ω20000ω) S_{3} = I_{4} \otimes \begin{pmatrix} 1 & 0 & 0 & 0 \\ 0 & \omega & 0 & 0 \\ 0 & 0 & \omega ^{2} & 0 \\ 0 & 0 & 0 & \omega ^{3} \end{pmatrix} \otimes \begin{pmatrix} 1 & 0 & 0 & 0 \\ 0 & \omega ^{3} & 0 & 0 \\ 0 & 0 & \omega ^{2} & 0 \\ 0 & 0 & 0 & \omega \end{pmatrix} S4=I4⊗I4⊗(0100001000011000) . S_{4} = I_{4} \otimes I_{4} \otimes \begin{pmatrix} 0 & 1 & 0 & 0 \\ 0 & 0 & 1 & 0 \\ 0 & 0 & 0 & 1 \\ 1 & 0 & 0 & 0 \end{pmatrix} \, .
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(i)

Find Sj4S_{j}^{4} for j=1,2,3,4j = 1,2,3,4.

(ii)

Find

S1S2S1−1S2−1,S2S3S2−1S3−1,S3S4S3−1S4−1,S4S1S4−1S1−1 . S_{1}S_{2}S_{1}^{-1}S_{2}^{-1}, \quad S_{2}S_{3}S_{2}^{-1}S_{3}^{-1}, \quad S_{3}S_{4}S_{3}^{-1}S_{4}^{-1}, \quad S_{4}S_{1}S_{4}^{-1}S_{1}^{-1} \, .
(iii)

Find the commutators [S1,S2],[S2,S3],[S3,S4],[S4,S1][S_{1},S_{2}], [S_{2},S_{3}], [S_{3},S_{4}], [S_{4},S_{1}].

Problem 3.56
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(i)

Consider the non-commutative two dimensional Lie algebra with [A,B]=A[A,B] = A and

A=(0100),B=(0001) . A = \begin{pmatrix} 0 & 1 \\ 0 & 0 \end{pmatrix}, \qquad B = \begin{pmatrix} 0 & 0 \\ 0 & 1 \end{pmatrix} \, .

Show that the matrices

{A⊗I2+I2⊗A,  B⊗I2+I2⊗B} \{ A \otimes I_{2} + I_{2} \otimes A, \; B \otimes I_{2} + I_{2} \otimes B \}

also form a non-commutative Lie algebra under the commutator, where ⊗\otimes denotes the Kronecker product. Discuss.

(ii)

We denote by sl(2,R)\mathfrak {sl}(2,\mathbb {R}) the semisimple Lie algebra spanned by a basis {E,F,H}\{ E,F,H\} with the Lie bracket defined by

[H,E]=2E,[H,F]=−2F,[E,F]=H . [H,E] = 2E, \qquad [H,F] = -2F, \qquad [E,F] = H \, .

Using 2×22 \times 2 matrices we have the representation

H=(100−1),F=(0010),E=(0100) . H = \begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix}, \qquad F = \begin{pmatrix} 0 & 0 \\ 1 & 0 \end{pmatrix}, \qquad E = \begin{pmatrix} 0 & 1 \\ 0 & 0 \end{pmatrix} \, .

Let ⊗\otimes be the Kronecker product. Do the three 4×44 \times 4 matrices

H⊗I2+I2⊗H,F⊗I2+I2⊗F,E⊗I2+I2⊗E H \otimes I_{2} + I_{2} \otimes H, \qquad F \otimes I_{2} + I_{2} \otimes F, \qquad E \otimes I_{2} + I_{2} \otimes E

form a basis of a Lie algebra? Calculate the commutators.

Problem 3.57

Consider the Lie algebra sl(2,R)\mathfrak {sl}(2,\mathbb {R}) with

x=(0100),y=(0010),h=(100−1) x = \begin{pmatrix} 0 & 1 \\ 0 & 0 \end{pmatrix}, \qquad y = \begin{pmatrix} 0 & 0 \\ 1 & 0 \end{pmatrix}, \qquad h = \begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix}

and the commutators [x,h]=−2x[x,h] = -2x, [x,y]=h[x,y] = h, [y,h]=2y[y,h] = 2y. Consider

h↦h⊗I2+I2⊗h,x↦x⊗h+h⊗x,y↦y⊗h+h⊗y . h \mapsto h \otimes I_{2} + I_{2} \otimes h, \qquad x \mapsto x \otimes h + h \otimes x, \qquad y \mapsto y \otimes h + h \otimes y \, .

Find the three commutators

[h⊗I2+I2⊗h,  x⊗h+h⊗x],[h⊗I2+I2⊗h,  y⊗h+h⊗y],[x⊗h+h⊗x,  y⊗h+h⊗y] [h\otimes I_{2}+I_{2}\otimes h, \; x\otimes h+h\otimes x], \quad [h\otimes I_{2}+I_{2}\otimes h, \; y\otimes h+h\otimes y], \quad [x\otimes h+h\otimes x, \; y\otimes h+h\otimes y]

and thus show that we have a Lie algebra. Is this Lie algebra isomorphic to sl(2,R)\mathfrak {sl}(2,\mathbb {R})?

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Problem 3.58

The four matrices

X=(0100),Y=(0010),H=(100−1),I2=(1001) X = \begin{pmatrix} 0 & 1 \\ 0 & 0 \end{pmatrix}, \qquad Y = \begin{pmatrix} 0 & 0 \\ 1 & 0 \end{pmatrix}, \qquad H = \begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix}, \qquad I_{2} = \begin{pmatrix} 1 & 0 \\ 0 & 1 \end{pmatrix}

form a basis of the Lie algebra gl(2,R)\mathfrak {gl}(2,\mathbb {R}). We have

[X,Y]=H,[H,X]=2X,[H,Y]=−2Y [X,Y] = H, \qquad [H,X] = 2X, \qquad [H,Y] = -2Y

and [I2,X]=[I2,Y]=[I2,H]=02[I_{2},X] = [I_{2},Y] = [I_{2},H] = 0_{2}. Can one find an invertible matrix SS over R\mathbb {R} such that

SXS−1=Y,SYS−1=X,SHS−1=−H  ? SXS^{-1} = Y, \qquad SYS^{-1} = X, \qquad SHS^{-1} = -H \; ?
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Problem 3.59

Let AA be an arbitrary n×nn \times n matrix over C\mathbb {C}. Let T1,T2T_{1}, T_{2} be n×nn \times n matrices over C\mathbb {C} satisfying

T1∗A+AT1=0,T2∗A+AT2=0 . T_{1}^{*}A + AT_{1} = 0, \qquad T_{2}^{*}A + AT_{2} = 0 \, .

Show that

[T1,T2]∗A+A[T1,T2]=0 . [T_{1},T_{2}]^{*}A + A[T_{1},T_{2}] = 0 \, .
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Problem 3.60

Show that the dimension of a Cartan sub-Lie algebra is not in general the maximal dimension of an abelian sub-Lie algebra. Consider the Lie algebra sl(2n,C)\mathfrak {sl}(2n,\mathbb {C}) of 2n×2n2n \times 2n matrices of trace 0.

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Problem 3.61

Show that the Lie algebras sl(2,C)\mathfrak {sl}(2,\mathbb {C}) and so(3,C)\mathfrak {so}(3,\mathbb {C}) are isomorphic.

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Problem 3.62

Let LL be any Lie algebra. If x,y∈Lx, y \in L, define

κ(x,y):=\tr(ad⁡xad⁡y) \kappa (x,y) := \tr (\operatorname {ad}x \operatorname {ad}y)

where κ\kappa is called the Killing form and \tr(⋅)\tr (\cdot ) denotes the trace.

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(i)

Show that

κ([x,y],z)=κ(x,[y,z]) . \kappa ([x,y],z) = \kappa (x,[y,z]) \, .
(ii)

If B1B_{1} and B2B_{2} are subspaces of a Lie algebra LL, we define [B1,B2][B_{1},B_{2}] to be the subspace spanned by all products [b1,b2][b_{1},b_{2}] with b1∈B1b_{1} \in B_{1} and b2∈B2b_{2} \in B_{2}. This is the set of sums

∑j[b1j,b2j] \sum _{j} [b_{1j}, b_{2j}]

where b1j∈B1b_{1j} \in B_{1} and b2j∈B2b_{2j} \in B_{2}. Let

L(1):=[L,L],L(2):=[L,L(1)],…,L(k):=[L,L(k−1)] . L_{(1)} := [L,L], \qquad L_{(2)} := [L,L_{(1)}], \qquad \ldots , \qquad L_{(k)} := [L,L_{(k-1)}] \, .

A Lie algebra LL is called nilpotent if

L(n)={0} L_{(n)} = \{ 0\}

for some positive integer nn. Prove that if LL is nilpotent, the Killing form of LL is identically zero.

Problem 3.63

Let gl(n,R)\mathfrak {gl}(n,\mathbb {R}) be the Lie algebra of all n×nn \times n matrices over R\mathbb {R}. Let

x∈gl(n,R)(1) x \in \mathfrak {gl}(n,\mathbb {R}) \tag {1}

have nn distinct eigenvalues λ1,…,λn\lambda_{1}, \ldots , \lambda_{n} in R\mathbb {R}. Prove that the eigenvalues of the n2×n2n^{2} \times n^{2} matrix

ad⁡x(2) \operatorname {ad}x \tag {2}

are the n2n^{2} scalars λi−λj\lambda_{i} - \lambda_{j}, where i,j=1,2,…,ni,j = 1,2,\ldots ,n.

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Problem 3.64

Consider the Lie algebra so(4)\mathfrak {so}(4). Show that the Lie algebra so(4)\mathfrak {so}(4) is semisimple, but not simple. Consider as a basis of so(4)\mathfrak {so}(4) the six vector fields

V12=x2∂∂x1−x1∂∂x2,V23=x3∂∂x2−x2∂∂x3,V31=x1∂∂x3−x3∂∂x1 V_{12} = x_{2}\frac{\partial }{\partial x_{1}} - x_{1}\frac{\partial }{\partial x_{2}}, \qquad V_{23} = x_{3}\frac{\partial }{\partial x_{2}} - x_{2}\frac{\partial }{\partial x_{3}}, \qquad V_{31} = x_{1}\frac{\partial }{\partial x_{3}} - x_{3}\frac{\partial }{\partial x_{1}} W41=x1∂∂x4−x4∂∂x1,W42=x2∂∂x4−x4∂∂x2,W43=x3∂∂x4−x4∂∂x3 . W_{41} = x_{1}\frac{\partial }{\partial x_{4}} - x_{4}\frac{\partial }{\partial x_{1}}, \qquad W_{42} = x_{2}\frac{\partial }{\partial x_{4}} - x_{4}\frac{\partial }{\partial x_{2}}, \qquad W_{43} = x_{3}\frac{\partial }{\partial x_{4}} - x_{4}\frac{\partial }{\partial x_{3}} \, .
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Problem 3.65

Consider the semisimple Lie algebra so(2,1)\mathfrak {so}(2,1) whose elements X1,X2,X3X_{1}, X_{2}, X_{3} satisfy the commutation relations

[X1,X2]=X3,[X2,X3]=−X1,[X3,X1]=X2 . [X_{1},X_{2}] = X_{3}, \qquad [X_{2},X_{3}] = -X_{1}, \qquad [X_{3},X_{1}] = X_{2} \, .
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(i)

Find the adjoint representation.

(ii)

Let YjY_{j} (j=1,…,nj = 1,\ldots ,n) be a basis for a Lie algebra. Then gjk=κ(Yj,Yk)g_{jk} = \kappa (Y_{j},Y_{k}) is called the metric tensor. From the adjoint representation find the metric tensor.

Problem 3.66

Consider the two matrices

A=(0100),B=(0010) . A = \begin{pmatrix} 0 & 1 \\ 0 & 0 \end{pmatrix}, \qquad B = \begin{pmatrix} 0 & 0 \\ 1 & 0 \end{pmatrix} \, .

Show that

[exp(tA),exp(tB)]=t2[A,B] . [\mathrm{exp}\left(tA\right), \mathrm{exp}\left(tB\right)] = t^{2}[A,B] \, .
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Problem 3.67

Let AA be an n×nn \times n matrix over C\mathbb {C}. Show that the n×nn \times n matrices RR over C\mathbb {C} satisfying R∗A+AR=0R^{*}A + AR = 0 form a Lie algebra.

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Problem 3.68

Show that the Lie algebras so(3)\mathfrak {so}(3) and su(2)\mathfrak {su}(2) of the Lie groups SO(3)SO(3) and SU(2)SU(2) are isomorphic.

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Problem 3.69

Consider the Lie algebra sl(2,R)\mathfrak {sl}(2,\mathbb {R}) with the basis H,X,YH, X, Y and the commutators

[H,X]=2X,[H,Y]=−2Y,[X,Y]=H [H,X] = 2X, \qquad [H,Y] = -2Y, \qquad [X,Y] = H

with

H=(100−1),X=(0100),Y=(0010) . H = \begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix}, \qquad X = \begin{pmatrix} 0 & 1 \\ 0 & 0 \end{pmatrix}, \qquad Y = \begin{pmatrix} 0 & 0 \\ 1 & 0 \end{pmatrix} \, .

Assume that v→∈R\overrightarrow {v} \in \mathbb {R} is an eigenvector of HH, i.e. Hv→=αv→H\overrightarrow {v} = \alpha \overrightarrow {v}, where α\alpha is the eigenvalue. Calculate H(Xv→)H(X\overrightarrow {v}). Discuss.

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Problem 3.70

Let S1:={(x1,x2):x12+x22=1}S^{1} := \left\{ (x_{1},x_{2}) : x_{1}^{2}+x_{2}^{2} = 1\right\}. Let Diff⁡+(S1)\operatorname {Diff}^{+}(S^{1}) be the space of orientation-preserving diffeomorphism of S1→S1S^{1} \to S^{1}. With the product given by the composition of diffeomorphism it is an infinite dimensional Lie group. The Lie algebra is the space of vector fields on S1S^{1}. A Lie subalgebra of the complexification of the Lie algebra of Diff⁡+(S1)\operatorname {Diff}^{+}(S^{1}) is given by

L:={f(z)ddz : f(z)∈C[z,z−1]} . L := \left\{ f(z)\frac{d}{dz} \, : \, f(z) \in \mathbb {C}{}[z,z^{-1}] \right\} \, .

This is a subspace of the space of vector fields on S1S^{1}, regarding S1S^{1} as the unit circle in C\mathbb {C}. We choose a basis {Ln}n∈Z\{ L_{n}\}_{n\in \mathbb {Z}} of LL defining

Ln:=−zn+1ddz . L_{n} := -z^{n+1}\frac{d}{dz} \, .

Find the commutator [Ln,Lm][L_{n},L_{m}].

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Problem 3.71

Let σ1,σ2,σ3\sigma_{1}, \sigma_{2}, \sigma_{3} be the Pauli spin matrices. Let I2I_{2} be the 2×22 \times 2 identity matrix and 020_{2} be the 2×22 \times 2 zero matrix. Consider the four 4×44 \times 4 matrices

J1=i2(02σ1−σ102),J2=12(σ20202σ2), J_{1} = \frac{i}{2}\begin{pmatrix} 0_{2} & \sigma _{1} \\ -\sigma _{1} & 0_{2} \end{pmatrix}, \qquad J_{2} = \frac{1}{2}\begin{pmatrix} \sigma _{2} & 0_{2} \\ 0_{2} & \sigma _{2} \end{pmatrix}, J3=i2(02σ3−σ302),J0=i2(02I2−I202) . J_{3} = \frac{i}{2}\begin{pmatrix} 0_{2} & \sigma _{3} \\ -\sigma _{3} & 0_{2} \end{pmatrix}, \qquad J_{0} = \frac{i}{2}\begin{pmatrix} 0_{2} & I_{2} \\ -I_{2} & 0_{2} \end{pmatrix} \, .
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(i)

Find the commutators.

(ii)

Consider the six 4×44 \times 4 matrices

K1=i2(02σ3σ302),K2=i2(I20202−I2),K3=−i2(02σ1σ102), K_{1} = \frac{i}{2}\begin{pmatrix} 0_{2} & \sigma _{3} \\ \sigma _{3} & 0_{2} \end{pmatrix}, \qquad K_{2} = \frac{i}{2}\begin{pmatrix} I_{2} & 0_{2} \\ 0_{2} & -I_{2} \end{pmatrix}, \qquad K_{3} = -\frac{i}{2}\begin{pmatrix} 0_{2} & \sigma _{1} \\ \sigma _{1} & 0_{2} \end{pmatrix}, Q1=−i2(σ30202−σ3),Q2=i2(02I2I202),Q3=i2(σ10202−σ1) . Q_{1} = -\frac{i}{2}\begin{pmatrix} \sigma _{3} & 0_{2} \\ 0_{2} & -\sigma _{3} \end{pmatrix}, \qquad Q_{2} = \frac{i}{2}\begin{pmatrix} 0_{2} & I_{2} \\ I_{2} & 0_{2} \end{pmatrix}, \qquad Q_{3} = \frac{i}{2}\begin{pmatrix} \sigma _{1} & 0_{2} \\ 0_{2} & -\sigma _{1} \end{pmatrix} \, .

Find the commutators. Find also the commutators [Kj,Jk],[Qj,Jk][K_{j},J_{k}], [Q_{j},J_{k}], where j,k=1,2,3j,k = 1,2,3 and [Kj,J0],[Qj,J0][K_{j},J_{0}], [Q_{j},J_{0}]. Thus show that we have a basis of a 10 dimensional Lie algebra.

Problem 3.72
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(i)

Consider the matrices

N1=(00i000000),N2=(00000i000),L=(0−i/20i/200000) . N_{1} = \begin{pmatrix} 0 & 0 & i \\ 0 & 0 & 0 \\ 0 & 0 & 0 \end{pmatrix}, \qquad N_{2} = \begin{pmatrix} 0 & 0 & 0 \\ 0 & 0 & i \\ 0 & 0 & 0 \end{pmatrix}, \qquad L = \begin{pmatrix} 0 & -i/2 & 0 \\ i/2 & 0 & 0 \\ 0 & 0 & 0 \end{pmatrix} \, .

Show that they form a basis of a Lie algebra.

(ii)

Is the Lie algebra semisimple?

Problem 3.73
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(i)

Consider the differential operators

J3=i2(p∂∂x−x∂∂p) J_{3} = \frac{i}{2}\left( p\frac{\partial }{\partial x} - x\frac{\partial }{\partial p} \right)

and

K1=i2(p∂∂p−x∂∂x),K2=−i2(x∂∂p+p∂∂x) . K_{1} = \frac{i}{2}\left( p\frac{\partial }{\partial p} - x\frac{\partial }{\partial x} \right), \qquad K_{2} = -\frac{i}{2}\left( x\frac{\partial }{\partial p} + p\frac{\partial }{\partial x} \right) \, .

Find the commutators. Show that we have a basis for a semisimple Lie algebra.

(ii)

Consider the differential operators

J~3=14(x2−d2dx2) \tilde{J}_{3} = \frac{1}{4}\left( x^{2} - \frac{d^{2}}{dx^{2}} \right)

and

K~1=i4(xddx+ddxx),K~2=14(x2+d2dx2) . \tilde{K}_{1} = \frac{i}{4}\left( x\frac{d}{dx} + \frac{d}{dx}x \right), \qquad \tilde{K}_{2} = \frac{1}{4}\left( x^{2} + \frac{d^{2}}{dx^{2}} \right) \, .

Find the commutators. Show that we have a basis for a semisimple Lie algebra. Are the two Lie algebras isomorphic?

Problem 3.74

Show that the vector fields

J1=−i2((p2∂∂x1+p1∂∂x2)−(x2∂∂p1+x1∂∂p2)) J_{1} = -\frac{i}{2}\left( \left( p_{2}\frac{\partial }{\partial x_{1}} + p_{1}\frac{\partial }{\partial x_{2}} \right) - \left( x_{2}\frac{\partial }{\partial p_{1}} + x_{1}\frac{\partial }{\partial p_{2}} \right) \right) J2=−i2((x1∂∂x2−x2∂∂x1)+(p1∂∂p2−p2∂∂p1)) J_{2} = -\frac{i}{2}\left( \left( x_{1}\frac{\partial }{\partial x_{2}} - x_{2}\frac{\partial }{\partial x_{1}} \right) + \left( p_{1}\frac{\partial }{\partial p_{2}} - p_{2}\frac{\partial }{\partial p_{1}} \right) \right) J3=−i2((p1∂∂x1−p2∂∂x2)−(x1∂∂p1−x2∂∂p2)) J_{3} = -\frac{i}{2}\left( \left( p_{1}\frac{\partial }{\partial x_{1}} - p_{2}\frac{\partial }{\partial x_{2}} \right) - \left( x_{1}\frac{\partial }{\partial p_{1}} - x_{2}\frac{\partial }{\partial p_{2}} \right) \right) J0=−i2((p1∂∂x1+p2∂∂x2)−(x1∂∂p1+x2∂∂p2)) J_{0} = -\frac{i}{2}\left( \left( p_{1}\frac{\partial }{\partial x_{1}} + p_{2}\frac{\partial }{\partial x_{2}} \right) - \left( x_{1}\frac{\partial }{\partial p_{1}} + x_{2}\frac{\partial }{\partial p_{2}} \right) \right) K1=−i2((p1∂∂x1−p2∂∂x2)+(x1∂∂p1−x2∂∂p2)) K_{1} = -\frac{i}{2}\left( \left( p_{1}\frac{\partial }{\partial x_{1}} - p_{2}\frac{\partial }{\partial x_{2}} \right) + \left( x_{1}\frac{\partial }{\partial p_{1}} - x_{2}\frac{\partial }{\partial p_{2}} \right) \right) K2=i2(−(x1∂∂x1+x2∂∂x2)+(p1∂∂p1+p2∂∂p2)) K_{2} = \frac{i}{2}\left( -\left( x_{1}\frac{\partial }{\partial x_{1}} + x_{2}\frac{\partial }{\partial x_{2}} \right) + \left( p_{1}\frac{\partial }{\partial p_{1}} + p_{2}\frac{\partial }{\partial p_{2}} \right) \right) K3=i2((p2∂∂x1+p1∂∂x2)+(x2∂∂p1+x1∂∂p2)) K_{3} = \frac{i}{2}\left( \left( p_{2}\frac{\partial }{\partial x_{1}} + p_{1}\frac{\partial }{\partial x_{2}} \right) + \left( x_{2}\frac{\partial }{\partial p_{1}} + x_{1}\frac{\partial }{\partial p_{2}} \right) \right) Q1=i2((x1∂∂x1−x2∂∂x2)−(p1∂∂p1−p2∂∂p2)) Q_{1} = \frac{i}{2}\left( \left( x_{1}\frac{\partial }{\partial x_{1}} - x_{2}\frac{\partial }{\partial x_{2}} \right) - \left( p_{1}\frac{\partial }{\partial p_{1}} - p_{2}\frac{\partial }{\partial p_{2}} \right) \right) Q2=−i2((p1∂∂x1+p2∂∂x2)+(x1∂∂p1+x2∂∂p2)) Q_{2} = -\frac{i}{2}\left( \left( p_{1}\frac{\partial }{\partial x_{1}} + p_{2}\frac{\partial }{\partial x_{2}} \right) + \left( x_{1}\frac{\partial }{\partial p_{1}} + x_{2}\frac{\partial }{\partial p_{2}} \right) \right) Q3=−i2((x2∂∂x1+x1∂∂x2)−(p2∂∂p1+p1∂∂p2)) Q_{3} = -\frac{i}{2}\left( \left( x_{2}\frac{\partial }{\partial x_{1}} + x_{1}\frac{\partial }{\partial x_{2}} \right) - \left( p_{2}\frac{\partial }{\partial p_{1}} + p_{1}\frac{\partial }{\partial p_{2}} \right) \right)

form a basis of a Lie algebra under the commutator.

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Problem 3.75

Consider the spin-matrices (spin-1)

S+=(020002000),S−=(000200020),Sz=(10000000−1) . S_{+} = \begin{pmatrix} 0 & \sqrt{2} & 0 \\ 0 & 0 & \sqrt{2} \\ 0 & 0 & 0 \end{pmatrix}, \qquad S_{-} = \begin{pmatrix} 0 & 0 & 0 \\ \sqrt{2} & 0 & 0 \\ 0 & \sqrt{2} & 0 \end{pmatrix}, \qquad S_{z} = \begin{pmatrix} 1 & 0 & 0 \\ 0 & 0 & 0 \\ 0 & 0 & -1 \end{pmatrix} \, .

Find the commutators and thus show that we have a basis of a Lie algebra. Show that we have a faithful representation using differential operators by

S+→z∂∂ζ,S−→ζ∂∂z,Sz→12(z∂∂z−ζ∂∂ζ) . S_{+} \to z\frac{\partial }{\partial \zeta }, \qquad S_{-} \to \zeta \frac{\partial }{\partial z}, \qquad S_{z} \to \frac{1}{2}\left( z\frac{\partial }{\partial z} - \zeta \frac{\partial }{\partial \zeta } \right) \, .
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Problem 3.76

Let A,BA, B be n×nn \times n matrices over C\mathbb {C}. Consider the expression

(A⊗B−B⊗A)⊕(−[A,B]) (A \otimes B - B \otimes A) \oplus (-[A,B])

where ⊗\otimes denotes the Kronecker product, ⊕\oplus denotes the direct sum and [ , ][\, , \, ] denotes the commutator. Find the trace of this expression. This expression plays a role for universal enveloping algebras.

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Problem 3.77

Consider the Lie algebra sl(2,R)\mathfrak {sl}(2,\mathbb {R}) with the basis e1,e2,e3e_{1}, e_{2}, e_{3} and the commutators

[e2,e1]=2e1,[e2,e3]=−2e3,[e1,e3]=e2 . [e_{2},e_{1}] = 2e_{1}, \qquad [e_{2},e_{3}] = -2e_{3}, \qquad [e_{1},e_{3}] = e_{2} \, .
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(i)

Find the adjoint representation.

(ii)

Calculate exp(ad⁡e1),exp(ad⁡e2),exp(ad⁡e3)\mathrm{exp}\left(\operatorname {ad}e_{1}\right), \mathrm{exp}\left(\operatorname {ad}e_{2}\right), \mathrm{exp}\left(\operatorname {ad}e_{3}\right).

Problem 3.78

The semisimple Lie algebra sl(3,C)\mathfrak {sl}(3,\mathbb {C}) has dimension 8 and rank 2. The standard basis is given by

h1=(1000−10000),h2=(00001000−1), h_{1} = \begin{pmatrix} 1 & 0 & 0 \\ 0 & -1 & 0 \\ 0 & 0 & 0 \end{pmatrix}, \qquad h_{2} = \begin{pmatrix} 0 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & -1 \end{pmatrix}, e1=(010000000),e2=(000001000), e_{1} = \begin{pmatrix} 0 & 1 & 0 \\ 0 & 0 & 0 \\ 0 & 0 & 0 \end{pmatrix}, \qquad e_{2} = \begin{pmatrix} 0 & 0 & 0 \\ 0 & 0 & 1 \\ 0 & 0 & 0 \end{pmatrix}, f1=(000100000),f2=(000000010), f_{1} = \begin{pmatrix} 0 & 0 & 0 \\ 1 & 0 & 0 \\ 0 & 0 & 0 \end{pmatrix}, \qquad f_{2} = \begin{pmatrix} 0 & 0 & 0 \\ 0 & 0 & 0 \\ 0 & 1 & 0 \end{pmatrix}, e13=(001000000),f13=(000000100) . e_{13} = \begin{pmatrix} 0 & 0 & 1 \\ 0 & 0 & 0 \\ 0 & 0 & 0 \end{pmatrix}, \qquad f_{13} = \begin{pmatrix} 0 & 0 & 0 \\ 0 & 0 & 0 \\ 1 & 0 & 0 \end{pmatrix} \, .

Note that e1=f1Te_{1} = f_{1}^{T}, e2=f2Te_{2} = f_{2}^{T}, e13=f13Te_{13} = f_{13}^{T}. Find the commutation relation table.

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Problem 3.79

Consider the 4×44 \times 4 matrices

J+=(0000001000000000),J−=(0100000000000000), J_{+} = \begin{pmatrix} 0 & 0 & 0 & 0 \\ 0 & 0 & 1 & 0 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 0 \end{pmatrix}, \qquad J_{-} = \begin{pmatrix} 0 & 1 & 0 & 0 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 0 \end{pmatrix}, J3=(0001010000000000),E=(0010000000000000) . J_{3} = \begin{pmatrix} 0 & 0 & 0 & 1 \\ 0 & 1 & 0 & 0 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 0 \end{pmatrix}, \qquad E = \begin{pmatrix} 0 & 0 & 1 & 0 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 0 \end{pmatrix} \, .
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(i)

Find the commutators and thus show that we have a basis of a Lie algebra. Is the Lie algebra semisimple?

(ii)

Let α,β,γ,δ∈R\alpha , \beta , \gamma , \delta \in \mathbb {R}. Calculate

exp(αJ+),exp(βJ−),exp(γJ3),exp(δE) . \mathrm{exp}\left(\alpha J_{+}\right), \quad \mathrm{exp}\left(\beta J_{-}\right), \quad \mathrm{exp}\left(\gamma J_{3}\right), \quad \mathrm{exp}\left(\delta E\right) \, .

Show that exp(αJ+)exp(δE)=exp(δE)exp(αJ+)\mathrm{exp}\left(\alpha J_{+}\right)\mathrm{exp}\left(\delta E\right) = \mathrm{exp}\left(\delta E\right)\mathrm{exp}\left(\alpha J_{+}\right).

Problem 3.80
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(i)

Let U,VU, V be n×nn \times n unitary matrices such that the commutator [U,V]=W[U,V] = W is again a unitary matrix, i.e. W∗=W−1W^{*} = W^{-1}. Show that

R+R−1=In R + R^{-1} = I_{n}

where R=U−1V−1UVR = U^{-1}V^{-1}UV is the group commutator of U−1U^{-1} and V−1V^{-1}.

(ii)

Give an example for such matrices U,VU, V for the case n=2n=2.

Problem 3.81

Let A,BA, B be n×nn \times n matrices over C\mathbb {C}. Assume that [A,B]≡AB−BA=0n[A,B] \equiv AB-BA = 0_{n}. Let ⊗\otimes be the Kronecker product. Can we conclude that

A⊗B−B⊗A=0n2  ? A \otimes B - B \otimes A = 0_{n^{2}} \; ?
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Problem 3.82

Consider the Lie algebra sl(3,C)\mathfrak {sl}(3,\mathbb {C}). Given the roots find the structure constants. The semisimple Lie algebra sl(3,C)\mathfrak {sl}(3,\mathbb {C}) has dimension 8 and rank 2. The root system of sl(3,C)\mathfrak {sl}(3,\mathbb {C}) consists of 6 vectors which go from the origin to vertices of regular hexagon. Check the Jacobi identities for the resulting structure constants.

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Problem 3.83

Consider the semisimple Lie algebra sl(n+1,F)\mathfrak {sl}(n+1,\mathbb {F}). Let Ei,jE_{i,j} (i,j∈{1,2,…,n+1}i,j \in \{ 1,2,\ldots ,n+1\}) denote the standard basis, i.e. (n+1)×(n+1)(n+1) \times (n+1) matrices with all entries zero except for the entry in the iith row and jjth column which is one. We can form a Cartan-Weyl basis with

Hj:=Ej,j−Ej+1,j+1,j∈{1,2,…,n} . H_{j} := E_{j,j} - E_{j+1,j+1}, \qquad j \in \{ 1,2,\ldots ,n\} \, .

Show that Ei,jE_{i,j} are root vectors for i≠ji \neq j, i.e. there exists λH,i,j∈F\lambda_{H,i,j} \in \mathbb {F} such that

[H,Ei,j]=λH,i,jEi,j [H,E_{i,j}] = \lambda _{H,i,j}E_{i,j}

for all H∈⟨H1,…,Hn⟩H \in \left\langle H_{1},\ldots ,H_{n}\right\rangle.

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Problem 3.84
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(i)

Let A,BA, B be n×nn \times n matrices over C\mathbb {C}. Let z∈Cz \in \mathbb {C}. Let u→,v→∈Cn\overrightarrow {u}, \overrightarrow {v} \in \mathbb {C}^{n}. Calculate

exp(z(A⊗B))(u→⊗v→) \mathrm{exp}\left(z(A \otimes B)\right)(\overrightarrow {u} \otimes \overrightarrow {v})

where ⊗\otimes denotes the Kronecker product.

(ii)

Simplify the result from (i) if A2=InA^{2} = I_{n} and B2=InB^{2} = I_{n}.

Problem 3.85

Let A,BA, B be n×nn \times n matrices over C\mathbb {C}. What is the condition on A,BA, B such that

[A⊗B,B⊗A]=0  ? [A \otimes B, B \otimes A] = 0 \; ?
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Problem 3.86

Let A,B,HA, B, H be n×nn \times n matrices such that

[H,A]=0,[H,B]=0 . [H,A] = 0, \qquad [H,B] = 0 \, .

Show that

[H⊗In+In⊗H,A⊗B]=0 . [H \otimes I_{n} + I_{n} \otimes H, A \otimes B] = 0 \, .
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Problem 3.87

Let A1,A2,A3A_{1}, A_{2}, A_{3} be n×nn \times n matrices over C\mathbb {C}. The ternary commutator [A1,A2,A3][A_{1},A_{2},A_{3}] (also called the ternutator) is defined as

[A1,A2,A3]:=∑π∈S3sgn⁡(π)Aπ(1)Aπ(2)Aπ(3)≡A1A2A3+A2A3A1+A3A1A2−A1A3A2−A2A1A3−A3A2A1 . \begin{align} [A_{1},A_{2},A_{3}] & := \sum _{\pi \in S_{3}} \operatorname {sgn}(\pi ) A_{\pi (1)}A_{\pi (2)}A_{\pi (3)} \\ & \equiv A_{1}A_{2}A_{3} + A_{2}A_{3}A_{1} + A_{3}A_{1}A_{2} - A_{1}A_{3}A_{2} - A_{2}A_{1}A_{3} - A_{3}A_{2}A_{1} \, . \end{align}
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(i)

Let n=2n=2 and consider the Pauli spin matrices σx,σy,σz\sigma_{x}, \sigma_{y}, \sigma_{z}. Calculate the ternutator

[σx,σy,σz] . [\sigma _{x}, \sigma _{y}, \sigma _{z}] \, .
(ii)

Calculate

A1⊗A2⊗A3+A2⊗A3⊗A1+A3⊗A1⊗A2−A1⊗A3⊗A2−A2⊗A1⊗A3−A3⊗A2⊗A1 . A_{1}\otimes A_{2}\otimes A_{3} + A_{2}\otimes A_{3}\otimes A_{1} + A_{3}\otimes A_{1}\otimes A_{2} - A_{1}\otimes A_{3}\otimes A_{2} - A_{2}\otimes A_{1}\otimes A_{3} - A_{3}\otimes A_{2}\otimes A_{1} \, .
Problem 3.88

Let c,x∈Rc, x \in \mathbb {R}. Consider the operators

K1=−iccos⁡(x),K2=−icsin⁡(x),K3=−ddx . K_{1} = -ic\cos (x), \qquad K_{2} = -ic\sin (x), \qquad K_{3} = -\frac{d}{dx} \, .

Find the commutators and thus show that we have a basis of a Lie algebra. Is the Lie algebra semisimple?

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Problem 3.89

SU(2)SU(2) is the Lie group of all 2×22 \times 2 unitary unimodular matrices, i.e., the group of all matrices of the form

A=(ab−bˉaˉ),∣a∣2+∣b∣2=1 A = \begin{pmatrix} a & b \\ -\bar{b} & \bar{a} \end{pmatrix}, \qquad \left|a\right|^{2} + \left|b\right|^{2} = 1

where a,b∈Ca, b \in \mathbb {C} and aˉ\bar{a} is the complex conjugate of aa.

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(i)

Find the inverse of AA.

(ii)

The Lie algebra su(2)\mathfrak {su}(2) of the Lie group SU(2)SU(2) can be identified with the vector space of all 2×22 \times 2 complex skew-hermitian matrices of trace 0. A basis of su(2)\mathfrak {su}(2) is given by

G1=(0i/2i/20)=i2σx, G_{1} = \begin{pmatrix} 0 & i/2 \\ i/2 & 0 \end{pmatrix} = \frac{i}{2}\sigma _{x}, G2=(01/2−1/20)=i2σy, G_{2} = \begin{pmatrix} 0 & 1/2 \\ -1/2 & 0 \end{pmatrix} = \frac{i}{2}\sigma _{y}, G3=(−i/200i/2)=−i2σz . G_{3} = \begin{pmatrix} -i/2 & 0 \\ 0 & i/2 \end{pmatrix} = -\frac{i}{2}\sigma _{z} \, .

Find the commutation relations [G1,G2],[G3,G1],[G2,G3][G_{1},G_{2}], [G_{3},G_{1}], [G_{2},G_{3}].

(iii)

Find the matrix

M=exp(ϕ1G3)exp(θG1)exp(ϕ2G3) . M = \mathrm{exp}\left(\phi _{1}G_{3}\right)\mathrm{exp}\left(\theta G_{1}\right)\mathrm{exp}\left(\phi _{2}G_{3}\right) \, .
Problem 3.90

Consider the real Lie algebra LL constructed from a linear vector space with basis

{Aij:i,j=1,2,…,n} . \left\{ A_{ij} : i,j = 1,2,\ldots ,n \right\} \, .

We assume that the structure of the Lie algebra is given by the commutation relations

[Aij,Akℓ]=δkjAiℓ−δℓiAkj [A_{ij}, A_{k\ell }] = \delta _{kj}A_{i\ell } - \delta _{\ell i}A_{kj}

where δij\delta_{ij} is the Kronecker symbol. Hence we consider the Lie algebra gl(n,R)\mathfrak {gl}(n,\mathbb {R}). The dimension of LL is n2n^{2}.

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(i)

Show that the Lie algebra is not simple.

(ii)

Show that the mapping

Aij↦xi∂∂xj A_{ij} \mapsto x_{i}\frac{\partial }{\partial x_{j}}

is a faithful representation of the Lie algebra gl(n,R)\mathfrak {gl}(n,\mathbb {R}).

Problem 3.91

Consider the Lie group O(2,R)O(2,\mathbb {R}) and its Lie algebra o(2,R)\mathfrak {o}(2,\mathbb {R}). Show that O(2,R)O(2,\mathbb {R}) is not commutative. Discuss the properties of o(2,R)\mathfrak {o}(2,\mathbb {R}).

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Problem 3.92

The Euclidean group E(2)E(2) in the plane is associated with the Lie algebra e(2)\mathfrak {e}(2) defined by the commutation relations

[X1,X2]=X3,[X1,X3]=−X2,[X2,X3]=0 . [X_{1},X_{2}] = X_{3}, \qquad [X_{1},X_{3}] = -X_{2}, \qquad [X_{2},X_{3}] = 0 \, .

Show that the Lie algebra is not semisimple.

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Problem 3.93

The vector space of n×nn \times n matrices over R\mathbb {R} form a Hilbert space with the scalar product defined

⟨A,B⟩:=\tr(AB∗) . \left\langle A, B \right\rangle := \tr (AB^{*}) \, .

This implies a norm

∥A∥2=\tr(AA∗) \left\| A\right\| ^{2} = \tr (AA^{*})

and a distance ∥A−B∥2=\tr((A−B)(A−B)∗)\left\| A-B\right\|^{2} = \tr ((A-B)(A-B)^{*}). Consider the matrices

A=(010−100000),B=(00000−1010) A = \begin{pmatrix} 0 & 1 & 0 \\ -1 & 0 & 0 \\ 0 & 0 & 0 \end{pmatrix}, \qquad B = \begin{pmatrix} 0 & 0 & 0 \\ 0 & 0 & -1 \\ 0 & 1 & 0 \end{pmatrix}

which are elements of the simple Lie algebra so(3)\mathfrak {so}(3).

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(i)

Are the matrices orthogonal to each other?

(ii)

Find the distance between AA and BB.

Problem 3.94

Let A,BA, B be n×nn \times n matrices over C\mathbb {C}. We define the quasi-multiplication

A∙B:=12(AB+BA) . A \bullet B := \frac{1}{2}(AB+BA) \, .

Obviously A∙B=B∙AA \bullet B = B \bullet A. Show that (A2∙B)∙A=A2∙(B∙A)(A^{2} \bullet B) \bullet A = A^{2} \bullet (B \bullet A). This is called the Jordan identity. This is an example of a Jordan algebra.

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Problem 3.95

The 2×22 \times 2 matrices

E=(0100),F=(0010),H=(1001) E = \begin{pmatrix} 0 & 1 \\ 0 & 0 \end{pmatrix}, \qquad F = \begin{pmatrix} 0 & 0 \\ 1 & 0 \end{pmatrix}, \qquad H = \begin{pmatrix} 1 & 0 \\ 0 & 1 \end{pmatrix}

form a basis for the Lie algebra sl(2,R)\mathfrak {sl}(2,\mathbb {R}) with the commutators [H,E]=2E[H,E] = 2E, [H,F]=−2F[H,F] = -2F, [E,F]=H[E,F] = H. Let k≥1k \geq 1. Do the matrices (mj=j(k−j+1)m_{j} = j(k-j+1))

ρk(H)=(k00…00k−20…000k−4…0⋮⋮⋮⋱⋮000…−k) \rho _{k}(H) = \begin{pmatrix} k & 0 & 0 & \ldots & 0 \\ 0 & k-2 & 0 & \ldots & 0 \\ 0 & 0 & k-4 & \ldots & 0 \\ \vdots & \vdots & \vdots & \ddots & \vdots \\ 0 & 0 & 0 & \ldots & -k \end{pmatrix} ρk(F)=(000…⋅0100…⋅0010…⋅0⋮⋮⋮…⋅⋮000…10),ρk(E)=(0m10…000m2…0000…0⋮⋮⋮…mk000…0) \rho _{k}(F) = \begin{pmatrix} 0 & 0 & 0 & \ldots & \cdot & 0 \\ 1 & 0 & 0 & \ldots & \cdot & 0 \\ 0 & 1 & 0 & \ldots & \cdot & 0 \\ \vdots & \vdots & \vdots & \ldots & \cdot & \vdots \\ 0 & 0 & 0 & \ldots & 1 & 0 \end{pmatrix}, \qquad \rho _{k}(E) = \begin{pmatrix} 0 & m_{1} & 0 & \ldots & 0 \\ 0 & 0 & m_{2} & \ldots & 0 \\ 0 & 0 & 0 & \ldots & 0 \\ \vdots & \vdots & \vdots & \ldots & m_{k} \\ 0 & 0 & 0 & \ldots & 0 \end{pmatrix}

satisfy the same commutation relations?

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Problem 3.96

The exceptional Lie algebra g2\mathfrak {g}_{2} has the simple roots

(0,1,−1)(1,−2,1) . (0,1,-1) \qquad (1,-2,1) \, .

Find the Cartan matrix. Verify the properties of the Cartan matrix.

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Problem 3.97

If {Xj:j=1,2,…,m}\{ X_{j} : j = 1,2,\ldots ,m \} form a basis for a finite dimensional Lie algebra LL then

gij=K(Xi,Xj) g_{ij} = K(X_{i},X_{j})

is called the metric tensor for LL. In terms of the structure constants,

gij=∑r,s=1mCisrCjrs . g_{ij} = \sum _{r,s=1}^{m} C_{is}^{r}C_{jr}^{s} \, .

For a given semisimple Lie algebra LL with basis {Xj:j=1,…,m}\{ X_{j} : j = 1,\ldots ,m\}, the Casimir operator is a quantity (which is not an element of the Lie algebra) that commutes with each element of the Lie algebra. The quadratic Casimir operator CC of a given semisimple Lie algebra LL is defined by

C:=∑i=1m∑j=1m(gij)XiXj C := \sum _{i=1}^{m}\sum _{j=1}^{m} (g^{ij})X_{i}X_{j}

where (gij)(g^{ij}) is the inverse matrix of (gij)(g_{ij}). Note that the Casimir operator is independent of the choice of the basis. Consider the Lie algebra so(3)\mathfrak {so}(3)

L1:=−i(x2∂∂x3−x3∂∂x2) L_{1} := -i\left( x_{2}\frac{\partial }{\partial x_{3}} - x_{3}\frac{\partial }{\partial x_{2}} \right) L2:=−i(x3∂∂x1−x1∂∂x3) L_{2} := -i\left( x_{3}\frac{\partial }{\partial x_{1}} - x_{1}\frac{\partial }{\partial x_{3}} \right) L3:=−i(x1∂∂x2−x2∂∂x1) L_{3} := -i\left( x_{1}\frac{\partial }{\partial x_{2}} - x_{2}\frac{\partial }{\partial x_{1}} \right)

with the commutation relations [L1,L2]=iL3[L_{1},L_{2}] = iL_{3}, [L2,L3]=iL1[L_{2},L_{3}] = iL_{1}, [L3,L1]=iL2[L_{3},L_{1}] = iL_{2}. Find the quadratic Casimir operator.

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Problem 3.98

Let Z2={0,1}\mathbb {Z}_{2} = \{ 0,1\} be the finite group of integers under addition modulo 2. The super-Lie algebra g=g0+g1\mathfrak {g} = \mathfrak {g}_{0}+\mathfrak {g}_{1} is a Z2\mathbb {Z}_{2}-graded Lie algebra with a super-Lie bracket [ , ][\, , \, ] which satisfies

[A,B]=AB−(−1)d(A)d(B)BA [A,B] = AB - (-1)^{d(A)d(B)}BA

and (super Jacobi identity)

[A,[B,C]]=[[A,B],C]+(−1)d(A)d(B)[B,[A,C]] [A,[B,C]] = [[A,B],C] + (-1)^{d(A)d(B)}[B,[A,C]]

where d(X)=0d(X) = 0 (1) if A∈g0A \in \mathfrak {g}_{0} (g1\mathfrak {g}_{1}). d(A)d(A) is called the degree of AA. We denote by [ , ]−[\, , \, ]_{-} the commutator and by [ , ]+[\, , \, ]_{+} the anticommutator. The super-Lie algebra sl(m/n)\mathfrak {sl}(m/n) is defined by

sl(m/n):={X=(RSTU) : Str⁡(X):=\tr(R)−\tr(U)=0} \mathfrak {sl}(m/n) := \left\{ X = \begin{pmatrix} R & S \\ T & U \end{pmatrix} \, : \, \operatorname {Str}(X) := \tr (R) - \tr (U) = 0 \right\}

where RR is an m×mm \times m matrix, SS a m×nm \times n matrix, TT an n×mn \times m matrix and DD an n×nn \times n matrix. We assume that m≠nm \neq n. Consider the super-Lie algebra sl(2/1)\mathfrak {sl}(2/1). A basis is given by

E1=(010000000),E2=(000001000), E_{1} = \begin{pmatrix} 0 & 1 & 0 \\ 0 & 0 & 0 \\ 0 & 0 & 0 \end{pmatrix}, \qquad E_{2} = \begin{pmatrix} 0 & 0 & 0 \\ 0 & 0 & 1 \\ 0 & 0 & 0 \end{pmatrix}, F1=(000100000),F2=(000000010), F_{1} = \begin{pmatrix} 0 & 0 & 0 \\ 1 & 0 & 0 \\ 0 & 0 & 0 \end{pmatrix}, \qquad F_{2} = \begin{pmatrix} 0 & 0 & 0 \\ 0 & 0 & 0 \\ 0 & 1 & 0 \end{pmatrix}, G1=(001000000),G2=(000000100), G_{1} = \begin{pmatrix} 0 & 0 & 1 \\ 0 & 0 & 0 \\ 0 & 0 & 0 \end{pmatrix}, \qquad G_{2} = \begin{pmatrix} 0 & 0 & 0 \\ 0 & 0 & 0 \\ 1 & 0 & 0 \end{pmatrix}, H1=(1000−10000),H2=(000010001) H_{1} = \begin{pmatrix} 1 & 0 & 0 \\ 0 & -1 & 0 \\ 0 & 0 & 0 \end{pmatrix}, \qquad H_{2} = \begin{pmatrix} 0 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{pmatrix}

i.e. we have four even elements E1,F1,H1,H2E_{1}, F_{1}, H_{1}, H_{2} and four odd elements E2,F2,G1,G2E_{2}, F_{2}, G_{1}, G_{2}. Find the non-vanishing commutators and anticommutators.

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Problem 3.99

Let q>0q > 0. The algebra suq(2)\mathfrak {su}_{q}(2) is generated by X+,X−=(X+)∗X_{+}, X_{-} = (X_{+})^{*} and H=H∗H = H^{*} with deformed commutation relations

[H,X+]=2X+,[H,X−]=−2X−,[X+,X−]=qH−q−Hq−q−1 . [H,X_{+}] = 2X_{+}, \qquad [H,X_{-}] = -2X_{-}, \qquad [X_{+},X_{-}] = \frac{q^{H}-q^{-H}}{q-q^{-1}} \, .

Show by direct computation of the commutators that this algebra has the same matrix representation as the undeformed Lie algebra su(2)\mathfrak {su}(2), i.e.

X+↦(0100),X−↦(0010),H↦(100−1) . X_{+} \mapsto \begin{pmatrix} 0 & 1 \\ 0 & 0 \end{pmatrix}, \qquad X_{-} \mapsto \begin{pmatrix} 0 & 0 \\ 1 & 0 \end{pmatrix}, \qquad H \mapsto \begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix} \, .
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Problem 3.100

Let V,WV, W be smooth vector fields defined in Rn\mathbb {R}^{n}. Let f,g:Rn→Rf,g : \mathbb {R}^{n} \to \mathbb {R} be smooth functions. Consider now the pairs (V,f),(W,g)(V,f), (W,g). One defines a commutator of such pairs as

[(V,f),(W,g)]:=([V,W],LVg−LWf) [(V,f),(W,g)] := ([V,W], L_{V}g - L_{W}f)

where LV(⋅)L_{V}(\cdot ) denotes the Lie derivative. Now [V,W][V,W] is a vector field again and LVg−LVfL_{V}g - L_{V}f is a smooth function again. The Lie derivative is linear and obeys the product rule. Consider n=2n=2. Let

V=u2∂∂u1−u1∂∂u2,W=u1∂∂u1+u2∂∂u2 V = u_{2}\frac{\partial }{\partial u_{1}} - u_{1}\frac{\partial }{\partial u_{2}}, \qquad W = u_{1}\frac{\partial }{\partial u_{1}} + u_{2}\frac{\partial }{\partial u_{2}}

and f(u1,u2)=g(u1,u2)=u12+u22f(u_{1},u_{2}) = g(u_{1},u_{2}) = u_{1}^{2}+u_{2}^{2}. Calculate the commutator.

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Problem 3.101
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(i)

Let LL be a three dimensional Lie algebra with basis a,b,ca, b, c and the commutation relations (simple Lie algebra so(3)\mathfrak {so}(3))

[a,b]=c,[b,c]=a,[c,a]=b . [a,b] = c, \qquad [b,c] = a, \qquad [c,a] = b \, .

Write a SymbolicC++ program to test whether the Jacobi identity is satisfied.

(ii)

Let LL be a three dimensional Lie algebra with basis a,b,ca, b, c and the commutation relations (solvable Lie algebra)

[a,b]=0,[b,c]=a+kb,[c,a]=−ka+b,k>0 . [a,b] = 0, \qquad [b,c] = a+kb, \qquad [c,a] = -ka+b, \qquad k > 0 \, .

Write a SymbolicC++ program to test whether the Jacobi identity is satisfied.

Problem 3.102

Let LL be a Lie algebra. One analyzes the structure of a Lie algebra LL by studying its ideals. A subspace II of a Lie algebra LL is called an ideal of LL if x∈Lx \in L and y∈Iy \in I together imply [x,y]∈I[x,y] \in I. If LL has no ideals except itself and 0, and if moreover [L,L]≠0[L,L] \neq 0 we call the Lie algebra LL simple.

If LL is a Lie algebra and x∈Lx \in L, the operator ad⁡X\operatorname {ad}X that maps yy to [x,y][x,y] is a linear transformation of LL into itself

(ad⁡x)y:=[x,y] . (\operatorname {ad}x)y := [x,y] \, .

Then x→ad⁡xx \to \operatorname {ad}x is a representation of the Lie algebra LL with LL itself considered as the vector space of the representation. The Killing form of a Lie algebra is the symmetric bilinear form

K(x,y):=\tr(ad⁡xad⁡y) K(x,y) := \tr (\operatorname {ad}x\operatorname {ad}y)

where \tr\tr denotes the trace. If xjx_{j} (j=0,1,…,n−1j = 0,1,\ldots ,n-1) form a basis of LL then

gjk=K(xj,xk) g_{jk} = K(x_{j},x_{k})

is called the metric tensor for LL. Note that a Lie algebra is semisimple if and only if the matrix (gjk)(g_{jk}) is nonsingular, i.e., det⁡((gjk))≠0\det ((g_{jk})) \neq 0.

We consider the simple Lie algebra so(3)\mathfrak {so}(3) with the basis elements x(0),x(1),x(2)x(0), x(1), x(2) and the commutation relations

[x(0),x(1)]=x(2),[x(1),x(2)]=x(0),[x(2),x(0)]=x(1) . [x(0),x(1)] = x(2), \qquad [x(1),x(2)] = x(0), \qquad [x(2),x(0)] = x(1) \, .

We find

ad⁡x(0)=(00000−1010),ad⁡x(1)=(001000−100), \operatorname {ad}x(0) = \begin{pmatrix} 0 & 0 & 0 \\ 0 & 0 & -1 \\ 0 & 1 & 0 \end{pmatrix}, \qquad \operatorname {ad}x(1) = \begin{pmatrix} 0 & 0 & 1 \\ 0 & 0 & 0 \\ -1 & 0 & 0 \end{pmatrix}, ad⁡x(2)=(0−10100000) . \operatorname {ad}x(2) = \begin{pmatrix} 0 & -1 & 0 \\ 1 & 0 & 0 \\ 0 & 0 & 0 \end{pmatrix} \, .

Write a SymbolicC++ program that calculates the metric tensor for this Lie algebra using a two-dimensional array comm(i,j) to store the commutators, and determines whether the Lie algebra is semisimple.

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Problem 3.103

Let LL be a Lie algebra. Given H,K⊂LH, K \subset L. We define their bracket by

[H,K]:=⟨[h,k] : h∈H, k∈K⟩ . [H,K] := \left\langle [h,k] \, : \, h \in H, \, k \in K \right\rangle \, .

The derived Lie algebra of LL is the ideal [L,L][L,L]. Show that the quotient Lie algebra L/[L,L]L/[L,L] is an abelian Lie algebra.

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Problem 3.104

Show that the Lie algebra consisting of n×nn \times n matrices over R\mathbb {R} (or C\mathbb {C}) with zeros below the main diagonal is solvable but not nilpotent.

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Problem 3.105
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(i)

Let LL be a finite-dimensional Lie algebra over a field F\mathbb {F}. The linear map κ:L×L→F\kappa : L \times L \to \mathbb {F} defined by

κ(a,b):=\tr(ad⁡(a)ad⁡(b)) \kappa (a,b) := \tr (\operatorname {ad}(a)\operatorname {ad}(b))

is called the Cartan-Killing form or Killing form of LL, where \tr\tr denotes the trace. Show that

κ([a,b],c)=κ(a,[b,c]) . \kappa ([a,b],c) = \kappa (a,[b,c]) \, .
(ii)

Consider the Cartan-Killing form of the finite-dimensional linear Lie algebra gl(n,R)\mathfrak {gl}(n,\mathbb {R}). Show that

κ(X,Y)=\tr((ad⁡X)(ad⁡Y))=2n\tr(XY)−2(\trX)(\trY) . \kappa (X,Y) = \tr ((\operatorname {ad}X)(\operatorname {ad}Y)) = 2n\tr (XY) - 2(\tr X)(\tr Y) \, .
Problem 3.106

Let A,BA, B be 2×22 \times 2 matrices over C\mathbb {C}. We define

A⋆B:=(a1100a120b11b1200b21b220a2100a22) . A \star B := \begin{pmatrix} a_{11} & 0 & 0 & a_{12} \\ 0 & b_{11} & b_{12} & 0 \\ 0 & b_{21} & b_{22} & 0 \\ a_{21} & 0 & 0 & a_{22} \end{pmatrix} \, .

Consider the Lie algebra sl(2,R)\mathfrak {sl}(2,\mathbb {R}) with the basis

h=(100−1),e=(0100),f=(0010) . h = \begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix}, \qquad e = \begin{pmatrix} 0 & 1 \\ 0 & 0 \end{pmatrix}, \qquad f = \begin{pmatrix} 0 & 0 \\ 1 & 0 \end{pmatrix} \, .

Find h⋆hh \star h, e⋆ee \star e, f⋆ff \star f. Calculate the commutators

[e⋆e,f⋆f],[h⋆h,e⋆e],[h⋆h,f⋆f] . [e\star e, f\star f], \qquad [h\star h, e\star e], \qquad [h\star h, f\star f] \, .

Discuss.

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Problem 3.107

Do the vector fields

∂∂xj,xk∂∂xj,xℓxk∂∂xj,j,k,ℓ=1,…,n \frac{\partial }{\partial x_{j}}, \qquad x_{k}\frac{\partial }{\partial x_{j}}, \qquad x_{\ell }x_{k}\frac{\partial }{\partial x_{j}}, \qquad j,k,\ell = 1,\ldots ,n

form a Lie algebra under the commutator? If so classify the Lie algebra. Consider first the case n=1n=1.

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Problem 3.108

Let s=0,1/2,1,3/2,…s = 0, 1/2, 1, 3/2, \ldots. The spin ss generators of the Lie algebra sl(2,C)\mathfrak {sl}(2,\mathbb {C}) at site kk are given by

S+,k=zk2∂∂zk−2szk,S−,k=−∂∂zk,S3,k=zk∂∂zk−s . S_{+,k} = z_{k}^{2}\frac{\partial }{\partial z_{k}} - 2sz_{k}, \qquad S_{-,k} = -\frac{\partial }{\partial z_{k}}, \qquad S_{3,k} = z_{k}\frac{\partial }{\partial z_{k}} - s \, .

Find the commutators.

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Problem 3.109

Let k≥1k \geq 1. Do the vector fields

∂∂x,∂∂u,x∂∂u,…,xk∂∂u,x∂∂x+(k+1)u∂∂u \frac{\partial }{\partial x}, \quad \frac{\partial }{\partial u}, \quad x\frac{\partial }{\partial u}, \quad \ldots , \quad x^{k}\frac{\partial }{\partial u}, \quad x\frac{\partial }{\partial x} + (k+1)u\frac{\partial }{\partial u}

form a basis of a Lie algebra under the commutator? If so classify the Lie algebra.

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Problem 3.110

The infinitesimal generators (vector fields) of the six dimensional Lie algebra so(4)\mathfrak {so}(4) can be written in terms of the variables (x1,x2,x3,x4)(x_{1},x_{2},x_{3},x_{4}) as

X1=x3∂∂x2−x2∂∂x3,X2=x1∂∂x3−x3∂∂x1,X3=x2∂∂x1−x1∂∂x2, X_{1} = x_{3}\frac{\partial }{\partial x_{2}} - x_{2}\frac{\partial }{\partial x_{3}}, \qquad X_{2} = x_{1}\frac{\partial }{\partial x_{3}} - x_{3}\frac{\partial }{\partial x_{1}}, \qquad X_{3} = x_{2}\frac{\partial }{\partial x_{1}} - x_{1}\frac{\partial }{\partial x_{2}}, Y1=x1∂∂x4−x4∂∂x1,Y2=x2∂∂x4−x4∂∂x2,Y3=x3∂∂x4−x4∂∂x3 . Y_{1} = x_{1}\frac{\partial }{\partial x_{4}} - x_{4}\frac{\partial }{\partial x_{1}}, \qquad Y_{2} = x_{2}\frac{\partial }{\partial x_{4}} - x_{4}\frac{\partial }{\partial x_{2}}, \qquad Y_{3} = x_{3}\frac{\partial }{\partial x_{4}} - x_{4}\frac{\partial }{\partial x_{3}} \, .
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(i)

Find the commutators.

(ii)

Show that the Lie algebra is semisimple, but not simple.

(iii)

Find elements of the compact Lie group SO(4)SO(4) by calculating

exp(α1X1+α2X2+α3X3+β1Y1+β2Y2+β3Y3) \mathrm{exp}\left(\alpha _{1}X_{1}+\alpha _{2}X_{2}+\alpha _{3}X_{3}+\beta _{1}Y_{1}+\beta _{2}Y_{2}+\beta _{3}Y_{3}\right)

and

exp(α1X1)exp(α2X2)exp(α3X3)exp(β1Y1)exp(β2Y2)exp(β3Y3) \mathrm{exp}\left(\alpha _{1}X_{1}\right)\mathrm{exp}\left(\alpha _{2}X_{2}\right)\mathrm{exp}\left(\alpha _{3}X_{3}\right)\mathrm{exp}\left(\beta _{1}Y_{1}\right)\mathrm{exp}\left(\beta _{2}Y_{2}\right)\mathrm{exp}\left(\beta _{3}Y_{3}\right)

where αj,βj∈R\alpha_{j}, \beta_{j} \in \mathbb {R}.