Section 18

Computing Values of Regular Branches of Multivalued Functions. Laurent Series for Regular Branches.

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Problem 18.1

Let GG be a simply connected domain not containing the points z=0z = 0 and z=∞z = \infty, but containing the point z=1z = 1. Determine how many distinct regular branches φ(z)\varphi (z) in the domain GG, satisfying the indicated condition, the following multivalued functions admit:

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(1)

(z−1)Ln⁡z,φ(1)=0(z-1) \operatorname {Ln} z, \varphi (1) = 0;

(2)

{zz},φ(1)=1\left\{ z^{z}\right\} , \varphi (1) = 1;

(3)

{ziz},φ(1)=1\left\{ z^{i z}\right\} , \varphi (1) = 1;

(4)

{z1/2z},φ(1)=1\left\{ z^{1 / 2 z}\right\} , \varphi (1) = 1;

(5)

{z1/4z},φ(1)=1\left\{ z^{1 / 4 z}\right\} , \varphi (1) = 1;

(6)

{zz},φ′(1)=1\left\{ z^{z}\right\} , \varphi^{\prime }(1) = 1.

Problem 18.2

Let φ(z)\varphi (z) be a regular branch of the multivalued function Ln⁡(z+i)\operatorname {Ln}(z+i) in a domain GG, satisfying the condition φ(1−i)=0\varphi (1-i) = 0. Find the value φ(−1−i)\varphi (-1-i) in the cases when the domain GG is:

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(1)

the entire complex plane with a cut along the ray [−i∞,−i][-i \infty ,-i];

(2)

the entire complex plane with a cut along the ray [−i,+i∞][-i,+i \infty ].

Problem 18.3

Let GG be the entire complex plane with cuts along the rays [−∞,−1][-\infty ,-1] and [1,+∞][1,+\infty ], and let φ(z)\varphi (z) be a regular branch of the multivalued function Ln⁡(1−z2)\operatorname {Ln}\left(1-z^{2}\right) in the domain GG, satisfying the condition φ(0)=0\varphi (0) = 0. Find:

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(1)

φ(i)\varphi (i);

(2)

φ(−i)\varphi (-i);

(3)

φ(1+i2)\varphi \left(\frac{1+i}{\sqrt{2}}\right);

(4)

φ(1−i2)\varphi \left(\frac{1-i}{\sqrt{2}}\right).

Problem 18.4

Let GG be the entire extended complex plane with a cut along the segment [−1,1][-1,1]. Denote by φ1(z)\varphi_{1}(z) a regular branch of the multivalued function {1+z1−z}\left\{ \sqrt{\frac{1+z}{1-z}}\right\} in the domain GG, satisfying the condition φ1(+i0)=1\varphi_{1}(+i 0) = 1, and by φ2(z)\varphi_{2}(z) a regular branch of the multivalued function Ln⁡1+z1−z\operatorname {Ln} \frac{1+z}{1-z} in the domain GG, satisfying the condition φ2(−i0)=0\varphi_{2}(-i 0) = 0. Find the quantities:

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(1)

φ1(−i0)\varphi_{1}(-i 0);

(2)

φ1(−i)\varphi_{1}(-i);

(3)

φ2(+i0)\varphi_{2}(+i 0);

(4)

φ2(i)\varphi_{2}(i).

Problem 18.5

Let GG be the entire extended complex plane with a cut along the straight-line segment [−i,i][-i, i], and let φ(z)\varphi (z) be a regular branch of the multivalued function Ln⁡1+iz1−iz\operatorname {Ln} \frac{1+i z}{1-i z} in the domain GG, satisfying the condition φ(1)=πi/2\varphi (1) = \pi i / 2. Find the values:

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(1)

φ(−0)\varphi (-0);

(2)

φ(−1)\varphi (-1);

(3)

φ(−3)\varphi (-\sqrt{3});

(4)

φ(∞)\varphi (\infty ).

Problem 18.6

Let GG be the entire complex plane with cuts along the segments [−2,−1][-2,-1] and [1,2][1,2], and let φ(z)\varphi (z) be a regular branch of the multivalued function {(z2−1)(z2−4)}\left\{ \sqrt{\left(z^{2}-1\right)\left(z^{2}-4\right)}\right\} in the domain GG, positive on the interval (−1,1)(-1,1). Find the values:

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(1)

φ(3)\varphi (3);

(2)

φ(−3)\varphi (-3);

(3)

φ(i)\varphi (i);

(4)

φ(−i)\varphi (-i).

Problem 18.7

Let GG be the entire complex plane with cuts along the segments [−1,i][-1, i] and [−i,1][-i, 1], and let φ(z)\varphi (z) be a regular branch of the multivalued function {1−z4}\left\{ \sqrt{1-z^{4}}\right\}, positive on the interval (−1,1)(-1,1). Find the values:

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(1)

φ(53)\varphi \left(\sqrt{\frac{5}{3}}\right);

(2)

φ(−53)\varphi \left(-\sqrt{\frac{5}{3}}\right);

(3)

φ(i53)\varphi \left(i \sqrt{\frac{5}{3}}\right);

(4)

φ(−i53)\varphi \left(-i \sqrt{\frac{5}{3}}\right).

Problem 18.8

Let aa and bb be two distinct finite points of the complex plane, and let γ\gamma be some simple continuous curve going from the point aa to the point bb. Denote by GG the entire complex plane with a cut along the curve γ\gamma, and by φ(z)\varphi (z) an arbitrary regular branch of the multivalued function Ln⁡z−ab−z\operatorname {Ln} \frac{z-a}{b-z} in the domain GG. Prove that for every point z0z_{0} of the curve γ\gamma, distinct from the points aa and bb, the equality φ(z0+)−φ(z0−)=2πi\varphi \left(z_{0}^{+}\right)-\varphi \left(z_{0}^{-}\right) = 2 \pi i holds, where the symbol φ(z0±)\varphi \left(z_{0}^{ \pm }\right) denotes the limit of the function φ(z)\varphi (z) as the point zz tends to the point z0z_{0} from the right (from the left for the sign "−-") of the curve γ\gamma.

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Problem 18.9

Let φ(z)\varphi (z) be a regular branch of the multivalued function {1−z23}\left\{ \sqrt[3]{1-z^{2}}\right\} in a domain GG, satisfying the condition φ(0)=1\varphi (0) = 1. Find the value φ(−3)\varphi (-3) in the cases when the domain GG is:

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(1)

the entire complex plane with cuts along the rays [1,+∞][1,+\infty ] and [−1,−1+i∞][-1,-1+i \infty ];

(2)

the entire complex plane with cuts along the rays [1,1−i∞][1,1-i \infty ] and [−1,−1+i∞][-1,-1+i \infty ];

(3)

the entire complex plane with cuts along the rays [1,1−i∞][1,1-i \infty ] and [−1,−1−i∞][-1,-1-i \infty ].

Problem 18.10

Let P(z)P(z) be a polynomial. Prove that any function f(z)f(z), regular in the entire complex plane with a cut along the positive part of the real axis, continuous up to the boundary of this domain, and satisfying, for all real x>0x > 0, the condition

f(x+i0)−f(x−i0)=P(x), f(x+i 0)-f(x-i 0) = P(x),

has the form

f(z)=−P(z)2πih(z)+g(z), f(z) = -\frac{P(z)}{2 \pi i} h(z)+g(z),

where g(z)g(z) is a function regular in the entire complex plane, and h(z)h(z) is a regular branch of the multivalued function Ln⁡z\operatorname {Ln} z in the plane with a cut along the positive part of the real axis.

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Problem 18.11

Find the general form of a function f(z)f(z), regular in the entire complex plane with a cut along the positive part of the real axis, continuous up to the boundary of this domain except at the point z=0z = 0, and satisfying one of the conditions (x>0)(x > 0):

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(1)

f(x+i0)−f(x−i0)=(1+x)2ln⁡xf(x+i 0)-f(x-i 0) = (1+x)^{2} \ln x;

(2)

f(x+i0)−f(x−i0)=ln⁡2xf(x+i 0)-f(x-i 0) = \ln^{2} x;

(3)

f(x+i0)−f(x−i0)=sin⁡xf(x+i 0)-f(x-i 0) = \sin \sqrt{x};

(4)

f(x+i0)−f(x−i0)=sin⁡(αln⁡x)x−1f(x+i 0)-f(x-i 0) = \frac{\sin (\alpha \ln x)}{x-1};

(5)

f(x+i0)−f(x−i0)=x+1ln⁡2x+π2f(x+i 0)-f(x-i 0) = \frac{x+1}{\ln^{2} x+\pi^{2}};

(6)

f(x+i0)−f(x−i0)=xln⁡xf(x+i 0)-f(x-i 0) = \sqrt{x} \ln x;

(7)

f(x+i0)−f(x−i0)=ln⁡xx3f(x+i 0)-f(x-i 0) = \frac{\ln x}{\sqrt[3]{x}};

(8)

f(x+i0)−f(x−i0)=xln⁡xln⁡2x+π2(x+1)f(x+i 0)-f(x-i 0) = \frac{\sqrt{x} \ln x}{\ln^{2} x+\pi^{2}}(x+1).

Problem 18.12

Let GG be the entire complex plane with a cut along the positive part of the real axis, and let φ(z)\varphi (z) be a regular branch of the multivalued function Ln⁡(1+z)\operatorname {Ln}(1+\sqrt{z}), satisfying the condition φ(−1)=12ln⁡2+πi4\varphi (-1) = \frac{1}{2} \ln 2+\frac{\pi i}{4}. Find the value φ(4−i0)\varphi (4-i 0).

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Problem 18.13

Let GG be the entire complex plane with cuts along the rays [−i∞,−i][-i \infty ,-i] and [i,+i∞][i,+i \infty ], and let the regular function φ(z)\varphi (z) be defined by the conditions

φ(z)∈Ln⁡(z+1+z2),φ(0)=0(z∈G). \varphi (z) \in \operatorname {Ln}\left(z+\sqrt{1+z^{2}}\right), \quad \varphi (0) = 0 \quad (z \in G).

Find the values:

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(1)

φ(i22)\varphi \left(\frac{i \sqrt{2}}{2}\right);

(2)

φ(−i2)\varphi \left(-\frac{i}{2}\right);

(3)

φ(5i3+0)\varphi \left(\frac{5 i}{3}+0\right).

Problem 18.14

Let φ(z)\varphi (z) be a regular branch of the multivalued function Ln⁡(z+21−z)\operatorname {Ln}(\sqrt{z}+2 \sqrt{1-z}), satisfying the condition

φ(12)=12ln⁡92 \varphi \left(\frac{1}{2}\right) = \frac{1}{2} \ln \frac{9}{2}

Find the value φ(4)\varphi (4) in the cases when the domain GG is:

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(1)

the entire complex plane with cuts along the rays [−∞,0][-\infty , 0] and [1,1+i∞][1,1+i \infty ];

(2)

the entire complex plane with cuts along the rays [−i∞,0][-i \infty , 0] and [1,1−i∞][1,1-i \infty ].

Problem 18.15

Let GG be the entire complex plane with cuts along the rays [−i∞,0][-i \infty , 0] and [1,1+i∞][1,1+i \infty ], and let the regular function φ(z)\varphi (z) be defined by the conditions

φ(z)∈Ln⁡Ln⁡z,φ(e2)=ln⁡2(z∈G). \varphi (z) \in \operatorname {Ln} \operatorname {Ln} z, \quad \varphi \left(e^{2}\right) = \ln 2 \quad (z \in G).

Find the value φ(−eπ)\varphi \left(-e^{\pi }\right).

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Problem 18.16

Let GG be the entire complex plane with a cut shown in Fig. 18.1, and let the regular function φ(z)\varphi (z) be defined by the conditions

Fig. 18.1Fig. 18.1

φ(z)∈{π2+Ln⁡2z},φ(1)=π(z∈G). \varphi (z) \in \left\{ \sqrt{\pi ^{2}+\operatorname {Ln}^{2} z}\right\} , \quad \varphi (1) = \pi \quad (z \in G).

Find the values:

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(1)

φ(i)\varphi (i);

(2)

φ(−i)\varphi (-i).

Problem 18.17

Let GG be the entire complex plane with a cut shown in Fig. 18.2, and let the regular function φ(z)\varphi (z) be defined by the conditions

Fig. 18.2Fig. 18.2

φ(z)∈{1+z+1},φ(8)=2(z∈G) \varphi (z) \in \left\{ \sqrt{1+\sqrt{z+1}}\right\} , \quad \varphi (8) = 2 \quad (z \in G)

Find the values:

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(1)

φ(−3/4)\varphi (-3 / 4);

(2)

φ(−2)\varphi (-2).

Problem 18.18

Let GG be the entire complex plane with a cut shown in Fig. 18.3, and let the regular function φ(z)\varphi (z) be defined by the conditions

Fig. 18.3Fig. 18.3

φ(z)∈Ln⁡(iz+1−z2),φ(0)=πi(z∈G). \varphi (z) \in \operatorname {Ln}\left(i z+\sqrt{1-z^{2}}\right), \quad \varphi (0) = \pi i \quad (z \in G).

Find the values:

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(1)

φ(1/2)\varphi (1 / 2);

(2)

φ(−1/2)\varphi (-1 / 2);

(3)

φ(4i/3)\varphi (4 i / 3).

Problem 18.19

Prove that the multivalued function {1−z23}\left\{ \sqrt[3]{1-z^{2}}\right\} does not admit the extraction of a regular branch in the domain G={z:1<∣z∣<∞}G = \left\{ z: 1 < \left|z\right| < \infty \right\}.

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Problem 18.20

Determine whether the multivalued functions given below admit the extraction of regular branches in the domains GG indicated in parentheses:

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(1)

{z+1z+i3}(G={z:1<∣z∣<∞})\left\{ \sqrt[3]{\frac{z+1}{z+i}}\right\} \quad (G = \left\{ z: 1 < \left|z\right| < \infty \right\} );

(2)

{2Ln⁡(z+1)−Ln⁡(z−i)}(G={z:1<∣z∣<∞})\left\{ 2 \operatorname {Ln}(z+1)-\operatorname {Ln}(z-i)\right\} (G = \left\{ z: 1 < \left|z\right| < \infty \right\} );

(3)

{(z2−1)(z2−4)}(G={z:Re(z)>0,∣z−3∣>2,5})\left\{ \sqrt{\left(z^{2}-1\right)\left(z^{2}-4\right)}\right\} \quad (G = \left\{ z: \mathrm{Re}\left(z\right) > 0,\left|z-3\right| > 2,5\right\} );

(4)

{1−z53}(G={z:Re(z)>0,z∉[1,e2πi/5],z∉[1,e−2πi/5]})\left\{ \sqrt[3]{1-z^{5}}\right\} \quad \left(G = \left\{ z: \mathrm{Re}\left(z\right) > 0, z \notin \left[1, e^{2 \pi i / 5}\right], z \notin \left[1, e^{-2 \pi i / 5}\right]\right\} \right).

Problem 18.21

Determine, for what relationship between the numbers α1\alpha_{1} and α2\alpha_{2}, the multivalued function

α1Ln⁡(z−1)+α2Ln⁡z \alpha _{1} \operatorname {Ln}(z-1)+\alpha _{2} \operatorname {Ln} z

admits the extraction of a regular branch in the domain 1<∣z∣<∞1 < \left|z\right| < \infty.

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Problem 18.22

Determine, for what relationship between the numbers α1,α2\alpha_{1}, \alpha_{2} and α3\alpha_{3}, the multivalued function

{(z−1)α1(z+1)α2zα3} \left\{ (z-1)^{\alpha _{1}}(z+1)^{\alpha _{2}} z^{\alpha _{3}}\right\}

admits the extraction of a regular branch in the domain 1<∣z∣<∞1 < \left|z\right| < \infty.

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Problem 18.23

Prove that in the plane with a cut along the negative part of the real axis there exists a regular branch of the multivalued function Ln⁡(1−z)\operatorname {Ln}(1-\sqrt{z}), satisfying the condition φ(2i)=−πi/2\varphi (2 i) = -\pi i / 2.

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Problem 18.24

Let φ(z)\varphi (z) be a regular branch of the multivalued function Ln⁡z\operatorname {Ln} z in the domain shown in Fig. 18.4, satisfying the condition φ(1)=0\varphi (1) = 0. Find φ′(2)\varphi^{\prime }(2). Expand the function φ(z)\varphi (z) in a Taylor series in a neighborhood of the point z=−3z = -3 in powers of z+3z+3.

Fig. 18.4Fig. 18.4

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Problem 18.25

Let g(z)g(z) be a regular branch of the multivalued function {z3}\left\{ \sqrt[3]{z}\right\} in the domain shown in Fig. 18.4, such that g(−1)=−1g(-1) = -1. Find g(−2),g′(−3)g(-2), g^{\prime }(-3). Expand g(z)g(z) in a Taylor series in a neighborhood of the point z=2z = 2 in powers of z−2z-2.

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Problem 18.26

Let φ1(z),φ2(z)\varphi_{1}(z), \varphi_{2}(z) be the functions from Problem 4. Find φ1′(−2),φ2′(2)\varphi_{1}^{\prime }(-2), \varphi_{2}^{\prime }(2). Expand the function φ2(z)\varphi_{2}(z) in a Taylor series in a neighborhood of the point z=4z = 4 in powers of (z−4)(z-4). Expand φ1(z)\varphi_{1}(z) and φ2(z)\varphi_{2}(z) in Laurent series in a neighborhood of the point z=∞z = \infty.

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Problem 18.27

Let g(z)g(z) be a regular branch of the multivalued function {z4}\left\{ \sqrt[4]{z}\right\} in the plane with a cut along the ray [0,+∞)[0,+\infty ), such that g(1+i0)=1g(1+i 0) = 1. Find g(1−i0)g(1-i 0), g(16−i0),g(−16),g′(−16),g′′(−16)g(16-i 0), g(-16), g^{\prime }(-16), g^{\prime \prime }(-16).

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Problem 18.28

Relying on the Taylor series expansion of the regular branches of the multivalued function {(1+z)a}\left\{ (1+z)^{a}\right\} (see Example 2 in the reference material), prove the formulas for all the resulting regular branches g(z),w(z),h(z)g(z), w(z), h(z) in the disk ∣z∣<1\left|z\right| < 1:

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(1)

1g(z)=1g(0)+∑n=1+∞(2n)!22n(n!)2z2n\frac{1}{g(z)} = \frac{1}{g(0)}+\sum_{n = 1}^{+\infty } \frac{(2 n)!}{2^{2 n}(n!)^{2}} z^{2 n}, where g(z)∈{1−z2}g(z) \in \left\{ \sqrt{1-z^{2}}\right\};

(2)

g(z)=g(0)+∑n=1+∞(−1)n+1(2n−2)!22n−1n!(n−1)!z2ng(z) = g(0)+\sum_{n = 1}^{+\infty }(-1)^{n+1} \frac{(2 n-2)!}{2^{2 n-1} n!(n-1)!} z^{2 n}, where g(z)∈{1+z2}g(z) \in \left\{ \sqrt{1+z^{2}}\right\};

(3)

w(z)=w(0)+∑n=0+∞(2n)!22n(n!)2(2n+1)z2n+1w(z) = w(0)+\sum_{n = 0}^{+\infty } \frac{(2 n)!}{2^{2 n}(n!)^{2}(2 n+1)} z^{2 n+1}, where w(z)∈Arcsin⁡zw(z) \in \operatorname {Arcsin} z;

(4)

h(z)=h(0)+∑n=0+∞(−1)n(2n)!z2n+122n(n!)2(2n+1)h(z) = h(0)+\sum_{n = 0}^{+\infty }(-1)^{n} \frac{(2 n)!z^{2 n+1}}{2^{2 n}(n!)^{2}(2 n+1)}, where h(z)∈Ln⁡(z+g(z))h(z) \in \operatorname {Ln}(z+g(z)), g(z)∈{1+z2}, g(0)=1g(z) \in \left\{ \sqrt{1+z^{2}}\right\} , ~ g(0) = 1.

Problem 18.29

For all regular branches h(z),w(z)h(z), w(z) of the multivalued functions in the disk ∣z∣<1\left|z\right| < 1, prove the formulas:

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(1)

h(z)=h(0)+2∑n=0+∞z2n+12n+1h(z) = h(0)+2 \sum_{n = 0}^{+\infty } \frac{z^{2 n+1}}{2 n+1}, where h(z)∈Ln⁡1+z1−zh(z) \in \operatorname {Ln} \frac{1+z}{1-z};

(2)

w(z)=w(0)+∑n=0+∞(−1)nz2n+12n+1w(z) = w(0)+\sum_{n = 0}^{+\infty }(-1)^{n} \frac{z^{2 n+1}}{2 n+1}, where w(z)∈Arctg⁡zw(z) \in \operatorname {Arctg} z;

(3)

1−zzh(z)=−1+∑n=1+∞znn(n+1)\frac{1-z}{z} h(z) = -1+\sum_{n = 1}^{+\infty } \frac{z^{n}}{n(n+1)}, where h(z)∈Ln⁡(1−z),h(0)=0h(z) \in \operatorname {Ln}(1-z), h(0) = 0.

Problem 18.30

Find the Taylor series expansion in powers of zz in a neighborhood of the point z=0z = 0 of the following functions, containing regular branches g(z),h(z)g(z), h(z) of multivalued functions:

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(1)

sh⁡g(z)⋅sin⁡g(z)\operatorname {sh} g(z) \cdot \sin g(z), where g(z)∈{z},g(0)=0g(z) \in \left\{ \sqrt{z}\right\} , g(0) = 0;

(2)

12g(z)h(1+g(z)1−g(z))\frac{1}{2 g(z)} h\left(\frac{1+g(z)}{1-g(z)}\right), where g(z)∈{z},g(0)=0,h(z)∈Ln⁡z,h(1)=0g(z) \in \left\{ \sqrt{z}\right\} , g(0) = 0, h(z) \in \operatorname {Ln} z, h(1) = 0;

(3)

1g(z)\frac{1}{g(z)}, where g(z)∈{1−z3},g(0)=1g(z) \in \left\{ \sqrt{1-z^{3}}\right\} , g(0) = 1;

(4)

h(z)\quad h(z), where h(z)∈Ln⁡(1+z+z2),h(0)=0h(z) \in \operatorname {Ln}\left(1+z+z^{2}\right), h(0) = 0.

Problem 18.31

Using the fact that the regular function f(z)∈{Arcsin⁡z1−z2}f(z) \in \left\{ \frac{\operatorname {Arcsin} z}{\sqrt{1-z^{2}}}\right\} satisfies the differential equation

(1−z2)f′(z)−zf(z)=1,f(0)=0 \left(1-z^{2}\right) f^{\prime }(z)-z f(z) = 1, \quad f(0) = 0

prove the formula

f(z)=∑n=0+∞(−1)n(2n)!!(2n+1)!!z2n+1,∣z∣<1. f(z) = \sum _{n = 0}^{+\infty }(-1)^{n} \frac{(2 n)!!}{(2 n+1)!!} z^{2 n+1}, \quad \left|z\right| < 1.
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Problem 18.32

For the regular branch

f(z)∈{(Arctg⁡zz)2},f(0)=1, f(z) \in \left\{ \left(\frac{\operatorname {Arctg} z}{z}\right)^{2}\right\} , \quad f(0) = 1,

prove the formula

f(z)=1+∑n=1+∞(−1)n(1+13+…+12n+1)z2nn+1,∣z∣<1. f(z) = 1+\sum _{n = 1}^{+\infty }(-1)^{n}\left(1+\frac{1}{3}+\ldots +\frac{1}{2 n+1}\right) \frac{z^{2 n}}{n+1}, \quad \left|z\right| < 1.
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Problem 18.33

Using the binomial series, prove the validity of the Laurent series expansion formulas for regular branches f(z)f(z) of multivalued functions:

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(1)

f(z)=1+∑n=−∞−1a(a+1)…(a−n−1)(−n)!znf(z) = 1+\sum_{n = -\infty }^{-1} \frac{a(a+1) \ldots (a-n-1)}{(-n)!} z^{n}, where

f(z)∈{(zz−1)a},f(∞)=1,∣z∣>1 f(z) \in \left\{ \left(\frac{z}{z-1}\right)^{a}\right\} , \quad f(\infty ) = 1, \quad \left|z\right| > 1
(2)

f(z)=1z+∑n=−∞−112⋅32…(12−n−1)(−n)!z2n−1f(z) = \frac{1}{z}+\sum_{n = -\infty }^{-1} \frac{\frac{1}{2} \cdot \frac{3}{2} \ldots \left(\frac{1}{2}-n-1\right)}{(-n)!} z^{2 n-1}, where

f(z)∈{1z2−1},f(2)=13,∣z∣>1 f(z) \in \left\{ \frac{1}{\sqrt{z^{2}-1}}\right\} , \quad f(2) = \frac{1}{\sqrt{3}}, \quad \left|z\right| > 1
(3)

f(z)=1+∑n=−∞−1α(α+1)…(α−n−1)(−n)!(b−a)−n⋅(z−a)nf(z) = 1+\sum_{n = -\infty }^{-1} \frac{\alpha (\alpha +1) \ldots (\alpha -n-1)}{(-n)!}(b-a)^{-n} \cdot (z-a)^{n}, where a≠b,f(z)∈{(z−az−b)α},f(∞)=1,∣z−a∣>∣b−a∣;a \neq b, \quad f(z) \in \left\{ \left(\frac{z-a}{z-b}\right)^{\alpha }\right\} , \quad f(\infty ) = 1, \quad \left|z-a\right| > \left|b-a\right| ;

(4)

f(z)=ln⁡2+∑n=−∞−1(−1)n+12n⋅12⋅32⋯(12−n−1)(−n)!z2nf(z) = \ln 2+\sum_{n = -\infty }^{-1} \frac{(-1)^{n+1}}{2 n} \cdot \frac{\frac{1}{2} \cdot \frac{3}{2} \cdots \left(\frac{1}{2}-n-1\right)}{(-n)!} z^{2 n}, where f(z)∈Ln⁡z+z2+1z,f(2)=ln⁡(1+52),∣z∣>1f(z) \in \operatorname {Ln} \frac{z+\sqrt{z^{2}+1}}{z}, \quad f(2) = \ln \left(1+\frac{\sqrt{5}}{2}\right), \quad \left|z\right| > 1.

Problem 18.34

Verify that the following multivalued functions admit the extraction of regular branches in the annulus GG, and expand all the regular branches in a Laurent series in powers of z−az-a in the annulus GG (the point aa and the annulus GG are indicated in parentheses):

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(1)

Ln⁡(z−1)(z−2)(z+1)(z+2)(a=0,G={z:1<∣z∣<2})\operatorname {Ln} \frac{(z-1)(z-2)}{(z+1)(z+2)} \quad (a = 0, G = \left\{ z: 1 < \left|z\right| < 2\right\} );

(2)

Ln⁡(z+1)2z2+4(a=0,G={z:∣z∣>2})\operatorname {Ln} \frac{(z+1)^{2}}{z^{2}+4}(a = 0, G = \left\{ z:\left|z\right| > 2\right\} );

(3)

Ln⁡z(z+3)(z+2)(z−1)(a=−1,G={z:1<∣z+1∣<2})\operatorname {Ln} \frac{z(z+3)}{(z+2)(z-1)}(a = -1, G = \left\{ z: 1 < \left|z+1\right| < 2\right\} );

(4)

Ln⁡(z−1)2(z+2)(z+3)(a=−1,G={z:∣z+1∣>2})\operatorname {Ln} \frac{(z-1)^{2}}{(z+2)(z+3)}(a = -1, G = \left\{ z:\left|z+1\right| > 2\right\} ).

Problem 18.35

Let g(z)g(z) be a regular branch of the multivalued function {z+93}\left\{ \sqrt[3]{z+9}\right\} in the plane with a cut along the curve z=9eit,−π⩽t⩽π2z = 9 e^{i t}, \quad -\pi \leqslant t \leqslant \frac{\pi }{2} and the ray z=9i+tiz = 9 i+t i, t⩾0t \geqslant 0, such that arg⁡g(10)=2π3\arg g(10) = \frac{2 \pi }{3}. Compute g(−8),g(−1),g(−9+8i),g′(0)g(-8), g(-1), g(-9+8 i), g^{\prime }(0). Expand g(z)g(z) in a Taylor series in a neighborhood of the point z=3z = 3 in powers of z−3z-3 and draw the largest domain in which this series converges to the function g(z)g(z).

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Problem 18.36

Let h(z)h(z) be a regular branch of the multivalued function Ln⁡(2−z)\operatorname {Ln}(2-z) in the plane with a cut along the curve z=2eit,0⩽t⩽32πz = 2 e^{i t}, 0 \leqslant t \leqslant \frac{3}{2} \pi, and the ray z=−2i+t,t⩾0z = -2 i+t, t \geqslant 0, such that Im(h(−3))=0\mathrm{Im}\left(h(-3)\right) = 0. Compute h(−2−0),h(−2+0),h(2+i)h(-2-0), \quad h(-2+0), \quad h(2+i), h′(0)h^{\prime }(0). Expand the function h(z)h(z) in a Taylor series centered at the point z=−1z = -1. Find the radius of convergence of this series. Draw the largest domain in which the series converges to the function h(z)h(z).

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Problem 18.37

Let g(z)g(z) be a regular branch of the multivalued function {z(2−z)23}\left\{ \sqrt[3]{z(2-z)^{2}}\right\} in the plane with a cut along the segment [0,2][0,2], such that g(1+i0)=1g(1+i 0) = 1. Find g(1−i0),g(−3),g′(3)g(1-i 0), \quad g(-3), \quad g^{\prime }(3). Expand g(z)g(z) in a Laurent series in powers of zz in a neighborhood of the point z=∞z = \infty.

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Problem 18.38

Let h(z)h(z) be a regular branch of the multivalued function Ln⁡z+13−z\operatorname {Ln} \frac{z+1}{3-z} in the plane with a cut along the segment [−1,3][-1,3], such that h(1+i0)=0h(1+i 0) = 0. Find h(1−i0)h(1-i 0), g(−2),g′(−3)g(-2), g^{\prime }(-3). Expand h(z)h(z) in a Taylor series centered at the point z=5z = 5 and in a Laurent series in powers of zz in a neighborhood of the point z=∞z = \infty. Find the domains of convergence of these series.

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Problem 18.39

Let h(z)h(z) be a regular branch of the multivalued function Ln⁡z+iz+1\operatorname {Ln} \frac{z+i}{z+1} in the plane with a cut along the line

{z:∣z∣=1,−π2⩽arg⁡z⩽π} \left\{ z:\left|z\right| = 1,-\frac{\pi }{2} \leqslant \arg z \leqslant \pi \right\}

such that h(0)=iπ2h(0) = i \frac{\pi }{2}. Expand h(z)h(z) in a Laurent series in powers of zz in a neighborhood of the point z=∞z = \infty.

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Problem 18.40

Let h(z)h(z) be a regular branch of the multivalued function

Ln⁡z−iz+i−1z−2 \operatorname {Ln} \frac{z-i}{z+i}-\frac{1}{z-2}

in the plane with the point z=2z = 2 removed and a cut along the semicircle {z:∣z∣=1,Re(z)⩾0}\left\{ z:\left|z\right| = 1, \mathrm{Re}\left(z\right) \geqslant 0\right\}, such that h(0)=−iπ+12h(0) = -i \pi +\frac{1}{2}. Expand h(z)h(z) in a Laurent series in powers of zz in the annulus 1<∣z∣<21 < \left|z\right| < 2.

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Problem 18.41

Let g(z)g(z) be a regular branch of the multivalued function

{z2(1−z)3}+1z−3i \left\{ \sqrt[3]{z^{2}(1-z)}\right\} +\frac{1}{z-3 i}

in the plane with the point z=3iz = 3 i removed and a cut along the segment [0,1][0,1], such that g(−1)=23−11+3ig(-1) = \sqrt[3]{2}-\frac{1}{1+3 i}. Expand g(z)g(z) in a Laurent series in powers of zz in the annulus 1<∣z∣<31 < \left|z\right| < 3.

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Problem 18.42

Let h(z)h(z) be a regular branch of the multivalued function Ln⁡(z2−z−6)\operatorname {Ln}\left(z^{2}-z-6\right) in the plane with cuts along the lines {Re(z)=−2,Im(z)⩽0}\left\{ \mathrm{Re}\left(z\right) = -2, \mathrm{Im}\left(z\right) \leqslant 0\right\} and {Re(z)=3,Im(z)⩽0}\left\{ \mathrm{Re}\left(z\right) = 3, \mathrm{Im}\left(z\right) \leqslant 0\right\}, such that h(4)=ln⁡6h(4) = \ln 6. Expand h(z)h(z) in a Taylor series centered at the point z=1z = 1 and find the radius of convergence of this series.

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Problem 18.43

Let f(z)f(z) be a regular branch of the multivalued function Ln⁡(z2−2z)\operatorname {Ln}\left(z^{2}-2 z\right) in the plane with cuts along the positive part of the imaginary axis and along the segment [0,2][0,2] of the real axis, singled out by the condition

Im(f(−1+3i))=−π2 \mathrm{Im}\left(f(-1+\sqrt{3} i)\right) = -\frac{\pi }{2}

Compute f(1+2i)f(1+2 i). Expand f(z)f(z) in a Taylor series centered at the point z=1+2iz = 1+2 i. Find the radius of convergence. Compute the sum of the series at z=−1+3iz = -1+\sqrt{3} i.

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Problem 18.44

Let f(z)f(z) be a regular branch of the multivalued function {z4+643}\left\{ \sqrt[3]{z^{4}+64}\right\} in the plane with cuts along the rays

{z:z=2−2it;t⩾−1} and {z:z=−2−2it;t⩾−1}, \begin{aligned} & \left\{ z: z = 2-2 i t ; t \geqslant -1\right\} \\ \text{ and } \quad & \left\{ z: z = -2-2 i t ; t \geqslant -1\right\} , \end{aligned}

singled out by the condition f(22)=423f(2 \sqrt{2}) = 4 \sqrt[3]{2}. Compute f(0)f(0). Expand f(z)f(z) in a Taylor series centered at the point z=0z = 0. Find the radius of convergence. Compute the ratio of the sum of the series to f(z)f(z) at z=−52z = -\frac{5}{2}.

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Problem 18.45

Let f(z)f(z) be a regular branch of the multivalued function Ln⁡(z+iz2)\operatorname {Ln}\left(z+i z^{2}\right) in the plane with cuts along the positive part of the real axis and along the segment [0,i][0, i] of the imaginary axis, singled out by the condition

Im(f)(e−iπ/6)=0 \mathrm{Im}\left(f\right)\left(e^{-i \pi / 6}\right) = 0

Compute f(1+i2)f\left(1+\frac{i}{2}\right). Expand f(z)f(z) in a Taylor series centered at the point z=1+i2z = 1+\frac{i}{2}. Find the radius of convergence. Compute the sum of the series at z=e−iπ/6z = e^{-i \pi / 6}.

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Problem 18.46

Let f(z)f(z) be a regular branch of the multivalued function {z4+46}\left\{ \sqrt[6]{z^{4}+4}\right\} in the plane with cuts along the rays {z:z=i+t;t⩾−1}\left\{ z: z = i+t ; t \geqslant -1\right\} and {z:z=−i+t;t⩽1}\left\{ z: z = -i+t ; t \leqslant 1\right\}, singled out by the condition f(2i)=−2f(\sqrt{2} i) = -\sqrt{2}. Compute f(0)f(0). Expand f(z)f(z) in a Taylor series centered at the point z=0z = 0. Find the radius of convergence. Compute the ratio of the sum of the series to f(z)f(z) at z=−65iz = -\frac{6}{5} i.

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Problem 18.47

Let f(z)f(z) be a regular branch of the multivalued function Ln⁡(1+z2)\operatorname {Ln}\left(1+z^{2}\right) in the plane with a cut along the ray of the imaginary axis [−i,+i∞)[-i,+i \infty ), with Im(f)(−15)=0\mathrm{Im}\left(f\right)\left(-\frac{1}{5}\right) = 0. Expand f(z)f(z) in a Taylor series centered at the point z=1z = 1 and find the radius of convergence. Compute the sum of the series at z=−15z = -\frac{1}{5}.

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Problem 18.48

Let f(z)f(z) be a regular branch of the multivalued function {9−z2}\left\{ \sqrt{9-z^{2}}\right\} in the plane with a cut along the circular arc {z:∣z−4i∣=5,Im(z)⩾0}\left\{ z:\left|z-4 i\right| = 5, \mathrm{Im}\left(z\right) \geqslant 0\right\}, with f(4i)=5f(4 i) = 5. Expand f(z)f(z) in a Laurent series in powers of zz in a neighborhood of z=∞z = \infty and find the domain of convergence. Compute the sum of the series at z=4iz = 4 i.

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Problem 18.49

Let f(z)f(z) be a regular branch of the multivalued function Ln⁡(1−z2)\operatorname {Ln}\left(1-z^{2}\right) in the plane with a cut along the ray of the real axis (−∞,1](-\infty , 1], with Im(f)(i5)=0\mathrm{Im}\left(f\right)\left(\frac{i}{5}\right) = 0.

Expand f(z)f(z) in a Taylor series centered at the point z=−iz = -i. Find the radius of convergence. Compute the sum of the series at z=i5z = \frac{i}{5}.

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Problem 18.50

Let f(z)f(z) be a regular branch of the multivalued function {z2+16}\left\{ \sqrt{z^{2}+16}\right\} in the plane with a cut along the circular arc {z:∣z+3∣=5,Re(z)⩾0}\left\{ z:\left|z+3\right| = 5, \mathrm{Re}\left(z\right) \geqslant 0\right\}, with the principal part of the Laurent series of the function f(z)f(z) in a neighborhood of z=∞z = \infty equal to zz. Expand f(z)f(z) in a Taylor series centered at the point z=0z = 0, find the radius of convergence. Compute the sum of the series at z=3z = 3.

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