Section 12

Isolated Singular Points of Single-Valued Character

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Problem 12.1

Prove that the point z=az = a is a removable singular point for the following functions:

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(1)

z2−1z−1(a=1)\frac{z^{2}-1}{z-1} \quad (a = 1);

(2)

sin⁡zz(a=0)\frac{\sin z}{z} \quad (a = 0);

(3)

ztg⁡z(a=0)\frac{z}{\operatorname {tg} z} \quad (a = 0);

(4)

1−cos⁡zz2(a=0)\frac{1-\cos z}{z^{2}}(a = 0);

(5)

ctg⁡z−1z(a=0)\operatorname {ctg} z-\frac{1}{z} \quad (a = 0);

(6)

1ez−1−1sin⁡z(a=0)\frac{1}{e^{z}-1}-\frac{1}{\sin z} \quad (a = 0);

(7)

1cos⁡2z−1(z−π2)2(a=π2)\frac{1}{\cos^{2} z}-\frac{1}{\left(z-\frac{\pi }{2}\right)^{2}} \quad \left(a = \frac{\pi }{2}\right);

(8)

z2−1z3+1(a=∞)\frac{z^{2}-1}{z^{3}+1} \quad (a = \infty ).

Problem 12.2

Prove that the point z=az = a is a pole of the following functions:

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(1)

1z(a=0)\frac{1}{z} \quad (a = 0);

(2)

1(z2+1)2(a=i)\frac{1}{\left(z^{2}+1\right)^{2}} \quad (a = i);

(3)

z2+1z+1(a=∞)\frac{z^{2}+1}{z+1} \quad (a = \infty );

(4)

z1−cos⁡z(a=0)\frac{z}{1-\cos z} \quad (a = 0);

(5)

z(ez−1)2(a=0)\frac{z}{\left(e^{z}-1\right)^{2}} \quad (a = 0);

(6)

ctg⁡πz(a=∞)\operatorname {ctg} \frac{\pi }{z} \quad (a = \infty );

(7)

z(ez+1)2(a=πi)\frac{z}{\left(e^{z}+1\right)^{2}} \quad (a = \pi i);

(8)

tg⁡πz(a=±12,±32,…)\operatorname {tg} \pi z \quad \left(a = \pm \frac{1}{2}, \pm \frac{3}{2}, \ldots \right).

Problem 12.3

Let the functions f(z)f(z) and g(z)g(z) be regular at the point z=az = a, with f(a)=g(a)=0f(a) = g(a) = 0. Prove that:

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(1)

lim⁡z→af(z)g(z)=lim⁡z→af′(z)g′(z)\lim_{z \rightarrow a} \frac{f(z)}{g(z)} = \lim_{z \rightarrow a} \frac{f^{\prime }(z)}{g^{\prime }(z)};

(2)

lim⁡z→af(z)g(z)=lim⁡z→a{g′(z)f2(z)f′(z)g2(z)}\lim_{z \rightarrow a} \frac{f(z)}{g(z)} = \lim_{z \rightarrow a}\left\{ \frac{g^{\prime }(z) f^{2}(z)}{f^{\prime }(z) g^{2}(z)}\right\}.

Problem 12.4

Let the functions f(z)f(z) and g(z)g(z) be regular at the point z=az = a, with f(a)=g(a)=0f(a) = g(a) = 0. Prove that the point z=az = a is an isolated singular point of single-valued character for the function F(z)=f(z)/g(z)F(z) = f(z) / g(z), and that it cannot be an essential singular point.

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Problem 12.5

Let z=az = a be an isolated singular point of single-valued character for the function f(z)f(z). Prove that the point z=az = a is an essential singular point of the function f(z)f(z) if and only if there exist two sequences z1′,z2′,…z_{1}^{\prime }, z_{2}^{\prime }, \ldots and z1′′,z2′′,…z_{1}^{\prime \prime }, z_{2}^{\prime \prime }, \ldots such that lim⁡n→∞zn′=lim⁡n→∞zn′′=a\lim_{n \rightarrow \infty } z_{n}^{\prime } = \lim_{n \rightarrow \infty } z_{n}^{\prime \prime } = a, while lim⁡n→∞f(zn′)=A,lim⁡n→∞f(zn′′)=B,A≠B\lim_{n \rightarrow \infty } f\left(z_{n}^{\prime }\right) = A, \lim_{n \rightarrow \infty } f\left(z_{n}^{\prime \prime }\right) = B, \quad A \neq B.

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Problem 12.6

Prove that the point z=∞z = \infty is an essential singular point for the function sin⁡z\sin z.

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Problem 12.7

Prove that the point z=az = a is an essential singular point of the functions:

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(1)

ez(a=∞);e^{z} \quad (a = \infty ) ;

(2)

e−z2(a=∞)e^{-z^{2}}(a = \infty );

(3)

sin⁡πz2(a=0)\sin \frac{\pi }{z^{2}} \quad (a = 0);

(4)

z2cos⁡πz(a=0)z^{2} \cos \frac{\pi }{z} \quad (a = 0);

(5)

etg⁡z(a=π2)e^{\operatorname {tg} z} \quad \left(a = \frac{\pi }{2}\right);

(6)

sin⁡(ez)(a=∞)\sin \left(e^{z}\right) \quad (a = \infty );

(7)

cos⁡zz+1(a=−1);\cos \frac{z}{z+1} \quad (a = -1) ;

(8)

sin⁡πz2+1(a=−i)\sin \frac{\pi }{z^{2}+1} \quad (a = -i).

Problem 12.8

Find all isolated singular points of single-valued character for the following functions and determine their type:

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(1)

zsin⁡z\frac{z}{\sin z};

(2)

1−cos⁡zsin⁡2z\frac{1-\cos z}{\sin^{2} z};

(3)

z2sin⁡zz+1z^{2} \sin \frac{z}{z+1};

(4)

1z2−1cos⁡πzz+1\frac{1}{z^{2}-1} \cos \frac{\pi z}{z+1};

(5)

ctg⁡z−1z\operatorname {ctg} z-\frac{1}{z};

(6)

z(e1/z−1)z\left(e^{1 / z}-1\right);

(7)

ectg⁡πze^{\operatorname {ctg} \frac{\pi }{z}};

(8)

sin⁡(e1/z)\sin \left(e^{1 / z}\right).

Problem 12.9

Prove that an isolated singular point of single-valued character z=az = a is a removable singular point for the function f(z)f(z), if one of the following conditions holds (arranged in order of decreasing restrictiveness):

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(1)

the function f(z)f(z) is bounded in some neighborhood of the point z=az = a;

(2)

lim⁡z→a(z−a)f(z)=0\lim_{z \rightarrow a}(z-a) f(z) = 0;

(3)

lim⁡ρ→0∫∣z−a∣=ρ∣f(z)∣∣d(z)∣=0\lim_{\rho \rightarrow 0} \int_{\left|z-a\right| = \rho }\left|f(z)\right|\left|d(z)\right| = 0.

Problem 12.10

Let z=az = a be an isolated singular point of single-valued character for a function f(z)f(z) satisfying, in some neighborhood of this point, the inequality ∣f(z)∣<M∣z−a∣−m\left|f(z)\right| < M\left|z-a\right|^{-m}, where MM and mm are some positive constants. Prove that the point z=az = a cannot be an essential singular point of the function f(z)f(z).

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Problem 12.11

Let the function f(z)f(z) have a pole of order mm at the finite point z=az = a. Determine the order of the pole at the point z=az = a of the function f(n)(z)f^{(n)}(z).

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Problem 12.12

Let Pm(z)P_{m}(z) and Qn(z)Q_{n}(z) be polynomials of degree mm and nn, respectively. Find the order of the pole at infinity for the following functions:

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(1)

Pm(z)+Qn(z),m≠nP_{m}(z)+Q_{n}(z), m \neq n;

(2)

Pm(z)⋅Qn(z)P_{m}(z) \cdot Q_{n}(z);

(3)

Pm(z)Qn(z),m>n\frac{P_{m}(z)}{Q_{n}(z)}, m > n.

Problem 12.13

Let the functions f(z)f(z) and g(z)g(z) have, at the point z=∞z = \infty, poles of orders mm and nn, respectively. Prove that the function F(z)=f(g(z))F(z) = f(g(z)) has, at the point z=∞z = \infty, a pole of order mnm n.

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Problem 12.14

Let the function g(z)g(z) be regular at the point z=az = a with g(a)=bg(a) = b, and let the function f(ζ)f(\zeta ) have a pole of order mm at the point ζ=b\zeta = b. Prove that the function F(z)=f(g(z))F(z) = f(g(z)) has, at the point z=az = a, a pole of order mnm n, where nn is the multiplicity of the zero of the function g(z)−bg(z)-b at the point z=az = a.

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Problem 12.15

Find all singular points of the function f(z)f(z) and determine their type, if:

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(1)

f(z)=1−ch⁡z2ez−e3zf(z) = \frac{1-\operatorname {ch} \frac{z}{2}}{e^{z}-e^{3 z}};

(2)

f(z)=z2−4z−5(z+3)(1+cos⁡πz)f(z) = \frac{z^{2}-4 z-5}{(z+3)(1+\cos \pi z)};

(3)

f(z)=e2z−ez(z2−1)sin⁡πzf(z) = \frac{e^{2 z}-e^{z}}{\left(z^{2}-1\right) \sin \pi z};

(4)

f(z)=14sh⁡(z−1)+1z2−6z+5f(z) = \frac{1}{4 \operatorname {sh}(z-1)}+\frac{1}{z^{2}-6 z+5};

(5)

f(z)=6sh⁡z−z(6+z2)(ez−1)5f(z) = \frac{6 \operatorname {sh} z-z\left(6+z^{2}\right)}{\left(e^{z}-1\right)^{5}};

(6)

f(z)=e3z−cos⁡2zz2−3cth⁡zf(z) = \frac{e^{3 z}-\cos^{2} z}{z^{2}}-3 \operatorname {cth} z;

(7)

f(z)=etg⁡πzsin⁡2πz3(2z+1)(ez+1)f(z) = \frac{e^{\operatorname {tg} \pi z} \sin \frac{2 \pi z}{3}}{(2 z+1)\left(e^{z}+1\right)};

(8)

f(z)=tg⁡zetg⁡ztg⁡4zf(z) = \frac{\operatorname {tg} z e^{\operatorname {tg} z}}{\operatorname {tg} 4 z};

(9)

f(z)=z3−sh3z(ez−1)5f(z) = \frac{z^{3}-\mathrm{sh}^{3} z}{\left(e^{z}-1\right)^{5}};

(10)

f(z)=ectg⁡πzcos⁡πz4(z−1)2(ch⁡z+1)f(z) = \frac{e^{\operatorname {ctg} \pi z} \cos \frac{\pi z}{4}}{(z-1)^{2}(\operatorname {ch} z+1)};

(11)

f(z)=4z2+4πz−8π2(e2iz−1)2−3πz+2πf(z) = \frac{4 z^{2}+4 \pi z-8 \pi^{2}}{\left(e^{2 i z}-1\right)^{2}}-\frac{3 \pi }{z+2 \pi };

(12)

f(z)=z3+2πz2+π2zsin⁡3z−πz+πf(z) = \frac{z^{3}+2 \pi z^{2}+\pi^{2} z}{\sin^{3} z}-\frac{\pi }{z+\pi }.

Problem 12.16

Let a sequence of functions {fn(z)}\left\{ f_{n}(z)\right\}, regular in the annulus 0<∣z−a∣<r0 < \left|z-a\right| < r, converge uniformly on every closed part of this annulus. Prove that if each function fn(z)f_{n}(z) has a pole of order mm at the point z=az = a, then the limit function f(z)f(z) is regular in the annulus 0<∣z−a∣<r0 < \left|z-a\right| < r and has, at the point z=az = a, either a pole of order not exceeding mm, or a removable singular point.

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Problem 12.17

Find all singular points of the function f(z)f(z) and determine their type, if:

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(1)

f(z)=sin⁡πzz2+z−2f(z) = \frac{\sin \frac{\pi }{z}}{z^{2}+z-2};

(2)

f(z)=cos⁡πzsin⁡z+1f(z) = \frac{\cos \frac{\pi }{z}}{\sin z+1};

(3)

f(z)=1−sin⁡iπzeπz−1f(z) = \frac{1-\sin \frac{i \pi }{z}}{e^{\pi z}-1};

(4)

f(z)=z2+4z−121+sin⁡3πzf(z) = \frac{z^{2}+4 z-12}{1+\sin \frac{3 \pi }{z}};

(5)

f(z)=8z2−6z+11−cos⁡πzf(z) = \frac{8 z^{2}-6 z+1}{1-\cos \frac{\pi }{z}};

(6)

f(z)=cos⁡πzz+11+cos⁡πzf(z) = \frac{\cos \frac{\pi z}{z+1}}{1+\cos \pi z};

(7)

f(z)=(z−2)(3z2−4z−4)1−sin⁡πzf(z) = \frac{(z-2)\left(3 z^{2}-4 z-4\right)}{1-\sin \frac{\pi }{z}};

(8)

f(z)=sin⁡πzeπ/(z+i)−if(z) = \frac{\sin \pi z}{e^{\pi /(z+i)}-i};

(9)

f(z)=e1/(z−2i)1−cos⁡iπzf(z) = \frac{e^{1 /(z-2 i)}}{1-\cos i \pi z};

(10)

f(z)=ecos⁡(πi/2z)−1i+sh⁡3πz2f(z) = \frac{e^{\cos (\pi i / 2 z)}-1}{i+\operatorname {sh} \frac{3 \pi z}{2}}.

Problem 12.18

Let z=az = a be a pole of the function f(z)f(z). Prove that for the function ef(z)e^{f(z)} the point z=az = a is an essential singular point.

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Problem 12.19

Let f(z)f(z) be a function, regular on the set C‾\overline{\mathbb {C}}, except for a single simple pole z=az = a. Prove that if a=∞a = \infty, then f(z)f(z) is a linear function, i.e., f(z)=Az+Bf(z) = A z+B, where A≠0A \neq 0, and if a≠∞a \neq \infty, then f(z)f(z) is a fractional-linear function, i.e., f(z)=az+bcz+df(z) = \frac{a z+b}{c z+d}, where ad−bc≠0a d-b c \neq 0, c≠0c \neq 0.

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Problem 12.20

Find all singular points of the function f(z)f(z) and determine their type, if:

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(1)

f(z)=z2+ln⁡22sin⁡z−54ch⁡1zf(z) = \frac{z^{2}+\ln^{2} 2}{\sin z-\frac{5}{4}} \operatorname {ch} \frac{1}{z};

(2)

f(z)=4z2+π21+e2z(ch⁡πz−1)f(z) = \frac{4 z^{2}+\pi^{2}}{1+e^{2 z}}\left(\operatorname {ch} \frac{\pi }{z}-1\right);

(3)

f(z)=z2+ln⁡22cos⁡z+3i4sh⁡1zf(z) = \frac{z^{2}+\ln^{2} 2}{\cos z+\frac{3 i}{4}} \operatorname {sh} \frac{1}{z};

(4)

f(z)=4z2−12iz−5sh⁡πz−ie1/(sh⁡π/z)f(z) = \frac{4 z^{2}-12 i z-5}{\operatorname {sh} \pi z-i} e^{1 /(\operatorname {sh} \pi / z)};

(5)

f(z)=sh⁡πz−cos⁡iπz(i−eπ/z)2f(z) = \frac{\operatorname {sh} \pi z-\cos \frac{i \pi }{z}}{\left(i-e^{\pi / z}\right)^{2}};

(6)

f(z)=(2z−π)e1/cos⁡zzcos⁡2zcos⁡zf(z) = \frac{(2 z-\pi ) e^{1 / \cos z}}{z \cos 2 z \cos z};

(7)

f(z)=cos⁡πi2(z−1)eπz+eπf(z) = \frac{\cos \frac{\pi i}{2(z-1)}}{e^{\pi z}+e^{\pi }};

(8)

f(z)=4z2−12z+5sin⁡πz−1e1/(sin⁡π/z)f(z) = \frac{4 z^{2}-12 z+5}{\sin \pi z-1} e^{1 /(\sin \pi / z)};

(9)

f(z)=e1/sin⁡z(z2+4π2)z2sh⁡zf(z) = \frac{e^{1 / \sin z}\left(z^{2}+4 \pi^{2}\right)}{z^{2} \operatorname {sh} z};

(10)

f(z)=z3sh⁡14ze1/z−e2/zf(z) = \frac{z^{3} \operatorname {sh} \frac{1}{4 z}}{e^{1 / z}-e^{2 / z}}.

Problem 12.21

Let f(z)f(z) be an entire function taking each finite value only once. Prove that f(z)f(z) is a linear function, i.e., f(z)=az+bf(z) = a z+b, a≠0a \neq 0.

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Problem 12.22

Let z=az = a be an essential singular point of the function f(z)f(z). Can one assert that for the function 1f(z)\frac{1}{f(z)} the point z=az = a is also essential?

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Problem 12.23

Let the point z=az = a be an essential singular point of the function f(z)f(z). Denote M(ρ)=max⁡∣z−a∣=ρ∣f(z)∣M(\rho ) = \max_{\left|z-a\right| = \rho }\left|f(z)\right|. Prove that for any k>0k > 0

lim⁡ρ→0ρkM(ρ)=+∞ \lim _{\rho \rightarrow 0} \rho ^{k} M(\rho ) = +\infty
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Problem 12.24

Let the function g(z)g(z) be regular at the point z=az = a with g(a)=bg(a) = b, and let ζ=b\zeta = b be an essential singular point of the function f(ζ)f(\zeta ). Prove that z=az = a is an essential singular point of the function F(z)=f(g(z))F(z) = f(g(z)).

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Problem 12.25

Let the functions a1(z),…,an(z)a_{1}(z), \ldots , a_{n}(z) be regular at the point aa or have a pole there, and let z=az = a be an essential singular point of the function f(z)f(z). Prove that z=az = a is an essential singular point of the function

F(z)=fn(z)+a1(z)fn−1(z)+…+an(z) F(z) = f^{n}(z)+a_{1}(z) f^{n-1}(z)+\ldots +a_{n}(z)
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Problem 12.26

Find all singular points of the function f(z)f(z) and determine their type, if:

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(1)

f(z)=ctg⁡ez−1ez+1f(z) = \operatorname {ctg} \frac{e^{z}-1}{e^{z}+1};

(2)

f(z)=1sh⁡(πi1+ez1−ez)f(z) = \frac{1}{\operatorname {sh}\left(\pi i \frac{1+e^{z}}{1-e^{z}}\right)};

(3)

f(z)=z2sin⁡2zsin⁡(z−(π/2))−1(cos⁡z−1)2esin⁡z/zf(z) = \frac{z^{2} \sin^{2} z \sin (z-(\pi / 2))^{-1}}{(\cos z-1)^{2}} e^{\sin z / z};

(4)

f(z)=e1/ch⁡2z(πz+π+1)1+cos⁡11+zf(z) = \frac{e^{1 / \operatorname {ch} 2 z}(\pi z+\pi +1)}{1+\cos \frac{1}{1+z}};

(5)

f(z)=ecos⁡z/2/(1+cos⁡z)(z+π)3(1+cos⁡2z)f(z) = \frac{e^{\cos z / 2 /(1+\cos z)}}{(z+\pi )^{3}\left(1+\cos^{2} z\right)};

(6)

f(z)=z2+π2sh⁡2z(eπ/z−e2)tg⁡2zf(z) = \frac{z^{2}+\pi^{2}}{\operatorname {sh} 2 z}\left(e^{\pi / z}-e^{2}\right) \operatorname {tg}^{2} z;

(7)

f(z)=esin⁡z/(1−cos⁡z)(2π−z)2(1+sin⁡2z)f(z) = \frac{e^{\sin z /(1-\cos z)}}{(2 \pi -z)^{2}\left(1+\sin^{2} z\right)};

(8)

f(z)=4z2+π2ch⁡3z(ez/(z−2)−1)ctg⁡2zf(z) = \frac{4 z^{2}+\pi^{2}}{\operatorname {ch} 3 z}\left(e^{z /(z-2)}-1\right) \operatorname {ctg}^{2} z;

(9)

f(z)=zsin⁡3zcos⁡11−z(cos⁡z−1)2esin⁡2z/z2f(z) = \frac{z \sin^{3} z \cos \frac{1}{1-z}}{(\cos z-1)^{2}} e^{\sin^{2} z / z^{2}};

(10)

f(z)=(z−π2)3cos⁡zcos⁡1z−π(sin⁡z−1)2ecos⁡z/(z−(π/2))f(z) = \frac{\left(z-\frac{\pi }{2}\right)^{3} \cos z \cos \frac{1}{z-\pi }}{(\sin z-1)^{2}} e^{\cos z /(z-(\pi / 2))}.

Problem 12.27

Let Pm(z)P_{m}(z) and Qn(z)Q_{n}(z) be polynomials of degree mm and nn, respectively, having no common zeros. Prove that the zeros of the polynomial Qn(z)Q_{n}(z), and only these points, are poles of the function f(z)=Pm(z)Qn(z)f(z) = \frac{P_{m}(z)}{Q_{n}(z)}, and the function f(z)f(z) has no other singular points in the finite plane. Show that the point z=∞z = \infty is a pole of order m−nm-n of the function f(z)f(z) if m>nm > n, and a point of regularity if m⩽nm \leqslant n.

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Problem 12.28

Let a meromorphic function f(z)f(z) have, in C‾\overline{\mathbb {C}}, only a finite number of poles a1,a2,…,ama_{1}, a_{2}, \ldots , a_{m} (the point z=∞z = \infty may also be a pole). Prove that f(z)f(z) is a rational function (a ratio of two polynomials) and is represented in the form

f(z)=A+f0(z)+∑k=1mfk(z), f(z) = A+f_{0}(z)+\sum _{k = 1}^{m} f_{k}(z),

where fk(z)f_{k}(z) and f0(z)f_{0}(z) are, respectively, the principal parts of the Laurent series of the function f(z)f(z) in the neighborhoods of the points aka_{k} and z=∞,A=lim⁡z→∞(f(z)−f0(z))z = \infty , A = \lim_{z \rightarrow \infty }\left(f(z)-f_{0}(z)\right).

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Problem 12.29

Let the function f(z)f(z) be regular in the domain D={z:0<∣z∣<ρ}D = \left\{ z: 0 < \left|z\right| < \rho \right\} and f(z)≢0f(z) \not\equiv 0. What conditions must the function f(z)f(z) satisfy at the point z=0z = 0 so that one can specify a function g(z)g(z), regular in the disk Bρ(0)={z:∣z∣<ρ}B_{\rho }(0) = \left\{ z:\left|z\right| < \rho \right\}, with g(z)≢0g(z) \not\equiv 0, such that lim⁡z→0[f(z)g(z)]=0\lim_{z \rightarrow 0}[f(z) g(z)] = 0.

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Problem 12.30

Let the function f(z)f(z) be regular in a punctured neighborhood of the point z=0z = 0, i.e., in the domain D={z:0<∣z∣<ρ}D = \left\{ z: 0 < \left|z\right| < \rho \right\}, and let the inequality

∣f(z)∣⩽A∣z∣, where A>0. \left|f(z)\right| \leqslant \frac{A}{\sqrt{\left|z\right|}}, \quad \text{ where } \quad A > 0.

hold for all z∈Dz \in D, where A>0A > 0. Prove that z=0z = 0 is a removable singular point of the function f(z)f(z).

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Problem 12.31

Let an entire function f(z)f(z) satisfy, in some domain ∣z∣>R\left|z\right| > R, the condition ∣f(z)∣⩾A∣z∣m\left|f(z)\right| \geqslant A\left|z\right|^{m}, where A>0A > 0 and m⩾0m \geqslant 0 is an integer. Prove that f(z)f(z) is a polynomial.

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