Cauchy's Theorem. The Cauchy-Type Integral.
[43/14%]Prove that if the function is regular in the disk and satisfies the condition , then for any two points and of this disk the inequality holds
Prove that the assertion of Problem 1 remains valid if the domain of regularity of the function is not necessarily a disk, but an arbitrary convex domain in .
A domain is called convex if, together with each pair of points belonging to this domain, it also contains the straight-line segment joining these points.
Let the function be regular in a convex domain and satisfy the condition . Prove that for any two points and of this domain
Prove that the assertion of Problem 3 remains valid if the condition
is replaced by the condition (the real number does not depend on the point ).
Let the function be regular in a simply connected domain . Prove that the function
is an antiderivative of the function .
Let the functions and be regular in a simply connected domain , and let and be, respectively, antiderivatives of these functions. Prove the integration-by-parts formula:
Find the antiderivatives of the functions:
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Let the function be regular in the annulus . Prove that the integral
does not depend on the number (the circle is traversed counterclockwise).
Let the function be regular in the annulus , and let a simple piecewise-smooth curve bound a domain that contains the disk and lies in the disk , so that while traversing the curve the domain remains on the left. Prove that the integral does not depend on the choice of the curve (satisfying the conditions stated above).
Let the function be regular in an arbitrary domain of the complex plane. Prove that a necessary and sufficient condition for the existence of an antiderivative of the function in the domain is that the integral of the function over any simple closed polygonal line lying in the domain be equal to zero.
Prove that the following functions have no antiderivatives in the domains indicated in parentheses:
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Let the function be regular in a bounded doubly connected domain , enclosed between two closed piecewise-smooth curves and , and continuous up to its boundary. Prove that the function has an antiderivative in the domain if and only if
Let the function be regular in a domain, simply connected in , containing the point . Prove that the function has an antiderivative in this domain if and only if .
Let the function be regular in a simply connected domain containing the point . Denote by the domain with the point removed. Prove that the function has an antiderivative in the domain if and only if
Let the functions and be regular in a domain containing the point , and have antiderivatives in the domain (the domain with the point removed). Prove that the functions an arbitrary polynomial) are also regular in the domain and have an antiderivative in the domain .
Let the function be regular in a bounded -connected domain whose boundary consists of closed piecewise-smooth curves . Prove that for the existence of an antiderivative of the function in the domain it is necessary and sufficient that
Let the function be regular in the strip and satisfy the condition
Prove that if the integral converges, then for any in the interval the integral also converges and does not depend on .
Let the function be regular in the angle and satisfy the conditions
Prove that if the integral converges, then for any in the interval the integral also converges and does not depend on .
It is known from analysis that . Compute the integral
Compute the integral .
Using Cauchy's integral formula, compute the integrals (all circles are traversed counterclockwise):
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, where :
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Let the functions and be regular in the disk and continuous in the closed disk . Prove that
Let the function be regular in a domain containing the point , and continuous up to its boundary. Prove that in this case Cauchy's integral formula takes the form
and the formula for the derivatives of retains its previous form.
Let the function be regular in the disk and continuous in the closed disk . Prove the formula
known as the mean value theorem.
Let the function be regular in the disk and continuous in the closed disk . Compute the integral
Prove that a function, regular in some domain and not identically constant, cannot attain its greatest absolute value at an interior point of this domain. (The maximum modulus principle.)
Let the function be harmonic in the disk . Prove that
Prove that a function, harmonic in some domain and not identically constant, can attain neither its greatest nor its least value at an interior point of this domain. (The maximum principle for harmonic functions.)
Let the function be regular in a bounded domain and continuous up to its boundary , consisting of a finite number of closed piecewise-smooth curves. Prove the inequality
where is the distance from the point to the boundary of the domain , and is the total length of the boundary of the domain .
Let the function be regular in the disk and continuous in the closed disk . Prove the inequality
where .
Let the function be regular in the disk and continuous in the closed disk . Prove the inequality
where , and show that for this inequality can be written in the form
Let the function be regular in the entire plane and satisfy the condition for all . Prove that is identically constant. (Liouville's theorem.)
Let the function be regular in the entire plane and satisfy the inequality
Prove that is a polynomial of degree not exceeding .
At all points not belonging to the curve of integration, compute the values of the following Cauchy-type integrals:
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Let the function be regular in the annulus . Prove that the Cauchy-type integral
does not depend on the number for (or for ).
Let the function be regular in the annulus and continuous in the closed annulus . Denote
(the circles are traversed counterclockwise). Prove that for the equality holds.
Let the function be regular in the annulus . Prove that it can be represented in the form , where the function is regular in the disk , and the function is regular for and .
Prove that the representation of the function from the previous problem is unique.
Let a simple closed curve bound a domain , and let a simple closed curve , lying in the domain , bound a domain . Prove that any function , regular in the ring-shaped domain , can be represented in the form , where the function is regular in the domain , and the function is regular outside the domain . Prove also that such a representation is unique if the condition is imposed.
Let be a simple closed curve bounding a domain , and let the function be regular in some domain containing the curve . Prove that for the existence of a function , regular in the closure of the domain and coinciding with the function on the curve , it is necessary and sufficient that
Let be a simple closed piecewise-smooth curve bounding a bounded domain , and let the function be continuous on the curve . Prove that for the equality
to hold it is necessary and sufficient that
and for the equality
to hold it is necessary and sufficient that
Let the function be regular in the strip and satisfy the conditions
Prove that the function can be represented in the form , where the function is regular in the half-plane and satisfies the condition
( arbitrary), and the function is regular in the half-plane and satisfies the condition
( arbitrary). Prove also that such a representation is unique.
Let the function be regular in the angle
continuous up to its boundary and satisfy the conditions
Denote
Prove that:
the function is regular in the entire -plane with a cut along the ray , and the function is regular in the entire -plane with a cut along the ray ;
outside the angle the equality holds;
inside the angle the equality holds.