Chapter 1.6

The Riemann-Stieltjes Integral

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Problem 1.6.1

Suppose α\alpha increases on [ a,ba, b ], a≤x0≤b,αa \leq x_{0} \leq b, \alpha is continuous at x0,f(x0)=1x_{0}, f\left(x_{0}\right) = 1, and f(x)=0f(x) = 0 if x≠x0x \neq x_{0}. Prove that f∈R(α)f \in \mathscr {R}(\alpha ) and that ∫fdα=0\int f d \alpha = 0.

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Problem 1.6.2

Suppose f≥0,ff \geq 0, f is continuous on [a,b], and ∫abf(x)dx=0\int_{a}^{b} f(x) d x = 0. Prove that f(x)=0f(x) = 0 for all x∈[a,b]x \in [a, b]. (Compare this with Exercise 1).

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Problem 1.6.3

Define three functions β1,β2,β3\beta_{1}, \beta_{2}, \beta_{3} as follows: βj(x)=0\beta_{j}(x) = 0 if x<0,βj(x)=1x < 0, \beta_{j}(x) = 1 if x>0x > 0 for j=1,2,3j = 1,2,3; and β1(0)=0,β2(0)=1,β3(0)=12\beta_{1}(0) = 0, \beta_{2}(0) = 1, \beta_{3}(0) = \frac{1}{2}. Let ff be a bounded function on [−1,1][-1,1].

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(a)

Prove that f∈R(β1)f \in \mathscr {R}\left(\beta_{1}\right) if and only if f(0+)=f(0)f(0+) = f(0) and that then

∫fdβ1=f(0) \int f d \beta _{1} = f(0)
(b)

State and prove a similar result for β2\beta_{2}.

(c)

Prove that f∈R(β3)f \in \mathscr {R}\left(\beta_{3}\right) if and only if ff is continuous at 0.

(d)

If ff is continuous at 0 prove that

∫fdβ1=∫fdβ2=∫fdβ3=f(0) \int f d \beta _{1} = \int f d \beta _{2} = \int f d \beta _{3} = f(0)
Problem 1.6.4

If f(x)=0f(x) = 0 for all irrational x,f(x)=1x, f(x) = 1 for all rational xx, prove that f∉Rf \notin \mathscr {R} on [a,b][a, b] for any a<ba < b.

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Problem 1.6.5

Suppose ff is a bounded real function on [a,b][a, b], and f2∈Rf^{2} \in \mathscr {R} on [a,b][a, b]. Does it follow that f∈Rf \in \mathscr {R}? Does the answer change if we assume that f3∈Rf^{3} \in \mathscr {R}?

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Problem 1.6.6

Let PP be the Cantor set constructed in Sec. 2.44. Let ff be a bounded real function on [0,1][0,1] which is continuous at every point outside PP. Prove that f∈Rf \in \mathscr {R} on [0,1][0,1]. Hint: PP can be covered by finitely many segments whose total length can be made as small as desired. Proceed as in Theorem 6.10.

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Problem 1.6.7

Suppose ff is a real function on (0,1](0,1] and f∈Rf \in \mathscr {R} on [c,1][c, 1] for every c>0c > 0. Define

∫01f(x)dx=lim⁡c→0∫c1f(x)dx \int _{0}^{1} f(x) d x = \lim _{c \rightarrow 0} \int _{c}^{1} f(x) d x

if this limit exists (and is finite).

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(a)

If f∈Rf \in \mathscr {R} on [0,1][0,1], show that this definition of the integral agrees with the old one.

(b)

Construct a function ff such that the above limit exists, although it fails to exist with ∣f∣\left|f\right| in place of ff.

Problem 1.6.8

Suppose f∈Rf \in \mathscr {R} on [a,b][a, b] for every b>ab > a where aa is fixed. Define

∫a∞f(x)dx=lim⁡b→∞∫abf(x)dx \int _{a}^{\infty } f(x) d x = \lim _{b \rightarrow \infty } \int _{a}^{b} f(x) d x

if this limit exists (and is finite). In that case, we say that the integral on the left converges. If it also converges after ff has been replaced by ∣f∣\left|f\right|, it is said to converge absolutely.

Assume that f(x)≥0f(x) \geq 0 and that ff decreases monotonically on [1,∞)[1, \infty ). Prove that

∫1∞f(x)dx \int _{1}^{\infty } f(x) d x

converges if and only if

∑n=1∞f(n) \sum _{n = 1}^{\infty } f(n)

converges. (This is the so-called "integral test" for convergence of series).

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Problem 1.6.9

Show that integration by parts can sometimes be applied to the "improper" integrals defined in Exercises 7 and 8. (State appropriate hypotheses, formulate a theorem, and prove it). For instance show that

∫0∞cos⁡x1+xdx=∫0∞sin⁡x(1+x)2dx \int _{0}^{\infty } \frac{\cos x}{1+x} d x = \int _{0}^{\infty } \frac{\sin x}{(1+x)^{2}} d x

Show that one of these integrals converges absolutely, but that the other does not.

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Problem 1.6.10

Let pp and qq be positive real numbers such that

1p+1q=1 \frac{1}{p}+\frac{1}{q} = 1

Prove the following statements.

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(a)

If u≥0u \geq 0 and v≥0v \geq 0, then

uv≤upp+vqq u v \leq \frac{u^{p}}{p}+\frac{v^{q}}{q}

Equality holds if and only if up=vqu^{p} = v^{q}.

(b)

If f∈R(α),g∈R(α),f≥0,g≥0f \in \mathscr {R}(\alpha ), g \in \mathscr {R}(\alpha ), f \geq 0, g \geq 0, and

∫abfpdα=1=∫abgqdα, \int _{a}^{b} f^{p} d \alpha = 1 = \int _{a}^{b} g^{q} d \alpha ,

then

∫abfgdα≤1 \int _{a}^{b} f g d \alpha \leq 1
(c)

If ff and gg are complex functions in R(α)\mathscr {R}(\alpha ), then

∣∫abfgdα∣≤{∫ab∣f∣pdα}1/p{∫ab∣g∣qdα}1/q. \left|\int _{a}^{b} f g d \alpha \right| \leq \left\{ \int _{a}^{b}\left|f\right|^{p} d \alpha \right\} ^{1 / p}\left\{ \int _{a}^{b}\left|g\right|^{q} d \alpha \right\} ^{1 / q}.

This is Hölder's inequality. When p=q=2p = q = 2 it is usually called the Schwarz inequality. (Note that Theorem 1.35 is a very special case of this).

(d)

Show that Hölder's inequality is also true for the "improper" integrals described in Exercises 7 and 8.

Problem 1.6.11

Let α\alpha be a fixed increasing function on [a,b][a, b]. For u∈R(α)u \in \mathscr {R}(\alpha ), define

∥u∥2={∫ab∣u∣2dα}1/2 \left\| u\right\| _{2} = \left\{ \int _{a}^{b}\left|u\right|^{2} d \alpha \right\} ^{1 / 2}

Suppose f,g,h∈R(α)f, g, h \in \mathscr {R}(\alpha ), and prove the triangle inequality

∥f−h∥2≤∥f−g∥2+∥g−h∥2 \left\| f-h\right\| _{2} \leq \left\| f-g\right\| _{2}+\left\| g-h\right\| _{2}

as a consequence of the Schwarz inequality, as in the proof of Theorem 1.37.

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Problem 1.6.12

With the notations of Exercise 11, suppose f∈R(α)f \in \mathscr {R}(\alpha ) and ε>0\varepsilon > 0. Prove that there exists a continuous function gg on [a,b][a, b] such that ∥f−g∥2<ε\left\| f-g\right\|_{2} < \varepsilon.

Hint: Let P={x0,…,xn}P = \left\{ x_{0}, \ldots , x_{n}\right\} be a suitable partition of [a,b][a, b], define

g(t)=xi−tΔxif(xi−1)+t−xi−1Δxif(xi) g(t) = \frac{x_{i}-t}{\Delta x_{i}} f\left(x_{i-1}\right)+\frac{t-x_{i-1}}{\Delta x_{i}} f\left(x_{i}\right)

if xi−1≤t≤xix_{i-1} \leq t \leq x_{i}.

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Problem 1.6.13

Define

f(x)=∫xx+1sin⁡(t2)dt f(x) = \int _{x}^{x+1} \sin \left(t^{2}\right) d t
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(a)

Prove that ∣f(x)∣<1/x\left|f(x)\right| < 1 / x if x>0x > 0.

Hint: Put t2=ut^{2} = u and integrate by parts, to show that f(x)f(x) is equal to

cos⁡(x2)2x−cos⁡[(x+1)2]2(x+1)−∫x2(x+1)2cos⁡u4u3/2du \frac{\cos \left(x^{2}\right)}{2 x}-\frac{\cos \left[(x+1)^{2}\right]}{2(x+1)}-\int _{x^{2}}^{(x+1)^{2}} \frac{\cos u}{4 u^{3 / 2}} d u

Replace cos⁡u\cos u by -1

(b)

Prove that

2xf(x)=cos⁡(x2)−cos⁡[(x+1)2]+r(x) 2 x f(x) = \cos \left(x^{2}\right)-\cos \left[(x+1)^{2}\right]+r(x)

where ∣r(x)∣<c/x\left|r(x)\right| < c / x and cc is a constant.

(c)

Find the upper and lower limits of xf(x)x f(x), as x→∞x \rightarrow \infty.

(d)

Does ∫0∞sin⁡(t2)dt\int_{0}^{\infty } \sin \left(t^{2}\right) d t converge?

Problem 1.6.14

Deal similarly with

f(x)=∫xx+1sin⁡(et)dt f(x) = \int _{x}^{x+1} \sin \left(e^{t}\right) d t

Show that

ex∣f(x)∣<2 e^{x}\left|f(x)\right| < 2

and that

exf(x)=cos⁡(ex)−e−1cos⁡(ex+1)+r(x) e^{x} f(x) = \cos \left(e^{x}\right)-e^{-1} \cos \left(e^{x+1}\right)+r(x)

where ∣r(x)∣<Ce−x\left|r(x)\right| < C e^{-x}, for some constant CC.

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Problem 1.6.15

Suppose ff is a real, continuously differentiable function on [a, b], f(a)=f(b)=0f(a) = f(b) = 0, and

∫abf2(x)dx=1 \int _{a}^{b} f^{2}(x) d x = 1

Prove that

∫abxf(x)f′(x)dx=−12 \int _{a}^{b} x f(x) f^{\prime }(x) d x = -\frac{1}{2}

and that

∫ab[f′(x)]2dx⋅∫abx2f2(x)dx>14 \int _{a}^{b}\left[f^{\prime }(x)\right]^{2} d x \cdot \int _{a}^{b} x^{2} f^{2}(x) d x > \frac{1}{4}
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Problem 1.6.16

For 1<s<∞1 < s < \infty, define

ζ(s)=∑n=1∞1ns \zeta (s) = \sum _{n = 1}^{\infty } \frac{1}{n^{s}}

(This is Riemann's zeta function, of great importance in the study of the distribution of prime numbers). Prove that

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(a)

ζ(s)=s∫1∞[x]xs+1dx\zeta (s) = s \int_{1}^{\infty } \frac{[x]}{x^{s+1}} d x and that

(b)

ζ(s)=ss−1−s∫1∞x−[x]xs+1dx\zeta (s) = \frac{s}{s-1}-s \int_{1}^{\infty } \frac{x-[x]}{x^{s+1}} d x, where [x][x] denotes the greatest integer ≤x\leq x. Prove that the integral in (b) converges for all s>0s > 0. Hint: To prove (a), compute the difference between the integral over [1,N] and the NN th partial sum of the series that defines ζ(s)\zeta (s).

Problem 1.6.17

Suppose α\alpha increases monotonically on [a,b],g[a, b], g is continuous, and g(x)=G′(x)g(x) = G^{\prime }(x) for a≤x≤ba \leq x \leq b. Prove that

∫abα(x)g(x)dx=G(b)α(b)−G(a)α(a)−∫abGdα. \int _{a}^{b} \alpha (x) g(x) d x = G(b) \alpha (b)-G(a) \alpha (a)-\int _{a}^{b} G d \alpha .

Hint: Take gg real, without loss of generality. Given P={x0,x1,…,xn}P = \left\{ x_{0}, x_{1}, \ldots , x_{n}\right\}, choose ti∈(xi−1,xi)t_{i} \in \left(x_{i-1}, x_{i}\right) so that g(ti)Δxi=G(xi)−G(xi−1)g\left(t_{i}\right) \Delta x_{i} = G\left(x_{i}\right)-G\left(x_{i-1}\right). Show that

∑i=1nα(xi)g(ti)Δxi=G(b)α(b)−G(a)α(a)−∑i=1nG(xi−1)Δαi \sum _{i = 1}^{n} \alpha \left(x_{i}\right) g\left(t_{i}\right) \Delta x_{i} = G(b) \alpha (b)-G(a) \alpha (a)-\sum _{i = 1}^{n} G\left(x_{i-1}\right) \Delta \alpha _{i}
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Problem 1.6.18

Let γ1,γ2,γ3\gamma_{1}, \gamma_{2}, \gamma_{3} be curves in the complex plane, defined on [0,2π][0,2 \pi ] by

γ1(t)=eit,γ2(t)=e2it,γ3(t)=e2πitsin⁡(1/t) \gamma _{1}(t) = e^{i t}, \quad \gamma _{2}(t) = e^{2 i t}, \quad \gamma _{3}(t) = e^{2 \pi i t \sin (1 / t)}

Show that these three curves have the same range, that γ1\gamma_{1} and γ2\gamma_{2} are rectifiable, that the length of γ1\gamma_{1} is 2π2 \pi, that the length of γ2\gamma_{2} is 4π4 \pi, and that γ3\gamma_{3} is not rectifiable.

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Problem 1.6.19

Let γ1\gamma_{1} be a curve in Rk\mathbb {R}^{k}, defined on [a,b][a, b]; let ϕ\phi be a continuous 1-1 mapping of [c,d][c, d] onto [a,b][a, b], such that ϕ(c)=a\phi (c) = a; and define γ2(s)=γ1(ϕ(s))\gamma_{2}(s) = \gamma_{1}(\phi (s)). Prove that γ2\gamma_{2} is an arc, a closed curve, or a rectifiable curve if and only if the same is true of γ1\gamma_{1}. Prove that γ2\gamma_{2} and γ1\gamma_{1} have the same length.

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