The Stone-Weierstrass Theorem
[13/100%]Suppose that is a topological space for which there is a collection of continuous real-valued functions on that separates points in . Show that is Hausdorff.
Let be a compact, Hausdorff space and an algebra that contains the constant functions. Show that is dense in if and only if separates points in .
Let be an algebra of continuous real-valued functions on a compact space that contains the constant functions. Let have the property that for some constant function and real number , the function belongs to . Show that also belongs to .
For , show that if and only if for all .
For and , show that there are real numbers for which
For and , show that there are real numbers for which
Let be a continuous real-valued function on that is periodic with period . For , show that there are real numbers, , such that
Let and be compact, Hausdorff spaces and belong to . Show that for each , there are functions in and in such that
Rather than use the Weierstrass Approximation Theorem in the proof of the Stone-Weierstrass Theorem, show that there are natural numbers and for which the polynomial satisfies (14).
Let be a collection of continuous real-valued functions on a compact, Hausdorff space that separates the points of . Show that every continuous real-valued function on can be uniformly approximated arbitrarily closely by a polynomial in a finite number of functions of .
Let be an algebra of continuous real-valued functions on a compact, Hausdorff space . Show that the closure of , also is an algebra.
Let be an algebra of continuous real-valued functions on a compact, Hausdorff space that separates points. Show that either or there is a point for which .
Let be a compact, Hausdorff space and an algebra of continuous functions on that separates points and contains the constant functions.
Given any two numbers and and points , show that there is a function in for which and .
Is it the case that given any two numbers and and disjoint closed subsets and of , there is a function in for which on and on ?