The Banach Contraction Principle and Picard's Theorem
[16/100%]Let be a polynomial. Show that is Lipschitz if and only if the degree of is less than 2.
Fix , define for in .
For what values of is ?
For what values of is and a contraction?
Does a mapping of a metric space into itself that is Lipschitz with Lipschitz constant less than 1 necessarily have a fixed-point?
Does a mapping of a complete metric space into itself that is Lipschitz with Lipschitz constant 1 necessarily have a fixed-point?
Let be a compact metric space and a mapping from into itself such that
Show that has a unique fixed-point.
Define for all real numbers . Show that
Show that does not have a fixed-point. Does this contradict the preceding problem?
In Euclidean space consider the closed unit ball . Let map into and be Lipschitz with Lipschitz constant 1. Without using the Brouwer Fixed-Point Theorem, show that has a fixed-point.
Suppose that the mapping is a contraction. Define for all in . Show that the mapping is both one-to-one and onto. Also show that and its inverse are continuous.
Let be a complete metric space containing the point and let be a positive real number. Define . Suppose that the mapping is Lipschitz with Lipschitz constant . Suppose also that . Prove that and that has a fixed-point.
Show that if the function has continuous first-order partial derivatives, then for each point in there is a neighborhood of () on which the Lipschitz assumption (7) holds.
In case the function has the form , where the function is continuous, prove that the following is an explicit formula for the solution of (5):
Consider the differential equation
Show that the function that is identically 0 is a solution and the function defined by , if and , if , is also a solution. Does this contradict the Picard Existence Theorem?
For a positive number , consider the differential equation
Show that on the interval there is a unique solution of this differential equation that is defined by and there is no solution in an interval strictly containing .
Let be an open interval in and suppose that the function has the property that there are points in and a number such that but does not belong to . Prove that there is no solution to the differential equation (5) by arguing that if is a solution, then the continuous function fails to attain a minimum value on the interval .
Use the preceding exercise to prove that if is an open interval in and the function is differentiable, then the image of the derivative is an interval.
State and prove a form of the Picard Existence Theorem for systems of differential equations in the following context: is an open subset of is continuous, the point () is in , and the system of differential equations is