Section 11.6

Products of Lebesgue Measure on Euclidean Spaces: Cavalieri's Principle

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Problem 11.49

Is every continuous real-valued function k:R×R→Rk: \mathbb {R} \times \mathbb {R} \rightarrow \mathbb {R} measurable with respect to the product measure space? Show that for any subset AA of R\mathbb {R}, the set A×QA \times Q is measurable with respect to the product measure, irrespective of the measurability of AA.

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Problem 11.50

Suppose that the function f:R2→Rf: \mathbb {R}^{2} \rightarrow \mathbb {R} is continuous with respect to each variable separately, show that it is Lebesgue measurable with respect to μ2\mu_{2}.

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Problem 11.51

If f:Rm→Rf: \mathbb {R}^{m} \rightarrow \mathbb {R} and g:Rk→Rg: \mathbb {R}^{k} \rightarrow \mathbb {R} are Lebesgue measurable, show that the function (x,y)↦f(x)⋅g(y)(x, y) \mapsto f(x) \cdot g(y) is Lebesgue measurable on Rm+k\mathbb {R}^{m+k}.

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Problem 11.52

Verify that

∫−11[∫−11x2−y2(x2+y2)2dx]dy=−π4 and ∫−11[∫−11x2−y2(x2+y2)2dy]dx=π4 \int _{-1}^{1}\left[\int _{-1}^{1} \frac{x^{2}-y^{2}}{\left(x^{2}+y^{2}\right)^{2}} d x\right] d y = -\frac{\pi }{4} \text{ and } \int _{-1}^{1}\left[\int _{-1}^{1} \frac{x^{2}-y^{2}}{\left(x^{2}+y^{2}\right)^{2}} d y\right] d x = \frac{\pi }{4}

by checking that, for (x,y)≠(0,0)(x, y) \neq (0,0),

∂∂y[yx2+y2]=x2−y2(x2+y2)2=∂∂x[−xx2+y2] \frac{\partial }{\partial y}\left[\frac{y}{x^{2}+y^{2}}\right] = \frac{x^{2}-y^{2}}{\left(x^{2}+y^{2}\right)^{2}} = \frac{\partial }{\partial x}\left[\frac{-x}{x^{2}+y^{2}}\right]

Explain why this example does not contradict either Tonelli's Theorem or Fubini's Theorem.

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Problem 11.53

Show that

∫−11[∫−11xy(x2+y2)2dx]dy≠∫−11[∫−11xy(x2+y2)2dy]dx \int _{-1}^{1}\left[\int _{-1}^{1} \frac{x y}{\left(x^{2}+y^{2}\right)^{2}} d x\right] d y \neq \int _{-1}^{1}\left[\int _{-1}^{1} \frac{x y}{\left(x^{2}+y^{2}\right)^{2}} d y\right] d x

Explain why this does not contradict either Tonelli's Theorem or Fubini's Theorem.

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Problem 11.54

Define f(x,y)=yexp⁡(−(1+x2)y2)f(x, y) = y \exp \left(-\left(1+x^{2}\right) y^{2}\right) for x≥0,y≥0x \geq 0, y \geq 0. Show that

∫0∞[∫0∞f(x,y)dy]dx=∫0∞[∫0∞f(x,y)dx]dy \int _{0}^{\infty }\left[\int _{0}^{\infty } f(x, y) d y\right] d x = \int _{0}^{\infty }\left[\int _{0}^{\infty } f(x, y) d x\right] d y

and conclude from this that

∫0∞exp⁡(−x2)dx=π/2 \int _{0}^{\infty } \exp \left(-x^{2}\right) d x = \sqrt{\pi } / 2
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Problem 11.55

Define f(x,y)=exp⁡(−xy2)⋅sin⁡xf(x, y) = \exp \left(-x y^{2}\right) \cdot \sin x for x≥0,y≥0x \geq 0, y \geq 0. Show that for each b>0b > 0

∫0b[∫0∞f(x,y)dy]dx=∫0∞[∫0bf(x,y)dx]dy \int _{0}^{b}\left[\int _{0}^{\infty } f(x, y) d y\right] d x = \int _{0}^{\infty }\left[\int _{0}^{b} f(x, y) d x\right] d y

and conclude from this that, as an improper Riemann integral,

∫0∞sin⁡xx1/2dx≡lim⁡b→∞∫0bsin⁡xx1/2dx=π/2 \int _{0}^{\infty } \frac{\sin x}{x^{1 / 2}} d x \equiv \lim _{b \rightarrow \infty } \int _{0}^{b} \frac{\sin x}{x^{1 / 2}} d x = \sqrt{\pi / 2}
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Problem 11.56

Assume that f:Rn→[0,∞)f: \mathbb {R}^{n} \rightarrow [0, \infty ) is finitely supported and Lebesgue integrable, and that g:R→Rg: \mathbb {R} \rightarrow \mathbb {R} is increasing, bounded, absolutely continuous and g(0)=0g(0) = 0. Show that g∘f:Rn→Rg \circ f: \mathbb {R}^{n} \rightarrow \mathbb {R} is Lebesgue integrable, and that

∫Rng(f(x))dμn(x)=∫0∞[μn{x∈Rn∣0≤t≤f(x)}⋅g′(t)]dt \int _{\mathbb {R}^{n}} g(f(x)) d \mu _{n}(x) = \int _{0}^{\infty }\left[\mu _{n}\left\{ x \in \mathbb {R}^{n} \mid 0 \leq t \leq f(x)\right\} \cdot g^{\prime }(t)\right] d t
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Problem 11.57

Show that the product of semi-rings is a semi-ring. Use this to show that the collection of bounded intervals in Rn\mathbb {R}^{n} is a semi-ring.

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Problem 11.58

Let the mapping N:Rn→Rn\mathcal{N}: \mathbb {R}^{n} \rightarrow \mathbb {R}^{n} be one-to-one and onto and there is a c>0c > 0 such that

∥N(x)−N(y)∥≥c⋅∥x−y∥∀x,y∈Rn \left\| \mathcal{N}(x)-\mathcal{N}(y)\right\| \geq c \cdot \left\| x-y\right\| \forall x, y \in \mathbb {R}^{n}

Show that if f:Rn→Rf: \mathbb {R}^{n} \rightarrow \mathbb {R} is Lebegue measurable, so is f∘Nf \circ \mathcal{N}.

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