Section 6.5

Integrating Derivatives: Differentiating Indefinite Integrals

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Problem 6.48

The Cantor-Lebesgue function φ\varphi is continuous and increasing on [0,1][0,1]. Conclude from Theorem 12 that φ\varphi is not absolutely continuous on [0,1][0,1].

Theorem 12: If the function f:[a,b]→Rf: \left[a, b\right] \rightarrow \mathbb {R} is absolutely continuous, then it is differentiable almost everywhere on (a,b)(a, b), its derivative f′f' is integrable, and ∫abf′ dm=f(b)−f(a)\int_{a}^{b} f' \, dm = f(b) - f(a). Compare this reasoning with that proposed in Problem 42.

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Problem 6.49

Let f:[a,b]→Rf:[a, b] \rightarrow \mathbb {R} be continuous and differentiable almost everywhere on (a,ba, b). Show that

∫abf′dm=f(b)−f(a) if and only if ∫ab[lim⁡n→∞Diff⁡1/nf]dm=lim⁡n→∞[∫abDiff⁡1/nf]dm \begin{gathered} \int _{a}^{b} f^{\prime } d m = f(b)-f(a) \\ \text{ if and only if } \\ \int _{a}^{b}\left[\lim _{n \rightarrow \infty } \operatorname {Diff}_{1 / n} f\right] d m = \lim _{n \rightarrow \infty }\left[\int _{a}^{b} \operatorname {Diff}_{1 / n} f\right] d m \end{gathered}
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Problem 6.50

Let f:[a,b]→Rf:[a, b] \rightarrow \mathbb {R} be continuous and differentiable almost everywhere on (a,ba, b). Show that if {Diff⁡1/nf}\left\{ \operatorname {Diff}_{1 / n} f\right\} is uniformly integrable over [a,b][a, b], then

∫abf′dm=f(b)−f(a) \int _{a}^{b} f^{\prime } d m = f(b)-f(a)
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Problem 6.51

Let f:[a,b]→Rf:[a, b] \rightarrow \mathbb {R} be continuous and differentiable almost everywhere on (a,ba, b). Suppose that there is a non-negative integrable function g:[a,b]→Rg:[a, b] \rightarrow \mathbb {R} for which

∣Diff⁡1/nf∣≤g on [a,b] for all n. \left|\operatorname {Diff}_{1 / n} f\right| \leq g \text{ on }[a, b] \text{ for all } n .

Show that

∫abf′dm=f(b)−f(a) \int _{a}^{b} f^{\prime } d m = f(b)-f(a)
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Problem 6.52

If f:[a,b]→Rf:[a, b] \rightarrow \mathbb {R} is absolutely continuous, show that ff is Lipschitz if and only if there is a c≥0c \geq 0 for which ∣f′∣≤c\left|f^{\prime }\right| \leq c almost everywhere on [a,b][a, b].

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Problem 6.53

Let f:[a,b]→Rf:[a, b] \rightarrow \mathbb {R} be of bounded variation, and define v(x)=TV(f[a,x])v(x) = T V\left(f_{[a, x]}\right) for all x∈[a,b]x \in [a, b].

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(i)

Show that ∣f′∣≤v′\left|f^{\prime }\right| \leq v^{\prime } almost everywhere on [a,b][a, b], and deduce from this that

∫ab∣f′∣dm≤TV(f) \int _{a}^{b}\left|f^{\prime }\right| d m \leq T V(f)
(ii)

Show that the above is an equality if and only if ff is absolutely continuous on [a,b][a, b].

(iii)

Compare parts (i) and (ii) with Corollaries 4 and 12, respectively.

Problem 6.54

Construct an absolutely continuous, strictly increasing function f:[0,1]→Rf:[0,1] \rightarrow \mathbb {R} for which f′=0f^{\prime } = 0 on a set of positive measure.

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Problem 6.55

For ff and gg as in the statement of Theorem 17, is it possible to establish the change of variables formula (30) by directly verifying that

ddx[∫ag(x)fdm−∫cx[f∘g]⋅g′dm]=0 for almost all x∈(c,d)? \frac{d}{d x}\left[\int _{a}^{g(x)} f d m-\int _{c}^{x}[f \circ g] \cdot g^{\prime } d m\right] = 0 \text{ for almost all } x \in (c, d) ?

Theorem 17 (Change of Variables): Let the function f:[a,b]→Rf: \left[a, b\right] \rightarrow \mathbb {R} be integrable. If the function g:[c,d]→Rg: \left[c, d\right] \rightarrow \mathbb {R} is increasing and absolutely continuous, a=g(c)a = g(c) and b=g(d)b = g(d), then ∫abf dm=∫cd[f∘g]⋅g′ dm\int_{a}^{b} f \, dm = \int_{c}^{d} \left[f \circ g\right] \cdot g' \, dm — the assertion (30) that this problem asks whether one can verify directly via the equation above.

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