Section 6.4

Absolutely Continuous Functions

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Problem 6.34

Let f:[0,1]→Rf:[0,1] \rightarrow \mathbb {R} be continuous, and be absolutely continuous on [ϵ,1][\epsilon , 1] for each 0<ϵ<10 < \epsilon < 1.

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(i)

Show that f:[0,1]→Rf:[0,1] \rightarrow \mathbb {R} may not be absolutely continuous.

(ii)

Show that f:[0,1]→Rf:[0,1] \rightarrow \mathbb {R} is absolutely continuous if it is increasing.

(iii)

Show that the function f:[0,1]→Rf:[0,1] \rightarrow \mathbb {R} defined by f(x)=xf(x) = \sqrt{x} for 0≤x≤10 \leq x \leq 1 is absolutely continuous, but not Lipschitz.

Problem 6.35

Verify that the inclusions in (19) are strict.

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Problem 6.36

Show that a Lipschitz function f:[a,b]→Rf:[a, b] \rightarrow \mathbb {R} is the difference of increasing Lipschitz functions.

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Problem 6.37

Assume that f:[a,b]→Rf:[a, b] \rightarrow \mathbb {R} is increasing. Show that ff is absolutely continuous if and only if for each ϵ>0\epsilon > 0, there is a δ>0\delta > 0 such that for every countable, disjoint collection {(ak,bk)}k=1∞\left\{ \left(a_{k}, b_{k}\right)\right\}_{k = 1}^{\infty } of open intervals in (a,ba, b),

∑k=1∞[f(bk)−f(ak)]<ϵ if ∑k=1∞[bk−ak]<δ \sum _{k = 1}^{\infty }\left[f\left(b_{k}\right)-f\left(a_{k}\right)\right] < \epsilon \text{ if } \sum _{k = 1}^{\infty }\left[b_{k}-a_{k}\right] < \delta
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Problem 6.38

Show that if f:[a,b]→Rf:[a, b] \rightarrow \mathbb {R} is increasing and absolutely continuous, then it maps sets of measure zero to sets of measure zero.

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Problem 6.39

Let f:[a,b]→Rf:[a, b] \rightarrow \mathbb {R} be continuous. Conclude from the continuity of ff and the compactness of [a,b][a, b] that ff maps closed sets to closed sets and therefore maps FσF_{\sigma } sets to FσF_{\sigma } sets.

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Problem 6.40

Show that if f:[a,b]→Rf:[a, b] \rightarrow \mathbb {R} is increasing and absolutely continuous, then ff maps measurable sets to measurable sets.

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Problem 6.41

Show that if f:[a,b]→Rf:[a, b] \rightarrow \mathbb {R} is continuous and increasing, then ff is absolutely continuous if and only if for each ϵ\epsilon, there is a δ>0\delta > 0 such that for each measurable subset EE of [a,b][a, b],

m(f(E))<ϵ if m(E)<δ. m(f(E)) < \epsilon \text{ if } m(E) < \delta .
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Problem 6.42

Show that the Cantor-Lebesgue function φ\varphi is not absolutely continuous on [0,1][0,1] by arguing that the function ψ\psi, defined by ψ(x)=x+φ(x)\psi (x) = x+\varphi (x) for 0≤x≤10 \leq x \leq 1, maps the Cantor, a set of measure zero, to a set of measure 1.

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Problem 6.43

Show that both the sum and product of absolutely continuous functions are absolutely continuous.

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Problem 6.44

Define the functions ff and gg on [−1,1][-1,1] by f(x)=x13f(x) = x^{\frac{1}{3}} for −1≤x≤1-1 \leq x \leq 1 and

g(x)={x2cos⁡(π/2x) if x≠0,x∈[−1,1]0 if x=0. g(x) = \begin{cases} x^{2} \cos (\pi / 2 x) & \text{ if } x \neq 0, x \in [-1,1] \\ 0 & \text{ if } x = 0.\end{cases}
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(i)

Show that both f:[−1,1]→Rf:[-1,1] \rightarrow \mathbb {R} and g:[−1,1]→Rg:[-1,1] \rightarrow \mathbb {R} are absolutely continuous.

(ii)

For the partition Pn={−1,0,1/2n,1/[2n−1],…,1/3,1/2,1}P_{n} = \left\{ -1,0,1 / 2 n, 1 /[2 n-1], \ldots , 1 / 3,1 / 2,1\right\} of [−1,1][-1,1], examine V(f∘g,Pn)V\left(f \circ g, P_{n}\right).

(iii)

Show that f∘g:[−1,1]→Rf \circ g:[-1,1] \rightarrow \mathbb {R} fails to be of bounded variation, and hence also fails to be absolutely continuous.

Problem 6.45

Let f:R→Rf: \mathbb {R} \rightarrow \mathbb {R} be Lipschitz and g:[a,b]→Rg:[a, b] \rightarrow \mathbb {R} be absolutely continuous. Show that the composition f∘g:[a,b]→Rf \circ g:[a, b] \rightarrow \mathbb {R} is absolutely continuous.

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Problem 6.46

Let f:R→Rf: \mathbb {R} \rightarrow \mathbb {R} be absolutely continuous and g:[a,b]→Rg:[a, b] \rightarrow \mathbb {R} be absolutely continuous and strictly increasing. Show that the composition f∘g:[a,b]→Rf \circ g:[a, b] \rightarrow \mathbb {R} is absolutely continuous.

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Problem 6.47

Prove the converse of the implication in Theorem 11.

Theorem 11: If the function f:[a,b+1]→Rf: \left[a, b+1\right] \rightarrow \mathbb {R} is absolutely continuous, then the collection of divided difference functions F={Diff⁡hf:[a,b]→R}0<h≤1\mathcal{F} = \left\{ \operatorname {Diff}_{h} f: \left[a, b\right] \rightarrow \mathbb {R}\right\}_{0 < h \leq 1} is uniformly integrable.

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