Section 4.5

Countable Additivity and Continuity of Integration

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Problem 4.37

Prove the theorem regarding the continuity of integration.

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Problem 4.38

Let f:[0,∞]→Rf:[0, \infty ] \rightarrow \mathbb {R} be integrable. Show that

lim⁡n→∞∫1/nnfdm=∫0∞fdm \lim _{n \rightarrow \infty } \int _{1 / n}^{n} f d m = \int _{0}^{\infty } f d m
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Problem 4.39

Let f:R→Rf: \mathbb {R} \rightarrow \mathbb {R} be integrable. Show that the function F:R→RF: \mathbb {R} \rightarrow \mathbb {R} defined by

F(x)=∫−∞xfdm for all x∈R F(x) = \int _{-\infty }^{x} f d m \text{ for all } x \in \mathbb {R}

is properly defined and continuous. Is it Lipschitz?

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Problem 4.40

For each of the two functions ff on [1,∞)[1, \infty ) defined below, show that lim⁡n→∞∫[1,n]fdm\lim_{n \rightarrow \infty } \int_{[1, n]} f d m exists while ff is not integrable over [1,∞)[1, \infty ). Does this contradict the continuity of integration?

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(i)

Define f(x)=(−1)k/kf(x) = (-1)^{k} / k, for k≤x<k+1k \leq x < k+1.

(ii)

Define f(x)=(sin⁡x)/xf(x) = (\sin x) / x for 1≤x<∞1 \leq x < \infty.

Problem 4.41

Let f:R→Rf: \mathbb {R} \rightarrow \mathbb {R} be integrable. Show that the following four assertions are equivalent:

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(i)

f=0f = 0 almost everywhere on R\mathbb {R}.

(ii)

∫Rfgdm=0\int_{\mathbb {R}} f g d m = 0 for every bounded, finitely supported, measurable function gg.

(iii)

∫Afdm=0\int_{A} f d m = 0 for every measurable set AA.

(iv)

∫Ofdm=0\int_{\mathcal{O}} f d m = 0 for every open set O\mathcal{O}.

Problem 4.42

Let f:[a,b]→Rf:[a, b] \rightarrow \mathbb {R} be integrable and ϵ>0\epsilon > 0. Establish the following approximations.

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(i)

There is a simple function η:[a,b]→R\eta :[a, b] \rightarrow \mathbb {R} for which ∫[a,b]∣f−η∣dm<ϵ\int_{[a, b]}\left|f-\eta \right| d m < \epsilon.

(ii)

There is a step-function s:[a,b]→Rs:[a, b] \rightarrow \mathbb {R} for which ∫[a,b]∣f−s∣dm<ϵ\int_{[a, b]}\left|f-s\right| d m < \epsilon.

(iii)

There is a continuous function g:[a,b]→Rg:[a, b] \rightarrow \mathbb {R} for which ∫[a,b]∣f−g∣dm<ϵ\int_{[a, b]}\left|f-g\right| d m < \epsilon.