Chapter 8

Distribution Functions and Their Basic Properties, Helly-Bray Type Results

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Problem 8.1

Let F:R→[0,1]F: \mathbb {R} \rightarrow [0,1] be nondecreasing, right continuous, F(−∞)=0F(-\infty ) = 0 and F(∞)=1F(\infty ) = 1 (i.e., a d.f. of a r.v.), and let F−1F^{-1} be defined by

F−1(y)=inf⁡{x∈R;F(x)≥y},y∈[0,1]. F^{-1}(y) = \inf \left\{ x \in \mathbb {R} ; F(x) \geq y\right\} , y \in [0,1] .

Next, consider the probability space (Ω,A,P)=([0,1],B[0,1],P)(\Omega , \mathcal{A}, P) = \left([0,1], \mathcal{B}_{[0,1]}, P\right), where P=λP = \lambda is the Lebesgue measure, and on Ω\Omega, define the function XX by X(ω)=F−1(ω)X(\omega ) = F^{-1}(\omega ). Then show that XX is a r.v. and that its d.f. is FF.

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Problem 8.2
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(i)

If Xn→n→∞PXX_{n} \xrightarrow [n \rightarrow \infty ]{P} X, then show that FXn⇒n→∞FXF_{X_{n}} \underset {n \rightarrow \infty }{\Rightarrow } F_{X}.

(ii)

By an example, show that the converse statement in part (i) need not be true.

Problem 8.3

Let Fn,n≥1F_{n}, n \geq 1, be d.f.s of r.v.s and suppose that Fn⇒n→∞FF_{n} \underset {n \rightarrow \infty }{\Rightarrow } F where FF is a d.f. with Var⁡[F]=1\operatorname {Var}\left[F\right] = 1. Then show that FF is the d.f. of a r.v.

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Problem 8.4

Show that the Weak Compactness Theorem (Theorem 5) still holds, if condition 1 in Definition 1 is replaced by: (0≤)F(x)≤B,x∈R,n≥1(0 \leq ) F(x) \leq B, x \in \mathbb {R}, n \geq 1, for some B<∞B < \infty.

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Problem 8.5

Show that Theorems 6−86-8 hold true if, for all x∈R,0≤F(x)≤Bx \in \mathbb {R}, 0 \leq F(x) \leq B and 0≤Fn(x)≤B,n=1,2,…0 \leq F_{n}(x) \leq B, n = 1,2, \ldots, for some B>0B > 0, as indicated in Remark 6.

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Problem 8.6

For n=1,2,…n = 1,2, \ldots, consider the r.v.s Xn,XX_{n}, X and YY such that ∣Xn∣≤Y,E[Yr]<∞\left|X_{n}\right| \leq Y, \mathbb {E}\left[Y^{r}\right] < \infty (for some r>0r > 0), and Xn→n→∞dXX_{n} \xrightarrow [n \rightarrow \infty ]{d} X. Then show that E[∣Xn∣r]⟶n→∞E[∣X∣r]\mathbb {E}\left[\left|X_{n}\right|^{r}\right] \underset {n \rightarrow \infty }{\longrightarrow } \mathbb {E}\left[\left|X\right|^{r}\right].

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Problem 8.7

Let XX be a r.v. with d.f. FF; i.e., F(x)=P(X≤x),x∈RF(x) = \mathbb {P}\left(X \leq x\right), x \in \mathbb {R}. Then show that

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(i)

P(X<x)=F(x−)\mathbb {P}\left(X < x\right) = F(x-) (the left-hand side limit).

(ii)

F(x)F(x) is continuous at xx if and only if P(X=x)=0\mathbb {P}\left(X = x\right) = 0.

Problem 8.8

In the following expression, determine the constants α\alpha and β\beta, so that the function FF defined is the d.f. of a r.v.

F(x)=0,x≤0, and F(x)=α+βe−x2/2,x>0 F(x) = 0, x \leq 0, \quad \text{ and } \quad F(x) = \alpha +\beta e^{-x^{2} / 2}, \quad x > 0
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Problem 8.9

For n=1,2,…n = 1,2, \ldots, let FnF_{n} and FF be d.f.s such that Fn→n→∞cFF_{n} \xrightarrow [n \rightarrow \infty ]{c} F, and let FF be continuous. Then show that Fn(x)⟶n→∞F(x)F_{n}(x) \underset {n \rightarrow \infty }{\longrightarrow } F(x) uniformly in x∈Rx \in \mathbb {R}.

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Problem 8.10

Let XX be a r.v. with continuous d.f. FXF_{X}, and define the r.v. YY as follows: Y=XY = X if X≤CX \leq C, and Y=CY = C if X>CX > C, where CC is a constant. Then

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(i)

Determine the d.f. of the r.v. Y,FYY, F_{Y}.

(ii)

Show that FY=F1+F2F_{Y} = F_{1}+F_{2}, where F1F_{1} is a continuous d.f. and F2F_{2} is a step function.

Problem 8.11

By a simple example demonstrate that it is possible that Fn,n≥1F_{n}, n \geq 1, are d.f.s of r.v.s with Fn⇒n→∞FF_{n} \underset {n \rightarrow \infty }{\Rightarrow } F, a d.f., but not that of a r.v.

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Problem 8.12

For n≥1n \geq 1, let XnX_{n} and XX be r.v.s defined on the probability space (Ω,A,P)(\Omega , \mathcal{A}, P), and suppose that, as n→∞,E[∣Xn∣]→E[∣X∣]<∞n \rightarrow \infty , \mathbb {E}\left[\left|X_{n}\right|\right] \rightarrow \mathbb {E}\left[\left|X\right|\right] < \infty and Xn→dXX_{n} \xrightarrow {d} X. Then show that ∣Xn∣,n≥1\left|X_{n}\right|, n \geq 1, are uniformly integrable.

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Problem 8.13

For n≥1n \geq 1, let FnF_{n} and FF be d.f.s of r.v.s, let fnf_{n} be real-valued measurable functions defined on R\mathbb {R}, let f:R→Rf: \mathbb {R} \rightarrow \mathbb {R} be continuous, and let g:R→[0,∞)g: \mathbb {R} \rightarrow [0, \infty ) be continuous. Assume that:

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(i)

Fn→FF_{n} \rightarrow F as n→∞n \rightarrow \infty.

(ii)

∣fn(x)∣≤g(x),x∈R,n≥1\left|f_{n}(x)\right| \leq g(x), x \in \mathbb {R}, n \geq 1.

(iii)

fn(x)⟶n→∞f(x)f_{n}(x) \underset {n \rightarrow \infty }{\longrightarrow } f(x) uniformly on finite intervals.

(iv)

∫RgdFn⟶n→∞∫RgdF\int_{\mathbb {R}} g d F_{n} \underset {n \rightarrow \infty }{\longrightarrow } \int_{\mathbb {R}} g d F and ∫RgdF<∞\int_{\mathbb {R}} g d F < \infty.

Then show that ∫RfndFn→n→∞⟶∫RfdF\int_{\mathbb {R}} f_{n} d F_{n} \xrightarrow [n \rightarrow \infty ]{\longrightarrow } \int_{\mathbb {R}} f d F and ∫RfdF\int_{\mathbb {R}} f d F is finite.