Chapter 7

The Hahn-Jordan Decomposition Theorem, The Lebesgue Decomposition Theorem, and the Radon-Nikodym Theorem

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Problem 7.1

Verify the relation An0=A+∑j=n0∞(Aj−Aj+1)A_{n_{0}} = A+\sum_{j = n_{0}}^{\infty }\left(A_{j}-A_{j+1}\right) used in the proof of Lemma 1; namely, if {An},n≥1\left\{ A_{n}\right\} , n \geq 1, form a nonincreasing sequence and A=⋂n=1∞AnA = \bigcap_{n = 1}^{\infty } A_{n}, then for any n0≥1n_{0} \geq 1, the given relation holds. In particular, A1=∑n=1∞(An−An+1)A_{1} = \sum_{n = 1}^{\infty }\left(A_{n}-A_{n+1}\right) if ⋂n=1∞An=⊘\bigcap_{n = 1}^{\infty } A_{n} = \oslash.

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Problem 7.2

Given the finite measures μn,n=1,2,…\mu_{n}, n = 1,2, \ldots, on the measurable space (Ω,A)(\Omega , \mathcal{A}), define a probability measure μ\mu such that μn≪μ\mu_{n} \ll \mu for all nn (i.e., μ(A)=0\mu (A) = 0 for A∈AA \in \mathcal{A} implies μn(A)=0,n≥1\mu_{n}(A) = 0, n \geq 1).

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Problem 7.3
(i)
Problem 7.4

Let U(α,β)U(\alpha , \beta ) be the uniform distribution over the interval [α,β](α<β)[\alpha , \beta ](\alpha < \beta ), and for n≥1n \geq 1, let PnP_{n} and QnQ_{n} be the (probability) measures corresponding to U(−1n,1)U\left(-\frac{1}{n}, 1\right) and U(0,1+1n)U\left(0,1+\frac{1}{n}\right). Then show that ∥Pn−Qn∥→0\left\| P_{n}-Q_{n}\right\| \rightarrow 0 as n→∞n \rightarrow \infty, by using part (ii) of Exercise 3.

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Problem 7.5

Let PP and QQ be two probability measures defined on the measurable space (Ω,A)(\Omega , \mathcal{A}), and suppose that P≈QP \approx Q (i.e., P≪QP \ll Q and Q≪PQ \ll P). Let f=dP/dμf = d P / d \mu and g=dQ/dμg = d Q / d \mu for some σ\sigma-finite measure μ\mu dominating both PP and QQ (e.g., μ=P+Q)\mu = P+Q), and let Z=log⁡(g/f)Z = \log (g / f), where as always, log⁡\log stands for the natural logarithm. Then (with reference to Exercise 3), show that

∥P−Q∥≤2(1−e−ε)+2P(∣Z∣>ε) for every ε>0. \left\| P-Q\right\| \leq 2\left(1-e^{-\varepsilon }\right)+2 \mathbb {P}\left(\left|Z\right| > \varepsilon \right) \text{ for every } \varepsilon > 0.
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Problem 7.6

Let P,QP, Q and f,gf, g be as in Exercise 3 and, without loss of generality, we suppose that the dominating measure μ\mu is a probability measure (e.g., μ=(P+Q)/2\mu = (P+Q) / 2). Define ρ\rho by ρ=∫Ω(fg)1/2dμ\rho = \int_{\Omega }(f g)^{1 / 2} d \mu, and show that:

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(i)

ρ≤1\rho \leq 1.

(ii)

2(1−ρ)≤d(P,Q)≤2(1−ρ2)1/22(1-\rho ) \leq d(P, Q) \leq 2\left(1-\rho^{2}\right)^{1 / 2}, where (by Exercise 3), d(P,Q)=∫Ω∣f−g∣dμ=∥P−Q∥d(P, Q) = \int_{\Omega }\left|f-g\right| d \mu = \left\| P-Q\right\|. Replacing P,QP, Q and f,g,ρf, g, \rho by Pn,QnP_{n}, Q_{n} and fn,gn,ρn,n≥1f_{n}, g_{n}, \rho_{n}, n \geq 1, part (ii) becomes:

2(1−ρn)≤d(Pn,Qn)≤2(1−ρn2)1/2 2\left(1-\rho _{n}\right) \leq d\left(P_{n}, Q_{n}\right) \leq 2\left(1-\rho _{n}^{2}\right)^{1 / 2}
(iii)

From this last relation, conclude that, as n→∞,d(Pn,Qn)→0n \rightarrow \infty , d\left(P_{n}, Q_{n}\right) \rightarrow 0 if and only if ρn→0\rho_{n} \rightarrow 0.

Problem 7.7

For n≥1n \geq 1, let fnf_{n} be real-valued measurable functions defined on an open set E⊂RE \subset \mathbb {R} containing 0 , and suppose that ∣fn(x)∣≤M(<∞)\left|f_{n}(x)\right| \leq M( < \infty ) for all nn and all x∈Ex \in E, and that fn(x)⟶n→∞0f_{n}(x) \underset {n \rightarrow \infty }{\longrightarrow } 0 for x∈Ex \in E. Then show that, for any sequence xn⟶n→∞0x_{n} \underset {n \rightarrow \infty }{\longrightarrow } 0, there exists a subsequence {xm}⊆{xn}\left\{ x_{m}\right\} \subseteq \left\{ x_{n}\right\} and a λ\lambda-null subset NN of EE (which may depend on {xn}\left\{ x_{n}\right\}) such that fm(x+xm)⟶m→∞0,x∈E−Nf_{m}\left(x+x_{m}\right) \underset {m \rightarrow \infty }{\longrightarrow } 0, x \in E-N; here λ\lambda is the Lebesgue measure.

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Problem 7.8

For n≥1n \geq 1, let fnf_{n} be real-valued measurable functions defined on R\mathbb {R}, and suppose that ∣fn(x)∣≤M(<∞)\left|f_{n}(x)\right| \leq M( < \infty ) for all nn and x∈Rx \in \mathbb {R}, and that lim⁡n→∞fn−(x)=0\lim_{n \rightarrow \infty } f_{n}^{-}(x) = 0 for x∈Rx \in \mathbb {R}. Then for any sequence {xn}\left\{ x_{n}\right\} with xn⟶n→∞0x_{n} \underset {n \rightarrow \infty }{\longrightarrow } 0 it holds lim sup⁡n→∞fn(x+xn)≥0\limsup_{n \rightarrow \infty } f_{n}\left(x+x_{n}\right) \geq 0 a.e. [λ][\lambda ], where λ\lambda is the Lebesgue measure.

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