Chapter 6

Standard Moment and Probability Inequalities, Convergence in the rth Mean and its Implications

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Problem 6.1

Establish the following generalized version of Theorem 2 (the Hölder inequality). Namely, show that for any n(≥2)n( \geq 2) r.v.s X1,…,XnX_{1}, \ldots , X_{n} and any positive numbers r1,…,rnr_{1}, \ldots , r_{n} with 1r1+⋯+1rn=1\frac{1}{r_{1}}+\cdots +\frac{1}{r_{n}} = 1, it holds that

E[∣X1…Xn∣]≤E[∣X1∣r1]1r1…E[∣Xn∣rn]1rn. \mathbb {E}\left[\left|X_{1} \ldots X_{n}\right|\right] \leq \mathbb {E}\left[\left|X_{1}\right|^{r_{1}}\right]^{\frac{1}{r_{1}}} \ldots \mathbb {E}\left[\left|X_{n}\right|^{r_{n}}\right]^{\frac{1}{r_{n}}} .
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Problem 6.2

Let g:Ig: I open interval in R→R\mathbb {R} \rightarrow \mathbb {R} be convex; i.e., for every x,x′∈Ix, x^{\prime } \in I and every α∈[0,1]\alpha \in [0,1], it holds g(αx+(1−α)x′)≤αg(x)+(1−α)g(x′)g\left(\alpha x+(1-\alpha ) x^{\prime }\right) \leq \alpha g(x)+(1-\alpha ) g\left(x^{\prime }\right). Then show that

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(i)

gg is continuous.

(ii)

For every x0∈Ix_{0} \in I, there exists λ(x0)∈R\lambda \left(x_{0}\right) \in \mathbb {R} such that g(x)−g(x0)≥λ(x0)×(x−x0),x∈Ig(x)-g\left(x_{0}\right) \geq \lambda \left(x_{0}\right) \times \left(x-x_{0}\right), x \in I.

Problem 6.3

Establish the following generalized version of Theorem 3 (the Minkowski inequality). Namely, show that for any n(≥2)n( \geq 2) r.v.s X1,…,XnX_{1}, \ldots , X_{n} and any r≥1r \geq 1, it holds that

E[∣X1+⋯+Xn∣r]1r≤E[∣X1∣r]1r+⋯+E[∣Xn∣r]1r. \mathbb {E}\left[\left|X_{1}+\cdots +X_{n}\right|^{r}\right]^{\frac{1}{r}} \leq \mathbb {E}\left[\left|X_{1}\right|^{r}\right]^{\frac{1}{r}}+\cdots +\mathbb {E}\left[\left|X_{n}\right|^{r}\right]^{\frac{1}{r}} .
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Problem 6.4

If ∑n=1∞E[∣Xn−X∣r]<∞\sum_{n = 1}^{\infty } \mathbb {E}\left[\left|X_{n}-X\right|^{r}\right] < \infty for some r>0r > 0, then Xn→n→∞ a.s. XX_{n} \xrightarrow [n \rightarrow \infty ]{\text{ a.s. }} X.

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Problem 6.5

If Xn→→∞ a.s. XX_{n} \xrightarrow [ \rightarrow \infty ]{\text{ a.s. }} X, and Xn→n→∞(r)YX_{n} \xrightarrow [n \rightarrow \infty ]{(r)} Y for some r>0r > 0, it follows that P(X≠Y)=0\mathbb {P}\left(X \neq Y\right) = 0.

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Problem 6.6

Construct r.v.s Xn,n≥1X_{n}, n \geq 1, and XX on some probability space (Ω,A,P\Omega , \mathcal{A}, P) such that Xn→n→∞P0X_{n} \xrightarrow [n \rightarrow \infty ]{P} 0, but Xn→n→∞(r)↛0X_{n} \xrightarrow [n \rightarrow \infty ]{(r)} \nrightarrow 0 for any r≥1r \geq 1.

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Problem 6.7

Construct r.v.s Xn,n≥1X_{n}, n \geq 1, and XX on some probability space (Ω,A,P\Omega , \mathcal{A}, P) such that Xn→n→∞ a.s. ↛XX_{n} \xrightarrow [n \rightarrow \infty ]{\text{ a.s. }} \nrightarrow X, but Xn→n→∞(r)XX_{n} \xrightarrow [n \rightarrow \infty ]{(r)} X for any r>0r > 0.

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Problem 6.8

Let Xn,n=1,2,…X_{n}, n = 1,2, \ldots, be r.v.s such that E[∣Xn∣β]≤M(<∞),n≥1\mathbb {E}\left[\left|X_{n}\right|^{\beta }\right] \leq M( < \infty ), n \geq 1, for some β>0\beta > 0. Then show that ∣Xn∣α,n≥1\left|X_{n}\right|^{\alpha }, n \geq 1, are uniformly integrable for all α\alpha with 0<α<β0 < \alpha < \beta.

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Problem 6.9

For n=1,2,…n = 1,2, \ldots, let XnX_{n} be r.v.s such that P(Xn=cn)=1n\mathbb {P}\left(X_{n} = c n\right) = \frac{1}{n} and P(Xn=0)=1−1n\mathbb {P}\left(X_{n} = 0\right) = 1-\frac{1}{n}, for some c>0c > 0. Investigate whether or not these r.v.s are uniformly integrable.

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Problem 6.10

If E[∣X∣]<∞\mathbb {E}\left[\left|X\right|\right] < \infty, show that ∫∣X∣\int \left|X\right| is absolutely continuous; that is, ∫A∣X∣→0\int_{A}\left|X\right| \rightarrow 0 when P(A)→0\mathbb {P}\left(A\right) \rightarrow 0.

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Problem 6.11

For n=1,2,…n = 1,2, \ldots, let Xn,YnX_{n}, Y_{n} and X,YX, Y be r.v.s such that P(Xn≥Yn≥0)=1\mathbb {P}\left(X_{n} \geq Y_{n} \geq 0\right) = 1, Xn→n→∞PX,Yn→n→∞PYX_{n} \xrightarrow [n \rightarrow \infty ]{P} X, Y_{n} \xrightarrow [n \rightarrow \infty ]{P} Y, and E[Xn]→n→∞E[X]\mathbb {E}\left[X_{n}\right] \underset {n \rightarrow \infty }{\rightarrow } \mathbb {E}\left[X\right] finite. Then show that E[∣Yn−Y∣]→n→∞0\mathbb {E}\left[\left|Y_{n}-Y\right|\right] \underset {n \rightarrow \infty }{\rightarrow } 0.

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Problem 6.12

For any r.v. XX defined on the measure space (Ω,A,μ)(\Omega , \mathcal{A}, \mu ), show directly that the Markov inequality holds; namely, μ(∣X∣≥c)≤c−r∫∣X∣rdμ\mu (\left|X\right| \geq c) \leq c^{-r} \int \left|X\right|^{r} d \mu for any r>0r > 0 and any c>0c > 0.

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Problem 6.13

For a r.v. XX and some r>0r > 0, show that E[∣X∣r]<∞\mathbb {E}\left[\left|X\right|^{r}\right] < \infty if and only if E[∣X−c∣r]<∞\mathbb {E}\left[\left|X-c\right|^{r}\right] < \infty for every (finite) constant cc.

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Problem 6.14

For a r.v. XX with E[X]=μ∈R\mathbb {E}\left[X\right] = \mu \in \mathbb {R} and Var⁡[X]=σ2=0\operatorname {Var}\left[X\right] = \sigma^{2} = 0, show that P(X=μ)=1\mathbb {P}\left(X = \mu \right) = 1.

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Problem 6.15

For n=1,2,…n = 1,2, \ldots, consider the r.v.s XnX_{n} and XX and show that

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(i)

∣Xn∣Pn→∞0\left|X_{n}\right| \underset {n \rightarrow \infty }{P} 0 if and only if ∣Xn∣1+∣Xn∣→n→∞P0\frac{\left|X_{n}\right|}{1+\left|X_{n}\right|} \xrightarrow [n \rightarrow \infty ]{P} 0.

(ii)

∣Xn∣→n→∞P0\left|X_{n}\right| \xrightarrow [n \rightarrow \infty ]{P} 0 if and only if E[∣Xn∣1+∣Xn∣]→n→∞0\mathbb {E}\left[\frac{\left|X_{n}\right|}{1+\left|X_{n}\right|}\right] \underset {n \rightarrow \infty }{\rightarrow } 0.

Problem 6.16
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(i)

For r>1r > 1 and xj∈R,j=1,…,nx_{j} \in \mathbb {R}, j = 1, \ldots , n, show that

∣n−1∑j=1nxj∣r≤n−1∑j=1n∣xj∣r. \left|n^{-1} \sum _{j = 1}^{n} x_{j}\right|^{r} \leq n^{-1} \sum _{j = 1}^{n}\left|x_{j}\right|^{r} .
(ii)

From part (i), deduce that

E[∣1n∑j=1nXj∣r]≤1n∑j=1nE[∣Xj∣r]. \mathbb {E}\left[\left|\frac{1}{n} \sum _{j = 1}^{n} X_{j}\right|^{r}\right] \leq \frac{1}{n} \sum _{j = 1}^{n} \mathbb {E}\left[\left|X_{j}\right|^{r}\right] .

(On the other hand, by the Minkowski inequality,

E[∣1n∑j=1nXj∣r]1/r≤1n∑j=1nE[∣Xj∣r]1/r. \mathbb {E}\left[\left|\frac{1}{n} \sum _{j = 1}^{n} X_{j}\right|^{r}\right]^{1 / r} \leq \frac{1}{n} \sum _{j = 1}^{n} \mathbb {E}\left[\left|X_{j}\right|^{r}\right]^{1 / r} .

)

Problem 6.17

For n=1,2,…n = 1,2, \ldots, suppose that XnX_{n} and XX are r.v.s defined on the probability space (Ω,A,P)(\Omega , \mathcal{A}, P), and suppose that Xn→n→∞PXX_{n} \xrightarrow [n \rightarrow \infty ]{P} X and {Xn}\left\{ X_{n}\right\} are uniformly integrable. Then show that ∫AXndP→n→∞∫AXdP\int_{A} X_{n} d P \underset {n \rightarrow \infty }{\rightarrow } \int_{A} X d P uniformly in A∈AA \in \mathcal{A}.

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Problem 6.18

If for n=1,2,…n = 1,2, \ldots, the r.v.s {Xn}\left\{ X_{n}\right\} and {Yn}\left\{ Y_{n}\right\} are uniformly integrable, show that {Xn+Yn}\left\{ X_{n}+Y_{n}\right\} are also uniformly integrable.

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Problem 6.19

For n=1,2,…n = 1,2, \ldots, let XnX_{n} be identically distributed with E[Xn]∈R\mathbb {E}\left[X_{n}\right] \in \mathbb {R}. Then show that {Xˉn}\left\{ \bar{X}_{n}\right\} are uniformly integrable, where Xˉn=1n∑j=1nXj\bar{X}_{n} = \frac{1}{n} \sum_{j = 1}^{n} X_{j} is the sample mean of X1,…,XnX_{1}, \ldots , X_{n}.

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Problem 6.20

Let Y=sup⁡n≥1∣Xn∣Y = \sup_{n \geq 1}\left|X_{n}\right| with E[Yr]<∞\mathbb {E}\left[Y^{r}\right] < \infty (for some r>0r > 0) and Xn→n→∞→ a.s. XX_{n} \xrightarrow [n \rightarrow \infty ]{\stackrel{\text{ a.s. }}{\rightarrow }} X. Then show that E[∣X∣r]<∞\mathbb {E}\left[\left|X\right|^{r}\right] < \infty and Xn→n→∞(r)XX_{n} \xrightarrow [n \rightarrow \infty ]{(r)} X.

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Problem 6.21

For n=1,2,…n = 1,2, \ldots, let XnX_{n} be r.v.s such that E[Xn]=μn∈R\mathbb {E}\left[X_{n}\right] = \mu_{n} \in \mathbb {R} and Var⁡[Xn]=σn2→n→∞0\operatorname {Var}\left[X_{n}\right] = \sigma_{n}^{2} \underset {n \rightarrow \infty }{\rightarrow } 0. Then show that Xn−μn→n→∞P0X_{n}-\mu_{n} \xrightarrow [n \rightarrow \infty ]{P} 0.

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Problem 6.22

Let the r.v.s Xn,n≥1X_{n}, n \geq 1, be defined as follows: Xn(ω)=2nX_{n}(\omega ) = 2^{n} if ω∈(0,1n)\omega \in \left(0, \frac{1}{n}\right), and Xn(ω)=0X_{n}(\omega ) = 0 otherwise, where (Ω,A,P)=((0,1],B(0,1],λ)(\Omega , \mathcal{A}, P) = \left((0,1], \mathcal{B}_{(0,1]}, \lambda \right) and λ\lambda is the Lebesgue measure. Then show that Xn→n→∞→0X_{n} \xrightarrow [n \rightarrow \infty ]{\rightarrow } 0 pointwise, but E[∣Xn∣r]→n→∞\mathbb {E}\left[\left|X_{n}\right|^{r}\right] \underset {n \rightarrow \infty }{\rightarrow } to any finite number for any r>0r > 0; in fact, E[∣Xn∣r]→n→∞∞\mathbb {E}\left[\left|X_{n}\right|^{r}\right] \underset {n \rightarrow \infty }{\rightarrow } \infty for any r>0r > 0.

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Problem 6.23

For n=1,2,…n = 1,2, \ldots, let the r.v. XnX_{n} be defined by

Xn={nc with probability 1n0 with probability 1−2nn−c with probability 1n, where c is a positive constant.  X_{n} = \left\{ \begin{array}{l} n^{c} \text{ with probability } \frac{1}{n} \\ 0 \text{ with probability } 1-\frac{2}{n} \\ n^{-c} \text{ with probability } \frac{1}{n}, \quad \text{ where } c \text{ is a positive constant. } \end{array}\right.

Then show that

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(i)

Xn→n→∞P0X_{n} \xrightarrow [n \rightarrow \infty ]{P} 0.

(ii)

E[∣Xn∣r]→n→∞0,0<cr<1;E[∣Xn∣r]→n→∞∞,cr>1\mathbb {E}\left[\left|X_{n}\right|^{r}\right] \underset {n \rightarrow \infty }{\rightarrow } 0,0 < c r < 1 ; \mathbb {E}\left[\left|X_{n}\right|^{r}\right] \underset {n \rightarrow \infty }{\rightarrow } \infty , c r > 1.

(iii)

Xn→n→∞(r)0,cr<1X_{n} \xrightarrow [n \rightarrow \infty ]{(r)} 0, c r < 1.

Problem 6.24

Let E[Xn2]<∞\mathbb {E}\left[X_{n}^{2}\right] < \infty for all nn. Then, if E[∣Xn−X∣2]→n→∞0\mathbb {E}\left[\left|X_{n}-X\right|^{2}\right] \underset {n \rightarrow \infty }{\rightarrow } 0, show that E[∣Xn2−X2∣]→n→∞0\mathbb {E}\left[\left|X_{n}^{2}-X^{2}\right|\right] \underset {n \rightarrow \infty }{\rightarrow } 0.

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Problem 6.25

For n=1,2,…n = 1,2, \ldots, let Xn,YnX_{n}, Y_{n} and X,YX, Y be r.v.s defined on the probability space (Ω,A,P)(\Omega , \mathcal{A}, P), and suppose that Xn→n→∞(r)X,Yn→n→∞(s)YX_{n} \xrightarrow [n \rightarrow \infty ]{(r)} X, Y_{n} \xrightarrow [n \rightarrow \infty ]{(s)} Y where r,s>1r, s > 1 with 1r+1s=1\frac{1}{r}+ \frac{1}{s} = 1. Then show that XnYn→n→∞(1)XYX_{n} Y_{n} \xrightarrow [n \rightarrow \infty ]{(1)} X Y.

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Problem 6.26

Let (Ω,A,P)=((0,1),B(0,1),λ)(\Omega , \mathcal{A}, P) = \left((0,1), \mathcal{B}_{(0,1)}, \lambda \right), where λ\lambda is the Lebesgue measure, and let XnX_{n} be a r.v. defined by

Xn={1,ω∈(0,1n)0,ω∈[1n,1),n=1,2,… X_{n} = \left\{ \begin{array}{l} 1, \omega \in \left(0, \frac{1}{n}\right) \\ 0, \omega \in \left[\frac{1}{n}, 1\right) \end{array}, \quad n = 1,2, \ldots \right.

Then show that Xn→n→∞→(r)0X_{n} \xrightarrow [n \rightarrow \infty ]{\stackrel{(r)}{\rightarrow }} 0 for any r>0r > 0, and Xn→n→∞→ a.s. 0X_{n} \xrightarrow [n \rightarrow \infty ]{\stackrel{\text{ a.s. }}{\rightarrow }} 0; indeed, Xn→n→∞⟶0X_{n} \xrightarrow [n \rightarrow \infty ]{\longrightarrow } 0 pointwise. (Compare it with Exercise 7.)

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Problem 6.27

If Xn→n→∞(r)XX_{n} \xrightarrow [n \rightarrow \infty ]{(r)} X, show that there is a subsequence {Xnk}⊆{Xn}\left\{ X_{n_{k}}\right\} \subseteq \left\{ X_{n}\right\} such that Xnk→→ a.s. XX_{n_{k}} \xrightarrow {\xrightarrow {\text{ a.s. }}} X.

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Problem 6.28

For n=1,2,…n = 1,2, \ldots, let the r.v. XnX_{n} be defined by

Xn={en with probability n−20 with probability 1−n−2 X_{n} = \left\{ \begin{array}{l} e^{n} \text{ with probability } n^{-2} \\ 0 \text{ with probability } 1-n^{-2} \end{array}\right.

Then show that

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(i)

Xn→n→∞P0X_{n} \xrightarrow [n \rightarrow \infty ]{P} 0 (indeed, Xn→n→∞ a.s. 0X_{n} \xrightarrow [n \rightarrow \infty ]{\text{ a.s. }} 0).

(ii)

Xn→n→∞(r)↛0X_{n} \xrightarrow [n \rightarrow \infty ]{(r)} \nrightarrow 0 for any r>0r > 0 (in fact, E[∣Xn∣r]→n→∞⟶∞\mathbb {E}\left[\left|X_{n}\right|^{r}\right] \xrightarrow [n \rightarrow \infty ]{\longrightarrow } \infty for all r>0r > 0). (Compare it with Exercises 6 and Theorem 8.)

Problem 6.29

For n=1,2,…n = 1,2, \ldots, let the r.v. XnX_{n} be defined by

Xn={2cn with probability 2−n0 with probability 1−2−n+1−2cn with probability 2−n, for some positive constant c. X_{n} = \begin{cases} 2^{c n} & \text{ with probability } 2^{-n} \\ 0 & \text{ with probability } 1-2^{-n+1} \\ -2^{c n} & \text{ with probability } 2^{-n}, \text{ for some positive constant } c . \end{cases}
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(i)

Show that Xn→n→∞ a.s. 0X_{n} \xrightarrow [n \rightarrow \infty ]{\text{ a.s. }} 0.

(ii)

Determine the condition cc and r(>0)r( > 0) must satisfy, so that X→(r)n→∞0X \underset {n \rightarrow \infty }{\stackrel{(r)}{\rightarrow }} 0. (Compare it with Exercises 6 and 8.)

Problem 6.30
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(i)

For any r.v. XX, show that P(∣X∣≥c)≤E[∣X∣]/c(c>0)\mathbb {P}\left(\left|X\right| \geq c\right) \leq \mathbb {E}\left[\left|X\right|\right] / c(c > 0), by using the obvious inequality ∣X∣≥cI(∣X∣≥c)\left|X\right| \geq c I(\left|X\right| \geq c). In particular, if X≥0X \geq 0, then P(X≥c)≤E[X]/c\mathbb {P}\left(X \geq c\right) \leq \mathbb {E}\left[X\right] / c.

(ii)

For any r.v. XX and any c>0c > 0, show that

P(X≥c)≤e−tcE[etX](t>0),P(X≤c)≤e−tcE[etX](t<0). \mathbb {P}\left(X \geq c\right) \leq e^{-t c} \mathbb {E}\left[e^{t X}\right](t > 0), \mathbb {P}\left(X \leq c\right) \leq e^{-t c} \mathbb {E}\left[e^{t X}\right](t < 0) .
(iii)

If E[X2]<∞\mathbb {E}\left[X^{2}\right] < \infty, then show that P(∣X∣>0)≥(E[∣X∣])2/E[X2]\mathbb {P}\left(\left|X\right| > 0\right) \geq (\mathbb {E}\left[\left|X\right|\right])^{2} / \mathbb {E}\left[X^{2}\right]. In particular, if X≥0X \geq 0, then P(X>0)≥(E[X])2/E[X2]\mathbb {P}\left(X > 0\right) \geq (\mathbb {E}\left[X\right])^{2} / \mathbb {E}\left[X^{2}\right].

Problem 6.31

For n≥1n \geq 1, let XnX_{n} be r.v.s with E[Xn]=μn,σ2(Xn)=σn2\mathbb {E}\left[X_{n}\right] = \mu_{n}, \sigma^{2}\left(X_{n}\right) = \sigma_{n}^{2}, and suppose that, as n→∞,μn→μ∈Rn \rightarrow \infty , \mu_{n} \rightarrow \mu \in \mathbb {R}, and σn2→0\sigma_{n}^{2} \rightarrow 0. Then show that E[Xn−μ2]→0\mathbb {E}\left[X_{n}-\mu^{2}\right] \rightarrow 0 and Xn→PμX_{n} \xrightarrow {P} \mu.

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Problem 6.32

For n≥1n \geq 1, let XnX_{n} and YnY_{n} be r.v.s defined on the probability space (Ω,A,P)(\Omega , \mathcal{A}, P), and suppose that ∣Xn∣\left|X_{n}\right| and ∣Yn∣,n≥1\left|Y_{n}\right|, n \geq 1, are uniformly integrable and Xn−Yn→P0X_{n}-Y_{n} \xrightarrow {P} 0 as n→∞n \rightarrow \infty. Then show that:

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(i)

∣Xn−Yn∣,n≥1\left|X_{n}-Y_{n}\right|, n \geq 1, are uniformly integrable.

(ii)

E[∣Xn−Yn∣]⟶n→∞0\mathbb {E}\left[\left|X_{n}-Y_{n}\right|\right] \underset {n \rightarrow \infty }{\longrightarrow } 0.

Problem 6.33

Consider the probability space (Ω,A,P)(\Omega , \mathcal{A}, P), and let Θ\Theta be an open subset of R\mathbb {R}. Let g(⋅;⋅):Ω×Θ→Rg(\cdot ; \cdot ): \Omega \times \Theta \rightarrow \mathbb {R} be (A×BΘ)\left(\mathcal{A} \times \mathcal{B}_{\Theta }\right)-measurable, where BΘ\mathcal{B}_{\Theta } is the σ\sigma-field of Borel subsets of Θ\Theta. We say that g(⋅;θ)g(\cdot ; \theta ) is differentiable in q.m. at θ\theta, if there exists a (A×BΘ)\left(\mathcal{A} \times \mathcal{B}_{\Theta }\right)-measurable function g˙(⋅;θ)\dot{g}(\cdot ; \theta ) (the quadratic mean derivative of g(⋅;θ)g(\cdot ; \theta ) at θ\theta) such that

h−1[g(⋅;θ+h)−g(⋅;θ)] q.m. n→∞g˙(⋅;θ). h^{-1}[g(\cdot ; \theta +h)-g(\cdot ; \theta )] \underset {n \rightarrow \infty }{\text{ q.m. }} \dot{g}(\cdot ; \theta ) .

Now let p(x;θ)=12e−∣x−θ∣,x∈R(θ∈R)p(x ; \theta ) = \frac{1}{2} e^{-\left|x-\theta \right|}, x \in \mathbb {R}(\theta \in \mathbb {R}) be the double exponential probability density function, and for θ,θ∗∈R\theta , \theta^{*} \in \mathbb {R}, set

g(x;θ,θ∗)=[p(x;θ∗)/p(x;θ)]1/2=exp⁡(12∣x−θ∣−12∣x−θ∗∣). g\left(x ; \theta , \theta ^{*}\right) = \left[p\left(x ; \theta ^{*}\right) / p(x ; \theta )\right]^{1 / 2} = \exp \left(\frac{1}{2}\left|x-\theta \right|-\frac{1}{2}\left|x-\theta ^{*}\right|\right) .
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(i)

Show that g(x;θ,θ∗)g\left(x ; \theta , \theta^{*}\right) is not pointwise differentiable with respect to θ∗\theta^{*} at (θ,θ)(\theta , \theta ) for any θ=x∈R\theta = x \in \mathbb {R}.

(ii)

If the r.v. XX is distributed according to p(⋅;θ)p(\cdot ; \theta ), show that g(X;θ,θ∗)g\left(X ; \theta , \theta^{*}\right) is differentiable in q.m. with respect to θ∗\theta^{*} at (θ,θ),θ∈R(\theta , \theta ), \theta \in \mathbb {R}, with q.m. derivative g˙(X;θ)\dot{g}(X ; \theta ) given by:

g˙(X;θ)={−1/2 if X<θ0 (for example)  if X=θ1/2 if X>θ \dot{g}(X ; \theta ) = \left\{ \begin{array}{cl} -1 / 2 & \text{ if } X < \theta \\ 0 \text{ (for example) } & \text{ if } X = \theta \\ 1 / 2 & \text{ if } X > \theta \end{array}\right.
Problem 6.34

All r.v.s appearing below are defined on the probability space (Ω,A,P)(\Omega , \mathcal{A}, P).

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(i)

If X≥0X \geq 0, then E[X]≥0\mathbb {E}\left[X\right] \geq 0 and E[X]=0\mathbb {E}\left[X\right] = 0 only if P(X=0)=1\mathbb {P}\left(X = 0\right) = 1.

(ii)

Let X≥YX \geq Y with finite expectations. Then E[X]≥E[Y]\mathbb {E}\left[X\right] \geq \mathbb {E}\left[Y\right] and E[X]=E[Y]\mathbb {E}\left[X\right] = \mathbb {E}\left[Y\right] only if P(X=Y)=1\mathbb {P}\left(X = Y\right) = 1.

(iii)

Let X>YX > Y with finite expectations. Then E[X]>E[Y]\mathbb {E}\left[X\right] > \mathbb {E}\left[Y\right].

(iv)

Let g:Ig: I open subset of R\mathbb {R} be strictly convex (i.e.,

g[αx+(1−α)x′]<αg(x)+(1−α)g(x′), g\left[\alpha x+(1-\alpha ) x^{\prime }\right] < \alpha g(x)+(1-\alpha ) g\left(x^{\prime }\right),

x,x′∈I,0<α<1x, x^{\prime } \in I, 0 < \alpha < 1), let ZZ be a r.v. taking values in II, let E[Z]∈I\mathbb {E}\left[Z\right] \in I, and let E[g(Z)]\mathbb {E}\left[g(Z)\right] exist. Then E[g(Z)]>g(E[Z])\mathbb {E}\left[g(Z)\right] > g(\mathbb {E}\left[Z\right]) unless \mathbb {P}\left(Z = constant \right) = 1.