Definition and Construction of a Measure and its Basic Properties
[35/97%]If is countable and is defined on by: number of points of , show that is a measure. Furthermore, is finite or -finite, depending on whether is finite or denumerable, respectively. (This measure is called the counting measure.)
Refer to the field of Example 4 in Chapter 1 and on , define the set function as follows: if is finite, and if is finite. Then show that
is finitely additive.
If is denumerable, is not -additive.
If is uncountable, is -additive and a probability measure.
Refer to the -field of Example 8 in Chapter 1 and on , define the function as follows: if is countable, and if is countable. Then show that is a probability measure.
Let be events in the probability space such that for all . Then show that .
Let be an uncountable collection of pairwise disjoint events in the probability space . Then show that for countably many only.
Let be an infinite set (countable or not) and let be the discrete -field. Let , and with each , associate a nonnegative number (such that ). On , define the set function by: . Then show that is a measure on .
In the measure space a set is called an atom, if and for any with , it follows that , or . In reference to Exercise 6 , identify the atoms of .
In any measure space and with any , show that
provided for some . In Exercises 9 and 10, show that the set function defined on is, indeed, an outer measure.
is an arbitrary set, is a fixed point of , and is defined by: .
is the set of 100 points arranged in a square array of 10 columns, each with 10 points, and is defined by: number of columns that contain at least one point of .
For an arbitrary set containing at least two points, consider the trivial field , and let (the finite measure) be defined on by: and .
Determine the set function on , as is given in the definition just prior to Theorem 3 (which is, actually, an outer measure, by Theorem 3(ii)).
Show that the -field of -measurable sets, , say, is the trivial -field, so that is strictly contained in .
Let , let , and define on as follows:
Next, on , define the measures and by taking
Then show that
is not a field.
is a measure on .
Both and are extensions of (from to ).
Construct the outer measure (as is defined in Definition 5) by means of defined on .
Conclude that (so that, if the class is not a field, the extension of (even a finite measure on ) need not be unique).
Let , let , and let . Let be the counting measure on , and let be defined on by
Then show that
is a field.
is not -finite on .
Both and are extensions of and are also -finite.
Determine the outer measure (as is defined in Definition 5) by showing that whenever .
Show that the -field of -measurable sets, say, is equal to . (From this example, we conclude that if is not -finite on the field , then there need not be a unique extension. Also, there may be -finite extensions, such as and here, when the original measure on is not -finite.)
Construct additional examples to illustrate the points made in Exercises 11(ii), 12 , and 13.
Consider the measure space , and define the classes and as follows:
Then show that
.
.
From parts (i) and (ii), conclude that .
Refer to the classes and , defined in Exercise 15, and show that (and hence ) is a -field.
Refer to Exercise 15 and on , define by: .
Show that .
By Exercise . Therefore, by part (i), we may define on by: .
Show that so defined is well defined; that is, if , where and are as in Exercise 15, then .
Show that is a measure on (and hence on , by Exercise ).
The measure space (and ) is called completion of .
Show that the class defined in Exercise 15 contains the class defined by ; either for some , or for some with . (That is, is taken from by supplementing with all subsets of all null sets in ; that is, sets of measure 0.)
Also, show that .
If is a measure space, by means of an example, show that there may be subsets , where are null sets in , with . (If it so happens, however, that for every for every null , then , we say that is complete with respect to .)
If is an outer measure and is the -field of -measurable sets, then show that is complete (with respect to ).
Consider the measure space where (finite interval) , and for , let be defined by
Then, by means of an example, show that need not be left-continuous.
Consider the measurable space , and let be a set function defined on and taking nonnegative values, and such that with . Then show that cannot be additive.
Let be -finite measures on and set (in the sense that ). Then show that is also -finite.
In the probability space , show that
.
.
Consider the probability space , where is the discrete -field, and is defined by
For , define by: . Determine the: and compute the probabilities:
Let and let be a -field of subsets of . Then show that
if and only if for all .
A measure on is determined by defining .
Suppose that , and let be the discrete -field. On , define the set function by
Then show that
is nonnegative, and is finitely additive, but it is not -additive.
for a sequence , with , and .
Let , and for any , let . On the discrete -field, define by
Then
Show that is an outer measure.
Determine the class of -measurable sets.
Recall that is a median of a r.v. if and . Then show that, if is a median of the r.v. , then is a median of the r.v. .
Recall that a r.v. is said to be symmetric about 0 , if and have the same distribution. If is symmetric (about 0), then show that 0 is a median of ; i.e., and .
Let be an outer measure, and suppose that for some . Then show that for every .
Consider the measure space , and suppose that is complete with respect to . Let be such that . Then show that, if one of or is measurable, then so is the other.
Consider the measure space , and let be complete with respect to . Let with , and let be an arbitrary function . Then is measurable.
If and are two measures on , then show that is also a measure, where .
If at least one of the measures and is complete, then so is .
Refer to Example 2 and:
Show that the class consists of the unions of any two members of the class .
Also, show that is closed under complementation and the formation of the union of any two of its members.
Conclude that is a field, and, indeed, the field generated by .