Problem 7.43

Problems and Theorems in Analysis · 7.3

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Problem 7.43

Let ϑ\vartheta be real and let the complex numbers

c−n,c−n+1,…,c−1,c0,c1,…,cn−1,cn,c−ν=cˉν,ν=0,1,2,…,n c_{-n}, c_{-n+1}, \ldots , c_{-1}, c_{0}, c_{1}, \ldots , c_{n-1}, c_{n}, \qquad c_{-\nu } = \bar{c}_{\nu }, \quad \nu = 0, 1, 2, \ldots , n

have the following property: If

g(ϑ)=α0+2(α1cos⁡ϑ+β1sin⁡ϑ+α2cos⁡2ϑ+β2sin⁡2ϑ+⋯+αncos⁡nϑ+βnsin⁡nϑ) g(\vartheta ) = \alpha _{0} + 2(\alpha _{1} \cos \vartheta + \beta _{1} \sin \vartheta + \alpha _{2} \cos 2\vartheta + \beta _{2} \sin 2\vartheta + \cdots + \alpha _{n} \cos n\vartheta + \beta _{n} \sin n\vartheta ) =∑ν=−nnγνe−iνϑ,γν=γˉ−ν=αν+iβν,ν=0,1,2,…,n;β0=0, = \sum _{\nu =-n}^{n} \gamma _{\nu } e^{-i\nu \vartheta }, \qquad \gamma _{\nu } = \bar{\gamma }_{-\nu } = \alpha _{\nu } + i\beta _{\nu }, \quad \nu = 0, 1, 2, \ldots , n; \quad \beta _{0} = 0,

denotes an arbitrary trigonometric polynomial of degree at most nn, that does not vanish identically and does not have a negative value for any value of ϑ\vartheta, let

∑ν=−nncνγνe−iνϑ≥0(or>0). \sum _{\nu =-n}^{n} c_{\nu } \gamma _{\nu } e^{-i\nu \vartheta } \geq 0 \qquad (\text{or} > 0).

Show that for this to be true, it is necessary and sufficient that the Hermitian form

∑λ=0n∑μ=0ncμ−λxλxˉμ \sum _{\lambda =0}^{n} \sum _{\mu =0}^{n} c_{\mu -\lambda } x_{\lambda } \bar{x}_{\mu }

is positive (or positive definite, respectively).

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Problem 7.43.1

Let G(z)G(z) be an entire function that takes real values for real zz, with G(0)=1G(0) = 1, and

−G′(z)G(z)=s1+s2z+s3z2+⋯+smzm−1+⋯ . -\frac{G'(z)}{G(z)} = s_{1} + s_{2} z + s_{3} z^{2} + \cdots + s_{m} z^{m-1} + \cdots .

If G(z)G(z) has infinitely many zeros, all real, and is of the form given in Problem 165 of Part V, then, for n=1,2,3,…n = 1, 2, 3, \ldots,

∣s2s3s4…sn+1s3s4s5…sn+2s4s5s6…sn+3\multicolumn5c\dotfillsn+1sn+2sn+3…s2n∣>0. \begin{vmatrix} s_{2} & s_{3} & s_{4} & \ldots & s_{n+1} \\ s_{3} & s_{4} & s_{5} & \ldots & s_{n+2} \\ s_{4} & s_{5} & s_{6} & \ldots & s_{n+3} \\ \multicolumn {5}{c}{\dotfill } \\ s_{n+1} & s_{n+2} & s_{n+3} & \ldots & s_{2n} \end{vmatrix} > 0.

(If G(z)G(z) of the form in Problem 165 of Part V has only a finite number of zeros, then only a finite number of these recurrent determinants can be ≠0\neq 0 [Problem 27].)

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Problem 7.43.2

Let G(z)G(z) be an entire function of the form given in Problem 165 of Part V, but not of the form eβze^{\beta z}, and

1G(z)=c0+c11!z+c22!z2+c33!z3+⋯ . \frac{1}{G(z)} = c_{0} + \frac{c_{1}}{1!} z + \frac{c_{2}}{2!} z^{2} + \frac{c_{3}}{3!} z^{3} + \cdots .

Then, for n=0,1,2,…n = 0, 1, 2, \ldots,

∣c0c1c2…cnc1c2c3…cn+1c2c3c4…cn+2\multicolumn5c\dotfillcncn+1cn+2…c2n∣>0. \begin{vmatrix} c_{0} & c_{1} & c_{2} & \ldots & c_{n} \\ c_{1} & c_{2} & c_{3} & \ldots & c_{n+1} \\ c_{2} & c_{3} & c_{4} & \ldots & c_{n+2} \\ \multicolumn {5}{c}{\dotfill } \\ c_{n} & c_{n+1} & c_{n+2} & \ldots & c_{2n} \end{vmatrix} > 0.
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