Section 1

Lagrange's Series. Applications

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Problem 3.207

We use the same notation and hypothesis as before and expand

f(z)1−wφ′(z)=∑n=0∞wnn![dnf(x)[φ(x)]ndxn]x=0. \frac{f(z)}{1-w\varphi '(z)} = \sum _{n=0}^{\infty } \frac{w^{n}}{n!}\left[\frac{d^{n}f(x)[\varphi (x)]^{n}}{dx^{n}}\right]_{x=0}.

Derive this formula from Lagrange's formula or Lagrange's formula from this one by correctly using the generality of both formulas. [The existence of one formula for a certain f(z)f(z) implies immediately the other formula for another f(z)f(z).]

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Problem 3.208

Prove the formula in problem 207 directly by expressing the coefficient of wnw^{n} as a Cauchy integral.

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Problem 3.209

Expand in ascending powers of ww the solution of the transcendental equation

ze−z=w ze^{-z} = w

that vanishes for w=0w=0.

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Problem 3.210

(continued). Expand eαze^{\alpha z} in powers of w=ze−zw=ze^{-z} where α\alpha is an arbitrary constant.

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Problem 3.211

Expand in ascending powers of ww the solution xx of the trinomial equation

1−x+wxβ=0 1 - x + wx^{\beta } = 0

that becomes 11 for w=0w=0.

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Problem 3.212

(continued). Expand xαx^{\alpha } in powers of ww, where α\alpha denotes an arbitrary constant. (xα=yx^{\alpha }=y is the solution of the trinomial equation

1−y1/α+wyβ/α=0.) 1 - y^{1/\alpha } + wy^{\beta /\alpha } = 0.)
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Problem 3.213

(continued). Note the cases β=0,1,2,−1,12\beta =0,1,2,-1,\frac{1}{2} and derive problems 209, 210 by taking the limit in problems 211, 212.

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Problem 3.214

Evaluate the sum of the power series

1+∑n=1∞(n+α)nwnn!. 1 + \sum _{n=1}^{\infty } \frac{(n+\alpha )^{n}w^{n}}{n!}.

What is its radius of convergence?

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Problem 3.215

Prove problem 156 with the help of the results of problem 214.

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Problem 3.216

Let α\alpha and β\beta denote rational numbers. Then the series

1+(α+β1)w+(α+2β2)w2+⋯+(α+nβn)wn+⋯ 1 + \binom {\alpha +\beta }{1}w + \binom {\alpha +2\beta }{2}w^{2} + \cdots + \binom {\alpha +n\beta }{n}w^{n} + \cdots

represents an algebraic function of ww.

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Problem 3.217

Arrange the successive powers of the trinomial 1+w+w21+w+w^{2} in a regular triangular array

1 1 1+w+w2 1 + w + w^{2} 1+2w+3w2+2w3+w4 1 + 2w + 3w^{2} + 2w^{3} + w^{4} 1+3w+6w2+7w3+6w4+3w5+w6 1 + 3w + 6w^{2} + 7w^{3} + 6w^{4} + 3w^{5} + w^{6} ⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯ \cdots \cdots \cdots \cdots \cdots \cdots \cdots \cdots \cdots \cdots \cdots \cdots \cdots

The sum of the middle terms (in boldface: 1,w,3w2,7w3,…1, w, 3w^{2}, 7w^{3}, \ldots) is

1+w+3w2+7w3+⋯=11−2w−3w2. 1 + w + 3w^{2} + 7w^{3} + \cdots = \frac{1}{\sqrt{1-2w-3w^{2}}}.
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Problem 3.218

Arrange the successive powers of the binomial 1+w1+w in a regular triangular array (Pascal's triangle)

1 1 1+w 1 + w 1+2w+w2 1 + 2w + w^{2} 1+3w+3w2+w3 1 + 3w + 3w^{2} + w^{3} 1+4w+6w2+4w3+w4 1 + 4w + 6w^{2} + 4w^{3} + w^{4} ⋯⋯⋯⋯⋯⋯⋯⋯⋯ \cdots \cdots \cdots \cdots \cdots \cdots \cdots \cdots \cdots

Find the sum of the middle terms (in boldface) and, more generally, the sum of any column.

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Problem 3.219

Find the generating functions of the polynomials Pn(x)P_{n}(x), Pn(α,β)(x)P_{n}^{(\alpha ,\beta )}(x), Ln(α)(x)L_{n}^{(\alpha )}(x), defined by the formulas

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(1)

Pn(x)=12nn!dndxn(x2−1)nP_{n}(x) = \dfrac {1}{2^{n}n!}\dfrac {d^{n}}{dx^{n}}(x^{2}-1)^{n} (Legendre's polynomials);

(2)

(1−x)α(1+x)βPn(α,β)(x)=(−1)n2nn!dndxn(1−x)n+α(1+x)n+β(1-x)^{\alpha }(1+x)^{\beta }P_{n}^{(\alpha ,\beta )}(x) = \dfrac {(-1)^{n}}{2^{n}n!}\dfrac {d^{n}}{dx^{n}}(1-x)^{n+\alpha }(1+x)^{n+\beta }, α>−1\alpha >-1, β>−1\beta >-1 (Jacobi's polynomials);

(3)

e−xxαLn(α)(x)=1n!dndxne−xxn+αe^{-x}x^{\alpha }L_{n}^{(\alpha )}(x) = \dfrac {1}{n!}\dfrac {d^{n}}{dx^{n}}e^{-x}x^{n+\alpha }, α>−1\alpha >-1 (generalized Laguerre's polynomials).

Remark.
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Cf.Part VI, problems 84, 98, 99. The generating function of the Legendre polynomials is the series

P0(x)+P1(x)w+P2(x)w2+⋯+Pn(x)wn+⋯=1+xw+3x2−12w2+⋯ , P_{0}(x) + P_{1}(x)w + P_{2}(x)w^{2} + \cdots + P_{n}(x)w^{n} + \cdots = 1 + xw + \frac{3x^{2}-1}{2}w^{2} + \cdots ,

the sum of which has to be found as a function of xx and ww; similarly in the other two cases.

Problem 3.220

Let ss be a constant of sufficiently small modulus. Then the following formulas are valid for F(z)=eszF(z)=e^{sz}:

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(1)
F(z)=F(0)+z1!ΔF(0)+z(z−1)2!Δ2F(0)+⋯+z(z−1)⋯(z−n+1)n!ΔnF(0)+⋯ ; F(z) = F(0) + \frac{z}{1!}\Delta F(0) + \frac{z(z-1)}{2!}\Delta ^{2}F(0) + \cdots + \frac{z(z-1)\cdots (z-n+1)}{n!}\Delta ^{n}F(0) + \cdots ;
(2)
F′(z)=ΔF(z)−12Δ2F(z)+13Δ3F(z)−⋯+(−1)n−11nΔnF(z)+⋯ ; F'(z) = \Delta F(z) - \frac{1}{2}\Delta ^{2}F(z) + \frac{1}{3}\Delta ^{3}F(z) - \cdots + (-1)^{n-1}\frac{1}{n}\Delta ^{n}F(z) + \cdots ;
(3)
F(z)=F(0)+z1!F′(1)+z(z−2)2!F′′(2)+⋯+z(z−n)n−1n!F(n)(n)+⋯[problem 210]; F(z) = F(0) + \frac{z}{1!}F'(1) + \frac{z(z-2)}{2!}F''(2) + \cdots + \frac{z(z-n)^{n-1}}{n!}F^{(n)}(n) + \cdots \quad [\text{problem 210}];
(4)
F(z)=F(0)+∑n=1∞z2(z2−12)(z2−22)⋯[z2−(n−1)2](2n)!Δ2nF(−n) F(z) = F(0) + \sum _{n=1}^{\infty } \frac{z^{2}(z^{2}-1^{2})(z^{2}-2^{2})\cdots [z^{2}-(n-1)^{2}]}{(2n)!}\Delta ^{2n}F(-n) +∑n=1∞z(z2−12)(z2−22)⋯[z2−(n−1)2](2n−1)!Δ2n−2[F(−n+2)−F(−n)]2[problems 212, 216]. + \sum _{n=1}^{\infty } \frac{z(z^{2}-1^{2})(z^{2}-2^{2})\cdots [z^{2}-(n-1)^{2}]}{(2n-1)!}\frac{\Delta ^{2n-2}[F(-n+2)-F(-n)]}{2} \quad [\text{problems 212, 216}].
Problem 3.221

The four formulas mentioned in problem 220 hold for any polynomial F(z)F(z). (In this case the series are obviously finite.)

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Problem 3.222

The formulas (1), (2) given in problem 220 are also valid for any rational function F(z)F(z) if the real part of zz is larger than the real part of any of the finite poles of F(z)F(z); formula (1) requires the additional condition that F(z)F(z) be regular for z=0,1,2,3,…z=0,1,2,3,\ldots. --Do the formulas (3) and (4) hold for rational but not entire functions?

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Problem 3.223
(1−z)n∑k=−∞∞akzk=∑k=−∞∞Δnakzn+k (1-z)^{n}\sum _{k=-\infty }^{\infty } a_{k}z^{k} = \sum _{k=-\infty }^{\infty } \Delta ^{n}a_{k}z^{n+k}

where aka_{k}, k=0,±1,±2,…k=0,\pm 1,\pm 2,\ldots, denote arbitrary constants.

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Problem 3.224

Define

F(z)=a0+a1z+a2z2+⋯+anzn+⋯ F(z) = a_{0}+a_{1}z+a_{2}z^{2}+\cdots +a_{n}z^{n}+\cdots

and establish the relation

11+tF(t1+t)=a0+Δa0t+Δ2a0t2+⋯+Δna0tn+⋯ . \frac{1}{1+t}F\left(\frac{t}{1+t}\right) = a_{0} + \Delta a_{0}t + \Delta ^{2}a_{0}t^{2} + \cdots + \Delta ^{n}a_{0}t^{n} + \cdots .
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Problem 3.225

Define

F(z)=a0+2a1z+2a2z2+⋯+2anzn+⋯a−n=an F(z) = a_{0}+2a_{1}z+2a_{2}z^{2}+\cdots +2a_{n}z^{n}+\cdots \quad a_{-n}=a_{n}

and show that

11+4tF(1+2t−1+4t2t)=a0+Δ2a−1t+Δ4a−2t2+⋯+Δ2na−ntn+⋯ . \frac{1}{\sqrt{1+4t}}F\left(\frac{1+2t-\sqrt{1+4t}}{2t}\right) = a_{0} + \Delta ^{2}a_{-1}t + \Delta ^{4}a_{-2}t^{2} + \cdots + \Delta ^{2n}a_{-n}t^{n} + \cdots .
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Problem 3.226

Define

F(z)=2a1z+2a2z2+2a3z3+⋯+2anzn+⋯ ,a−n=−an F(z) = 2a_{1}z+2a_{2}z^{2}+2a_{3}z^{3}+\cdots +2a_{n}z^{n}+\cdots , \quad a_{-n}=-a_{n}

and show that

1tF(1+2t−1+4t2t)=a1−a−1+(Δ2a0−Δ2a−2)t \frac{1}{t}F\left(\frac{1+2t-\sqrt{1+4t}}{2t}\right) = a_{1}-a_{-1} + (\Delta ^{2}a_{0}-\Delta ^{2}a_{-2})t +(Δ4a−1−Δ4a−3)t2+⋯+(Δ2na−n+1−Δ2na−n−1)tn+⋯ . + (\Delta ^{4}a_{-1}-\Delta ^{4}a_{-3})t^{2} + \cdots + (\Delta ^{2n}a_{-n+1}-\Delta ^{2n}a_{-n-1})t^{n} + \cdots .
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Problem 3.227
sin⁡πxπ=x(1−x1)(1+x1)(1−x2)(1+x2)⋯ \frac{\sin \pi x}{\pi } = x\left(1-\frac{x}{1}\right)\left(1+\frac{x}{1}\right)\left(1-\frac{x}{2}\right)\left(1+\frac{x}{2}\right)\cdots sin⁡πxπx(1−x)=∏n=1∞(1+xn)(1−xn+1)=∏n=1∞(1+x(1−x)n(n+1)). \frac{\sin \pi x}{\pi x(1-x)} = \prod _{n=1}^{\infty } \left(1+\frac{x}{n}\right)\left(1-\frac{x}{n+1}\right) = \prod _{n=1}^{\infty } \left(1+\frac{x(1-x)}{n(n+1)}\right).
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Problem 3.228

sin⁡πz\sin \pi z is a single-valued function of w=z(1−z)w=z(1-z). The expansion of sin⁡πz\sin \pi z in powers of ww contains only positive coefficients (except the constant term) [problem 227].

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Problem 3.229

Prove that

[dn(π−x)−n−1cos⁡xdxn]x=0>0,n=0,1,2,… \left[\frac{d^{n}(\pi -x)^{-n-1}\cos x}{dx^{n}}\right]_{x=0} > 0, \quad n=0,1,2,\ldots
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