Section 2

Various Propositions on Real Series and Sequences

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Problem 1.156

Assume that φ(x)\varphi (x) is defined for positive xx and that for xx large enough it can be represented in the form

φ(x)=a0+a1x+a2x2+⋯+akxk+⋯ \varphi (x) = a_0 + \frac{a_1}{x} + \frac{a_2}{x^2} + \cdots + \frac{a_k}{x^k} + \cdots

aka_k real, k=0,1,2,…k=0,1,2,\ldots The infinite series

φ(1)+φ(2)+φ(3)+⋯+φ(n)+⋯ \varphi (1)+\varphi (2)+\varphi (3)+\cdots +\varphi (n)+\cdots

converges if and only if a0=a1=0a_0=a_1=0.

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Problem 1.157

(continued). Suppose φ(n)≠0\varphi (n) \neq 0. The infinite product

φ(1)φ(2)φ(3)⋯φ(n)⋯ \varphi (1)\varphi (2)\varphi (3) \cdots \varphi (n) \cdots

converges if and only if a0=1a_0=1, a1=0a_1=0.

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Problem 1.158

(continued). Under what conditions does the following infinite series converge

φ(1)+φ(1)φ(2)+φ(1)φ(2)φ(3)+⋯+φ(1)φ(2)φ(3)⋯φ(n)+⋯ ? \varphi (1) + \varphi (1)\varphi (2) + \varphi (1)\varphi (2)\varphi (3) + \cdots + \varphi (1)\varphi (2)\varphi (3) \cdots \varphi (n) + \cdots \, ?
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Problem 1.159

For which positive values of α\alpha does the following series converge

∑n=1∞(2−eα)(2−eα/2)⋯(2−eα/n) ? \sum _{n=1}^{\infty } (2-e^{\alpha })(2-e^{\alpha /2}) \cdots (2-e^{\alpha /n}) \, ?
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Problem 1.160
∫01x−x dx=∑n=1∞n−n. \int _0^1 x^{-x} \, dx = \sum _{n=1}^{\infty } n^{-n} .
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Problem 1.161

Considering positive square roots only we find

1+1+1+⋯=1+11+11+⋱ . \sqrt{1+\sqrt{1+\sqrt{1+\cdots }}} = 1 + \cfrac {1}{1+\cfrac {1}{1+\ddots }} \, .
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Problem 1.162

Let a1,a2,…,an,…a_1, a_2, \ldots , a_n, \ldots be positive numbers and put

tn=a1+a2+⋯+an , t_n = \sqrt{a_1+\sqrt{a_2+\cdots +\sqrt{a_n}}} \, ,

where only positive square roots are considered. The convergence of the sequence

(t)t1,t2,t3,…,tn,… (t) \qquad t_1, t_2, t_3, \ldots , t_n, \ldots

is related to

lim sup⁡n→∞log⁡log⁡ann=α \limsup _{n \rightarrow \infty } \frac{\log \log a_n}{n} = \alpha

in the following way:

if α<2 then (t) converges, \text{if } \alpha <2 \text{ then } (t) \text{ converges,} if α>2 then (t) diverges. \text{if } \alpha >2 \text{ then } (t) \text{ diverges.}
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Remark.
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G. Pólya, Problem: Arch. Math. Phys. Ser. 3, Vol. 24, p. 84 (1916). Solved by G. Szegö: Arch. Math. Phys. Ser. 3, Vol. 25, pp. 88-89 (1917).

Problem 1.163

(continued). The sequence (t)(t) is certainly convergent if the series

∑n=1∞2−nan(a1a2⋯an)−12 converges. \sum _{n=1}^{\infty } 2^{-n} a_n (a_1 a_2 \cdots a_n)^{-\frac{1}{2}} \text{ converges.}
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Problem 1.164

We have for 0<q<10<q<1

1−q1+q(1−q21+q2)12(1−q41+q4)14(1−q81+q8)18⋯=(1−q)2. \frac{1-q}{1+q} \left(\frac{1-q^2}{1+q^2}\right)^{\frac{1}{2}} \left(\frac{1-q^4}{1+q^4}\right)^{\frac{1}{4}} \left(\frac{1-q^8}{1+q^8}\right)^{\frac{1}{8}} \cdots = (1-q)^2 .
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Remark.
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Jacobi, l.c.solution 53, §52, Corollarium: Werke, Vol. 1, pp. 200-201.

Problem 1.165

The series

⋯+f′′(x)+f′(x)+f(x)+∫0xf(ξ1) dξ1+∫0xdξ1∫0ξ1f(ξ2) dξ2+⋯ \cdots + f''(x) + f'(x) + f(x) + \int _0^x f(\xi _1) \, d\xi _1 + \int _0^x d\xi _1 \int _0^{\xi _1} f(\xi _2) \, d\xi _2 + \cdots

is infinite in two directions. Suppose it does converge uniformly on some interval. Which function does the series represent?

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Problem 1.166

Let φn(x)\varphi_n(x) and ψn(x)\psi_n(x) denote the polynomials of degree nn, n=0,1,2,…n=0,1,2,\ldots defined by the formulas

φ0(x)=1,φn′(x)=φn−1(x),φn(0)=0, \varphi _0(x)=1, \quad \varphi _n'(x)=\varphi _{n-1}(x), \quad \varphi _n(0)=0 , ψ0(x)=1,ψn(x+1)−ψn(x)=ψn−1(x),ψn(0)=0,n=1,2,3,… \psi _0(x)=1, \quad \psi _n(x+1)-\psi _n(x)=\psi _{n-1}(x), \quad \psi _n(0)=0, \qquad n=1,2,3,\ldots

Find the two sums φ(x)\varphi (x) and ψ(x)\psi (x),

φ(x)=φ0(x)+φ1(x)+⋯+φn(x)+⋯ , \varphi (x) = \varphi _0(x)+\varphi _1(x)+\cdots +\varphi _n(x)+\cdots , ψ(x)=ψ0(x)+ψ1(x)+⋯+ψn(x)+⋯ . \psi (x) = \psi _0(x)+\psi _1(x)+\cdots +\psi _n(x)+\cdots .
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Problem 1.167

We define

xn=yne−112n,yn=n! n−n−12en,n=1,2,3,… x_n = y_n e^{-\frac{1}{12n}}, \qquad y_n = n! \, n^{-n-\frac{1}{2}} e^n, \qquad n=1,2,3,\ldots

Then each interval (xk,yk)(x_k,y_k), k=1,2,3,…k=1,2,3,\ldots, contains the interval (xk+1,yk+1)(x_{k+1},y_{k+1}) as a subinterval.

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Problem 1.168

The sequence

an=(1+1n)n+p,n=1,2,3,… a_n = \left(1+\frac{1}{n}\right)^{n+p}, \qquad n=1,2,3,\ldots

is monotone decreasing if and only if p≥12p \geq \dfrac {1}{2}.

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Remark.
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I. Schur.

Problem 1.169

The sequence

an=(1+1n)n(1+xn),n=1,2,3,… a_n = \left(1+\frac{1}{n}\right)^n \left(1+\frac{x}{n}\right), \qquad n=1,2,3,\ldots

is monotone decreasing if and only if x≥12x \geq \dfrac {1}{2}.

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Problem 1.170

Let nn be a positive integer. Then we have

e2n+2<e−(1+1n)n<e2n+1. \frac{e}{2n+2} < e - \left(1+\frac{1}{n}\right)^n < \frac{e}{2n+1} .
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Remark.
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Cf.problem No. 1098, Nouv. Annls Math. Ser. 2, Vol. 11, p. 480 (1872). Solved by C. Moreau; Nouv. Annls Math. Ser. 2, Vol. 13, p. 61 (1874).

Problem 1.171

As is well-known, the number e=lim⁡n→∞(1+1n)ne = \lim_{n \rightarrow \infty } \left(1+\dfrac {1}{n}\right)^n is contained in the interval

(1+1n)n<e<(1+1n)n+1[problem 168] \left(1+\frac{1}{n}\right)^n < e < \left(1+\frac{1}{n}\right)^{n+1} \qquad \text{[problem 168]}

In which quarter of the interval is it contained?

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Remark.
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I. Schur.

Problem 1.172

The sequence

an=(1+xn)n+1,n=1,2,3,… a_n = \left(1+\frac{x}{n}\right)^{n+1}, \qquad n=1,2,3,\ldots

is monotone decreasing if and only if 0<x≤20<x \leq 2.

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Remark.
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I. Schur.

Problem 1.173

Prove that the nn-times iterated sine function

sin⁡nx=sin⁡(sin⁡n−1x),sin⁡1x=sin⁡x, \sin _n x = \sin (\sin _{n-1} x), \qquad \sin _1 x = \sin x ,

converges to 00 as n→∞n \rightarrow \infty if sin⁡x>0\sin x>0 and that, moreover,

lim⁡n→∞n3sin⁡nx=1. \lim _{n \rightarrow \infty } \sqrt{\frac{n}{3}} \sin _n x = 1 .
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Remark.
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Proof based on a communication of E. Jacobsthal.

Problem 1.174

Assume that 0<f(x)<x0<f(x)<x and

f(x)=x−axk+bxl+xlε(x),lim⁡x→0ε(x)=0 f(x) = x - ax^k + bx^l + x^l \varepsilon (x), \qquad \lim _{x \rightarrow 0} \varepsilon (x) = 0

for 0<x<x00<x<x_0, where 1<k<l1<k<l and a,ba,b positive. Put

v0=x,v1=f(v0),v2=f(v1),…,vn=f(vn−1),… v_0=x, \quad v_1=f(v_0), \quad v_2=f(v_1), \quad \ldots , \quad v_n=f(v_{n-1}), \quad \ldots

Then we have for n→∞n \rightarrow \infty

n1k−1vn→[(k−1)a]−1k−1. n^{\frac{1}{k-1}} v_n \rightarrow \big[(k-1)a\big]^{-\frac{1}{k-1}} .
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Problem 1.175

Discuss the convergence of the series

v1s+v2s+v3s+⋯ , v_1^s + v_2^s + v_3^s + \cdots ,

where

v1=sin⁡x,v2=sin⁡sin⁡x,…,vn=sin⁡vn−1,… v_1 = \sin x, \quad v_2 = \sin \sin x, \quad \ldots , \quad v_n = \sin v_{n-1}, \quad \ldots

We can obviously assume that v1>0v_1>0.

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Remark.
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J. Ouspensky, Problem: Arch. Math. Phys. Ser. 3, Vol. 20, p. 83 (1913).

Problem 1.176

Prove the formula

ex−1=u1+u1u2+u1u2u3+⋯ e^x - 1 = u_1 + u_1 u_2 + u_1 u_2 u_3 + \cdots

where

u1=x≥0,un+1=log⁡eun−1un,n=1,2,3,… u_1 = x \geq 0, \qquad u_{n+1} = \log \frac{e^{u_n}-1}{u_n}, \qquad n=1,2,3,\ldots
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Remark.
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Cf.E. Cesàro, Problem: Nouv. Annls Math. Ser. 3, Vol. 7, p. 400 (1888). Solved by Audibert: Nouv. Annls Math. Ser. 3, Vol. 11, p. 35 (1892).

Problem 1.177

Compute

s=cos⁡3φ−13cos⁡33φ+132cos⁡332φ−133cos⁡333φ+⋯ . s = \cos ^3 \varphi - \frac{1}{3} \cos ^3 3\varphi + \frac{1}{3^2} \cos ^3 3^2\varphi - \frac{1}{3^3} \cos ^3 3^3 \varphi + \cdots .
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Remark.
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C. A. Laisant, Problem: Nouv. Annls Math. Ser. 2, Vol. 9, p. 144 (1870). Solved by H. Rumpen: Nouv. Annls Math. Ser. 2, Vol. 11, p. 232 (1872).

Problem 1.178

Let ana_n, bnb_n, bn≠0b_n \neq 0, n=0,1,2,3,…n=0,1,2,3,\ldots, be two sequences that satisfy the conditions:

  1. the power series f(x)=∑n=0∞anxnf(x) = \sum_{n=0}^{\infty } a_n x^n has a positive radius of convergence rr.

  2. the limit

    lim⁡n→∞bnbn+1=q \lim _{n \rightarrow \infty } \frac{b_n}{b_{n+1}} = q

    exists and ∣q∣<r\left|q\right|<r.

We define

cn=a0bn+a1bn−1+⋯+anb0,n=0,1,2,… c_n = a_0 b_n + a_1 b_{n-1} + \cdots + a_n b_0, \qquad n=0,1,2,\ldots

Then cnbn\dfrac {c_n}{b_n} converges to f(q)f(q) as n→∞n \rightarrow \infty.

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Remark.
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I. Schur, Problem: Arch. Math. Phys. Ser. 3, Vol. 27, p. 162 (1918). Cf.O. Szász: Sber. Berlin Math. Ges. Vol. 21, pp. 25-29 (1922).

Problem 1.179

Let

fn(x)=an1x+an2x2+an3x3+⋯ ,n=1,2,3,… f_n(x) = a_{n1}x + a_{n2}x^2 + a_{n3}x^3 + \cdots , \qquad n=1,2,3,\ldots

be arbitrary functions, ∣ank∣<A\left|a_{nk}\right|<A for all positive integral values of nn and kk and

lim⁡n→∞fn(x)=0if0<x<1. \lim _{n \rightarrow \infty } f_n(x) = 0 \quad \text{if} \quad 0<x<1 .

Then we have for fixed kk, k=1,2,3,…k=1,2,3,\ldots

lim⁡n→∞ank=0. \lim _{n \rightarrow \infty } a_{nk} = 0 .
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Remark.
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Special case of an important proposition in function theory by Vitali. Cf.E. Lindelöf: Bull. Soc. Math. France Vol. 41, p. 171 (1913).

Problem 1.180

Suppose that the series

an0+an1+an2+⋯+ank+⋯=sn,n=0,1,2,…, a_{n0}+a_{n1}+a_{n2}+\cdots +a_{nk}+\cdots = s_n, \qquad n=0,1,2,\ldots ,

have a common convergent majorant

A0+A1+A2+⋯+Ak+⋯=S, A_0+A_1+A_2+\cdots +A_k+\cdots = S ,

i.e.for each kk the inequalities ∣ank∣≤Ak\left|a_{nk}\right| \leq A_k hold simultaneously for all nn. Assume furthermore that

lim⁡n→∞ank=ak \lim _{n \rightarrow \infty } a_{nk} = a_k

exists for k=0,1,2,…k=0,1,2,\ldots Then the series

a0+a1+a2+⋯+ak+⋯=s a_0+a_1+a_2+\cdots +a_k+\cdots = s

is convergent and

lim⁡n→∞sn=s. \lim _{n \rightarrow \infty } s_n = s .
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Problem 1.181

Justify the limits in problems 53 and 59.

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Problem 1.181.1

Assume that

ai1+ai2+⋯+ain+⋯=si a_{i1}+a_{i2}+\cdots +a_{in}+\cdots = s_i

converges for i=1,2,3,…i=1,2,3,\ldots, define UiU_i as the least upper bound of

∣ai1+ai2+⋯+ain∣,n=1,2,3,…, \left|a_{i1}+a_{i2}+\cdots +a_{in}\right|, \qquad n=1,2,3,\ldots ,

and assume that

U1+U2+⋯+Un+⋯ U_1+U_2+\cdots +U_n+\cdots

converges. Then the series

(∗)a11+a12+a21+a13+a22+a31+⋯+a1n+a2,n−1+⋯ , (*) \qquad a_{11}+a_{12}+a_{21}+a_{13}+a_{22}+a_{31}+\cdots +a_{1n}+a_{2,n-1}+\cdots ,

which you obtain by arranging the numbers in the array

a11a12a13⋯a1n⋯a21a22a23⋯a2,n−1⋯a31a32a33⋯⋯⋯⋯⋯⋯ \begin{matrix} a_{11} & a_{12} & a_{13} & \cdots & a_{1n} & \cdots \\ a_{21} & a_{22} & a_{23} & \cdots & a_{2,n-1} & \cdots \\ a_{31} & a_{32} & a_{33} & \cdots & & \\ \cdots & \cdots & \cdots & \cdots & \cdots & \end{matrix}

``diagonally'', converges and its sum is

s1+s2+⋯+sn+⋯ . s_1+s_2+\cdots +s_n+\cdots .
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Remark.
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The interesting point is that the absolute convergence of the double series ∑∑aik\sum \sum a_{ik} is not assumed.

Problem 1.182

If α\alpha is fixed, α>0\alpha >0, and nn an integer increasing to +∞+\infty, then

∑ν=1∞′ να−1(nα−να)−2∼n1−α3(πα)2. {\sum _{\nu =1}^{\infty }}' \, \nu ^{\alpha -1} (n^{\alpha }-\nu ^{\alpha })^{-2} \sim \frac{n^{1-\alpha }}{3} \left(\frac{\pi }{\alpha }\right)^2 .

The meaningless term with subscript ν=n\nu =n has to be omitted, which is indicated by the comma at the summation sign. Notice the case α=1\alpha =1.

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Problem 1.183

Let the numbers ε0,ε1,ε2,…,εn,…\varepsilon_0, \varepsilon_1, \varepsilon_2, \ldots , \varepsilon_n, \ldots assume one of the three values −1,0,1-1, 0, 1. Then we have

ε02+ε12+ε22+⋯=2sin⁡(π4∑n=0∞ε0ε1ε2⋯εn2n). \varepsilon _0 \sqrt{2+\varepsilon _1 \sqrt{2+\varepsilon _2 \sqrt{2+\cdots }}} = 2 \sin \left( \frac{\pi }{4} \sum _{n=0}^{\infty } \frac{\varepsilon _0 \varepsilon _1 \varepsilon _2 \cdots \varepsilon _n}{2^n} \right) .
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Remark.
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The left hand side must be interpreted as the limit of

ε02+ε12+ε22+⋯+εn2 ,n=0,1,2,… \varepsilon _0 \sqrt{2+\varepsilon _1 \sqrt{2+\varepsilon _2 \sqrt{2+\cdots +\varepsilon _n \sqrt{2}}}} \, , \qquad n=0,1,2,\ldots

for n→∞n \rightarrow \infty. These expressions are well defined for all nn. Non-negative square roots are used throughout.

Problem 1.184

Every value xx of the interval [−2,2][-2,2] can be written in the form

x=ε02+ε12+ε22+⋯ x = \varepsilon _0 \sqrt{2+\varepsilon _1 \sqrt{2+\varepsilon _2 \sqrt{2+\cdots }}}

where εk\varepsilon_k, k=0,1,2,…k=0,1,2,\ldots, is either −1-1 or +1+1. The representation is unique if xx is not of the form 2cos⁡p2qπ2 \cos \dfrac {p}{2^q} \pi, p,qp, q integers, 0<p<2q0<p<2^q. These are the only numbers that may be written in the finite form

ε02+ε12+ε22+⋯+εn2 . \varepsilon _0 \sqrt{2+\varepsilon _1 \sqrt{2+\varepsilon _2 \sqrt{2+\cdots +\varepsilon _n \sqrt{2}}}} \, .

The finite representation can be extended to an infinite one in two ways: by putting either

εn+1=1,εn+2=−1,εn+3=εn+4=⋯=1, \varepsilon _{n+1}=1, \quad \varepsilon _{n+2}=-1, \quad \varepsilon _{n+3}=\varepsilon _{n+4}=\cdots =1 ,

or

εn+1=−1,εn+2=−1,εn+3=εn+4=⋯=1. \varepsilon _{n+1}=-1, \quad \varepsilon _{n+2}=-1, \quad \varepsilon _{n+3}=\varepsilon _{n+4}=\cdots =1 .
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Remark.
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Cf.S. Pincherle: Atti Accad. Sci. Torino, Cl. Sci. Fis. Mat. Natur. Vol. 53, pp. 745-763 (1917-1918); Atti Accad. Naz. Lincei Rend. Cl. Sci. Fis. Mat. Natur. Ser. 5, Vol. 27, 2nd Sem. pp. 177-183 (1918).

Problem 1.185

(continued). The number xx is of the form x=2cos⁡kπx=2\cos k\pi, kk rational, if and only if the sequence ε0,ε1,ε2,…\varepsilon_0, \varepsilon_1, \varepsilon_2, \ldots is periodical after a certain term.

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Problem 1.185.1

Construct a sequence of real numbers a1,a2,…,an,…a_1, a_2, \ldots , a_n, \ldots so that the series

a1l+a2l+⋯+anl+⋯ a_1^l + a_2^l + \cdots + a_n^l + \cdots

diverges for l=5l=5, but converges when ll is any odd positive integer different from 5.

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Remark.
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For precursory heuristic considerations see MD, Vol. 2, pp. 49-50 and 171.

Problem 1.185.2

(continued). Let the set of all odd positive integers be divided (arbitrarily) into two complementary subsets CC and DD (having no element in common). Show that there exists a sequence of real numbers a1,a2,…,an,…a_1, a_2, \ldots , a_n, \ldots such that the series mentioned converges when ll belongs to CC and diverges when ll belongs to DD.

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Remark.
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G. Pólya, Problem: Amer. Math. Monthly Vol. 51, p. 593 (1944). Solved by N. J. Fine: Amer. Math. Monthly Vol. 53, pp. 283-284 (1946).