Section 2.4

Limits of Functions

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Problem 2.4.1

Let ( M,dM, d ) be a metric space, A⊂M,f,g:M→RA \subset M, f, g: M \rightarrow \mathbb {R}, and let aa be a cluster point of AA. Also, let α\alpha be a real number. If lim⁡x→af(x)\lim_{x \rightarrow a} f(x) and lim⁡x→ag(x)\lim_{x \rightarrow a} g(x) both exist prove that

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(a)

lim⁡x→a(αf(x))=αlim⁡x→af(x);\lim_{x \rightarrow a}(\alpha f(x))=\alpha \lim_{x \rightarrow a} f(x) ;

(b)

lim⁡x→a(f(x)+g(x))=lim⁡x→af(x)+lim⁡x→ag(x)\lim_{x \rightarrow a}(f(x)+g(x))=\lim_{x \rightarrow a} f(x)+\lim_{x \rightarrow a} g(x);

(c)

lim⁡x→a(f(x)g(x))=(lim⁡x→af(x))(lim⁡x→ag(x))\lim_{x \rightarrow a}(f(x) g(x))=\left(\lim_{x \rightarrow a} f(x)\right)\left(\lim_{x \rightarrow a} g(x)\right);

(d)

lim⁡x→a(f(x)/g(x))=lim⁡x→af(x)/lim⁡x→ag(x)\lim_{x \rightarrow a}(f(x) / g(x))=\lim_{x \rightarrow a} f(x) / \lim_{x \rightarrow a} g(x), with the additional assumption that lim⁡x→ag(x)≠0\lim_{x \rightarrow a} g(x) \neq 0.

Problem 2.4.2

Let ( M,dM, d ) be a metric space, A⊂MA \subset M, and f,g:M→Rf, g: M \rightarrow \mathbb {R} satisfy f(x)<g(x)f(x)<g(x) for all x∈Ax \in A. If aa is a cluster point of AA and if lim⁡x→af(x)\lim_{x \rightarrow a} f(x) and lim⁡x→ag(x)\lim_{x \rightarrow a} g(x) both exist to prove that lim⁡x→af(x)≤lim⁡x→ag(x)\lim_{x \rightarrow a} f(x) \leq \lim_{x \rightarrow a} g(x).

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Problem 2.4.3

Let F:C[0,1]→RF: C[0,1] \rightarrow \mathbb {R} be defined by F(f)=f(0)F(f)=f(0), and let g(x)=x2g(x)=x^{2}. Find lim⁡f→gF(f)\lim_{f \rightarrow g} F(f).

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Problem 2.4.4

Let dd be a metric on C[0,1]C[0,1] defined by

d(f,g)=∫01∣f(x)−g(x)∣dx d(f, g)=\int _{0}^{1}\left|f(x)-g(x)\right| d x

(see Exercise 2.1.3). Let F:C[0,1]→RF: C[0,1] \rightarrow \mathbb {R} be defined by F(f)=f(0)F(f)=f(0), and let g(x)=x2g(x)=x^{2}. Find lim⁡f→gF(f)\lim_{f \rightarrow g} F(f).

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Problem 2.4.5

Let dd be a metric on R\mathbb {R} defined by

d(x,y):=∣x−y∣1+∣x−y∣ d(x, y):=\frac{\left|x-y\right|}{1+\left|x-y\right|}

(see Exercise 2.1.8), and let ρ\rho denote the usual distance on R,ρ(x,y)=∣x−y∣\mathbb {R}, \rho (x, y)=\left|x-y\right|. Let f:(R,d)→(R,ρ)f:(\mathbb {R}, d) \rightarrow (\mathbb {R}, \rho ) be defined by f(x)=x2f(x)=x^{2}. Find lim⁡x→2f(x)\lim_{x \rightarrow 2} f(x).

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Problem 2.4.6

Prove Theorem 2.4.5.

Theorem 2.4.5: Let (an)n=1∞\left(a_{n}\right)_{n=1}^{\infty } be a sequence of real numbers. Then

lim sup⁡an=inf⁡k≥1sup⁡n≥kanandlim inf⁡an=sup⁡k≥1inf⁡n≥kan. \limsup a_{n} = \inf _{k \geq 1} \sup _{n \geq k} a_{n} \quad \text{and} \quad \liminf a_{n} = \sup _{k \geq 1} \inf _{n \geq k} a_{n}.
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Problem 2.4.7

Let ( M,dM, d ) be a metric space, let f:M→Rf: M \rightarrow \mathbb {R}, and let a∈Ma \in M. Prove that lim sup⁡x→af(x)\limsup_{x \rightarrow a} f(x) and lim inf⁡x→af(x)\liminf_{x \rightarrow a} f(x) always exist either as finite numbers or ±∞\pm \infty.

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Problem 2.4.8

Let {an}\left\{ a_{n}\right\} be a sequence of real numbers. Prove that lim⁡sup⁡an\lim \sup a_{n} equals lim sup⁡x→0f(x)\limsup_{x \rightarrow 0} f(x), where the function f:{1,1/2,1/3,…}→Rf:\left\{ 1,1 / 2,1 / 3, \ldots \right\} \rightarrow \mathbb {R} is defined by f(1/n)=anf(1 / n)=a_{n}.

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Problem 2.4.9

Prove that lim⁡x→af(x)\lim_{x \rightarrow a} f(x) exists if and only if both limit superiors and both limit inferiors (left and right) are all equal.

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Problem 2.4.10

If ff is defined on [−c,c][-c, c] and x0∈(−c,c)x_{0} \in (-c, c), prove the following:

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(a)

lim sup⁡sup⁡x→x0+(−f(x))=−lim inf⁡x→x0+f(x),lim sup⁡x→x0−(−f(x))=−lim inf⁡x→x0−f(x)\limsup \sup_{x \rightarrow x_{0}+}(-f(x))=-\liminf_{x \rightarrow x_{0}+} f(x), \limsup_{x \rightarrow x_{0}-}(-f(x))= -\liminf_{x \rightarrow x_{0}-} f(x).

(b)

lim sup⁡x→x0+(f(−x))=lim sup⁡x→−x0−f(x),lim inf⁡x→x0+(f(−x))=lim inf⁡x→−x0−f(x)\limsup_{x \rightarrow x_{0}+}(f(-x))=\limsup_{x \rightarrow -x_{0}-} f(x), \liminf_{x \rightarrow x_{0}+}(f(-x))= \liminf_{x \rightarrow -x_{0}-} f(x).

(c)

lim sup⁡sup⁡x→x0−(f(−x))=lim sup⁡x→−x0+f(x),lim inf⁡x→x0−(f(−x))=lim inf⁡x→−x0+f(x)\limsup \sup_{x \rightarrow x_{0}-}(f(-x))=\limsup_{x \rightarrow -x_{0}+} f(x), \liminf_{x \rightarrow x_{0}-}(f(-x))= \liminf_{x \rightarrow -x_{0}+} f(x).

Problem 2.4.11

Let ( M,dM, d ) be a metric space, let f:M→Rf: M \rightarrow \mathbb {R}, and let g:M→Rg: M \rightarrow \mathbb {R} be defined by g(x)=lim sup⁡t→xf(t)g(x)=\limsup_{t \rightarrow x} f(t). Prove that gg is upper semicontinuous.

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Problem 2.4.12

Let {An}\left\{ A_{n}\right\} be an arbitrary collection of subsets of a set XX. Prove that

lim sup⁡An={x∈X:lim sup⁡χAn(x)=1}. \limsup A_{n}=\left\{ x \in X: \limsup \chi _{A_{n}}(x)=1\right\} .
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Problem 2.4.13

Let ( M,dM, d ) be a metric space and for every n∈Nn \in \mathbb {N} let fn:M→[0,+∞]f_{n}: M \rightarrow [0,+\infty ]. Prove that

sup⁡{∑k=1∞fk(xk):{xk}⊂M}=∑k=1∞sup⁡{fk(x):x∈M}. \sup \left\{ \sum _{k=1}^{\infty } f_{k}\left(x_{k}\right):\left\{ x_{k}\right\} \subset M\right\} =\sum _{k=1}^{\infty } \sup \left\{ f_{k}(x): x \in M\right\} .
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Problem 2.4.14

Let ff and gg be real-valued functions on an interval (a−η,a+η)(a-\eta , a+\eta ). Prove that

lim inf⁡x→af(x)+lim inf⁡x→ag(x)≤lim inf⁡x→a(f(x)+g(x))≤lim inf⁡x→af(x)+lim sup⁡x→ag(x)≤lim sup⁡x→a(f(x)+g(x))≤lim sup⁡x→af(x)+lim sup⁡x→ag(x) \begin{aligned} \liminf _{x \rightarrow a} f(x)+ & \liminf _{x \rightarrow a} g(x) \leq \liminf _{x \rightarrow a}(f(x)+g(x)) \leq \liminf _{x \rightarrow a} f(x)+\limsup _{x \rightarrow a} g(x) \\ & \leq \limsup _{x \rightarrow a}(f(x)+g(x)) \leq \limsup _{x \rightarrow a} f(x)+\limsup _{x \rightarrow a} g(x) \end{aligned}
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Problem 2.4.15

Let ff and gg be strictly positive functions on an interval (a−η,a+η)(a-\eta , a+\eta ) and suppose that lim inf⁡x→af(x)\liminf_{x \rightarrow a} f(x) and lim sup⁡x→af(x)\limsup_{x \rightarrow a} f(x) exist and are not 0 . Prove that:

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(a)

lim sup⁡x→a1f(x)=1lim inf⁡x→af(x)\limsup_{x \rightarrow a} \frac{1}{f(x)}=\frac{1}{\liminf_{x \rightarrow a} f(x)}.

(b)

lim inf⁡x→a1f(x)=1lim sup⁡x→af(x)\liminf_{x \rightarrow a} \frac{1}{f(x)}=\frac{1}{\limsup_{x \rightarrow a} f(x)}.

Problem 2.4.16

Let ff and gg be nonnegative functions on an interval ( a−η,a+η)a-\eta , a+ \eta ) and suppose that lim inf⁡x→af(x),lim sup⁡x→af(x),lim inf⁡x→ag(x)\liminf_{x \rightarrow a} f(x), \limsup_{x \rightarrow a} f(x), \liminf_{x \rightarrow a} g(x), and lim sup⁡x→ag(x)\limsup_{x \rightarrow a} g(x) exist and are not 0 . Prove that

lim inf⁡x→af(x)⋅lim inf⁡x→ag(x)≤lim inf⁡x→a(f(x)⋅g(x))≤lim inf⁡x→af(x)⋅lim sup⁡x→ag(x)≤lim sup⁡x→a(f(x)⋅g(x))≤lim sup⁡x→af(x)⋅lim sup⁡x→ag(x) \begin{aligned} \liminf _{x \rightarrow a} f(x) \cdot \liminf _{x \rightarrow a} g(x) & \leq \liminf _{x \rightarrow a}(f(x) \cdot g(x)) \leq \liminf _{x \rightarrow a} f(x) \cdot \limsup _{x \rightarrow a} g(x) \\ & \leq \limsup _{x \rightarrow a}(f(x) \cdot g(x)) \leq \limsup _{x \rightarrow a} f(x) \cdot \limsup _{x \rightarrow a} g(x) \end{aligned}
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Problem 2.4.17

Let ff and gg be nonnegative functions on an interval ( a−η,a+ηa-\eta , a+\eta ) and suppose that lim⁡x→af(x)\lim_{x \rightarrow a} f(x) exists. Prove that:

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(a)

lim sup⁡sup⁡x→a(f(x)+g(x))=lim⁡x→af(x)+lim sup⁡x→ag(x)\limsup \sup_{x \rightarrow a}(f(x)+g(x))=\lim_{x \rightarrow a} f(x)+\limsup_{x \rightarrow a} g(x).

(b)

lim inf⁡x→a(f(x)+g(x))=lim⁡x→af(x)+lim inf⁡x→ag(x)\liminf_{x \rightarrow a}(f(x)+g(x))=\lim_{x \rightarrow a} f(x)+\liminf_{x \rightarrow a} g(x).

(c)

lim sup⁡x→a(f(x)⋅g(x))=lim⁡x→af(x)⋅lim sup⁡x→ag(x)\limsup_{x \rightarrow a}(f(x) \cdot g(x))=\lim_{x \rightarrow a} f(x) \cdot \limsup_{x \rightarrow a} g(x).

(d)

lim inf⁡x→a(f(x)⋅g(x))=lim⁡x→af(x)⋅lim inf⁡x→ag(x)\liminf_{x \rightarrow a}(f(x) \cdot g(x))=\lim_{x \rightarrow a} f(x) \cdot \liminf_{x \rightarrow a} g(x).

Problem 2.4.18

Let ( M,dM, d ) be a metric space, A⊂MA \subset M, and f:M→Rf: M \rightarrow \mathbb {R}. If aa is a cluster point of AA prove that:

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(a)

If y<inf⁡W(f,a)y<\inf W(f, a), then there exists δ>0\delta >0 such that f(x)>yf(x)>y whenever 0<d(x,a)<δ,x∈A0<d(x, a)<\delta , x \in A.

(b)

If y>inf⁡W(f,a)y>\inf W(f, a), then for every δ>0\delta >0, there exists x∈Ax \in A with 0<d(x,a)<δ0<d(x, a)<\delta, such that f(x)<yf(x)<y.

Problem 2.4.19

Prove Corollary 2.4.9.

Corollary 2.4.9: Let (M,d)(M,d) be a metric space, let f:M→Rf: M \rightarrow \mathbb {R}, and let A⊂MA \subset M. If aa is a cluster point of AA then

lim sup⁡x→af(x)=sup⁡W(f,a), \limsup _{x \rightarrow a} f(x) = \sup W(f, a),

where W(f,a)={w:∃(an)⊂A∖{a},lim⁡an=a,lim⁡f(an)=w}W(f, a) = \left\{ w : \exists \left(a_{n}\right) \subset A \setminus \left\{ a\right\} , \lim a_{n} = a, \lim f(a_{n}) = w\right\} is the set of all subsequential limits of ff along sequences in A∖{a}A \setminus \left\{ a\right\} converging to aa.

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Problem 2.4.20

Let ( M,dM, d ) be a metric space, let f:M→Rf: M \rightarrow \mathbb {R}, and let A⊂MA \subset M. If aa is a cluster point of AA prove that

lim inf⁡x→af(x)=inf⁡W(f,a). \liminf _{x \rightarrow a} f(x)=\inf W(f, a) .
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Problem 2.4.21

Let a∈Ra \in \mathbb {R} and f:(a,+∞)→Rf:(a,+\infty ) \rightarrow \mathbb {R}. Prove that the limit lim⁡x→+∞f(x)\lim_{x \rightarrow +\infty } f(x) exists if and only if lim sup⁡x→+∞f(x)=lim inf⁡x→+∞f(x)\limsup_{x \rightarrow +\infty } f(x)=\liminf_{x \rightarrow +\infty } f(x) and in this situation they are all equal.

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Problem 2.4.22

Let f:R→Rf: \mathbb {R} \rightarrow \mathbb {R}. Prove that

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(a)

lim sup⁡sup⁡x→+∞(−f(x))=−lim inf⁡x→+∞f(x),lim sup⁡x→+∞(−f(x))=−lim inf⁡x→+∞f(x)\limsup \sup_{x \rightarrow +\infty }(-f(x))=-\liminf_{x \rightarrow +\infty } f(x), \limsup_{x \rightarrow +\infty }(-f(x))= -\liminf_{x \rightarrow +\infty } f(x).

(b)

lim sup⁡x→+∞(f(−x))=lim sup⁡x→−∞f(x),lim inf⁡x→+∞(f(−x))=lim inf⁡x→−∞f(x)\limsup_{x \rightarrow +\infty }(f(-x))=\limsup_{x \rightarrow -\infty } f(x), \liminf_{x \rightarrow +\infty }(f(-x))= \liminf_{x \rightarrow -\infty } f(x).

Problem 2.4.23

Let a∈Ra \in \mathbb {R} and f:(a,+∞)→Rf:(a,+\infty ) \rightarrow \mathbb {R}. Prove that lim sup⁡x→+∞f(x)=L\limsup_{x \rightarrow +\infty } f(x)=L if and only if, for any sequence {an}\left\{ a_{n}\right\} converging to +∞,lim sup⁡x→+∞f(an)=L+\infty , \limsup_{x \rightarrow +\infty } f\left(a_{n}\right)=L.

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Problem 2.4.24

Let f:(a,+∞)→Rf:(a,+\infty ) \rightarrow \mathbb {R}. Prove that

lim sup⁡x→∞f(x)=sup⁡W(f,∞) and lim inf⁡x→∞f(x)=inf⁡W(f,∞) \limsup _{x \rightarrow \infty } f(x)=\sup W(f, \infty ) \quad \text{ and } \quad \liminf _{x \rightarrow \infty } f(x)=\inf W(f, \infty )
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Problem 2.4.25

Prove Theorem 2.4.20.

Theorem 2.4.20: Let ff be a differentiable function on a set E⊂RE \subset \mathbb {R}. Then ff is Lipschitz with constant K=sup⁡{∣f′(x)∣:x∈E}K = \sup \left\{ \left|f'(x)\right| : x \in E\right\} if and only if it has a bounded derivative.

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Problem 2.4.26

Suppose that ff is a real-valued Lipschitz function on (a,b)(a, b). Prove that ff is uniformly continuous on (a,b)(a, b).

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Problem 2.4.27

Let ( M,dM, d ) be a metric space and x0∈Mx_{0} \in M. Let f:M→Rf: M \rightarrow \mathbb {R} be defined by f(x)=d(x,x0)f(x)=d\left(x, x_{0}\right). Prove that ff is uniformly continuous.

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Problem 2.4.28

Give an example of a function that is continuous but not uniformly continuous. Give an example of a function that is uniformly continuous but not Lipschitz.

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Problem 2.4.29

Give an example of a function that is Lipschitz on a set EE but not differentiable at a point x∈Ex \in E.

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Problem 2.4.30

Let ff be a real-valued function defined on a set A⊂R2A \subset \mathbb {R}^{2} such that it is a continuous function of xx (with yy fixed), and let ff satisfy the Lipschitz condition with respect to yy, i.e., suppose that there exists M>0M>0 such that

∣f(x,y1)−f(x,y2)∣≤M∣y1−y2∣ \left|f\left(x, y_{1}\right)-f\left(x, y_{2}\right)\right| \leq M\left|y_{1}-y_{2}\right|

for all (x,y1),(x,y2)∈A\left(x, y_{1}\right),\left(x, y_{2}\right) \in A. Prove that ff is continuous on AA.

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Problem 2.4.31

Let d(x,y)=∣x−y∣d(x, y)=\sqrt{\left|x-y\right|}, let ρ(x,y)=∣x−y∣\rho (x, y)=\left|x-y\right|, and consider ff : ([0,1],d)→([0,1],ρ)([0,1], d) \rightarrow ([0,1], \rho ) defined by f(x)=xαf(x)=x^{\alpha }. Determine what values of α>0\alpha >0 is ff Lipschitz.

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Problem 2.4.32

Let (C[0,1],d)(C[0,1], d) be the metric space with d(f,g)=sup⁡{∣f(x)−g(x)∣:x∈[0,1]}d(f, g)=\sup \left\{ \left|f(x)-g(x)\right|: x \in [0,1]\right\}, and let F:C[0,1]→C[0,1]F: C[0,1] \rightarrow C[0,1] be defined by F(f)=f2F(f)=f^{2}. Determine whether FF is Lipschitz.

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Problem 2.4.33

Let ( C[0,1],dC[0,1], d ) be the metric space with d(f,g)=sup⁡{∣f(x)−g(x)∣:x∈[0,1]}d(f, g)=\sup \left\{ \left|f(x)-g(x)\right|: x \in [0,1]\right\}, and let F:C[0,1]→C[0,1]F: C[0,1] \rightarrow C[0,1] be defined by F(f)=sin⁡fF(f)=\sin f. Determine whether FF is Lipschitz.

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Problem 2.4.34

Let d:R→Rd: \mathbb {R} \rightarrow \mathbb {R} be defined by d(x,y)=1d(x, y)=1 if x≠yx \neq y and d(x,y)=0d(x, y)=0 if x=yx=y, let ρ(x,y)=∣x−y∣\rho (x, y)=\left|x-y\right|, and consider f:(R,d)→(R,ρ)f:(\mathbb {R}, d) \rightarrow (\mathbb {R}, \rho ) defined by f(x)=x2f(x)=x^{2}. Determine if ff is uniformly continuous. Is it Lipschitz?

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