Section 7.10

Difference Equations, Limits, and Summability

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Problem 7.10.1

Which of the following are convergent, and which are summable?

A=(−1/23/2−3/210−1/21−11/2),B=(010001100),C=(−1−2−3/2121113/2). \mathbf{A} = \begin{pmatrix} -1/2 & 3/2 & -3/2 \\ 1 & 0 & -1/2 \\ 1 & -1 & 1/2 \end{pmatrix}, \quad \mathbf{B} = \begin{pmatrix} 0 & 1 & 0 \\ 0 & 0 & 1 \\ 1 & 0 & 0 \end{pmatrix}, \quad \mathbf{C} = \begin{pmatrix} -1 & -2 & -3/2 \\ 1 & 2 & 1 \\ 1 & 1 & 3/2 \end{pmatrix}.
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Problem 7.10.2

For the matrices in Exercise 7.10.1, evaluate the limit of each convergent matrix, and evaluate the Cesaro limit for each summable matrix.

If A\mathbf{A} is convergent or summable to G\mathbf{G}, and if I−A=BC\mathbf{I}-\mathbf{A} = \mathbf{B}\mathbf{C} is a full-rank factorization, then G=I−B(CB)−1C\mathbf{G} = \mathbf{I} - \mathbf{B}(\mathbf{C}\mathbf{B})^{-1}\mathbf{C}.

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Problem 7.10.3

Verify that

x→(k)=Akx→(0)andx→(k)=Akx→(0)+∑j=0k−1Ak−j−1b→(j)for k=1,2,3,… \overrightarrow {x}(k) = \mathbf{A}^k\overrightarrow {x}(0) \quad \text{and} \quad \overrightarrow {x}(k) = \mathbf{A}^k\overrightarrow {x}(0) + \sum _{j=0}^{k-1}\mathbf{A}^{k-j-1}\overrightarrow {b}(j) \quad \text{for } k=1,2,3,\ldots

are indeed the respective solutions to the difference equations x→(k+1)=Ax→(k)\overrightarrow {x}(k+1) = \mathbf{A}\overrightarrow {x}(k) (a homogeneous system) and x→(k+1)=Ax→(k)+b→(k)\overrightarrow {x}(k+1) = \mathbf{A}\overrightarrow {x}(k)+\overrightarrow {b}(k) (a nonhomogeneous system).

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Problem 7.10.4

Determine the limiting vector for the following shell game by first computing the Cesaro limit G\mathbf{G} with a full-rank factorization.

Shell game: a pea starts under one of four shells and, after each move, is shuffled to one of the (at most three) adjacent shells with equal probability, described by a 4×44\times 4 column-stochastic transition matrix A\mathbf{A} with p→(k)=Akp→(0)\overrightarrow {p}(k) = \mathbf{A}^k\overrightarrow {p}(0) giving the probability distribution over shell positions after kk moves. If I−A=BC\mathbf{I}-\mathbf{A} = \mathbf{B}\mathbf{C} is a full-rank factorization, then the Cesaro limit is G=I−B(CB)−1C\mathbf{G} = \mathbf{I}-\mathbf{B}(\mathbf{C}\mathbf{B})^{-1}\mathbf{C}, and the limiting vector of expected proportions is p→=Gp→(0)\overrightarrow {p} = \mathbf{G}\overrightarrow {p}(0).

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Problem 7.10.5

Verify that

x→(k)=Akx→(0)andx→(k)=Akx→(0)+∑j=0k−1Ak−j−1b→(j)for k=1,2,3,… \overrightarrow {x}(k) = \mathbf{A}^k\overrightarrow {x}(0) \quad \text{and} \quad \overrightarrow {x}(k) = \mathbf{A}^k\overrightarrow {x}(0) + \sum _{j=0}^{k-1}\mathbf{A}^{k-j-1}\overrightarrow {b}(j) \quad \text{for } k=1,2,3,\ldots

are indeed the respective solutions to the difference equations x→(k+1)=Ax→(k)\overrightarrow {x}(k+1) = \mathbf{A}\overrightarrow {x}(k) (a homogeneous system) and x→(k+1)=Ax→(k)+b→(k)\overrightarrow {x}(k+1) = \mathbf{A}\overrightarrow {x}(k)+\overrightarrow {b}(k) (a nonhomogeneous system).

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Problem 7.10.6

Prove that if there exists a matrix norm such that ∥A∥<1\left\| \mathbf{A}\right\| < 1, then lim⁡k→∞Ak=0\lim_{k\to \infty }\mathbf{A}^k = \mathbf{0}.

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Problem 7.10.7

By examining the iteration matrix, compare the convergence of Jacobi's method and the Gauss--Seidel method for each of the following coefficient matrices with an arbitrary right-hand side. Explain why this shows that neither method can be universally favored over the other.

A1=(12−2111221),A2=(2−11222−1−12). \mathbf{A}_1 = \begin{pmatrix} 1 & 2 & -2 \\ 1 & 1 & 1 \\ 2 & 2 & 1 \end{pmatrix}, \quad \mathbf{A}_2 = \begin{pmatrix} 2 & -1 & 1 \\ 2 & 2 & 2 \\ -1 & -1 & 2 \end{pmatrix}.
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Problem 7.10.8

Let A=(2−10−12−10−12)\mathbf{A} = \begin{pmatrix} 2 & -1 & 0 \\ -1 & 2 & -1 \\ 0 & -1 & 2 \end{pmatrix} (the finite-difference matrix of Example 1.4.1).

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(a)

Verify that A\mathbf{A} satisfies the special-case conditions that guarantee the validity of the SOR optimum-relaxation formula: det⁡(αD−L−U)=det⁡(αD−βL−β−1U)\operatorname {det}\left(\alpha \mathbf{D}-\mathbf{L}-\mathbf{U}\right) = \operatorname {det}\left(\alpha \mathbf{D}-\beta \mathbf{L}-\beta^{-1}\mathbf{U}\right) for all real α\alpha and β≠0\beta \ne 0, and the Jacobi iteration matrix HJ\mathbf{H}_J has real eigenvalues with ρ(HJ)<1\rho (\mathbf{H}_J)<1, where D\mathbf{D}, L\mathbf{L}, U\mathbf{U} are A\mathbf{A}'s diagonal, strictly-lower, and strictly-upper parts.

(b)

Determine the optimum SOR relaxation parameter, given that ωopt=21+1−ρ2(HJ)\omega_{\text{opt}} = \dfrac {2}{1+\sqrt{1-\rho^2(\mathbf{H}_J)}} and ρ(Hωopt)=ωopt−1\rho (\mathbf{H}_{\omega_{\text{opt}}}) = \omega_{\text{opt}}-1.

(c)

Find the asymptotic rates of convergence for Jacobi, Gauss--Seidel, and optimum SOR.

(d)

Use x→(0)=(1,1,1)T\overrightarrow {x}(0) = (1,1,1)^T and b→=(2,4,6)T\overrightarrow {b} = (2,4,6)^T to run through several steps of Jacobi, Gauss--Seidel, and optimum SOR to solve Ax→=b→\mathbf{A}\overrightarrow {x}=\overrightarrow {b} until you can see a convergence pattern.

Problem 7.10.9

Prove that if ρ(Hω)<1\rho (\mathbf{H}_{\omega }) < 1, where Hω\mathbf{H}_{\omega } is the iteration matrix for the SOR method, then 0<ω<20 < \omega < 2.

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Remark.
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Hint: Use det⁡(Hω)\operatorname {det}\left(\mathbf{H}_{\omega }\right) to show ∣λk∣≥∣1−ω∣\left|\lambda_k\right| \ge \left|1-\omega \right| for some λk∈σ(Hω)\lambda_k \in \sigma (\mathbf{H}_{\omega }).

Problem 7.10.10

Show that the spectral radius of the Jacobi iteration matrix for the discrete Laplacian Ln2×n2\mathbf{L}_{n^2\times n^2} described in Example 7.6.2 is ρ(HJ)=cos⁡(π/(n+1))\rho (\mathbf{H}_J) = \cos \bigl(\pi /(n+1)\bigr).

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Problem 7.10.11

Consider a scalar sequence {α1,α2,α3,…}\left\{ \alpha_1, \alpha_2, \alpha_3, \ldots \right\} and the associated Cesaro sequence of averages {μ1,μ2,μ3,…}\left\{ \mu_1, \mu_2, \mu_3, \ldots \right\}, where μn=(α1+α2+⋯+αn)/n\mu_n = (\alpha_1+\alpha_2+\cdots +\alpha_n)/n. Prove that if {αn}\left\{ \alpha_n\right\} converges to α\alpha, then {μn}\left\{ \mu_n\right\} also converges to α\alpha.

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Remark.
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Like scalars, a vector sequence {v→n}\left\{ \overrightarrow {v}_n\right\} in a finite-dimensional space converges to v→\overrightarrow {v} if and only if for each ε>0\varepsilon >0 there is a natural number N=N(ε)N=N(\varepsilon ) such that ∥v→n−v→∥<ε\left\| \overrightarrow {v}_n-\overrightarrow {v}\right\| <\varepsilon for all n≥Nn\ge N, and it doesn't matter which norm is used. Therefore, your proof should also be valid for vectors (and matrices).

Problem 7.10.12

For matrices with nonpositive off-diagonal entries (ZZ-matrices), prove that the following statements are equivalent.

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(a)

A\mathbf{A} is an MM-matrix.

(b)

All leading principal minors of A\mathbf{A} are positive.

(c)

A\mathbf{A} has an LU\mathbf{L}\mathbf{U} factorization, and both L\mathbf{L} and U\mathbf{U} are MM-matrices.

(d)

There exists a vector x→>0→\overrightarrow {x}>\overrightarrow {0} such that Ax→>0→\mathbf{A}\overrightarrow {x}>\overrightarrow {0}.

(e)

Each aii>0a_{ii}>0 and AD\mathbf{A}\mathbf{D} is diagonally dominant for some diagonal matrix D\mathbf{D} with positive diagonal entries.

(f)

Ax→≥0→\mathbf{A}\overrightarrow {x} \ge \overrightarrow {0} implies x→≥0→\overrightarrow {x} \ge \overrightarrow {0}.

Problem 7.10.13

Suppose that λ∈σ(A)\lambda \in \sigma (\mathbf{A}), and let M1=A−λI\mathbf{M}_1 = \mathbf{A}-\lambda \mathbf{I}. The following procedure yields the value of index⁡(λ)\operatorname {index}(\lambda ): factor M1=B1C1\mathbf{M}_1 = \mathbf{B}_1\mathbf{C}_1 as a full-rank factorization, set M2=C1B1\mathbf{M}_2 = \mathbf{C}_1\mathbf{B}_1, factor M2=B2C2\mathbf{M}_2 = \mathbf{B}_2\mathbf{C}_2 as a full-rank factorization, set M3=C2B2\mathbf{M}_3 = \mathbf{C}_2\mathbf{B}_2, and so on. In general, Mi=Ci−1Bi−1\mathbf{M}_i = \mathbf{C}_{i-1}\mathbf{B}_{i-1}, where Mi−1=Bi−1Ci−1\mathbf{M}_{i-1} = \mathbf{B}_{i-1}\mathbf{C}_{i-1} is a full-rank factorization.

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(a)

Explain why this procedure must eventually produce a matrix Mk\mathbf{M}_k that is either nonsingular or zero.

(b)

Prove that if kk is the smallest positive integer such that Mk−1\mathbf{M}_k^{-1} exists or Mk=0\mathbf{M}_k = \mathbf{0}, then

index⁡(λ)={k−1if Mk is nonsingular,kif Mk=0. \operatorname {index}(\lambda ) = \begin{cases} k-1 & \text{if } \mathbf{M}_k \text{ is nonsingular}, \\ k & \text{if } \mathbf{M}_k = \mathbf{0}. \end{cases}
Problem 7.10.14

Use the procedure in Exercise 7.10.13 to find the index of each eigenvalue of A=(−3−8−95119−1−21)\mathbf{A} = \begin{pmatrix} -3 & -8 & -9 \\ 5 & 11 & 9 \\ -1 & -2 & 1 \end{pmatrix}.

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Remark.
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Hint: σ(A)={4,1}\sigma (\mathbf{A}) = \left\{ 4,1\right\}.

Problem 7.10.15

Let A\mathbf{A} be the matrix given in Exercise 7.10.14.

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(a)

Find the Jordan form for A\mathbf{A}.

(b)

For any function ff defined at A\mathbf{A}, find the Hermite interpolation polynomial, and describe f(A)f(\mathbf{A}).

Problem 7.10.16

Given a matrix Bn×n\mathbf{B}_{n\times n} of rank rr such that index⁡(B)≤1\operatorname {index}(\mathbf{B}) \le 1 (i.e., index⁡(λ=0)≤1\operatorname {index}(\lambda =0)\le 1), the Jordan form for B\mathbf{B} looks like (000Cr×r)=P−1BP\begin{pmatrix} 0 & 0 \\ 0 & \mathbf{C}_{r\times r} \end{pmatrix} = \mathbf{P}^{-1}\mathbf{B}\mathbf{P}, so B=P(000C)P−1\mathbf{B} = \mathbf{P}\begin{pmatrix} 0 & 0 \\ 0 & \mathbf{C} \end{pmatrix}\mathbf{P}^{-1}, where C\mathbf{C} is nonsingular. This implies that B\mathbf{B} belongs to an algebraic group G\mathcal{G} with respect to matrix multiplication, and the inverse of B\mathbf{B} in G\mathcal{G} is B#=P(000C−1)P−1\mathbf{B}^{\# } = \mathbf{P}\begin{pmatrix} 0 & 0 \\ 0 & \mathbf{C}^{-1} \end{pmatrix}\mathbf{P}^{-1}; B#\mathbf{B}^{\# } is called the group inverse of B\mathbf{B}. Prove that if lim⁡k→∞Ak\lim_{k\to \infty }\mathbf{A}^k exists, and if B=I−A\mathbf{B} = \mathbf{I}-\mathbf{A}, then

lim⁡k→∞Ak=I−BB#. \lim _{k\to \infty }\mathbf{A}^k = \mathbf{I}-\mathbf{B}\mathbf{B}^{\# }.

In other words, the limiting matrix can be characterized as the difference of two identity elements---I\mathbf{I} is the identity in the multiplicative group of nonsingular matrices, and BB#\mathbf{B}\mathbf{B}^{\# } is the identity element in the multiplicative group containing B\mathbf{B}.

Limits of powers: for A∈Cn×n\mathbf{A} \in \mathbb {C}^{n \times n}, lim⁡k→∞Ak\lim_{k\to \infty }\mathbf{A}^k exists if and only if ρ(A)<1\rho (\mathbf{A})<1, or else ρ(A)=1\rho (\mathbf{A})=1 where λ=1\lambda =1 is the only eigenvalue on the unit circle and λ=1\lambda =1 is semisimple.

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Problem 7.10.17

If Mn×n\mathbf{M}_{n\times n} is a group matrix (i.e., if index⁡(M)≤1\operatorname {index}(\mathbf{M}) \le 1), then the group inverse of M\mathbf{M} can be characterized as the unique solution M#\mathbf{M}^{\# } of the equations MM#M=M\mathbf{M}\mathbf{M}^{\# }\mathbf{M} = \mathbf{M}, M#MM#=M#\mathbf{M}^{\# }\mathbf{M}\mathbf{M}^{\# } = \mathbf{M}^{\# }, and MM#=M#M\mathbf{M}\mathbf{M}^{\# } = \mathbf{M}^{\# }\mathbf{M}. In fact, some authors use these equations to define M#\mathbf{M}^{\# }. Use this characterization to show that if M=BC\mathbf{M} = \mathbf{B}\mathbf{C} is any full-rank factorization of M\mathbf{M}, then M#=B(CB)−2C\mathbf{M}^{\# } = \mathbf{B}(\mathbf{C}\mathbf{B})^{-2}\mathbf{C}. In particular, if M=U1DV1∗\mathbf{M} = \mathbf{U}_1\mathbf{D}\mathbf{V}_1^{*} is the full-rank factorization derived from the singular value decomposition, then

M#=U1D−1/2(V1∗U1)−2D−1/2V1∗=U1D−1(V1∗U1)−2V1∗=U1(V1∗U1)−2D−1V1∗. \mathbf{M}^{\# } = \mathbf{U}_1\mathbf{D}^{-1/2}(\mathbf{V}_1^{*}\mathbf{U}_1)^{-2}\mathbf{D}^{-1/2}\mathbf{V}_1^{*} = \mathbf{U}_1\mathbf{D}^{-1}(\mathbf{V}_1^{*}\mathbf{U}_1)^{-2}\mathbf{V}_1^{*} = \mathbf{U}_1(\mathbf{V}_1^{*}\mathbf{U}_1)^{-2}\mathbf{D}^{-1}\mathbf{V}_1^{*}.
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