Section 4.3

Covering transformations

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Problem 4.3.1

If p:A→Bp : A \to B is a covering map, then a homeomorphism T:A→AT : A \to A with pT=ppT = p is called a covering transformation. Suppose p:A→Bp : A \to B is a covering map, p(a1)=p(a2)=bp(a_1) = p(a_2) = b and Gi=p∗(π1(A,ai))⊂π1(B,b)G_i = p_*(\pi_1(A, a_i)) \subset \pi_1(B, b). Suppose that T:A→AT : A \to A is a covering transformation with T(a1)=a2T(a_1) = a_2. Show that G1=G2G_1 = G_2.

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Problem 4.3.2

Suppose p:A→Bp : A \to B is a covering map with p(a1)=p(a2)=bp(a_1) = p(a_2) = b. Show that there is a covering transformation T:A→AT : A \to A with T(a1)=a2T(a_1) = a_2 iff p∗(π1(A,a1))=p∗(π1(A,a2))p_*(\pi_1(A, a_1)) = p_*(\pi_1(A, a_2)).

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Problem 4.3.3

Show that the set of all covering transformations of p:A→Bp : A \to B forms a group, which we denote GpG_p, under the operation of composition of homeomorphisms.

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Problem 4.3.4

Show that if T1,T2T_1, T_2 are covering transformations with T1(a)=T2(a)T_1(a) = T_2(a) for some a∈Aa \in A, then T1=T2T_1 = T_2.

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Problem 4.3.5

Consider the homeomorphism Tn:R→RT_n : \mathbb {R} \to \mathbb {R}, Tn(x)=x+nT_n(x) = x + n, n∈Zn \in \mathbb {Z}. Let p:R→S1p : \mathbb {R} \to S^1 be the standard covering map p(t)=e2πitp(t) = e^{2\pi i t}.

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(a)

Show that pTn=ppT_n = p.

(b)

Show that if f1,f2f_1, f_2 are two liftings of a loop f:I→S1f : I \to S^1, then for n=f2(0)−f1(0)n = f_2(0) - f_1(0) we have Tnf1=f2T_n f_1 = f_2.

Problem 4.3.6

Show that if T:R→RT : \mathbb {R} \to \mathbb {R} is a covering transformation, then T=TnT = T_n for some nn (Exercise 4.3.5). Conclude that Gp≃ZG_p \simeq \mathbb {Z} for (R,p,S1)(\mathbb {R}, p, S^1).

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Problem 4.3.7

Find the group of covering transformations of the covering p:S2→Pp : S^2 \to P, p(x)=[x]p(x) = [x] (where P=S2/x∼−xP = S^2/x \sim -x and [x][x] denotes the equivalence class of xx).

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Problem 4.3.8

Find the group of covering transformations of the covering pm:S1→S1p_m : S^1 \to S^1, pm(z)=zmp_m(z) = z^m (see Exercise 4.1.3).

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Problem 4.3.9

Consider the covering space of S1∨S1S^1 \vee S^1 from Exercise 4.2.8. Show that there is no covering transformation sending v1v_1 to v2v_2.

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Problem 4.3.10

Prove the following theorem: Suppose p:A→Bp : A \to B is a covering space with p(a)=bp(a) = b and π1(A,a)≃{e}\pi_1(A, a) \simeq \left\{ e\right\}. Then the group of covering transformations GpG_p is isomorphic to the fundamental group π1(B,b)\pi_1(B, b).

Follow the outline below. Define a map r:Gp→π1(B,b)r : G_p \to \pi_1(B, b) as follows. Given T∈GpT \in G_p, let ss be a path in AA connecting aa and T(a)T(a), and let r(T)=[ps]r(T) = [ps]. Prove that rr is an isomorphism as follows.

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(a)

Show that if ss is homotopic rel {0,1}\left\{ 0,1\right\} to s′s', then ps∼ps′ps \sim ps'.

(b)

Use π1(A,a)≃{e}\pi_1(A, a) \simeq \left\{ e\right\} to conclude that any two paths connecting aa and T(a)T(a) are homotopic rel {0,1}\left\{ 0,1\right\} and so rr is well defined.

(c)

Show that rr is a homomorphism.

(d)

Show that rr is 11--11.

(e)

Show rr is onto.

Problem 4.3.11
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(a)

Suppose p:A→Bp : A \to B is a covering space with p(ai)=bp(a_i) = b, i=1,2i = 1, 2. Let Gi=p∗(π1(A,ai))⊂π1(B,b)G_i = p_*(\pi_1(A, a_i)) \subset \pi_1(B, b). Show that if there is a covering transformation T:A→AT : A \to A with T(a1)=a2T(a_1) = a_2, then G1=G2G_1 = G_2, and if we call this common subgroup GG, there is an element g∈π1(B,b)g \in \pi_1(B, b) with gGg−1=GgGg^{-1} = G, where gg is represented by a loop which lifts to a path from a1a_1 to a2a_2.

(b)

For the converse, suppose that G=p∗(π1(A,ai))G = p_*(\pi_1(A, a_i)), i=1,2i = 1, 2, and gGg−1=GgGg^{-1} = G, where g∈π1(B,b)g \in \pi_1(B, b) is represented by a loop which lifts to a path from a1a_1 to a2a_2. Show that there is a covering transformation T:A→AT : A \to A which sends a1a_1 to a2a_2.

Problem 4.3.12

Use Exercise 4.3.11 to give another argument for Exercise 4.3.9.

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Problem 4.3.13

The normalizer N(H)N(H) of a subgroup H⊂GH \subset G is the subgroup {g∈G:gHg−1=H}\left\{ g \in G : gHg^{-1} = H\right\}. Prove the following theorem, which generalizes Theorem 4.3.1 (Exercise 4.3.10): there is an isomorphism between the group of covering transformations GpG_p of p:A→Bp : A \to B and the quotient N(H)/HN(H)/H of H=p∗(π1(A,a))⊂π1(B,b)H = p_*(\pi_1(A, a)) \subset \pi_1(B, b).

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Problem 4.3.14

Show that there is a bijection between

{c∈p−1(b):there is a covering transformation T with T(a)=c} \left\{ c \in p^{-1}(b) : \text{there is a covering transformation } T \text{ with } T(a) = c\right\}

and N(H)/HN(H)/H (notation as in Exercise 4.3.13).

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Problem 4.3.15
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(a)

Suppose that H=p∗(π1(A,a))H = p_*(\pi_1(A, a)) is a normal subgroup of π1(B,b)\pi_1(B, b). Then show that for every pair of points a1,a2a_1, a_2 in the pre-image p−1(b)p^{-1}(b), there is a covering transformation TT with T(a1)=a2T(a_1) = a_2.

(b)

Show that the converse is true: whenever it is the case that for every pair of points a1,a2a_1, a_2 in the pre-image p−1(b)p^{-1}(b), there is a covering transformation TT with T(a1)=a2T(a_1) = a_2, then H=p∗(π1(A,a))H = p_*(\pi_1(A, a)) is a normal subgroup of π1(B,b)\pi_1(B, b).

Problem 4.3.16

A group GG of homeomorphisms of a space AA is called properly discontinuous if for every a∈Aa \in A there is an open set UU containing aa such that g(U)g(U) is disjoint from UU whenever g≠eg \neq e. Show that if GG is a group of homeomorphisms which is properly discontinuous, then for every a∈Aa \in A there is an open set UU containing aa such that g0(U)∩g1(U)=∅g_0(U) \cap g_1(U) = \emptyset for all g0≠g1∈Gg_0 \neq g_1 \in G.

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Problem 4.3.17

Recall that a covering space p:A→Bp : A \to B is called regular if p∗(π1(A,a))p_*(\pi_1(A, a)) is a normal subgroup of π1(B,b)\pi_1(B, b); by Exercise 4.3.15, this is equivalent to the group of covering transformations acting transitively on p−1(b)p^{-1}(b). Recall also that a group GG of homeomorphisms of a space AA is properly discontinuous (Exercise 4.3.16) if for every a∈Aa \in A there is an open set UU containing aa such that g(U)∩U=∅g(U) \cap U = \emptyset whenever g≠eg \neq e.

Suppose that AA is path connected and locally path connected and GG is a group of homeomorphisms of AA. Let A/GA/G denote the quotient space formed from AA, where a∼g(a)a \sim g(a) for g∈Gg \in G.

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(a)

Show that the quotient map q:A→A/Gq : A \to A/G is a covering map iff the action of GG is properly discontinuous.

(b)

Show that when the conditions of (a) are satisfied, then the covering map q:A→A/Gq : A \to A/G is regular and GG is its group of covering transformations.

Problem 4.3.18

Prove the following theorem (characterization of regular covering spaces): suppose p:A→Bp : A \to B is a regular covering space (Exercise 4.3.17) and GG is its group of covering transformations. Then p=hqp = hq, where q:A→A/Gq : A \to A/G is the quotient covering space and hh is a homeomorphism induced by pp via the quotient construction.

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