Section 4.1

Basic examples and properties

[21/100%]
Show
LaTeX
Problem 4.1.1

Show that whenever p:A→Bp : A \to B is a covering map and CC is a path-connected, locally path-connected Hausdorff space, then P:A×C→B×CP : A \times C \to B \times C, P(a,c)=(p(a),c)P(a, c) = (p(a), c) is a covering map.

?
Problem 4.1.2

Show that if p1:A1→B1p_1 : A_1 \to B_1, p2:A2→B2p_2 : A_2 \to B_2 are covering maps, then so is P:A1×A2→B1×B2P : A_1 \times A_2 \to B_1 \times B_2, P(a1,a2)=(p1(a1),p2(a2))P(a_1, a_2) = (p_1(a_1), p_2(a_2)).

?
Problem 4.1.3

Show that pm:S1→S1p_m : S^1 \to S^1, pm(z)=zmp_m(z) = z^m (complex multiplication) --- or, equivalently, p(cos⁡x,sin⁡x)=(cos⁡mx,sin⁡mx)p(\cos x, \sin x) = (\cos mx, \sin mx) --- is a covering map.

?
Problem 4.1.4

Show that if AA is compact, and p:A→Bp : A \to B is a covering map, then for any b∈Bb \in B, p−1(b)p^{-1}(b) consists of a finite number of points.

?
Problem 4.1.5

Using the framework of Exercise 4.1.4 (that AA is compact and p:A→Bp : A \to B is a covering map), show that since BB is assumed path connected, then the number of points in p−1(b)p^{-1}(b) does not depend on bb.

?
Problem 4.1.6

Recall that the order of a covering map is the (constant) number of points in each inverse image p−1(x)p^{-1}(x); when this number is a finite kk, the covering is called a kk-fold cover.

?
(a)

Show that Pm,n:S1×S1→S1×S1P_{m,n} : S^1 \times S^1 \to S^1 \times S^1, Pm,n(z,w)=(zm,wn)P_{m,n}(z, w) = (z^m, w^n), is a covering space.

(b)

Show that the order of this cover is mnmn.

Problem 4.1.7

Consider the cover P2,1:T→TP_{2,1} : T \to T given by Exercise 4.1.6. Figure 4.1(a) pictures this cover. Now change the base space to T(2)T^{(2)} by using the same construction used to get TT from S2S^2 (doing surgery by removing two disks and replacing them with a cylinder), and in the top space TT do this surgery twice, as pictured in Figure 4.1(b).

Constructing a cover p : T^{(3)} \to T^{(2)}.Constructing a cover p : T^{(3)} \to T^{(2)}.

?
(a)

Show that the construction described above leads to a double covering P:T(3)→T(2)P : T^{(3)} \to T^{(2)}.

(b)

By starting with Pm,1P_{m,1}, construct an mm-fold cover p:T(m+1)→T(2)p : T^{(m+1)} \to T^{(2)}.

Problem 4.1.8

Continuing with the surgery construction of Exercise 4.1.7 and starting with Pm,1P_{m,1} but now performing nn surgeries on the base space, construct an mm-fold cover p:T(mn+1)→T(n+1)p : T^{(mn+1)} \to T^{(n+1)}.

?
Problem 4.1.9

Recall (from the study of nonorientable surfaces) that there are 2-fold covering spaces p:S→Pp : S \to P and p:T→Kp : T \to K, where S,TS, T are the sphere and torus and P,KP, K are the projective plane and Klein bottle. New covering spaces can be obtained from these by doing surgery (removing a disk from both the covering space and the base space, in a way compatible with the covering map, and replacing each by a handle) as in Exercises 4.1.7-4.1.8. Show that there is a 2-fold covering space pn:T(2n)→P(2n+1)p_n : T^{(2n)} \to P^{(2n+1)}.

?
Problem 4.1.10

Show that there is a 2-fold covering space pn:T(2n+1)→P(2n+2)p_n : T^{(2n+1)} \to P^{(2n+2)}.

?
Problem 4.1.11

Start with K=S1×S1/(z,w)∼(−z,w‾)K = S^1 \times S^1 / (z, w) \sim (-z, \overline{w}) (the usual construction of the Klein bottle KK as a quotient of the torus). For nn odd, form a new space Kn=S1×S1/(z,w)∼(eπi/nz,w‾)K_n = S^1 \times S^1 / (z, w) \sim (e^{\pi i/n} z, \overline{w}); note that n=1n = 1 gives back the usual construction of KK. There is a natural map from KK to KnK_n induced by the identity map of T=S1×S1T = S^1 \times S^1 to itself (well defined because nn is odd, so that (z,w)∼(−z,w‾)(z, w) \sim (-z, \overline{w}) is part of the equivalence relation defining KnK_n). Show that KnK_n is homeomorphic to KK.

?
Problem 4.1.12

For each of the finite covering spaces p:A→Bp : A \to B of surfaces constructed by surgery in Exercises 4.1.6-4.1.11, verify that there is a formula

χ(A)=kχ(B) \chi (A) = k \chi (B)

relating the Euler characteristics of AA and BB, where kk is the order of the cover.

?
Problem 4.1.13

Assuming the formula χ(A)=kχ(B)\chi (A) = k\chi (B) for surfaces (Exercise 4.1.12), show that the only surfaces without boundary that can cover themselves with order k>1k > 1 are TT (the torus) and KK (the Klein bottle).

?
Problem 4.1.14

Suppose that p:A→Bp : A \to B is a covering map of finite order kk from one surface to another and we have a handle decomposition of BB where each handle lies within an evenly covered neighborhood.

?
(a)

Then there is an equivariant handle decomposition of AA with kk ii-handles for each ii-handle of BB.

(b)

Use (a) to show that χ(A)=kχ(B)\chi (A) = k \chi (B).

Problem 4.1.15

Let WW be the wedge Sa1∨Sb1S^1_a \vee S^1_b of two circles, labeled a,ba, b. A covering space of order 22 can be pictured by labeling the cover with a1,a2,b1,b2a_1, a_2, b_1, b_2. Figure 4.2 shows one example, in which each circle of WW is double covered by a single circle.

A double cover of S^1 \vee S^1.A double cover of S^1 \vee S^1.

There are two other nonequivalent 2-fold covering spaces of WW, other than the one pictured above. Give pictures of them.

?
Problem 4.1.16

Figure 4.3 shows a 3-fold cover of W=Sa1∨Sb1W = S^1_a \vee S^1_b. The edges labeled aa are mapped to one circle and those labeled bb are mapped to the other.

A three-fold cover of S^1 \vee S^1.A three-fold cover of S^1 \vee S^1.

Give pictures of two different nonequivalent 3-fold covering spaces of WW from the one given in Figure 4.3.

?
Remark.
?

There are more than two others, so there are many answers possible.

Problem 4.1.17

Prove the following lemma: Suppose p:A→Bp : A \to B is a covering map and U⊂BU \subset B is a path-connected open set which is evenly covered, with p−1(U)=⋃iUip^{-1}(U) = \bigcup_i U_i, and b∈Ub \in U. Let ai∈Uia_i \in U_i satisfy p(ai)=bp(a_i) = b. If XX is connected and f:X→Bf : X \to B is continuous with f(X)⊂Uf(X) \subset U, f(x)=bf(x) = b, then there is a unique lift f~i\tilde{f}_i of ff with f~i(x)=ai\tilde{f}_i(x) = a_i. Moreover, f~i(X)⊂Ui\tilde{f}_i(X) \subset U_i.

?
Problem 4.1.18

Prove the unique path lifting theorem: Suppose p:A→Bp : A \to B is a covering map with p(a)=bp(a) = b. Given a path f:I→Bf : I \to B with f(0)=bf(0) = b, there is a unique path f~:I→A\tilde{f} : I \to A with f~(0)=a\tilde{f}(0) = a and pf~=fp\tilde{f} = f.

?
Problem 4.1.19

Suppose r:I→Br : I \to B is a path in BB with r(0)=b1r(0) = b_1 and r(1)=b2r(1) = b_2. Define a map from p−1(b1)p^{-1}(b_1) to p−1(b2)p^{-1}(b_2) as follows: for each a∈p−1(b1)a \in p^{-1}(b_1), let rar_a be the unique path lifting of rr with ra(0)=ar_a(0) = a. Then send aa to ra(1)r_a(1). Show that this defines a bijection between p−1(b1)p^{-1}(b_1) and p−1(b2)p^{-1}(b_2).

?
Problem 4.1.20

Prove the following theorem: Suppose that F:(I×I,{0}×I,1×I)→(B,b1,b2)F : (I \times I, \left\{ 0\right\} \times I, 1 \times I) \to (B, b_1, b_2) is a homotopy between f0,f1f_0, f_1, and p(a)=b1p(a) = b_1.

?
(a)

There is a unique lifting F~\tilde{F} with F~(0,0)=a\tilde{F}(0,0) = a.

(b)

If f~0,f~1\tilde{f}_0, \tilde{f}_1 are liftings with f~0(0)=f~1(0)=a\tilde{f}_0(0) = \tilde{f}_1(0) = a, then f~0(1)=f~1(1)\tilde{f}_0(1) = \tilde{f}_1(1).

Problem 4.1.21

Utilize Exercise 4.1.20 to define a map from π1(B,b)\pi_1(B, b) to p−1(b)p^{-1}(b) as follows: assign to [f][f] the point f~(1)\tilde{f}(1), where f~\tilde{f} is the unique path lifting of ff with f~(0)=a\tilde{f}(0) = a.

?
(a)

Use the assumption that AA is path connected to show that this map is onto.

(b)

Let G⊂π1(B,b)G \subset \pi_1(B, b) be the subset of [f][f] with f~(1)=a\tilde{f}(1) = a. Show that GG is a subgroup of π1(B,b)\pi_1(B, b).