Section III.5.6

Rigidity and rationality in finite groups

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Problem III.5.6.1

Let G,HG, H be finite groups with strongly rigid families

S~(K1,…,Km),S~(K1′,…,Km′′) \tilde{\mathcal{S}}\left(\mathcal{K}_{1}, \ldots , \mathcal{K}_{m}\right), \quad \tilde{\mathcal{S}}\left(\mathcal{K}_{1}^{\prime }, \ldots , \mathcal{K}_{m^{\prime }}^{\prime }\right)

Show that then

S~(Ki×Kj′∣1⩽i⩽m,1⩽j⩽m′) \tilde{\mathcal{S}}\left(\mathcal{K}_{i} \times \mathcal{K}_{j}^{\prime } \mid 1 \leqslant i \leqslant m, 1 \leqslant j \leqslant m^{\prime }\right)

is a strongly rigid family in G×HG \times H.

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Problem III.5.6.2

Let σ\sigma be an outer automorphism of a finite group, and let (K1,…,Km\mathcal{K}_{1}, \ldots , \mathcal{K}_{m}) be a rigid family of conjugacy classes in GG. Show that then σ(Ki)≠Ki\sigma \left(\mathcal{K}_{i}\right) \neq \mathcal{K}_{i} for some ii.

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Problem III.5.6.3

Show that in the alternating group A5A_{5}, with the conjugacy classes 1A,2A,3A,5A,5B1 A, 2 A, 3 A, 5 A, 5 B already known to us, the triples

(2A,3A,5A),(2A,5A,5B),(3A,5A,5B) (2 A, 3 A, 5 A), \quad (2 A, 5 A, 5 B), \quad (3 A, 5 A, 5 B)

are strongly rigid. It follows from this that A5≅GalF/Q(5)A_{5} \cong \mathrm{Gal} F / \mathbb {Q}(\sqrt{5}).

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Problem III.5.6.4

Denote by K1(z)K_{1}(z) the number of representations of an element zz of a finite group GG as a commutator, i.e., the number of solutions of the equation z=xyx−1y−1z=x y x^{-1} y^{-1}. Show that

K1(z)=∣G∣∑i=1rχi(z)χi(e) K_{1}(z)=\left|G\right| \sum _{i=1}^{r} \frac{\chi _{i}(z)}{\chi _{i}(e)}

More generally: if Km(z)K_{m}(z) is the number of solutions of the equation

z=(x1y1x1−1y1−1)(x2y2x2−1y2−1)…(xmymxm−1ym−1) z=\left(x_{1} y_{1} x_{1}^{-1} y_{1}^{-1}\right)\left(x_{2} y_{2} x_{2}^{-1} y_{2}^{-1}\right) \ldots \left(x_{m} y_{m} x_{m}^{-1} y_{m}^{-1}\right)

then

Km(z)=∣G∣2m−1∑iχi(z)χi(e)2m−1 K_{m}(z)=|G|^{2 m-1} \sum _{i} \frac{\chi _{i}(z)}{\chi _{i}(e)^{2 m-1}}
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